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MAPPING PROPERTIES OF THE MARCINKIEWICZ INTEGRALS ON HOMOGENEOUS GROUPS

Youngwoo Choi and Kyung Soo Rim

Abstract. Under the cancellation property and the Lipschitz con- dition on kernels, we prove that the Marcinkiewicz integrals de- fined on a homogeneous group H are bounded from H

1

(H) to L

1

(H), from L

c

(H) to BM O (H), and from L

p

(H) to L

p

(H) for 1 < p < ∞ assuming the L

q

-boundedness for some q > 1.

1. Introduction

Stein [8] defined a higher dimensional analogue of the Marcinkiewicz integral by

(1.1) µ f (x) =

Z ∞ 0

|F t (x)| 2 dt t 3



12

, where

F t (x) = Z

|y−x|<t

Ω (x − y)

|x − y| n−1 f (y) dy,

Ω is a homogeneous function of degree zero whose restriction to S n−1 belongs to Λ α S n−1  and satisfies the cancellation property,

Z

S

n−1

Ω(x ) dσ x 

= 0.

Here, S n−1 denotes the unit sphere in R n and Λ α S n−1  denotes the Lipschitz space of order α on S n−1 . The continuity of Marcinkiewicz

Received June 26, 2000. Revised April 19, 2001.

2000 Mathematics Subject Classification: Primary 42B20; Secondary 47B38.

Key words and phrases: Marcinkiewicz integrals, homogeneous groups.

The first author was supported by grant No. 1999-2-112-004-3 from the Interdis-

ciplinary Research program of the KOSEF.

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integrals is very useful in harmonic analysis [9, 10, 15]. Stein [8] proved that if Ω is in Λ α S n−1  with 0 < α ≤ 1, then

(1.2)

{x ∈ R n : µ Ω f (x) > λ}

≤ C

λ kf k L

1

and

(1.3) kµ Ω f k L

p

≤ C p kf k L

p

,

where 1 < p ≤ 2, and if Ω is an integrable odd function, then (1.4) kµ Ω f k L

p

≤ C p kf k L

p

for 2 < p < ∞.

The problem most immediately suggested by Marcinkiewicz [7], who conjectured the L p -boundedness of (1.1) for n = 1 and for Ω(t) = sign t until Zygmund [14] proved that the conjecture holds for 1 < p < ∞, has been extensively studied beginning with the 1958’s article of Stein [8].

Benedek, Calderon and Panzone [1] proved that if Ω ∈ C 1 (R n \ {0}) is a homogeneous function of degree zero satisfying the cancellation property, then µ Ω is bounded on L p (H) for 1 < p < ∞. Torchinsky and Wang considered the weighted L p -boundedness of µ , and showed that if Ω is in Λ α S Q−1  and µ Ω is bounded on L p (R n ) for 1 < p < ∞, then for ω satisfying an A p condition, µ is bounded on L p (ω) [13]. Further results on (1.1) were obtained when Ω satisfies some smoothness conditions [1], [8] and [13].

In this paper, we prove the H 1 -L 1 , L c -BM O and L p -L p (1 < p < ∞) boundedness of Marcinkiewicz integrals defined on homogeneous groups under the cancellation property and the Lipschitz condition on Ω and under the L q -boundedness of µ .

This paper is organized as follows: in the next section, some prelim- inary materials are introduced. The main theorem is stated in Section 3. End-point results appear in Sections 4 and 5. Combined with an in- terpolation argument, the L p boundedness for 1 < p < ∞ will be shown in Section 6.

2. Preliminaries and notations

In this section, we introduce notations related to homogeneous groups

along with some preliminary materials. Mainly, we follow [6].

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2.1. Homogeneous groups

A nilpotent Lie group H with a dilation group {δ r } r>0 is said to be a homogeneous group. The dilation group is given by

δ r = exp (A ln r)

with a suitable matrix A having positive eigenvalues.

H has a natural homogeneous norm | · |, and the homogeneous di- mension Q. Abusing the notation, the bi-invariant measure on H will be denoted by | · |.

Remark 2.1. Let H, {δ r }, | · | and Q be as above. The eigenvalues of the matrix defining {δ r } are listed as 1 = d 1 ≤ d 2 ≤ · · · ≤ d n and we let ¯ d = max {d i : i = 1, · · · , n}.

1. |δ r x| = r|x| for each x ∈ H, r > 0.

2. There exist C 1 , C 2 > 0 such that

C 1 kxk ≤ |x| ≤ C 2 kxk d ¯ whenever |x| ≤ 1.

Here, k·k denotes the euclidean norm.

3. There exists a constant γ > 0 such that for all x, y ∈ H,

|x ◦ y| ≤ γ(|x| + |y|) for all x ∈ H (2.1)

|x ◦ y| − |x|

≤ γ|y| for all x, y ∈ H such that |y| ≤ |x|/2.

(2.2)

4. |δ r E| = r Q |E|.

5. We let

S = {x ∈ H : |x| = 1} .

There is a unique Radon measure σ on S such that for all f ∈ L 1 (H),

Z

H

f (x) dx = Z ∞

0

Z

S

f (δ r y)r Q−1 dσ(y) dr.

2.2. The Hardy space H 1 (H)

For the definition of the Hardy space H 1 (H), we refer the interested

readers to [6].

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2.2.1. H q,0 1 -atoms. Let q ∈ (1, ∞]. A function a(x) on H is said to be an H q,0 1 -atom (associated to a ball B) if it satisfies the following conditions:

(a) a(x) is supported in ¯ B;

(b) |a(x)| ≤ |B|

1q

−1 almost everywhere; and (c) R

H a(x) dx = 0.

Remark 2.2. Let a(x) be an H ∞,0 1 -atom. Then we have kak L

1

(H) ≤ 1.

(2.3)

2.3. Atomic decomposition

An equivalent way of looking at H 1 (H) is the decomposition of ele- ments in H 1 (H) into H q,0 1 -atoms.

Theorem 2.1 (Decomposition Theorem). Let q ∈ (1, ∞]. For f ∈ H 1 (H) there exist a collection of H q,0 1 atoms {a k } k∈N and a sequence of nonnegative real numbers {λ k } k∈N with P

k=1 λ k < ∞ so that f =

X

k=1

λ k a k

in the sense of distributions, and we have kf k H

1

X

k=1

λ k .

2.4. BMO

Definition 2.3. A locally integrable function f : H → C is said to be in BM O if there exists a constant C such that for each ball B

1

|B|

Z

B

|f (x) − f B | dx ≤ C, holds, where

f B = 1

|B|

Z

B

f (x) dx.

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3. Marcinkiewicz integrals

Let Ω be a measurable function on a homogeneous group H, which is homogeneous of degree 0 in the sense that

Ω (δ r x) = Ω(x)

holds for a.e. x ∈ H \ {0} and r > 0. We define the Marcinkiewicz integral µ f as follows:

(3.1) µ f (x) =

Z

0

|F t (x)| 2 dt t 3



12

, where

F t (x) = Z

B

t

(x)

Ω x ◦ y −1 

|x ◦ y −1 | Q−1 f (y) dy.

We will study the mapping properties of µ . To be more specific, we will prove:

Theorem 3.1. Let H, Ω and µ be as above. We assume the follow- ing:

• Ω

S ∈ Λ α (S);

• R

S Ω (x ) dσ (x ) = 0; and

• µ Ω is bounded in L q (H) for some q > 1.

Then the following inequalities hold:

f k L

1

≤ C 1 kf k H

1

, f ∈ H 1 (H) (3.2)

kµ Ω f k BM O ≤ C ∞ kf k L

, f ∈ L c (H) (3.3)

and

f k L

p

≤ C p kf k L

p

, f ∈ L p (H) (3.4)

for 1 < p < ∞.

4. H 1 -L 1 boundedness

In this section, we establish H 1 -L 1 boundedness of the Marcinkiewicz

integral. In view of Theorem 2.1 and the sublinearity of µ Ω , it suffices to

verify the inequality (3.2) when f is an arbitrary H ∞,0 1 -atom. Let a(x)

(6)

be an H ∞,0 1 -atom supported in B r (x 0 ). We split the integral into two parts,

Z

H

µ a(x) dx = Z

B

2λr

(x

0

)

µ a(x) dx + Z

H \B

2λr

(x

0

)

µ a(x) dx

≡ I + II.

4.1. Estimation on I By hypothesis, we have (4.1)

Z

B

2λr

(x

0

)

a(x)] q dx . Z

B

r

(x

0

)

|a(x)| q dx . |B r (x 0 )| −q+1 . By H¨ older’s inequality and (4.1), we obtain

I ≤ Z

B

2λr

(x

0

)

a(x)] q dx

!

1

q

|B 2λr (x 0 )|

q1

. 1.

4.2. Estimation on II

Before we proceed, we introduce some simple facts on balls in H.

Definition 4.1. For E ⊂ H and x 6∈ E, we will use the following notation.

d(x, E) = inf 

x ◦ y −1

: y ∈ E . Lemma 4.2. Let x 6∈ B 2λr (x 0 ). Then we have

d (x, B r (x 0 )) ≥ r.

Proof. Suppose

d (x, B r (x 0 )) < r.

Then there exists y ∈ B r (x 0 ) such that

y ◦ x −1

< r. So we get

x ◦ x −1 0

≤ λ

x ◦ y −1 +

y ◦ x −1 0

 < 2λr.

A contradiction to x 6∈ B 2λr (x 0 ).

Lemma 4.3. Let x 6∈ B 2λr (x 0 ) and y ∈ B r (x 0 ). Then we have

x ◦ y −1

≤ 2λ

x ◦ x −1 0

≤ 4λ 2

x ◦ y −1

.

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Proof. Observe that x ◦ y −1

≤ λ

x ◦ x −1 0 +

x 0 ◦ y −1



≤ 2λ

x ◦ x −1 0

≤ 2λ 2

x ◦ y −1 +

y ◦ x −1 0



≤ 4λ 2

x ◦ y −1 , from

x ◦ y −1

≥ d (x, B r (x 0 )) ≥ r ≥

y ◦ x −1 0 .

Lemma 4.4. Let x 6∈ B 2λr (x 0 ) and t < d (x, B r (x 0 )). Then we have B r (x 0 ) ∩ B t (x) = ∅.

Proof. If y ∈ B r (x 0 ), then we have

y ◦ x −1

≥ d (x, B r (x 0 )) ≥ t.

Also, observe the following fact.

Fact 4.5. There exist constants C > 0, ε ∈ (0, 1) and ρ > 0 such that

δ s x ◦ x −1

≤ C|1 − s| ρ |x|

uniformly in x ∈ H and |1 − s| < ε.

Fix x ∈ H \ B 2λr (x 0 ). Then, by Lemma 4.2 we have d (x, B r (x 0 )) ≤

x ◦ x −1 0

≤ 2λd (x, B r (x 0 )) . We have

µ a(x) 2 = Z ∞

d(x,B

r

(x

0

))

Z

B

r

(x

0

)∩B

t

(x)

Ω x ◦ y −1 

|x ◦ y −1 | Q−1 a(y) dy

2 dt t 3

= Z

d(x,B

r

(x

0

))

Z

B

r

(x

0

)∩B

t

(x)

Ω x ◦ y −1 

t |x ◦ y −1 | Q−1 a(y) dy

· J t a(x) dt t 2 , where

J t a(x) = Z

B

r

(x

0

)∩B

t

(x)

Ω x ◦ y −1 

|x ◦ y −1 | Q−1 a(y) dy

.

(8)

Lemma 4.6. Let Ω, a, and B r (x 0 ) be as above. Then we have

Z

B

r

(x

0

)∩B

t

(x)

Ω x ◦ y −1 

t |x ◦ y −1 | Q−1 a(y) dy

. Ma(x), whenever t > d (x, B r (x 0 )), x ∈ H \ B 2λr (x 0 ).

Proof. There are two cases.

Case 1. t ≤ 2d (x, B r (x 0 )).

Z

B

r

(x

0

)∩B

t

(x)

Ω x ◦ y −1 

t |x ◦ y −1 | Q−1 a(y) dy

. kΩk

t · d (x, B r (x 0 )) Q−1 Z

B

t

(x)

|a(y)| dy . kΩk

t Q Z

B

t

(x)

|a(y)| dy . Ma(x).

Case 2. t ≥ 2 (d (x, B r (x 0 ))). From B r (x 0 ) ∩ B t (x) ⊂ B d(x,B

r

(x

0

)) (x), we have

Z

B

r

(x

0

)∩B

t

(x)

Ω x ◦ y −1 

t |x ◦ y −1 | Q−1 a(y) dy

. kΩk

d (x, B r (x 0 )) Q Z

B

d(x,Br(x0))

(x

0

)

|a(y)| dy . Ma(x),

which completes the proof.

For J t a(x) we have the following:

Lemma 4.7. With Ω, a, and B r (x 0 ) as above,

J t a(x) .

 

 

 

 

tMa(x)

if d (x, B r (x 0 )) ≤ t ≤ λ (d (x, B r (x 0 )) + 2λr) r ν

x ◦ x −1 0

−Q+1−ν

if t ≥ λ (d (x, B r (x 0 )) + 2λr)

for any x ∈ H \ B 2λr (x 0 ), where ν = min {α, ρα, 1}.

(9)

Proof. We have two cases.

Case 1. t ≥ λ (d (x, B r (x 0 )) + 2λr).

From B r (x 0 ) ⊂ B t (x), R

B

r

(x

0

) a(y) dy = 0 and the Lipschitz condition on Ω| S , we get

J t a(x) = Z

B

r

(x

0

)∩B

t

(x)

Ω x ◦ y −1 

|x ◦ y −1 | Q−1 a(y) dy

= Z

B

r

(x

0

)

"

Ω x ◦ y −1 

|x ◦ y −1 | Q−1 − Ω x ◦ x −1 0 

x ◦ x −1 0

Q−1

#

a(y) dy . Notice the following:

Ω x ◦ y −1 

|x ◦ y −1 | Q−1 − Ω x ◦ x −1 0  x ◦ x −1 0

Q−1

Ω x ◦ y −1  − Ω x ◦ x −1 0 

|x ◦ y −1 | Q−1 +

Ω x ◦ x −1 0  ·

1

|x ◦ y −1 | Q−1 − 1 x ◦ x −1 0

Q−1

.

δ |x◦y

1

|

1

x ◦ y −1  ◦ δ | x◦x

01

|

1

x ◦ x −1 0  −1

α

x ◦ x −1 0

Q−1 +

y ◦ x −1 0

x ◦ x −1 0

Q . From (2.1), we obtain

δ

1

|

x◦y1

| x ◦ y −1  ◦ δ

1

|

x◦x01

| x ◦ x −1 0  −1

.

δ

1

|

x◦y1

|

 x ◦ y −1  ◦ x ◦ x −1 0  −1  +

δ

1

|

x◦y1

| x ◦ x −1 0  ◦ δ

1

|

x◦x01

| x ◦ x −1 0  −1

. r

|x ◦ y −1 | +



1 − | x◦x

01

|

|x◦y

1

|

 ρ

x ◦ x −1 0

x ◦ x −1 0

. r

x ◦ x −1 0

+ r ρ

x ◦ x −1 0

ρ ,

(10)

and so,

Ω x ◦ y −1 

|x ◦ y −1 | Q−1 − Ω x ◦ x −1 0  x ◦ x −1 0

Q−1

. r α

x ◦ x −1 0

Q+α−1 + r ρα

x ◦ x −1 0

Q+ρα−1 + r

x ◦ x −1 0

Q

. r ν

x ◦ x −1 0

Q+ν−1 , since

x ◦ x −1 0

≥ 2λr. Therefore we obtain J t a(x) . r ν x ◦ x −1 0

Q−1+ν . Case 2. t ≤ λ (d (x, B r (x 0 )) + 2λr).

Since t ∼ d (x, B r (x 0 )), we get

J t a(x) ≤ kΩk Z

B

t

(x)

1

|x ◦ y −1 | Q−1 |a(y)| dy

. 1

t Q−1 Z

B

t

(x)

|a(y)| dy . tMa(x).

The proof of Lemma 4.7 is completed.

Thus, for x ∈ H \ B 2λr (x 0 ),

µ a(x) 2 .

Z ∞ d(x,B

r

(x

0

))

J t a(x) dt t 2

!

· Ma(x)

=

Z λ(d(x,B

r

(x

0

))+2λr)

d(x,B

r

(x

0

))

J t a(x) dt t 2 +

Z

λ(d(x,B

r

(x

0

))+2λr)

J t a(x) dt t 2

!

· Ma(x)

(11)

.

Z λ(d(x,B

r

(x

0

))+2λr) d(x,B

r

(x

0

))

dt t

!

Ma(x) 2

+ Z

λ(d(x,B

r

(x

0

))+2λr)

r ν x ◦ x −1 0

Q−1+ν

dt t 2

!

· Ma(x)

. r

d (x, B r (x 0 )) · Ma(x) 2 + r ν

x ◦ x −1 0

Q+ν · Ma(x), and so we obtain

µ a(x) . r

12

· Ma(x)

x ◦ x −1 0

1 2

+ r

ν2

· Ma(x)

12

x ◦ x −1 0

Q+ν 2

. Pick p 1 , p 2 , q 1 , and q 2 with the following properties:

• 2Q < p 1 < ∞;

Q+ν 2Q < p 2 < 2;

p 1

1

+ q 1

1

= 1; and

p 1

2

+ q 1

2

= 1.

From H¨ older’s inequality, the Maximal theorem, and (2.3), we obtain r

12

Z

H \B

2λr

(x

0

)

Ma(x)

x ◦ x −1 0

1 2

dx

. r

12

Z

H \B

2λr

(x

0

)

x ◦ x −1 0

p12

dx

!

1

p1

kMak q

1

. r

12

Z

2r

ρ

p12

+Q−1



1

p1

kak q

1

. 1

and

r

ν2

Z

H \B

2λr

(x

0

)

Ma(x)

12

x ◦ x −1 0

Q+ν 2

dx

. r

ν2

Z

H \B

2λr

(x

0

)

|x − x 0 |

(Q+ν)p22

dx

!

1

p2

kMak

12q2 2

. r

ν2

Z

2r

ρ

(Q+ν)p22

+Q−1



1

p2

kak

1 2q2

2

. 1.

(12)

This shows

II . 1.

Altogether, we obtain Z

H

µ Ω a(x) dx . 1 and the proof is complete.

5. L -BM O boundedness

In this section, we study the L -BM O boundedness of the Mar- cinkiewicz integrals. Let f ∈ L (H) be compactly supported and let B r (x 0 ) be any ball. We write

f = f χ B

2λr

(x

0

) + f χ H \B

2λr

(x

0

)

≡ f 1 + f 2 .

Then f 1 ∈ L 2 (H). By H¨ older’s inequality and by hypothesis, Z

B

r

(x

0

)

µ f 1 (x) dx ≤ |B r (x 0 )|

q1

Z

B

r

(x

0

)

f 1 (x)] q dx

!

1q

. |B r (x 0 )|

q1

kf 1 k L

q

(H)

. |B r (x 0 )|

q1

|B 2λr (x 0 )|

1q

kf 1 k L

. |B r (x 0 )| · kf k L

.

Thus we obtain

(5.1) 1

|B r (x 0 )|

Z

B

r

(x

0

)

µ f 1 (x) dx . kf k L

.

For x ∈ B r (x 0 ) we have

x ◦ y −1

> r whenever y ∈ H \ B 2λr (x 0 ). Let x ∈ B r (x 0 ) and let

III =

Z

0

|F t (x) − F t (x 0 )| 2 dt t 3



12

.

(13)

Then we have

III =

 Z

0

Z

B

t

(x)

"

Ω x ◦ y −1 

|x ◦ y −1 | Q−1 − Ω x 0 ◦ y −1 

|x 0 ◦ y −1 | Q−1

#

f 2 (y) dy

2 dt t 3

1 2

=

 Z ∞

r

Z

B

t

(x)

"

Ω x ◦ y −1 

|x ◦ y −1 | Q−1 − Ω x 0 ◦ y −1 

|x 0 ◦ y −1 | Q−1

#

f 2 (y) dy

2 dt t 3

1 2

.

 Z ∞

r

Z

B

2λt

(x

0

)\B

2λr

(x

0

)

r ν

|y − x 0 | Q−1+ν dy

! 2

dt t 3

1 2

kf 2 k L

. Z

r

Z 2λt

2λr

r ν s ν ds

 2

dt t 3

!

12

kf 2 k L

. kf k L

.

A triangle inequality provides us

|µ Ω f (x) − µ Ω f 2 (x 0 )| ≤ µ Ω f 1 (x) + III, which verifies

1

|B r (x 0 )|

Z

B

r

(x

0

)

|µ Ω f (x) − µ Ω f 2 (x 0 )| dx . kf k L

. This proves the L c -BM O boundedness.

6. L p -boundedness

From H 1 -L 1 boundedness and the L q -boundedness, it is clear that µ is bounded in L p for 1 < p ≤ q. To prove the L p -boundedness for q < p < ∞, we define Stein’s linearizing function ϕ(x, t) which is a function defined for x ∈ H, 0 < t < ∞, so that it satisfies the conditions:

(a) ϕ vanishes if t is small enough, or if t is large enough and is bounded.

(b) For all x, (6.1)

Z ∞ 0

|ϕ(x, t)| 2 dt

t 3 ≤ 1

holds.

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Now we define T ϕ f (x) =

Z ∞ 0

Z

B

t

(x)

Ω x ◦ y −1 

|x ◦ y −1 | Q−1 f (y) dyϕ(x, t) dt t 3 . By (a), (b) and by H¨ older’s inequality,

(6.2) |T ϕ f (x)| ≤ µ f (x) and µ f (x) = sup

ϕ |T ϕ f (x)|

for all ϕ satisfying (a) and (b) of the above.

It can be shown that T ϕ is bounded from L c (H) to BM O (H) with uniform bounds for those ϕ with the above properties. An interpolation yields the L p boundedness for p ∈ (q, ∞) of T ϕ uniformly in ϕ with above properties, which implies the L p boundedness of µ .

References

[1] A. Benedek, A. Calderon, and R. Panzone, Convolution operators on Banach space valued functions, Proc. Nat. Acad. Sci. U.S.A. 48 (1962), 356–365.

[2] A. P. Calder´ on, On the theorem of Marcinkiewicz and Zygmund, Trans. Amer.

Math. Soc. 68 (1950), 55–61.

[3] A. P. Calder´ on and A. Zygmund, On the existence of certain singular integrals, Acta Math. 88 (1952), 85–139.

[4] J. Duoandikoetxea and J. L. Rubio de Francia, Maximal and singular integral operators via Fourier transform estimates, Invent. Math. 84 (1986), 541–561.

[5] C. Fefferman and E. M. Stein, H

p

spaces of several variables, Acta Math. 129 (1972), 137–193.

[6] G. B. Folland and E. M. Stein, Hardy spaces on homogeneous groups, Princeton Univ. Press, 1982.

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61-62 (1990), 235–243.

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[15] , Trigonometric Series, 2nd ed. Vol. 2, Cambridge Univ. Press, Cam-

bridge, 1968.

(15)

Youngwoo Choi

Department of Mathematics Ajou University

Suwon 442-749, Korea

E-mail : [email protected] Kyung Soo Rim

School of Mathematics

Korea Institute for Advanced Study Seoul 130-012, Korea

E-mail : [email protected]

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