J. Korean Math. Soc. 31 (1994), No. 3, pp. 367-373
CAUCHY PROBLEM FOR THE EULER EQUATIONS OF A NONHOMOGENEOUS
IDEAL INCOMPRESSIBLE FLUID
SHIGEHARU ITOH
1. Introduction
Let us consider the Cauchy problem pt + v· Vp = 0
p[Vt + (v· V)v] + Vp = pf
div v = 0 (1.1)
plt=o = po(x) vlt=o = vo(x)
in QT =]R3 X [0, T], where f(x,t),po(x) and vo(x) are given, while the density p(x,t), the velocity vector v(x,t) = (v
1(X,t),v
2(X,t),v
3(x,t)) and the pressure p(x,t) are unknowns. The equations (1.1)1 - (1.1)a describe the motion of a nonhomogeneous ideal incompressible fluid.
The aim of the present paper is to establish the unique solvability, local in time, of the problem (1.1). For the problem in a bounded domain with the boundary condition v . n = 0, where n is the unit out normal to the boundary, that fact has been proved under appropriate assumptions by many authors, for instance, [1], [2], [3], [7], [8]. On the other hand, as far as we know, there is no investigation in an unbounded domain.
Our theorem is the following.
THEOREM. Assume that
po(x) - P E H 3 (]R3) for some positive constant p, (1.2) inf po(x) == m> 0 and suppo(x) == M <
00,(1.3) vo(x) E H 3(]R3) and div Vo = 0 (1.4)
Received April 9, 1993.
and
f(x, t) E L l (0, T : H 3 (R 3)) and div f E Ll(QT). (1.5) Then there exists T* E (0, T] such that the problem (1.1) has a unique solution (p, v,p) which satisfies
. , "
(p - p,v, "Vp) ELOO(O,T* : H
3(R
3))(1.6) x LOO(O,T*: H
3(R
3)) XLl(O,T*: H
3(R
3)).Moreover, if f(x, t) E CO (0, T : H3(R3)) and div f E CO(o, T L
l(R
3)),then the solution (p,v,p) is classical.
In section 2, we solve three linear problems in sequence and get the estimates. In section 3, we first show the existence of a fixed point of some map, and then it is proved that this becomes the solution of (1.1).
2. Preliminaries
LEMMA
2.1. For a given v
ELoo(O,T : H
3(R
3))with div v = 0, the problem
'{ Pt + v . "V p = °
, plt=o = po(x)
has a solution satisfying
m$. p $. M.
Moreover, if we put p = P - p, then
(2.1)
(2.3)
where po = po - p,
Clis a positive constant depending only on imbed- ding theorems and 11· Ilk =
1I·IIHk(1l3).Proof. It is well-known that, using the classical method of charac- teristics, the solution of (2.1) is given by
p(x,t) = po (y(r,X,t)IT=O)' (2.4)
Cauchy problem for the Euler equations
where y( r, x, t) is the solution of the Cauchy problem
{* ylr=t = v(y,r) = x.
369
(2.5)
(2.6) Thus the first assertion has shown. Next we establish the estimate for
p. It follows from (1.1)1 and (1.1)4 that p satisfies the equation
{ Pt + v . \7 P = 0
plt=o = po( x).
Applying the operator DQ (= (8/
8X1)Ql (8/
8X2)Q2 (8/
8X3)Qs) to (2.6h, multiplying the result by D
Qp, integrating over]R3 and adding in a with
10'1 (=
0'1+
0'2+
0'3):s: 3, then we have
(2.7)
Hence, by Gronwall's inequality, it is easy to see that (2.3) holds.
Q.E.D.
LEMMA
2.2. Let p and v be in Lemma 2.1. Then the problem div (p-1\7p) = - 2: V~j V~i + div f == F (2.8)
i,j
has a solution satisfying
lI\7p(t)lh (2.9)
9
:S:C2
(2: IIp(t)1I0 (IIv(t)lI~ + Ilf(t)1I3 +
11div f(t)II£1(]iS»),
j=o
where
C2is a positive constant depending only on rn, M, imbedding theorems and interpolation inequalities.
Proof. Thanks to (2.2), the solvability easily follows from the general theory of the elliptic partial differential equations of second order (cf.
[5]), and so we can restrict ourselves to get the estimate (2.9).
Multiplying (2.8) by P and integrating over lRa , then we obtain M-II1VpII~ ~IIFIIL6/5(Ji'.3) IIpIIL6(Ji'.3) (2.10)
~c3lIFll L6/5(Ji'.3) llVpllo
I 2/3 1/3 I
~C4 IF
11£1(Ji'.3) IIFllo lI\7pl
0~C4 [(2/3)IIFIILl(l!3) + (1/3)IIFllo] II Vpllo.
Hence we get
IIVpllo ~
C5(II F lILl(Ji'.3) + IIFllo). (2.11) In order to accomplish our purpose, we use the following inequality (cf. [7]):
lIull2 ~ (3/2)1/2 (IILlullo + IIullo) for any u E H
2(R
3).(2.12) Noting that (2.8) can be written in the form Llp = pF + p-
1V p. Vp, we get that for a with lal = 2
IIDQpll2 ~ (3/2)1/2 (II DQ (pF + p-
1Vp. Vp)lIo + IIDQpllo). (2.13) By the direct calculation, we obtain
the right hand of (2.13)
:'S C6 [(M + 11'7plhlllFlh + et. m -; 11'7 pllO II'7PII + (2.14)
Now, from the interpolation inequality and Young's inequality, we have
AIIV'plb ~ AIIVpll;/311Vpll~/3 (2.15)
=AIIVpllo + AII\72pll;/311\7pll~/3
~ell\72pll2 + (A + e- 2 A 3 )IIVpllo.
Therefore, we find that
9
IIVpll3 ~
C7(2: 11\7 plI~) (IIFII£1(Ji'.3) + IIFlb)· (2.16)
j=O
On the other hand, it is easy to verify that
11F1I£1(Ji'.3) + 11F1I2 ~
Cs(11 div 1I1Ll(Ji'.3) + 11 div 1112 + lI\7vIlD· (2.17) Consequently, the desired estimate is established. Q.E.D.
Moreover, similar to the above lenmlas, we have
Cauchy problem for the Euler equations
371 LEMMA2.3. Let p and v be in Lemma 2.1 and p in Lemma 2.2.
Then the problem
{
Wt
+ (v. V')w = _p-1V'p + f
wlt=o = vo(x) has a solution satisfying
(2.18)
3. Proof of Theorem
Let P be the orthogona.l projector in {£2(JR3)} 3 onto H = the closure of J = {u E {Cgo(JR 3) P : div u = o} in {£2 (lR3)}3. Then it is immediately follows from lemmas in section 2 that if 11;50113 ::; A and SUP0StS;T IlV(t)1l3 = Il v(t)lb,oo,T ::; K, then
IIPw(t)lh (3.1)
[ KT
sllw(t)1l3 S Il v ol13 + IlfIILJ(o,T:H3(J!3» + h(Ae C1 ) (J{
2T + IIfIILl(O,T:H3(li.3» + 11 div fIILJ(QT»] e C1KT ,
where her) =
C2(L::~=o r i ) (L::~=o
m-(j+l)ri ).
Therefore if we choose
4K 2:llvoll3 + 11/11£1 (0,T:H3(li.3
»(3.2)
+ h(2A) (1Ifll£l(0,T:H3(J!3» +
11div fll£l(QT»)
and define S = {v E £00(0, T; H 3(JR3» : Pv = v, Ilv(t)1I3,00,T ::; K},
then, from (3.1), the map F : v -. Pw satisfies F(S) C S for sufficiently
small T, for example T ::; T* = min{[4Kh(2A)]-I, (c
II()-110g2}. Let
{Vj} C S. Then we can verify that {Fvj} is the Cauchy sequence in
£<Xl(O, T; H3(R3 » with few difficulties. Hence, as F becomes a compact map, there exists a fixed point v = Pw from Schauder's theorem. We have thus solved the problem
Pt+Pw,Vp=O
Wt + (Pw. V)w = _p-l\lp + f
div [p-l\lp + (Pw. \l)Pw - f] = 0 (3.3) plt=o = po(x)
Wlt=o = vo(x) This is equivalent to (1.1) if Pw = w.
Let us show that Qw = (I - P)w = O. Apply the projection Q to (3.3)2, then, due to (3.3)a, we have
(Qw)t + Q[(Pw. V)Qw] = O.
Multiplying (3.4) by Qw and integrating over R3, we get
(3.4)
d d r IQwl
2dx + r Q[(Pw. V)Qw] . Qw dx = O. (3.5)
t 1m3 1m3
Furthermore, from the definition of P, we obtain
r Q[(Pw. V)Qw] . Qw dx (3.6)
1m.
3= r (Pw. V)Qw· Qw dx - r P[(Pw. V)Qw] . Qw dx
1m3 1m3
=.!. r Pw. VIQwl2dx = O.
21m.
3Hence we find that Qw = 0, since Qwlt=o = Qvo = O.
Uniqueness is proved in [4].
This completes the proof.
Cauchy problem for the Euler equations References
373
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