Bong-Kee Lee
School of Mechanical Systems Engineering Chonnam National University
Engineering Mathematics I
5. Series Solutions of ODEs. Special Functions
5.1 Power Series Method
n계 선형상미분방정식
p
x y p
xy p
x y r
x yn n1 n1 1 ' 0 a y ay ay r
xyn n1 n1 1 ' 0
1 1 0 0
1
an n a a
n
characteristic equation ex
y
x y
x y
x y h pgeneral solution of nonhomogeneous ODE
x cy cnyny 1 1 general solution of homogeneous ODE
constant coefficients
School of Mechanical Systems Engineering Engineering Mathematics I
5.1 Power Series Method
거듭제곱급수(멱급수, power series) 해법
– 변수계수를 가지는 선형상미분방정식을 풀이하는 표준해 법
• 해의 수치적 값을 계산하거나 특성을 조사하는데 사용됨
• 해에 대한 다른 표현을 유도하는데 사용됨
거듭제곱급수
– x – x
0의 거듭제곱을 가지는 무한급수의 형태
– x
0= 0 인 경우
2 0 2 0 1 0 0
0 a a x x a x x
x x a
m
m m
coefficient center
2 2 1 0 0
x a x a a x a
m m m
5.1 Power Series Method
거듭제곱급수
– 거듭제곱급수의 예: Maclaurin 급수
! 5
! 3
! 1 2 sin 1
! 4
! 1 2
! 2 cos 1
! 3
! 1 2
! 1 1
1
5 3
0
1 2
2 2
0 2
3 2
0
2 0
2 2 1 0 0
x x x m x x
x x m
x x
x x x m e x
x x x x
x a x a a x a
m m m m
m m m
m x
m m m
m m
School of Mechanical Systems Engineering Engineering Mathematics I
5.1 Power Series Method
거듭제곱급수 해법의 개념
m m
m m m
m m
m m m
a
y x q y x p y y y y
x a a x a m m y
x a x a a x ma y
x a x a x a a x a y x q x p
y x q y x p y
obtain
0 '
'' , ' , ''
2 3 2 1
''
&
3 2 '
&
solution
series power
~ ,
0 '
''
3 2 2
2
2 3 2 1 1
1
3 3 2 2 1 0 0
5.1 Power Series Method
거듭제곱급수 해법의 개념
2 0 6
4 2 0
0 6 0 4 2 0 0 3 3 2 2 1 0
0 2 6 0 2 4 0 2
2 6 2 4 0 2 5
3 1
3 5 2 4 1 3 0 2 1
4 3 3 2 2 1 0
3 3 2 2 1 0 2
3 2 1
2 3 2 1 1
1 3
3 2 2 1 0 0
! 3
! 1 2
! 3
! 2
!, 3 , 3
! 2 , 2
3, 2, ,
&
0
2 5 , 2 4 , 2 3 , 2 2 , 0
2 2 2 2
2 3
2
3 2 '
2 ' example
x
m m m m
m m
e x a
x x a
a x a x x a a x a x a x a a y
a a a
a a a
a a
a a a a a a a
a a
a a a a a a a a a
x a x a x a x a
x a x a x a a x x
a x a a
x a x a a x ma y x
a x a x a a x a y
xy y
School of Mechanical Systems Engineering Engineering Mathematics I
5.1 Power Series Method
거듭제곱급수 해법의 개념
– 첨수이동(shift of index)
2, 3 3 , 1 5 0 , 2 2 2 , 1 3 0 , 2
2 2 2
2 , 0
2 2
2 2
2 ' '
&
0 4 6 3 5 0 2 4 1 3 0 2
2 2
1
0 1 0
1 2 1
0 1 2
1 1
0 1
1 1
1 0
a a a a a a
a a a a a a
s a a a a s a
x a x
a s a
x a x
ma a x a x x ma
xy y x ma y x a y
s s
s s
s s s s
s s
m m m m
m m m
m m m
m m
m m m m
m m
m – 2 = s m = s
5.1 Power Series Method
거듭제곱급수 해법의 개념
x a x x a
x x x a
a x
x a x a x a x a x a a x a y
a a a
a a a
a a a a
s s s a a a a s s
x a x
a s s x
a x
a m m
x a m m y x ma y x a y
y y
m m m
s s
s s
s s s s
s s m
m m m
m m
m
m m m
m m m
m m
sin
! cos 5
! 3
! 4
! 1 2
!, 5 4 , 5
! 4 3 , 4
! , 3
! 2
, 2 , 1 , 0 1 1 2
2
1 2 1
1 ''
, '
0 '' example
1 0
5 3 1 4
2 0
5 5 4 4 3 3 2 2 1 0 0
1 3 5 0 2 4 1 3 0 2
2 2
0 0
2 0
2
2
2
2 1
1 0
순환공식, 점화공식 (recursion formula)
School of Mechanical Systems Engineering Engineering Mathematics I
5.2 Theory of the Power Series Method
거듭제곱급수 해법의 이론
– 기본 개념
• 거듭제곱급수: 무한급수의 형태
• n-번째까지의 부분합(n-th partial sum)
• 나머지(remainder)
• 수렴 및 발산: x = x1에서 수렴한다
2 0 2 0 1 0 0
0 a a x x a x x
x x a
m
m m
n
nn x a a x x a x x a x x
s 0 1 0 2 0 2 0
n1
0
n1 n2
0
n2n x a x x a x x
R
1
10
0 1 1
lims x1 s x a x x sn x Rn x
m
m m
n n
수렴값
5.2 Theory of the Power Series Method
거듭제곱급수 해법의 이론
– 기본 개념
• 수렴
• 세 가지 대표적인 경우
– 경우 1. 무용: x = x0 에서만 유일하게 수렴하는 경우 – 경우 2. 보통: 수렴구간 내에서 수렴하는 경우
– 경우 3. 유용: 모든 구간에서 수렴하는 경우 (수렴구간이 무한대)
x s
x s
x n N Rn 1 1 n 1 for R x x 0
중점(midpoint) 수렴반지름
m m m m
m m
a a R a R
lim 1
or 1 lim
1
School of Mechanical Systems Engineering Engineering Mathematics I
5.2 Theory of the Power Series Method
거듭제곱급수 해법의 이론
0
as
! 1
!
! 1
6 2 1
! 1
1
3 2 0
R
m m m
m a m a a
x x x x m
m m m
m
m
1
as 1 1 1
1 1 1
2 1
1
3 2 0
R
a m a a
x x x x x x
m m m
m
m
R
m m m
m a a a m
x x m e x
m m m
m m x
as 1 0 1
! 1
!
! 1
! 1 2 3 !
1 2
0
2 8 0
8
8 1 8
8 8
1
512 64 1 8
8 4 1
3 3
1 1
9 6 3
0 3
x x
R x R
a a a
x x x x
m m
m m m
m
m m
m m
m
5.2 Theory of the Power Series Method
거듭제곱급수 해법의 이론
– 거듭제곱급수의 연산
• 항별 미분(termwise differentiation)
• 항별 덧셈(termwise addition)
• 항별 곱셈(termwise multiplication)
• 모든 계수가 0이 됨(vanishing of all coefficients)
– 만일 어떤 거듭제곱급수가 양의 수렴반지름을 갖고, 수렴구간 전체 에서 합이 항등적으로 0이라면, 급수의 모든 계수는 0이다.
1
1 0 0
0 '
m
m m m
m
m x x y x ma x x
a x y
0
0 0
0 0
0
m
m m m m
m m m
m
m x x b x x a b x x
a x g x f
0
0 0 1
1 0 0
0 0
0
m
m m
m m m
m m m
m
m x x b x x ab ab a b x x
a x g x
f
School of Mechanical Systems Engineering Engineering Mathematics I
5.2 Theory of the Power Series Method
거듭제곱급수 해법의 이론
– 실수 해석함수(real analytic function)
• 실수함수 f(x)가 수렴반지름 R>0을 갖고, x – x0의 거듭제곱급수로 나타내어지면, f(x)는 x = x0에서 해석적이라 한다.
– 거듭제곱급수 해의 존재
0.and~ at
analytic
~ are ' ~
'' ~ in ~ and~
~,
~,
~, if true is same the Hence . 0 e convergenc
of radius with of
powers in series power a by d represente be
can thus and at
analytic is solution every then , at analytic are in
and If
solution series power of existence
0 0
0 0
0
x h x x
x r y x q y x p y x h r q p h R
x x x
x
x x x
r y x q y' x p y'' r p, q,
5.3 Legendre’s Equation. Legendre Polynomials
Legendre의 방정식
Adrien-Marie Legendre
spherical coordinate system
1x2
y''2xy'n
n1
y0Legendre function 매개변수(parameter), n
1 0 ' 1 1
'' 22 2
y
x n y n x y x
analytic at x = 0
2
2 1
1 0
1 ''
, '
m
m m m
m m m
m m
x a m m y x ma y
x a y
1
1
2 01
0 1
1 2
2
2
m m m m
m m m
m
mx x ma x k a x
a m m x n n k
1 2
1
0
y nn y dx
x d dx or d
School of Mechanical Systems Engineering Engineering Mathematics I
5.3 Legendre’s Equation. Legendre Polynomials
Legendre의 방정식
0,1,2,
1 2
1
0 1 2
1 1
2
0 1 2
2 1 2 3 4 2 :
0 1 2
2 3 1 :
0 1 1
2 0 :
0 2
1 1
2
0 2
1 1
0 2
1 1
2
2
2 2
2 4 2
1 1
3 1
0 2
0
0 1
2 0
2
0 1
2 2
2
0 1
1 2
2 2
s s a
s s n s a n
a n n s s s a s s
a n n a a a s
x
a n n a a s
x
a n n a s
x
x ka x sa x
a s s x a s s
x ka x ma x
a m m x
a m m
x a k x ma x x a m m x
s s
s s
s s s s
s s s
s s s
s s
m m m m
m m m
m m m
m m
m m m m
m m m
m m
순환공식, 점화공식 (recursion formula)
5.3 Legendre’s Equation. Legendre Polynomials
Legendre의 방정식
5 1
4 0 3
1 2
0 1
0
5 5 4 4 3 3 2 2 1 0 0
1 3 5
1 3
0 2 4
0 2
2
! 5
4 2 1 3
! 4
3 1 2
! 3
2 1
! 2
1
2 3 4 5
4 2 1 3
4 5
4 3
2 3
2 1
1 2 3 4
3 1 2
3 4
3 2 1 2
1
, 2 , 1 , 0 1
2 1
x n a n n n
x n a n n x n
n a x n
n a x n a a
x a x a x a x a x a a x a x y
n a n n n
n a a n
n a a n
n a n n n
n a a n
n a a n
s s a
s s n s a n
m m m
s s
School of Mechanical Systems Engineering Engineering Mathematics I
5.3 Legendre’s Equation. Legendre Polynomials
Legendre의 방정식
5 3
2
4 2
1
2 1 1 0
5 3
1
4 2
0
! 5
4 2 1 3
! 3
2 1
! 4
3 1 2
! 2 1 1
! 5
4 2 1 3
! 3
2 1
! 4
3 1 2
! 2 1 1
n x n n x n
n x n
x y
n x n n x n
n x n
y
x y a x y a x y
n x n n x n
n x n
a
n x n n x n
n a n x y
5.3 Legendre’s Equation. Legendre Polynomials
Legendre 다항식, Pn(x)
1 2
1
0
P x nn P x dx
x d dx
d
n n
1 2
1
0 y nn y dx
x d dx
d Legendre’s equation
Legendre polynomials
x a y
x ay
x y 0 1 1 2음이 아닌 정수, n = s
ss a
s s
s n s a n
1 2
1
2
0 m
m mx a x y
:n-th order polynomial 32 1 0
3 2 1 0
x P n
x P
n x P
n x
P
n x P
n
School of Mechanical Systems Engineering Engineering Mathematics I
5.3 Legendre’s Equation. Legendre Polynomials
Legendre 다항식, Pn(x)
:positiveinteger
& 1! 1 2 5 3 1
! 2
! 2
2 0
n a
n n n
an n n
! 2
!! 2
! 2 1 2
! 2
! 1 2
! 2 2
! 2 1
! 1 2
! 2 2 1 2 2 1 2 2
1
! 2
! 2 1 2 2
1 1
2 2 : 1
2
2 1
1 2 1
2 1
2 2
2 2
2 2
m n m n m
m a n
n n a n
n n n n n
n n n n
n n n n n n a n
n n a n
n s
n s s a
n s n
s a s
s a s
s n s a n
n m m n n
n
n n n
n
s s
s s
integer : 2 or 1 2
! 2
!
! 2
! 2 1 2
0
2
n M n
m x n m n m
m x n
P
M
m
m n n
m
n Legendre polynomials
5.3 Legendre’s Equation. Legendre Polynomials
Legendre 다항식, Pn(x)
x x x x P
x x x
P
x x x P
x x P
x x P
x P
15 70 863 1
3 30 8 35 1
3 2 5 1
1 23 1 1
3 5 5
2 4 4
3 3
2 2
1 0
x P0
xP1
xP2 P3
x
xP4
x P5School of Mechanical Systems Engineering Engineering Mathematics I
5.4 Frobenius Method
Frobenius 해법
– 해석적이지 않은 계수를 가지는 특수한 2계 상미분방정식 의 해법을 제공
– 정리 1. Frobenius method
Ferdinand Georg Frobenius
0 '
'
' 2 y
x x y c x
x y b
x,cx :analyticat x0 b
number complex or real any :
0 0
2 2 1 0 0
r
a x
a x a a x x a x x
y r
m m m
r
5.4 Frobenius Method
Frobenius 해법
– 결정방정식(indicial equation)
1
00 1
1 , for
0
1 1
1
1 1
1 ''
1 '
&
0 '
'' 0 '
''
0 0
0 0 0 0
0 0 0 0
2 2 1 0 2
2 1 0
1 0
2 2 1 0 1
0
1 0
2 0
2
1 0
1 0
1
2 2 1 0 0
2 2 1 0
2 2 1 0
2 2
c r b r r
a c r b r r a c ra b a r r x
x a x a a x x c x c c
x a r ra x x b x b b x ra r a r r x
x ra r a r r x x a r m r m x y
x a r ra x x a r m x y
x a x a a x x a x x x y
c x c c x c
x b x b b x b
y x c y x xb y x x y
x y c x
x y b
r
r
r r
r
m
r m m
r
m
r m m
r
m m m r
School of Mechanical Systems Engineering Engineering Mathematics I
5.4 Frobenius Method
Frobenius 해법
– 정리 2. 해의 기저
• 경우 1. 두 근의 차가 정수가 아닌 서로 다른 근들
• 경우 2. 이중근
• 경우 3. 두 근의 차가 정수인 서로 다른 근들
2 2 1 0 2
2 2 1 0 1
2 1
x A x A A x x y
x a x a a x x y
r r
integer
2 1r r
2
1 r
r r
integer
2 1r r
0
ln 1 2 2
1 2
2 2 1 0 1
x x
A x A x x x y x y
x a x a a x x y
r r
0 be may
&
0 ln
2 1
2 2 1 0 1
2
2 2 1 0 1
2 1
k r r
x A x A A x x x ky x y
x a x a a x x y
r r
5.4 Frobenius Method
Frobenius 해법
2 2 1 0 2
2 1 0 1
2 0
2 0
0 1
0 0
1 0
0
1 0
0
2 0
1 0
2
root double : 0 0 0
0 1
0 3
1 1
1 ''
, '
0 at analytic 1 : 1,
1 3
1 0 ' / 1 / 1 '' 3 1 0
' 1 1 1 '' 3
0 ' 1 3 '' 1 example
x a x a a x
a x a a x x y
r r
a r ra a r r x
x a x
a r m x
a r m
x a r m r m x
a r m r m
x a r m r m y x a r m y x a x y
x x x x x c x x b
x y x y x x
x y x
x y y x x x y x
y y x y x x
r r
m r m m m
r m m m
r m m
m
r m m m
r m m
m
r m m m
r m m m
m m r