Chapter2 Vector analysis
Chapter2. Vector analysis
2 1 Introduction 2-1 Introduction
1. vector algebra
addition, subtraction and multiplication , p
2. orthogonal coordinate systems 3. vector calculation
differentiation, integration (line, surface and volume differentiation, integration (line, surface and volume integrals)
del( ) operator, gradient, divergence and curl operation ∇
2 2 Vector Addition and Subtraction 2-2 Vector Addition and Subtraction
1 Addition 1. Addition
, , A
A Aa A A a
= = = A
Commutative law : A B C
A B B A + =
+ = + 1
Associative law : 2 A + ( B C + ) = ( A + B ) + C 2. Subtraction
( )
A B − = + − A B
2 3 Products of Vectors 2-3 Products of Vectors
1. Scalar or dot product 1. Scalar or dot product
A B i = AB cos θ
A θ B
Commutative law :
Distributive law : ( ) A B B A
A B C A B A C
=
+ = +
i i
i i i
1 2
θ B
2
or
A A i = A A = A A i
( ) ( )
C = C C i = A + B i A + B
2 2
2 2
2 cos
2 cos
A B AB
A B AB
θ α
= + +
= + −
B C
α
θA
2. Vector or cross product 2. Vector or cross product A B × = a AB
nsin θ
B
A B ×
A B × = − × B A
θ A
an
ω
V
d
sin V = ω d = ω R θ
θ
d • p
R
V = × ω R
3 Product of three vectors 3. Product of three vectors
( ) ( ) ( )
A B C i × = B C i × A = C A B i ×
( ) ( ) ( )
A × B C × = B A C i − C A B i
2 4 Orthogonal Coordinate Systems 2.4 Orthogonal Coordinate Systems
1 2 3
Base vector ( , , ) u
1u
2u
31 2 3 2 3 1 3 1 2
1 2 2 3 3 1
( )
, ,
0
u u u u u u u u u
u u u u u u
× = × = × =
= = =
i i i
1 2 2 3 3 1
1 1 2 2 3 3
u u i = u u i = u u i = 1
1 1 2 2 3 3 1 1 2 2 3 3
,
( 1, 2, 3) : const does not mean that the surface in plane. It can
u u u u u u
i
A A u A u A u B B u B u B u u i
= + + = + +
=
be curved surfaces
e.g) spherical coordinate system( , r θ , )
h f f h
φ : const means the surface of a sphere
(it is not plane, but , , are perpendicular to each other) r
r θ φ
A B A B + A B + A B
1 1 2 2 3 3
1 2 3
u u u u u u
A B A B A B A B
u u u
A B A A A
= + +
i
1 2 3
1 2 3
( ) ( ) ( )
u u u
u u u
A B A A A
B B B
A B A B A B A B A B A B
× =
2 3 3 2 1 3 3 1 1 2 2 1
1 2 3
= u A B (
u u− A B
u u) − u A B (
u u− A B
u u) + u A B (
u u− A B
u u)
1. Differential change in one of the coordinates 와 Diffetential length change 의 상관 관계
1 2 3
, ( : metric coefficient, may be a function of , , ) e.g) polar coordinate(the subset of c
i i i i
dl =h du h u u u
ylindrical coordinate) (u u1 2)=(r φ) dφ inφ → dl2 = rdφ inφ direction ( , )=( , ) in in direction
2. differential length change : vector
u u r d dl rd
l
φ φ φ → = φ φ
임의의 방향의
1 1 2 2 3 3 1( 1 1) 2( 2 2) 3( 3 3)
3
dl = dll =u dl +u dl +u dl =u h du +u h du +u h du
Differential volume change : scalar 3
1 2 3 1 2 3
. Differential volume change : scalar dv =h h h du du du
1 1
4. Differential area change : vector (right hand rule)
) Differential area normal to the unit vector ds dsn
cf ds u
=
1 1
) Differential area normal to the unit vector
cf ds u
1 2 3 2 3 2 3
ds =dl dl = h h du du
2 4 1 Cartesian Coordinates 2-4.1 Cartesian Coordinates
di l h h h 1
1 2 3
( , u u u , ) = ( , , ) x y z distance element. so h
1= h
2= h
3= 1
u1 = x u2 = y u3 = z , ,
position vector to the point ( , , )
u x u y u z
x y z
x y z
= = =
× =
1 1 1
x x y y z z
OP x x y y z z A B A B A B A B
= + +
= + +
i
1 2 3
( ,u u u, )=( , , )x y z
x y z
x y z
x y z
A B A A A
B B B
× =
, ,
x y z
x y z
dl xdx ydy zdz
ds dydz ds dxdz ds d
= + +
= = = xdy
dv =dxdydz
2 4 2 Cylindrical Coordinates 2-4.2 Cylindrical Coordinates
( u u u
1 2 3) = ( r φ z ) h = h = 1 h = r
( , u u u , ) = ( , , ) r φ z h
1= h
3= 1, h
2= r
, , r × = φ z φ × = z r z r × = φ
r z
A = rA + φ A
φ+ zA
1 2 3
( ,u u u, )=( , , )r φ z
dl d φ φ d d
dl=rdr+φ φd +zdz
, ,
r z
dl rdr rd zdz
ds rd dz ds drdz ds rdrd dv rdrd dz
φ
φ φ
φ φ
φ
= + +
= = =
=
, ,
r z
ds rd sz ds drdz ds rdrd dv rdrd dz
φ φ φ
φ
= = =
=
) r z x y z
cf A=rA +φAφ +zA ⇒ xA + yA + zA
φ
cos sin
sin cos
y
x r r
y r r
A A x A r x A x A A
A A y A r y A y A A
φ
φ φ
φ φ
φ φ φ
φ φ φ
= = + = −
= = + = +
i i i
i i i
cos sin 0 sin cos 0
0 0 1
x r
y
A A
A A
A A
φ
φ φ
φ φ
⎡ ⎤ ⎡ − ⎤ ⎡ ⎤
⎢ ⎥ ⎢ ⎥ ⎢ ⎥
⇒ ⎢ ⎥ ⎢= ⎥ ⎢ ⎥
⎢ ⎥ ⎢ ⎥ ⎢ ⎥
⎣ ⎦ ⎣Az 0 0 1⎦ ⎣ ⎦Az 대입
⎢ ⎥ ⎢ ⎥ ⎢ ⎥
⎣ ⎦ ⎣ ⎦ ⎣ ⎦
cos , sin , x=r φ y =r φ z = z
대입
2 2 1
, tan ( ), y
r x y z z
φ − x
= + = =
2 4 3 Spherical Coordinate 2-4.3 Spherical Coordinate
( u u u
1 2 3) = ( R θ φ ) h = 1 h = R h = R sin θ ( , u u u , ) = ( , , ) R θ φ h
1= 1, , sin h
2= R h
3= R θ
, , R × = θ φ θ φ × = R φ × = R θ
A = RA
R+ θ A
θ+ φ A
φsindl = RdR+θ θ φRd + R θ θd
2
2
sin , sin ,
sin
dsR R d d ds R dRd ds RdRd
dv R dRd d
θ φ
θ θ φ θ φ θ
θ θ φ
= = =
=
) sin cos sin sin cos
cf x = R θ φ y = R θ φ z = R θ
2 2
2 2 2 1 1
) sin cos , sin sin , cos
, tan , tan
cf x R y R z R
x y y
R x y z
z x
θ φ θ φ θ
θ − φ −
= = =
= + + = + =
H.W1 : Find the conversion matrix from spherical into cartesian
2 5 Integrals Containing Vector Functions 2-5 Integrals Containing Vector Functions
Fdv vdl F dl A ds
∫
,∫
,∫
i ,∫
i1. (for cartesian)
2 ( )[ ] ( ) ( ) ( )
v c c s
v z y x
Fdv vdl F dl A ds
Fdv Fdxdydz
vdl v x y z xdx ydy zdz x v x y z dx y v x y z dy z v x y z dz
=
= + + = + +
∫ ∫ ∫ ∫
∫ ∫ ∫ ∫
∫ ∫ ∫ ∫ ∫
1
2. ( , , )[ ] ( , , ) ( , , ) ( , , )
) from point P
cvdl cv x y z xdx ydy zdz x v x y z dxc y v x y z dyc z v x y z dzc
cf
= + + = + +
∫ ∫ ∫ ∫ ∫
2
to point P2
around path
p vdl C ⇒ vdl
∫
1∫
, around path
p vdl C ⇒ cvdl
∫ ∫
y
2) evaluate
0Pex ∫ r dr
P2
(1,1) P
2 2 2
where from the original to the point (1,1) ) along the direct path
r x y P
a OP
= +
1
2
) along the path ) along the path
b OP P
c OP P
x
P1
o
2 2
2 2 2
0 0
-1
) 2 2
3
where cos sin and . since tan tan
a
Pr dr r r dr r
y y
r x φ y φ φ π φ φ π
= =
= + = = ⇒ = =
∫ ∫
where cos sin and . since tan tan
4 4
2 2
3 3
r x y
x x
x y
φ + φ φ φ ⇒ φ
= +
1
1
1
2 2 2 2 2
0 0
) along O
4 1
( ) (0 ) ( 1)
3 3
P P P
P
b P P
x + y dr = + y dy y + x + dxx = x + y
∫
0∫
0∫
12 2
0
3 3
1 4
) same way, ( )
3
c ∫
Px + y dr = x + 3 y
3 ∫ F dl i = ?
3. ?
) Given 2 , evaluate
C
B A
F dl
ex F xxy y x F dl
=
= −
∫
∫
i
i ) In cartesian coordinates
) In cylindrical coordinates a
b
) I t i
x=0,y=3
2 2
) In cartesian
( 2 ) ( ) 2
( 2 ) 9(1 ) using 9
a
F dl xxy y x xdx ydy xydx xdy
xydx xdy π x y
= − + = −
− = − + + =
∫
i i
3, 0
( 2 ) 9(1 ) using 9
2 ) In cylindrical
( cos 2 sin ) ( sin 2 cos )
x y xydx xdy x y
b
F r xy φ xy φ φ xy φ x φ
= = = + + =
= − − +
∫
where x =rcos , φ y =rsin , φ dl =φr 3
3( sin 2 cos )
d d
F dl xy x d
π
φ φ φ
φ φ φ
π
=
= − +
i
2
0 3( sin 2 cos ) 9(1 ), where 3cos and 3sin
xy φ x φ φd π2 x φ y φ
− + = − + = =
∫
4 ∫ A d ∫ A d h i l h fl f h
4. the integral measures the flux of the vector field flowing through the area
s
A ds
sA nds
A S
= ⇒
∫ i ∫ i
cf ) the convention for the positive direction of or a closed surface
ds n
an open surface
depend on the direction in which the perimeter of the open
f i d
⇒
surface is traversed
disk
1 2
) Given k k , ( 3, 2)
ex ) Given F = a + a , ( z = ± 3, r = 2) evaluate .
r z
s
ex F a a z r
r r
F ds
+ ±
∫ i
∫ ∫ ∫ ∫
)
a)top face : , , 3 ( 0 2, 0 2 )
top bottom side
S face face wall
sol F ds F nds F nds F nds
n z ds rdrdφ z r φ π
= + +
= = = = → = →
∫
i∫
i∫
i∫
i2 2
2 2
0 0
3 12
b)bottom face : , , 3
top face
F nds k rdrd k
n z ds rdrd z
π φ π
φ
= =
= − = = −
∫
i∫ ∫
) , ,
φ
2 2
2 2
0 0 3 12
c)side wall : 2
bottom face
F nds k rdrd k
n r ds rdrd r
π φ π
φ
= =
= = =
∫
i∫ ∫
2 3
1 1
0 3
c)side wall : , , 2
side 12
wall
n r ds rdrd r F nds π k rdrd k
φ
φ π
−
= = =
= =
∫ ∫ ∫
∫
i
1 2
12 ( 2 )
S F ds π k k
∴
∫
i = +2 6 Gradient of a Scalar Field 2-6 Gradient of a Scalar Field
scalar or vector fields : function of ( t ; u u u
1 2 3) scalar or vector fields : function of ( ; , , ) space rate of change of a scalar fields at a given time
the gradient of the scalar : the vector that represents both the magnitude and t u u u
g p g
the direction of the maximum space rate of increase of a scalar
grad dV or dV (where, )
V n V n dl dn
dn ∇ dn ≠
) cos ( )
( )
dn dn
dV dV dn dV dV
cf n l V l
dl dn dl dn dn dV V dl
α
= = = = ∇
∇
i i
∵ dV = ∇ i ( V dl )
V V V dV ∂ dl1+ ∂ dl2 + ∂ dl3
1 2 3
1 1 2 2 3 3 1 1 1 2 2 2 3 3 3
where, ( ) ( ) ( )
dV dl dl dl
l l l
dl u dl u dl u dl u h du u h du u h du
V V V V V V
= + +
∂ ∂ ∂
= + + = + +
⎛ 1 ∂ 2 ∂ 3 ∂ ⎞
(
1 1 2 2 3 3)
⎛ 1 ∂ 2 ∂ 3 ∂ ⎞1 2 3 1 2 3
1
V V V V V V
dV u u u u dl u dl u dl u u u dl
l l l l l l
V u V
⎛ ∂ ∂ ∂ ⎞ ⎛ ∂ ∂ ∂ ⎞
=⎜⎝ ∂ + ∂ + ∂ ⎟⎠ + + =⎜⎝ ∂ + ∂ + ∂ ⎟⎠
∇ = ∂
∴
i i
2 3 1 2 3
V V V V V
u ∂ u ∂ u ∂ u ∂ u ∂
+ + = + +
V u1
∇ l
∴ ∂1 2 2 3 3 1 1 1 2 2 2 3 3 3
1 2 3
1 1 2 2 3 3
u u u u u
l l h u h u h u
u u u V
h u h u h u
+ + + +
∂ ∂ ∂ ∂ ∂
⎛ ∂ ∂ ∂ ⎞
=⎜⎝ 1∂ 1 + 2∂ 2 + 3∂ 3 ⎟⎠
1 2 3
1 1 2 2 3 3
u u u
h u h u h u
⎝ ⎠
∂ ∂ ∂
⇒ ∇ ≡ + +
∂ ∂ ∂
) divergence operation curl opetation
cf ∇ ⇒
∇× ⇒ i
Vector differential operator
∇× ⇒ curl opetation
2 7 Divergence of a Vector Field 2-7 Divergence of a Vector Field
Divergence of a vector field at a point ( )
Net outward flux of per unit volume as the volume about the
A div A
⇒ A
point tends to zero
∫ A d lim
0 Sv
A ds div A
Δ →
v
= ∫ Δ i
→ (two d imensional surface/three dimensional volume) spatial
derivatives as the volume approaches zero pp
. ) In cartesian coordinates
s
e g
A ds
⎡ ⎤
∫ i
front back right left top bottom
face face face face face face
⎡ ⎤ A ds
= ⎢ + + + + + ⎥
⎣ ∫ ∫ ∫ ∫ ∫ ∫ ⎦ i
0 0 0
front face
( ) ( , , )
front front front x 2
front face
A ds = A Δs = A x Δ Δ =y z A x + Δx y z Δ Δy z
∫
i i i0 , 0 0
0 0 0 0 0 0
( , )
( , , ) ( , , )
2 2
back face
x
x x
x y z
A
x x
A x y z A x y z high order term
x
∂
Δ Δ
∴ + = + +
∂
bac A dsi ( ) ( 0 , 0, 0)
2
( ) ( )
back back back x
k face
x
A s A x y z A x x y z y z
A
x x
A A hi h d t
= Δ = − Δ Δ = − − Δ Δ Δ
Δ Δ ∂ +
∫
i i0, 0 0
0 0 0 0 0 0
( , )
( , , ) ( , , )
2 2
x
x x
x y z
A x y z A x y z high order term
∴ − = − x +
∂
⎛ ⎞
( 0, 0 0, )
[ ] . . .
x y z
x front back
face face
A ds A H O T x y z
x
A A A
⎛ ∂ ⎞
∴ + = ⎜ ⎝ ∂ + ⎟ ⎠ Δ Δ Δ
⎛ ∂ ∂ ∂ ⎞
∫ ∫ i
( 0, 0 0, )
. . . in , ,
x y z
x y z
s
A A A
A ds x y z H O T x y z
x y z
⎛ ∂ ∂ ∂ ⎞
∴ ∫ i = ⎜ ⎝ ∂ + ∂ + ∂ ⎟ ⎠ Δ Δ Δ + Δ Δ Δ
2 3 1 1
1 2 3 1 2
1 ( ) (
x
A
y zA A
div A A h h A h h
x y z h h h u u
∂ ∂ ∂ ∂ ∂
≡ ∇ = + + = +
∂ ∂ ∂ ∂
∴
i ∂
3 2 1 2 33
) ( )
A h h A
u
⎡ + ∂ ⎤
⎢ ∂ ⎥
⎣ ⎦
depend on the position of the point on which it is evaluated
⎣ ⎦
⇒
∂ ∂ ∂
1 2 3
1 1 2 2 3 3
cf ) u u u
h u h u h u
∂ ∂ ∂
∇ ≡ + +
∂ ∂ ∂
( )
ˆ ˆ ˆ ˆ ˆ ˆ
A ⎛ ∂ ∂ ∂ ⎞ A A A
∇ ⎜ + + ⎟
(
+ +)
( ) ( ) ( )
1 2 3 1 1 2 2 3 3
1 1 2 2 3 3
1 1 1 2 2 2 3 3 3
ˆ ˆ ˆ ˆ ˆ ˆ
A u u u u A u A u A
h u h u h u
u u A u u A u u A
h u h u h u
∇ =⎜⎝ ∂ + ∂ + ∂ ⎟⎠ + +
∂ ∂ ∂
= + +
∂ ∂ ∂
i i
i i i
1 1 2 2 3 3
h u∂ h u∂ h u∂
cos sin , sin cos
r x y x y
r
φ φ φ φ φ
φ
= + = − +
∂ ∂
y
r , φ r φ φ φ
∂ = ∂ =
∂ ∂
) cylindrical coordinate eg
x φ
φ
( ) ( ) ( )
1 2 3 1 2 3
) y
, , and 1, , 1
r z
g
u r u u z h h r h
r rA r A r zA
r r φ r
φ
φ
= = = = = =
∂ + ∂ + ∂
∂ i ∂ i ∂ i
x
r r z z z
r r A r r A r A r A r A r z A
r r r φ r φ r r
φ φ
⎛ ⎞ ⎛ ⎞
∂ ∂ ∂ ∂ ∂ ∂ ∂
⎛ ⎞
= ⎜⎝i∂ ⎟⎠ + i ∂ +⎜⎜⎝ i∂ ⎟⎟⎠ + i ∂ + ⎜⎜⎝i∂ ⎟⎟⎠ + i ∂ = ∂ 1
( )
Ar
r
∂
( )
∂ A)1 r r Ar
cf rA A
r r r r
∂ = ∂ +
∂ ∂
2 8 Divergence Theorem 2-8 Divergence Theorem
Adv A ds
∇ =
∫ i ∫ i
from definition of divergence, ( A)
j
V s
j j
s
Adv A ds
v A ds
∇
∇ Δ =
∫ ∫
∫
i i
0 0
1 1
lim ( ) lim
j j j
N N
j j s
v v
j j
A v A ds
Δ → = Δ → =
⎡ ⎤ ⎡ ⎤
∇ Δ =
⎢ ⎥ ⎢ ⎥
⎣ ∑ i ⎦ ⎣ ∑ ∫ i ⎦
Volume integral
0 1
lim
j j
N
s s
v j
A ds A ds
Δ →
⎡ ⎤
⎢ ⎥ =
⎣ ∑∫ i ⎦ ∫ i
( )
V
∇ A dv
∫
Vi
j⎣
j=1 j⎦
∫
( ∇ A dv ) = A ds
∴ ∫ ∫V ( i ) ∫ ∫s i
i
2 9 Curl of a Vector Field 2-9 Curl of a Vector Field
Flow source outward flux divergence
Vortex source
C
cause a circulation of a vector around it
circulation of around contour C A
∫
A dli . ) a force acting on ane g objectcirculation will be the work done by the force in moving the object once around the contour
→
electric field e.m.f water whi lr
→
ing down a sink drain → vortex sink
( ) (
0)
max( )
lim 1
1
n C
curl A A s a A dl
Δ → s ⎡ ⎤
≡ ∇× Δ ⎣
∫
⎦∫
i
( ) ( )
0 1( )
) lim
u u
u s C
u u
cf A a A A dl
Δ → s
∇× = ∇× =
Δ
∫
i i
( )
ˆ ˆ
u , , : , , ,
1
u u
x s x y C
= Δ = Δ Δ
⎛ ⎞
( )
0∫
sides1,2,3,4
lim 1
x y z
A A dl
Δ Δ → y z
⎛ ⎞
∇× = Δ Δ ⎝⎜
∫
i ⎟⎠0 0 0
side1
, ( , , )
z 2
dl = Δz z A dli = A x y + Δy z Δz
0 0 0
0 0 0 0 0 0
( , , )
where, ( , , ) ( , , ) . . .
2 2
( )
z
z z
x y z
A
y y
A x y z A x y z H O T
y A
A dl A y H O T
∂
Δ Δ
+ = + +
∂
⎧ Δ ∂ ⎫
⎪ ⎪Δ
⎨ ⎬
∫
0 0 0
0 0 0
side1
( , , )
( , , ) . . .
2 side3
z z
x y z
A
A dl A x y z y H O T z
y
∂
⎪ Δ ⎪
∴
∫
i =⎨⎪⎩ + ∂ + ⎬⎪⎭ΔA
y ⎧ y ∂ ⎫
Δ ⎪ Δ ⎪
∫
dl 0 0 0 0 0 0
side3
( , , )
, ( , , ) ( , , ) . . . ( )
2 2
z
z z
x y z
A
y y
z z A dl A x y z z A dl A x y z H O T z
y
⎧ ∂ ⎫
Δ ⎪ Δ ⎪
= − Δ i = − Δ ∴
∫
i = ⎨⎪⎩ − ∂ + ⎬⎪⎭ −Δside1 side3+
0 0 0
( , , )
. .
side2 side4
z
x y z
A H O T y z
y
⎛∂ ⎞
=⎜⎝ ∂ + ⎟⎠ Δ Δ
+
. . 0 , when 0 and z 0
H O T → Δ → y Δ →
0 0 0
( , , )
side2 side4
. . ( )
y z y
x x y z
A A A
H O T y z A
y y z
+
∂ ∂
⎛ ⎞ ∂
= −⎜⎝ ∂ + ⎟⎠ Δ Δ ∴ ∇× = ∂ − ∂
General expression in cartesian
z Ay
A x⎛∂A ∂ ⎞ y ∂
∇× = ⎜ − ⎟+ x z y x
x y z
A A A A
z⎛∂ ∂ ⎞
∂ ∂ ∂ ∂
⎛ − ⎞+ ⎜ − ⎟=
⎜ ⎟
A x y
y z
∇× = ⎜⎝ ∂ − ∂ ⎟⎠+
General expression for orthogonal curvilinear systems
x y z
z x z x y x y z
A A A
− + ⎜ − ⎟=
⎜ ∂ ∂ ⎟ ∂ ∂ ∂ ∂ ∂
⎝ ⎠ ⎝ ⎠
1 1 2 2 3 3
1 2 3 1 2 3
ˆ ˆ ˆ
1
u h u h u h
A h h h u u u
∂ ∂ ∂
∇× = 1 2 3 ∂ 1 ∂ 2 ∂ 3
1 1 2 2 3 3
h A h A h A
2 10 Stokes’s Theorem 2-10 Stokes s Theorem
( ∇× A ds ) = A dl
∫ i ∫ i
from definition of curl, ( ) ( )
j
j j C
A s A dl
∇× i Δ =
∫
i( )
S
∇× A ds =
CA dl
∫ i ∫ i
0 1
lim ( ) ( ) ( )
j
j
N
j j S
s j
A s A ds
Δ → =
⇒
∑
∇× i Δ =∫
∇× i∑ ∫
N∫
0 1
lim
j Cj C
s j
A dl A dl
Δ → =
∑ ∫
i =∫
i) ( ) 0,
cf ∫
S∇× A ds i =
closed surface no boundary contour
S
⇒
∫
2 11 Two Null Identities 2-11 Two Null Identities
1 ∇× ∇ ( V ) ≡ 0
the curl of the gradient of any scalar field is identically zero
1. ( ) 0
[ ] ( ) 0
V
V ds V dl dV
∇× ∇ ≡
→
∇×∇ = ∇ = =
∫ i ∫ i ∫
[ ] ( ) 0
cos ( )
S
V ds
CV dl
CdV
dV dV dn dV dV
n l V l dl dn dl dn α dn
∇×∇ = ∇ = =
= = = = ∇
∫ i ∫ i ∫
∵ i i
( )
dl dn dl dn dn
dV = ∇ V d
∵ i l
참 고
the divergence of the curl of any vector field is identically zer
2. ( ) 0
o
∇ ∇× A =
→ i
참 고
the divergence of the curl of any vector field is identically zer
( ) ) 0
o
V
A dv
S( A ds
→
∇ ∇× = ∇× =
∫ i ∫ i
) ˆ
nof should be outward, cf a ds
1 2
ˆ ˆ
so , also outward
n
n n
a a
∫ ∫
1ˆ
1∫
2ˆ
2. ) ( ) ( ) ( )
0
n n
S S S
i e A ds A a ds A a ds
A dl A dl
∇× = ∇× + ∇×
= + =
∫ ∫ ∫
∫ ∫
i i i
i i
1 2
1 2
( and are same, but opposite in direction)
C C