2
86
11 8
1
-1 150 cm1
-2 84 742
-1 9.52
-23
-13
-248000, 8000 8000 10
50 kg
1
-1 ( )== =150(cm)
1
-2 ( )= = =84( )x
=82, 336+x=410 x=74 74
2
-1 12, 3, 4, 4, 5, 6, 7, 8 a= =4.5( ) 2
1, 3, 4, 5, 5, 6, 7, 10
b= =5( )
a+b=4.5+5=9.5
2
-2 =8, 7+x=16 x=93
-1 5 3 5 a2 3, 7 7+x
2
5+52 4+52 336+x
5
3364 90+82+86+78
4 750
5
110+147+153+161+179 5
D x
=80 338+x=400 x=62( )
=10 a+b+c+d+e=50
= = =28
x cm
=171.2, 2752-x=2568 x=184(cm)
50 kg
68, 69, 70, 72, 76, 78, 80, 82
=74(g)
n n
n { +1}
, 2
3 3
x
=83 x=86( )
, 92 3
86
A 9 7<a<12 6, 7, a, 12 =9 a=11 A, B
6, 7, 7, 8, 10, 11, 12, 13
=9
14 a=14
8, 9, 10, 12, 14, 14 ( )= 10+12=11
2 8+10
2 7+a
2 80+x
2 n 2
n 2
n+1 2 72+76
2 16_172-x
15
140 5 3(a+b+c+d+e)-10
5
(3a-2)+(3b-2)+ +(3e-2) 5
a+b+c+d+e 5
82+76+88+x+92 5
( )= =14=2( )
4+0+2+1+1+3+3 7 7
2, 3, 4, 5, 5, 6, 7, 7, 8, 8, 8, 9 ( )=
= =6
( )= =6.5, ( )=8
( )>( )>( )
73 11 A
, 73 x 1
+1= , A+73+12=A+x x=85( )
12 aæ12
20 a…16
12…a…16
=2 a+b=12
, 2 a=2 b=2
a=2 , b=10, b=2 , a=10 , a>b a=10, b=2 a-b=10-2=8
80 50 (-30 ) 90 (+10 ) ,
(-6)+4+2+(-1)+3+a+b 7
A+x 12 A+7312
6+7 2 72 12
2+3+4+5+5+6+7+7+8+8+8+9 12
10 8
, , 4
15 , 16 , 18 , 18
x ,
=17.2 67+x=86 x=19( )
19 15+16+18_2+x
5
1
-11
-2 762
-1 2 '22
-23
-13
-2 384
-1 1402'3å5 kg
4
-2 '1∂7.å65
-1 845
-2 1206
-16
-2 C, B82 -12, -2, 8, -2, 8 56
2'1å4 11 20.6
1
-1 0(-4)+7+2+(-1)+x=0 x=-4
1
-2 x73 3
x-73=3 x=76( )
2
-1 ( )= = =6( )( )= =2
( )='2( )
2
-2 =9 x=14( )=
=60=12 5
(-3)¤ +(-1)¤ +5¤ +(-4)¤ +3¤
5 6+8+x+5+12
5
(-1)¤ +2¤ +(-2)¤ +0¤ +1¤
5 305 5+8+4+6+7
5
3 ( )=9.4 , ( )=7 , (
)=8 , 19
2+x+3+y+1=10 x+y=4
=21 3x+7y=16
, x=3, y=1
xy=3_1=3 ( )=
= =9.4( )
( )= =7( )
8 3 8
6+8 2 94 10
2+3_2+4+6+8_3+12+40 10
5_2+15_x+25_3+35_y+45_1 10
3
-1 3, 5, a, 6, b 5=5, a+b+14=25 a+b=11
, 5.4
=5.4 4+0+(a-5)¤ +1+(b-5)¤ =27
(a¤ -10a+25)+(b¤ -10b+25)+5=27 a¤ +b¤ -10(a+b)+28=0
a¤ +b¤ -10_11+28=0 a¤ +b¤ =82
3
-2 =6 x+y+z=18=2 x¤ +y¤ +z¤ -12(x+y+z)+108=6 x¤ +y¤ +z¤ -12_18+108=6 x¤ +y¤ +z¤ =114
= =38
4
-1 ( )== =75(kg)
( )
=
= =140
( )='1∂40=2'3å5(kg)
4
-2 ( )== =10( )
( )
=
= ='1∂7.å6( )
5
-1 ( )== =79( ) ( )=
= =84
5
-2 55 kg x2+4+x+4+2=20 x=8 84010
(-14)¤ _2+(-4)¤ _3+6¤ _4+16¤ _1 10
79010
65_2+75_3+85_4+95_1 10
352 20
(-8)¤ _2+(-4)¤ _4+0¤ _7+4¤ _6+8¤ _1 20
20020
2_2+6_4+10_7+14_6+18_1 20
420030
(-20)¤ _3+(-10)¤ _8+0¤ _9+10¤ _6+20¤ _4 30
2250 30
55_3+65_8+75_9+85_6+95_4 30
114 3 x¤ +y¤ +z¤
3
(x-6)¤ +(y-6)¤ +(z-6)¤
3 x+y+z
3
(3-5)¤ +(5-5)¤ +(a-5)¤ +(6-5)¤ +(b-5)¤
5 3+5+a+6+b
5
( )=
= =55(kg)
( )
=
= =120
6
-16
-2 C ,B C, B
2400 20
(-20)¤ _2+(-10)¤ _4+0¤ _8+10¤ _4+20¤ _2 20
1100 20
35_2+45_4+55_8+65_4+75_2 20
95 5
8
11 21
0
4+a+(-3)+b+(-1)+(-2)=0 a+b=2
3 x
(-3)+2+x+1+(-5)=0 x=5( )
90 5 3
95
(-3)+1+x+(-1)+0=0 x=3(kg)
( )= = =4
( )='4=2(kg)
( )= = =5( )
( )= = =2.5
( )= =8, 40+x=48
x=8 ( )=
= =5
=8 21+x+y=40 x+y=19
=2 9+1+1+x¤ -16x+64+y¤ -16y+64=10
x¤ +y¤ =16_19-129=175
(-3)¤ +(-1)¤ +1¤ +(x-8)¤ +(y-8)¤
5 5+7+9+x+y
5 306
(-4)¤ +(-1)¤ +2¤ +0¤ +0¤ +3¤
6 4+7+10+8+x+11
6
10 4 (-1)¤ +2¤ +(-2)¤ +1¤
4 20
4 4+7+3+6
4
205 (-3)¤ +1¤ +3¤ +(-1)¤ +0¤
5
æ≠ ≠ ≠ ≠ ≠ ≠ ≠ ≠ ≠ ≠ ≠
æ≠
6 x=8, y=6 81 90
=5'2
='7å0
x¡+x™+x£+ +x¡º=10 ( )=;1!0);=1
x¡¤ +x™¤ +x£¤ + +x¡º¤ =370 ( )
=
=
= = =36
'3å6=6
=78 450+75x+85y=1560 15x+17y=222 4+x+y+2=20 x+y=14
- _15 2y=12 y=6
y=6 x+6=14 x=8
( )=
= =81
5 x
80+75+85+90+95=85+70+95+85+x x=90
5 90
( )= 425 =85( ) 5
1620 20
(-13)¤ _4+(-3)¤ _8+7¤ _6+17¤ _2 20
65_4+75_x+85_y+95_2 20
360 10 370-2_10+10
10
x¡¤ +x™¤ +x£¤ + +x¡º¤ -2(x¡+x™+x£+ +x¡º)+10 10
(x¡-1)¤ +(x™-1)¤ +(x£-1)¤ + +(x¡º-1)¤
10 (x+y)¤ =x¤ +y¤ +2xy 19¤ =175+2xy
186=2xy xy=93
( )= = =5
( )=
= =1
( )='1=1
(-2)¤ _1+(-1)¤ _2+0¤ _3+1¤ _4=10
2 1 0
( )= = =8
2+4+a+1+1=10 a=2 ( )=
= =7( )
( )
=
= =5.8
=
=' ∂ ∂ ( )=
= =72( )
( )
=
='1å2å1=11( )
=5 a+b+c+d+e=25
=3¤
( )=10_{ }+ º;;=50+2=52
( )
=
=10
=10_3=30
(a-5)¤ +(b-5)¤ +(c-5)¤ +(d-5)¤ +(e-5)¤
5
(10a-50)¤ +(10b-50)¤ +(10c-50)¤ +(10d-50)¤ +(10e-50)¤
5 a+b+c+d+e
5
(a-5)¤ +(b-5)¤ +(c-5)¤ +(d-5)¤ +(e-5)¤
5 a+b+c+d+e
5
(-17)¤ _3+(-7)¤ _6+3¤ _6+13¤ _4+23¤ _1 20
1440 20
55_3+65_6+75_6+85_4+95_1 20
{( )¤ _ }
( )
5810
(-3)¤ _2+(-1)¤ _4+1¤ _2+3¤ _1+5¤ _1 10
70 10
4_2+6_4+8_2+10_1+12_1 10
80 10 6_10+4_5
10
'63 2'6
3 1010
(-2)¤ _1+(-1)¤ _2+0¤ _3+1¤ _4 10
50 10 3+4_2+5_3+6_4
10
( )=
= =81( )
( )
=
= =84
( )='8å4=2'2å1( )
A B '7å0
'1å0 5 5 840
10
(-16)¤ _1+(-6)¤ _4+4¤ _3+14¤ _2 10
810 10
65_1+75_4+85_3+95_2 10
æ≠ ≠ ≠ ≠ ≠ ≠ ≠ ≠ ≠ ≠
æ≠ ≠ ≠ ≠ ≠ ≠ ≠ ≠ ≠ ≠ —
æ≠ ≠ ≠ ≠ ≠ ≠ ≠ ≠ ≠ –
( )
=
= ='5å0=5'2( )
( )
= = 350 ='7å0( )
5 0¤ +(-15)¤ +10¤ +0¤ +5¤
5 250
5
(-5)¤ +(-10)¤ +0¤ +5¤ +10¤
æ≠ ≠ ≠ ≠ 5 ≠ ≠ ≠
æ≠
æ≠
æ≠ ≠ ≠ ≠ ≠ ≠
1
-11
-22
-12
-2 4'1å03
-1 5 cm3 cm 28 cm
3
-2 1694
-1 49 cm¤4
-25
-15
-2 5 cm6
-16
-2 35 4'5
1
-1 ACD x="1√3√¤ -≈5¤ ='1∂44=12ABD y="2√0√¤ -≈x¤ ="2√0√¤ √-√≈1≈2¤ ='2∂56=16 x+y=12+16=28
1
-2 ABC AB”="1√0√¤ -≈6¤ ='6å4=8 ABD x="√AB”¤ √+BçD”¤ ="8√¤ √+√1≈2¤='2ß0å8=4'1å3
2
-1 AC”="1√¤ +1¤ ='2, AD”="(√'2)¤ ç+≈1Ω¤ ='3 AE”="(√'3)¤ ç+≈1Ω¤ =2, AF”="2¤√ +1¤ ='5AG”="(√'5)¤¤ ç+≈1Ω¤ ='6
2
-2 A BC” HABH AH”="8√¤ -2¤ =2'1å5 CD”=AH”=2'1å5
BCD BD”="1√0¤ +√(2'1åç5)Ω¤ =4'1å0
3
-1 AEH™ BFE™ CGF™ DHG(SAS )HEF=90 EFGH
EH”¤ =25 EH”=5(cm) EFGH
EH”=EF”=GF”=GH”=5(cm)
AEH AH”="√5¤√ -4¤ ='9=3(cm)
AEH™ BFE™ CGF™ DHG AH”=BE”=CF”=DG”=3(cm)
AB”=BC”=CD”=DA”=4+3=7(cm)
ABCD 4_7=28(cm)
3
-2 AEH EH”="5√¤ +√1≈2¤ ='1∂69=13 EFGH=13¤ =1694
-1 BCG BG”="1√7¤ -≈8≈¤ ='2∂25=15(cm) FG”=BG”-BF”=15-8=7(cm)EFGH=7¤ =49(cm¤ )
4
-2 PQRS PS”='4å9=7(cm)ASD
AS”=AP”+PS”=DS”+PS”=5+7=12(cm) AD”="1√2¤ +≈5Ω¤ =13(cm)
ABCD
ABCD=AD”¤ =169(cm¤ )
5
-1 EBC™ ABF(SAS ) EBC= ABF, EBC EBA, ABF BFL
EBA= EBC= ABF= BFL
5
-2 ADEB= BFGC+ ACHI 34=BC”¤ +9, BC”¤ =25BC”=5(cm)( BC”>0)
6
-1 2¤ =1¤ +('3)¤ ('1å7)¤ =1¤ +4¤(2'2)¤ =2¤ +2¤ 5¤ =3¤ +4¤
6¤+4¤ +('1å5)¤
6
-2 (x+2)¤ =(x+1)¤ +3¤x¤ +4x+4=x¤ +2x+10, 2x=6 x=3
2
20 72 cm¤
6 cm¤
10
AB”=BC”=9 cm, CF”=3 cm
ABF AF”="√AB”¤ √+BçF”¤ ="9¤√ +1ç2¤ =15(cm) ABC BC”="1√3¤√ -≈5¤ ='1∂44=12
CD”=;2!; BC”=;2!;_12=6 ADC x="5√¤ +6¤ ='6å1
AB”=x
BP”='2x, “CP='3x, “DP=2x, “EP='5x '5x=2'5 x=2
ABC AC”=AD”="1√¤ +1¤ ='2 ADE AE”=AF”="1√¤ +(√'2)¤ ='3 AFG AG”=AH”="1√¤ +(√'3)¤ =2
D BC” H
DH”=AB”=4(cm)
BH”=AD”=2(cm) CH”=5-2=3(cm) CDH CD”="3√¤ +4¤ =5(cm)
ABCD AD”='3å6=6
AH”=6-2=4
AEH EH”="4√¤ +2¤ =2'5 EFGH=EH”¤ =20
ABQ=;2!;_'3_1=
“AQ='3 PQRS '3-1
.
PQRS=('3-1)¤ =4-2'3 CBH= ABH= CBG= LBG
BHIC= LMGB
BFMN= ADEB BFMN=16(cm¤ )
BFN=;2!; BFMN BFN=;2!;_16=8(cm¤ ) ABE™ CDB BE”=DB”
EBD=90 EBD
EBD=;2!;_EB”¤ =40 EB”=4'5(cm)( EB”>0)
EA”="(√4'5√)√¤ -4¤ =8(cm)
ACDE=;2!;_(8+4)_12=72(cm¤ ) 4¤ =3¤ +('7)¤ ( )
4¤ =(2'3)¤ +2¤ ( ) (2'3)¤ =2¤ +(2'2)¤ ( ) i) x , x¤ =5¤ +12¤ =169
x=13( x>0)
ii) 12 , 12¤ =5¤ +x¤ , x¤ =119 x='1∂19( x>0)
ABE AE”="1√5¤ -ç12¤Ω =9(cm) ED”=12-9=3(cm)
ABEª DFE AA
9 3=12 FD” FD”=4(cm) '32
16 6 6'5 88 cm¤ 5 cm
13 cm ;1^3); cm
ABC BC”="2√0¤ -ç12Ω¤ =16 CD”=x BD”=16-x
20 12=(16-x) x, 20x=12(16-x) 20x=192-12x, 32x=192 x=6
ADC AD”="6¤√ +1≈2Ω¤ =6'5
A, D BC
E, F
AD”=EF”=5(cm)
BE”=;2!;_(17-5)=6(cm)
ABE AE”="1√0¤ -≈6Ω¤ ='6å4=8(cm) ABCD=;2!;_(5+17)_8=88(cm¤ )
ABGF AE”
AE”¤ =25 AE”=5(cm)( AE”>0) AED AD”="1√2¤ +≈5¤Ω ='1∂69=13(cm) EF”=x AED=;2!;_12_5=;2!;_13_x 13x=60 x=;1^3);(cm)
FED=;2!;_3_4=6(cm¤ ) AB”=18-12=6(cm)
ABC
AC”="1√0¤ -Ω6Ω¤ =8(cm) x=20-8=12(cm)
ABC BC”="√4¤ +≈6Ω¤ ='5å2=2'1å3(cm) BDEC=(2'1å3)¤ =52(cm¤ )
FDE=;2!; BDEC=;2!;_52=26(cm¤ ) (x+4)¤ =x¤ +(x+2)¤ , x¤ +8x+16=x¤ +x¤ +4x+4 x¤ -4x-12=0, (x+2)(x-6)=0
x=6( x>0)
10 .
20 cm
12 cm 18 cm
10 cm x cm
A
B 6 cm C
B
A D
F C E
5 cm
10 cm
6 cm 5 cm
1
-11
-2 2'1å3<a<102
-12
-23
-1 73
-2 ;1^3); cm4
-14
-25
-15
-26
-1 13p6
-27
-17
-2 º;; cmx= ™5¢;;, y= ™;; 3'2 cm ™2∞;;p
1
-18-5<x<8+5 3<x<13 x>8 8<x<13
x¤ <5¤ +8¤ , x¤ <89 0<x<'8å9
, 8<x<'8å9
1
-26-4<a<6+4 2<a<10 a>6 6<a<10
a¤ >4¤ +6¤
a>2'1å3
, 2'1å3<a<10
2
-1 11¤ <7¤ +9¤ ( ) 3¤ =('5)¤ +2¤ ( ) 4¤ >2¤ +3¤ ( ) 6¤ >('1å4)¤ +4¤ ( ) 13¤ =5¤ +12¤ ( )2
-2 ('1å0)¤ >2¤ +('5)¤3
-1 BC”="3√¤ +4¤ ='2å5=53¤ =x_5 x=;5(;, 4¤ =y_5 y=
y¤ -x¤ ={ }¤ -{;5(;}¤ =7
3
-2 ABCAC”="1√3¤ -ç5¤ ='1∂44=12(cm) , AB”_AC”=BC”_AH”
5_12=13_AH”
AH”=;1^3);(cm)
4
-1 AB”¤ +“CD¤ =“AD¤ +“BC¤AB”¤ +“CD¤ =4¤ +8¤ =16+64=80
4
-2 AB¤” +“CD¤ =“AD¤ +“BC¤('1å3)¤ +x¤ =(2'2)¤ +5¤ , x¤ =20 x=2'5( x>0)
5
-1 AP”¤ +“CP¤ =“BP¤ +“DP¤ 5¤ +3¤ =4¤ +“DP¤“DP¤ =18 “DP=3'2(cm)( “DP>0)
5
-2 PA”¤ +PC”¤ =PB”¤ +PD”¤PB”¤ -PA”¤ =PC”¤ -PD”¤ =4¤ -('7)¤
=16-7=9
6
-1 (R )=;2!;_p_{ }¤ = pP+Q=R
P+Q+R=2R=2_ p=13p
6
-2( )= ABC=;2!;_6_8
=24(cm¤ )
7
-1 DB”=x cm DC”=DA”=(9-x) cm DBC (9-x)¤ =x¤ +6¤81-18x+x¤ =x¤ +36, 18x=45 x=;2%;(cm)
7
-2 ABP AP”=10 cmBP”="1√0¤√ -6¤ ='6å4=8(cm) PC”=10-8=2(cm) PQ”=DQ”=x QC”=6-x
PCQ x¤ =2¤ +(6-x)¤
x¤ =4+36-12x+x¤ , 12x=40 x=PQ”= º;;(cm)
2'1å3 2
4'3 cm
14p ;8%;
4'5 5
(x+3)¤ >x¤ +9¤ x>12 ('5)¤ =1¤ +2¤ ( ) (3'6)¤ >3¤ +6¤ ( ) 10¤ >4¤ +7¤ ( )
9¤ <7¤ +8¤ ( )
10¤ =(2'5)¤ +(4'5)¤ ( )
C<90 c¤ <a¤ +b¤ . c¤ =a¤ +b¤ C=90 .
C A B
. AC”¤ =CH”_BC” 4¤ =2_BC”
BC”=8(cm) , BH”=8-2=6(cm)
AB”¤ =BH”_BC” AB”¤ =6_8=48 AB”=4'3(cm)( AB”>0) AB”¤ =BH”_BC” 6¤ =BH”_12
BH”=3(cm)
H”M”=B’M”-BH”=;2!;_12-3=3(cm) AH”¤ =BH”_CH”” AH”¤ =3_9=27
AH”=3'3(cm)( AH”>0) AHM=;2!;_H”M”_AH”
=;2!;_3_3'3= (cm¤ )
4x-2y+8=0 y 4 ,
x -2
AB”="2√¤ +4¤ ='2å0=2'5 2_4=OH”_2'5
OH”=
BC”¤ +DE”¤ =BE”¤ +CD”¤ , 8¤ +DE”¤ =7¤ +6¤
DE”¤ =21 DE”='2å1( DE”>0) DOC CD”="7¤√ +≈2¤ ='5å3 AB”¤ +CD”¤ =AD”¤ +BC”¤
5¤ +('5å3)¤ =AD”¤ +8¤ , AD”¤ =14
“AD='1å4( AD”>0) 8¤ +(x+2)¤ =(2'2å1)¤ +x¤
64+x¤ +4x+4=84+x¤ , 4x=16 x=4 AB”, BC”, AC”
S¡, S™, S£
S¡=;2!;_p_(2'3)¤ =6p, S™=8p S£=S¡+S™ S£=6p+8p=14p
ABC AB”="(√3'5)¤√ -3¤ ='3å6=6(cm)
( )= ABC
=;2!;_3_6=9(cm¤ ) 4'5
5
9'3 2
2 ;2%; ;5*; 4"5 cm 3 cm 6 cm¤
ABC AG”¤ =BG”_CG”
AG”¤ =1_4 AG”=2( AG”>0)
M ABC
A’M”=B’M”=C’M”=;2!; BC”=;2%;
AMG AG”¤ =AH”_A’M”
2¤ =AH”_;2%; AH”=;5*;
ABE™ C'DE BE”=DE”=x cm AE”=C’'E”=(6-x) cm
ABE 3¤ +(6-x)¤ =x¤ x= ∞;;(cm)
(5, 7, 8), (5, 7, 11), (5, 8, 11), (5, 11, 13), (7, 8, 11), (7, 8, 13), (7, 11, 13), (8, 11, 13) 8 (5, 7, 11), (5, 8, 11), (5, 11, 13), (7, 8, 11), (7, 8, 13) 5
;8%;
DE”
ADE DE”="3√¤ +4¤ =5 ABE BE”="1√0¤ +ç4¤ =2'2å9
DE”¤ +BC”¤ =BE”¤ +CD”¤
5¤ +BC”¤ =(2'2å9)¤ +CD”¤
BC”¤ -CD”¤ =116-25=91
S¡+S™= ABD S£+S¢= BCD
S¡+S™+S£+S¢
= ABD+ BCD
= ABCD=8(cm¤ )
ABD' BD”'’="1√5¤ -ç9¤ =12(cm) CD”'’=15-12=3(cm)
CE”=x E”=DE”=9-x
D'CE 3¤ +x¤ =(9-x)¤ x=4(cm) ABD'=;2!;_9_12=54(cm¤ ) D'CE=;2!;_3_4=6(cm¤ )
ABD' D'CE=54 6=9 1
2 4
B O
H A
A D
B C
4 2
1
-11
-2 6'52
-1 5'2 cm2
-23
-13
-2 ;5&; cm4
-14
-2 4 35
-15
-26
-1 60 cm¤6
-2 2'6 cm4'5 cm 3'2 cm 2 cm 4 cm 4'3 cm h=3, S=12
1
-1 ( )="1≈3≈¤ √-√12¤ ='2å5=5(cm)( )=12_5=60(cm¤ )
1
-2 2k, k(k>0)"(√2k)¤ ç+≈kΩ¤ =15, 5k¤ =225 k¤ =45 k=3'5( k>0)
2_3'5=6'5
2
-1 x'2x=10 x=5'2(cm)
2
-2 a'2a=8'6 a=8'3(cm)
8'3_4=32'3(cm)
3
-1 BD”="6√¤ +8¤ ='1∂00=10(cm)“AB_“AD=“BD_A’H” 6_8=10_“AH 10“AH=48 “AH=4.8(cm)
3
-2 BD”="3¤√ +4¤ =5(cm) AB”¤ =BE”_BD”3¤ =BE”_5 BE”=;5(;(cm) DF”=;5(;(cm) EF”=5-2_;5(;=;5&;(cm)
4
-1 ABC aAH”= a=4'3 a=8(cm) ABC
_8¤ =16'3(cm¤ )
4
-2 AD”=øπAB”¤∑ ∑-∑“B∑D¤ =Æa¤ …-{;…2!;a}¤ =Æ;4#;¬a¤ = a ABC= a¤ , ADE= _{ a}¤ = a¤ABC ADE=4 3
5
-1 AC” B=60 AB”=BC”ABC ACD
ABCD a
ABCD=2 ABC=2_ a¤ =50'3 a=10(cm)( a>0)
5
-2 66_{ _6¤}=54'3(cm¤ )
6
-1 A BC” HBH”=CH”=;2!;BC”=;2!;_10=5(cm)
ABH AH”="1√3¤ -≈5Ω¤ =12(cm) ABC=;2!;_10_12=60(cm¤ )
6
-2 BH”=x CH”=6-x5¤ -x¤ =7¤ -(6-x)¤ , 25-x¤ =49-36+12x-x¤
12x=12 x=1(cm)
AH”="5√¤ -1¤ ='2å4=2'6(cm) '34
'34
3'3 '3 16
'3 2 '3 4
4
'32 '34
'32
6'5 cm
;; cm cm¤
10('5+1)cm cm¤
9'3 4
( )="1√7¤ -ç1ç5¤ ='6å4=8(cm)
( )=2_(15+8)=46(cm)
S¡=2p cm¤ , S¡ S™=1 4 S™=8p cm¤
S£=S¡+S™ S£=2p+8p=10p(cm¤ ) BC”=2x
;2!;_p_x¤ =10p, x¤ =20 x=2'5(cm)( x>0) BC”=2_2'5=4'5(cm)
BE”=x cm DE”=AE”=(8-x) cm BD”=DC”=;2!;_8=4(cm)
BDE (8-x)¤ =x¤ +4¤
64-16x+x¤ =x¤ +16, 16x=48 x=3(cm) DBE=;2!;_BD”_BE”=;2!;_4_3=6(cm¤ )
r (2r)¤ +(2r)¤ =20¤ , 8r¤ =400 r¤ =50 r=5'2( r>0)
( )=pr¤ =p_(5'2)¤ =50p a
26¤ =(5a)¤ +a¤ a='2å6(cm)( a>0)
“AC="(√2√'2å6)√¤ √+('√2å6)¤ ='1å3å0(cm)
ABCD x '2x=6'2
x=6(cm)
ECFG y '2y=12'2
y=12(cm)
DCF
DF”="x√¤ +y¤ ='3∂6ƒ+14å4=6'5(cm) BD”="9√¤ +1≈2Ω¤ =15(cm)
AB”_AD”=BD”_AH” 9_12=15_x x= (cm)
AD”¤ =DH”_DB” 12¤ =y_15 y= (cm)
x+y= + =;; (cm) a
_a¤ =64'3, a¤ =256 a=16(cm)( a>0) ( )= _16=8'3(cm)
a h, S
h= a, S= a¤
AD”= _4=2'3(cm)
AG” 1 AG”= _2'3= (cm)
( )
= ABC+ DEF- GEC=2 ABC- GEC
=2_{ _4¤}-{ _2¤}=8'3-'3=7'3(cm¤ )
ABC 4 cm
AD”= _4=2'3(cm)
ADE 2'3 cm
AF”= _2'3=3(cm)
AFG 3 cm
AFG= _3¤ = 9'3(cm¤ ) '3 4
4 '32
'32
'34 '34
4'3 2 3
3 '32
'34 '32
'32 '34
6 .
a 6_ a¤=96'3, a¤ =64
a=8(cm)( a>0)
6_8=48(cm) BH”=CH”=;2!;_10=5(cm)
ABC AB”="5√¤ +1≈0Ω¤ =5'5(cm) ABC
5'5+5'5+10=10('5+1) cm
A BC” H
BH”=x CH”=14-x
13¤ -x¤ =15¤ -(14-x)¤ , 28x=140 x=5(cm)
AH”="√13√¤ -5¤ ='1∂44=12(cm) ABC=;2!;_14_12=84(cm¤ ) BD”="1√2¤ +ç16¤Ω =20(cm)
AB”_AD”=BD”_AE” 12_16=20_AE”
AE”= (cm)
AB”¤ =BE”_BD”” 12¤ =BE”_20 BE”= (cm)
EF”=BD”-2BE”=20-2_ = ™5•;;(cm) AECF=2 AEF
=2_{;2!;_ ™5•;;_ }
= (cm¤ )
ABC= APB+ BPC+ CPA
_2¤ =;2!;_2_“PD+;2!;_2_“PE+;2!;_2_“PF
“PD+“PE+“PF='3 r cm
r 12 cm
r= _12=6'3
p_(6'3)¤ =108p(cm¤ )
A EF” H
A EF” AH”
AE”=AF”="8√¤ +2¤ ='6å8=2'1å7
EF”="6¤√ +6¤ ='7å2=6'2 EH”=3'2 AEH
AH”="(√2'1å7√)¤ -√(√3√'2)¤ ='5å0=5'2 '32
'34 '34
r cm 12 cm
1
-11
-2 4('3+1)2
-1 2'3 cm2
-23
-13
-2 60 cm¤4
-14
-2 -25
-15
-229
6
-16
-2 57
-17
-2 2'4å1x=4 cm, y=4'2 cm x=4'3 cm, y=4 cm x=6'3, y=3'6 '5 '2å6 2'5
1
-1 ABC x=4'3BCD 4'3 y='3 2 y=8 xy=4'3_8=32'3
1
-2 A BC” HABH 8 BH”=2 '3 BH”=4'3 8 AH”=2 1 AH”=4
ACH 4 HC”=1 1 HC”=4
BC”=BH”+HC”=4'3+4=4('3+1)
2
-1 ABC 8 BC”=2 '3 BC”=4'3(cm)BCD 4'3 BD”=2 1 BD”=2'3(cm)
2
-2 ABH 4 BH”=2 1 BH”=2(cm)4 AH”=2 '3 AH”=2'3(cm) ACH CH”=8-2=6(cm) AC”="(√2'3)√¤ +6¤ =4'3(cm)
3
-1 EBF EF”='1∂44=12(cm) EB” 12='3 2 EB”=6'3(cm) BF” 12=1 2 BF”=6(cm)AB”=AE”+EB”=BF”+EB”
=6+6'3=6(1+'3)(cm)
3
-2 A BC” HABH 4'3 AH”=2 '3 AH”=6(cm) ABCD=10_6=60(cm¤ )
4
-1 "3√¤ +4¤ =5 "4√¤ +0¤ =4"1√¤ +2¤ ='5 "0¤√ +4¤ =4
"2√¤ +1¤ ='5
4
-2 AB”="(√3-a√)¤ +√(√-√4√-1)Ω¤ =5'2 a¤ -6a+9+25=50, a¤ -6a-16=0 (a-8)(a+2)=0 a=8 a=-2A 2 a=-2
5
-1 OA”="1√¤ +2¤ ='5, OB”="(√-2)√¤ +3¤ ='1å3 AB”="(√-2√-1)√¤ +(√3-2≈)Ω¤ ='1å0OB” , OB”¤ <OA”¤ +AB”¤
OAB .
5
-2 AB”="(√-4√-6)√¤ +(√0+4≈)¤Ω ='1∂16=2'2å9 BC”="(√3+4√)¤ +√(3-ç0)Ω¤ ='5å8CA”="(√3-6√)¤ +√(3+≈4≈)Ω¤ ='5å8 AB”¤ =BC”¤ +CA”¤ , BC”=CA”
4'2cm 4 cm (48p-64) cm¤
8'2 cm 2'6 cm 6'3 cm¤ 3'7 cm '7å9 cm
8cm 8'2cm
;2!;_8'2=4'2(cm) 8cm 8cm
;2!;_8=4(cm)
= - +
=p_(4'2)¤ -8¤ +p_4¤
=48p-64(cm¤ ) ABC
BC”="(√4'6)√¤ +(√4'2)Ω¤ ='1∂28=8'2(cm) AB”_AC”=BC”_AD”
4'6_4'2=8'2_AD” AD”=2'6(cm) ADE= _(2'6)¤ =6'3(cm¤ )
CH”=x BH”=10-x
AH”¤ =12¤ -(10-x)¤ =8¤ -x¤ x=1(cm) ACH AH”="8√¤ -1¤ ='6å3=3'7(cm) B’M”=CM”=;2!;BC”=;2!;_10=5(cm) M”H”=M”C”-CH”=5-1=4(cm)
AMH A’M”="4¤√ +(√3'7)Ω¤ ='7å9(cm) '34
-2-1 1 2 3 B
A x y
2
-2 -1 -3 1 O
ABC C=90 . ABC=;2!;_'5å8_'5å8=29
6
-1y=(x¤ -4x+4-4)+2=(x-2)¤ -2 P(2, -2)x=0 , y=2 Q(0, 2) PQ”="(√2-0√)¤ +√(-2√-2)Ω¤ =2'5
6
-2y=2x¤ +4x+1=2(x¤ +2x+1-1)+1=2(x+1)¤ -1
(-1, -1)
(-1, -1) A(2, 3)
"(√2+1√)¤ +√(3+√1)¤ ='2å5=5
7
-1 B xB' B'(5, -1)
(AP”+BP” )
=A’B'”
="(√5-1√)¤ +√(-1√-ç3)Ω¤
='3å2=4'2
7
-2 A BC”A', A' BC”
DC” D'
DA'D' A’'D”="1√0¤ +Ω8Ω¤ ='1∂64=2'4å1
4 cm 6+10'3
6'2 2'1å3 (8+4'3) cm B(4, 8)
ABC AB” BC”=1 '3 2 BC”=1 '3 BC”=2'3(cm)
BDC BC” CD”='2 1 2'3 CD”='2 1 CD”='6(cm)
45 , 45 , 90 1 1 '2 , 30 , 60 , 90
1 '3 2 .
ACD AD” AC”=1 '2
2'6 AC”=1 '2 AC”=4'3(cm) ABC AC” BC”='3 2
4'3 BC”='3 2 BC”=8(cm) HBC BH” BC”='3 2 6 BC”='3 2 BC”=4'3(cm)
ABC BC” AC”='3 1 4'3 AC”='3 1 AC”=4(cm)
A=60 BAD= DAC=30
ABC AB “AC=2 1, 2'3 AC”=2 1
“AC='3(cm)
ADC AD “AC=2 '3, AD '3=2 '3 AD”=2(cm)
x
ABC AC” BC”=1 '2 AC” x=1 '2
AC”= x
20 cm x+x+ x=20, ('2+1)x=20
x= = =20('2-1)(cm)
A,
D BC
E, F ABE
AB” BE”='2 1
2'6 BE”='2 1 BE”=2'3 DFC DF” FC”='3 1 2'3 FC”='3 1 FC”=2
ABCD
;2!;_{4+(2'3+4+2)}_2'3
=(10+2'3)_'3=6+10'3
'5 '1å3 '3å7 3'2 '3å4
PQ”¤ =(a-2)¤ +(-1-2)¤ =45 a¤ -4a+4+9=45, a¤ -4a-32=0 (a-8)(a+4)=0 a=-4( a<0)
x C(x, 0)
AC”=BC”
"(√x+1√)¤ +√(0-ç3)Ω¤ ="(√x-2√)¤ +√(0-ç4)Ω¤
x¤ +2x+10=x¤ -4x+20, 6x=10 x=;3%;
20('2-1) ('2+1)('2-1) 20
'2+1 '22 '22
'22
y
x 4
2
O 2 P 4
B' B A
6 2
2 10 2
A B
D
P C
A' D'
45
A C
B 20 cm
2'6 2'3
45 60
4
4 2 C
B
D
E F A
AB”="(√2+1√)¤ +√(1-ç3)¤Ω ='å1å3 BC”="(√4-2√)¤ +√(4-ç1)¤Ω ='1å3 CA”="(√4+1√)¤ +√(4-≈3Ω)Ω¤ ='2å6 CA”¤ =AB”¤ +BC”¤ , AB”=BC”
B=90 .
ABC=;2!;_'1å3_'1å3=
y=x+4 y=;2!;x¤
x+4=;2!;x¤ , x¤ -2x-8=0, (x-4)(x+2)=0
x=-2 x=4
, A(-2, 2), B(4, 8)
“AB="(√4+2√)¤ +√(8-√ç2)¤ ='7å2=6'2 A y
A'(-2, 5) AP”=A’'P”
AP”+BP”
A’'B”="{√4-(√-2)√}¤ +(√1-5≈)≈¤
='5å2=2'1å3
ADC AD” 4=2 1 AD”=8(cm) DC” 4='3 1 DC”=4'3(cm)
ADC= ABD+ BAD
30 =15 + BAD BAD=15 , ABD BD”=AD”
BD”=AD”=8(cm)
BC”=BD”+DC”=8+4'3(cm)
A CE” H
ACE=60 ACH “AC “AH=2 '3
4 AH”=2 '3 AH”=2'3(cm) ACE=;2!;_6_2'3=6'3(cm¤ )
B {a, ;2!;a¤ } OA”¤ +AB”¤ =OB”¤
(-2)¤ +2¤ +{ a-(-2) }¤ +{;2!;a¤ -2}¤ =a¤ +{;2!;a¤ }¤
2a¤ -4a-16=0, a¤ -2a-8=0, (a+2)(a-4)=0
a=-2 a=4
B 1 a=4
B(4, 8)
P Q BC”, AD”
P', Q'
P’'Q'”
P’'Q'”="1√0¤ √+√10¤ ='2∂00=10'2(cm)
72('3-1) 4 cm 4'3 cm 8'3 cm¤
AB”=5'2, BC”=2'1å0, CA”='1å0 C=90 10
ADC AC” DC”=1 1 AC” 12=1 1 AC”=12
ABC BC” AC”='3 1 BC” 12='3 1 BC”=12'3
BD”=BC”-DC”=12'3-12
ABD=;2!;_(12'3-12) 12=72('3-1) ABC AB” 8=1 2 AB”=4(cm) ABC AC” 8='3 2 AC”=4'3(cm)
ABC
( )= ABC=;2!;_4_4'3
=8'3(cm¤ ) AB”="(√-3√-2)¤√ +(√0-5≈)≈¤ ='5å0=5'2
BC”="(√3+3√)¤ +√(2-ç0)≈Ω¤ ='4å0=2'1å0 CA”="(√3-2√)¤ +√(2-ç5)≈¤ ='1å0
“AB¤ =“BC¤ +“CA¤
ABC C=90 .
ABC=;2!;_2'1å0_'1å0=10
'7å0 cm 4'3 cm 2'7 cm
cm‹ 4 cm 12p cm‹
'1∂37 cm 32'7
3
1
-11
-2 cm¤2
-1 27 cm‹2
-23
-13
-2 12 cm4
-1 8'3å4 cm¤4
-2 64'2 cm‹5
-1 3'3 cm 9'3p cm‹5
-26
-16
-25'1å1 2
x A'
y
1 2 O
-2 4
A
P B 5
2 cm
2 cm Q' A
P'
C D 6 cm
10 cm B
1
-1 h"4√¤ +3√¤ +h¤ =5'2, 25+h¤ =50, h¤ =25 h=5( h>0)
1
-2AE”=x"4√¤ +3√¤ +x¤ =6, 25+x¤ =36, x¤ =11 x='1å1(cm)( x>0)
, EG”="3√¤ +4¤ =5(cm)
AEG=;2!;_5_'1å1= (cm¤ )
2
-1 a'3a=3'3 a=3(cm) ( )=3‹ =27(cm‹ )
2
-2 DAB “BD="9¤√ +9¤ ='1∂62=9'2(cm) DAE “DE="9¤√ +9¤ ='1∂62=9'2(cm) BEF “BE="9¤√ +9¤ ='1∂62=9'2(cm)( DEB )=“BD+“DE+“BE
=9'2+9'2+9'2
=27'2(cm)
3
-1 aa=2'3 a=3'2(cm)
( )= _(3'2)‹ =9(cm‹ )
3
-2 aa‹ =144'2 a=12(cm)
4
-1BD”="8√¤ +8¤ =8'2(cm)HD”=;2!;BD”=;2!;_8'2=4'2(cm) OH”="1√0¤ -√(4'√2)¤ ='6å8=2'1å7(cm)
OBD=;2!;_BD”_OH”
=;2!;_8'2_2'1å7=8'3å4(cm¤ )
4
-2 OCH CH”="(√5'2)√¤ -(√3'2)Ω¤ =4'2(cm) AC”=2CH”=2_4'2=8'2(cm)ABCD
a '2a=8'2 a=8(cm)
( )=;3!;_8¤ _3'2=64'2(cm‹ )
5
-1 r2p_r=6p r=3(cm) AOB
( )="6√¤ -3¤ ='2å7=3'3(cm)
( )=;3!;_(p_3¤ )_3'3=9'3p(cm‹ ) '212
'212 '63
5'1å1 2
5
-2 AC”="8√¤ -4¤ ='4å8=4'3(cm) ( )=;3!;_(p_4¤ )_4'3= p(cm‹ )
6
-1 ( )=“AG="6¤√ +9¤='1å1å7
=3'1å3(cm)
6
-2 OABCAC” OB”
A’M”=C’M”, O’M”=B’M”
A’M”= _2'3=3(cm)
( )=AC”=2A’M”=2_3=6(cm) '32
64'3 3
5'3 cm 9'2 cm¤
5p cm¤ 10p
96 cm¤
EFG
EG”="8√¤ +6¤ =10, EO”=;2!;EG”=;2!;_10=5 AEO AO”="8√¤ +5¤ ='8å9
AG”="8√¤ +6√¤ +1ç0¤ ='2∂00=10'2(cm) EG”="8√¤ +6¤ ='1∂00=10(cm)
AEG AE”_EG”=AG”_E’I’
10_10=10'2_E’I’ E’I’=5'2(cm)
"1√0¤ +√10¤ √+√10¤ =10'3(cm)
;2!;_10'3=5'3(cm) .
AMGN A’M”=MÚG”=GN”=NÚA”=2'5(cm)
“AG=4'3(cm), M”N”=“FH=4'2(cm) AMGN=;2!;_“AG_M”N”
=;2!;_4'3_4'2=8'6(cm¤ )
4 cm A
B 8 cm
l
C G
F A
6 cm
5 cm B 4 cm D
2'3 cm
A C
B M
O
;3$; 2'3 6 cm 216p cm‹ 90 8'5 cm
2'3 3 A’M”=D’M”= _18=9'3(cm)
M”H”=;3!;_9'3=3'3(cm) AMH
AH”="(√9'3)¤√ -(√3√'3)¤ ='2∂16=6'6(cm) AMH=;2!;_3'3_6'6=27'2(cm¤ ) B’M”=C’M”= _6
=3'3(cm) BH”=CH”=3(cm)
M”H”="(√3'3)√¤ -3¤ =3'2(cm) BCM=;2!;_6_3'2=9'2(cm¤ ) CE”="6¤√ +6¤ =6'2(cm)
CH”=3'2(cm) ACH
“AH="9√¤ -(√3√'2)¤ =3'7(cm) ( )=;3!;_6¤ _3'7
=36'7(cm‹ )
"1√0¤ -≈8≈¤ ='3å6=6
;3!;_(p_6¤ )_8=96p r
2pr=2p_6_ r=2(cm)
( )="6¤√ -2¤ =4'2(cm) AHO AH”="3¤√ -2¤ ='5(cm)
'5 cm
( )=p_('5)¤ =5p(cm¤ )
( )=DE”="3√¤ +9¤ ='9å0=3'1å0(cm)
( )=“AB
="(√8p)¤ √+(6çp)Ω¤
="1ç00ç≈p¤ =10p 120360
'32
'32 AD”=x
AB”=BC”="√x¤ +√3¤ +≈4Ω¤ ="√x¤ +ç25, AC”=x+x=2x , ABC=90 AB”¤ +BC”¤ =AC”¤
(x¤ +25)+(x¤ +25)=(2x)¤ , x¤ =25 x=5( x>0) AC”=2x=10 D’M”=D’N”="1√6¤ +ç8¤ =8'5(cm) M”N”="8√¤ +8¤ =8'2(cm)
DMN
( )="(√8'5√)¤ -√(4'ç2)Ω¤ =12'2(cm) DMN=;2!;_8'2_12'2=96(cm¤ )
AQ”
AQ”= _4=2'3(cm) QH”="(√2'3)√¤ -1¤ ='1å1(cm)
ABPQ=;2!;_(2+4)_'1å1
=3'1å1(cm¤ )
( )
=( )
=2p_2=4p(cm)
2p_6_ =4p ( )=120
BAC 2 '3=6 AC” AC”=3'3(cm) BA'C 2 '3=6 A’'C” A’'C”=3'3(cm)
( )=A’A'”=AC”+A’'C”=6'3(cm) 360
'32
( B-AFC )=( C-ABF
)
C-ABF ABF
BC”
C-ABF ;3!;_;2!;_2¤ _2=;3$;
( B-AFC )=;3$;
AFC 2'2
AFC _(2'2)¤ =2'3
B-AFC ;3$;
;3$;=;3!;_2'3_B’I’ B’I’= 2'33 '34
M
B C
6 cm 3'3 cm 3'3 cm
H
6 cm 9 cm
6 cm A
C
D
E
B
A 8p
6p A
D C G H
B F E
3 cm
3 cm 3 cm 3 cm
Q
A H B
2 P
4 2 2'3
1 1
B
A 30 C 30 A'
60 60
6 cm 6 cm
AO”=CO”=10 cm OH”=18-10=8(cm) OHC HC”="1√0¤ √-8¤ ="3Ω6=6(cm) ( )=;3!;_(p_6¤ )_18=216p(cm‹ )
x
2p_4=2p_16_
x=90
( )=B’M”="1√6¤ +ç8¤ =8'5(cm) x
360
86 60
57 kg 59
16
2'2å1 km cm¤
3'4å1
3'3 cm 256'5p
3
=6 a+b+c+d=8
a, b c, d
=;4*;=2
12, 13, 14, 15, 15, 16, 17, 18, 18, 19
=15.5( )
4, 7, a 7 aæ7
11, 13, a 11 a…11
7…a…11 x
=84, 334+x=420 x=86( )
82 , 86 , 72 , 86 , 94 86
82+x+72+86+94 5
15+16 2 a+b+c+d
4
(4a-2)+(4b-2)+(4c-2)+(4d-2) 4
80 x=80( )
, 4 =80( )
5 a 5
=80-4, 320+a=380 a=60( )
B x kg
4+x+(-2)+1+(-6)=0 x=3(kg)
B 3+54=57(kg)
=5 x=3
( )= = º;;=2
3 8
(A )= Ƽ;;= ( )
(B )= ∆;;= ( )
(C )= ™∆;;='2( )
A, C, B
=8 x+y=15
=4 x¤ +y¤ =107 xy=59
( )=
=;1%0);=5( )
( )
=
=Æ;1%¬0*;='5ß.8( )
(A )=(B )= ∞;;=7( )
(B )
= ='2( )
(A )
= =Æ;5@;= ( )
B A
'1å05 1¤ +0¤ +0¤ +(-1)¤ +0¤
5
0¤ +(-2)¤ +1¤ +2¤ +(-1)¤
5
(-3)¤ _2+(-1)¤ _4+1¤ _2+3¤ _1+5¤ _1 10
2_2+4_4+6_2+8_1+10_1 10
(-3)¤ +0¤ +(x-8)¤ +(y-8)¤ +4¤
5 5+8+x+y+12
5
2'6 3 '1å53
(-1)¤ +(-2)¤ +2¤ +0¤ +1¤
5 4+x+7+5+6
5
90+70+80+80+a 5
90+70+80+80 4
æ≠ ≠ ≠ ≠ ≠ ≠ ≠ ≠ ≠
æ≠ ≠ ≠ ≠ ≠ ≠ ≠
æ≠ ≠ ≠ ≠ ≠ ≠
B
A
16 cm 8 cmM
4 cm
ADC x¤ +6¤ =10¤ x=8( x>0) ABC 17¤ =x¤ +(y+6)¤ , 289=64+(y+6)¤
y¤ +12y-189=0, (y+21)(y-9)=0 y=9( y>0)
x+y=17
ABCD '6å4=8(cm)
, AB”=BC”=CD”=DA”=8(cm) AH”=8-3=5(cm)
AEH EH”="3√¤ +5¤ ='3å4(cm) EFGH=('3å4)¤ =34(cm¤ )
x-4<x<x+4 x+4
(x+4)¤ =(x-4)¤ +x¤ , x¤ -16x=0 x(x-16)=0 x=16( x>4)
ABC BC”="8√¤ +6¤ ='1∂00=10 AB”¤ =BD”_BC”
8¤ =BD”_10 BD”=6.4 4¤ +OC”¤ =6¤ +8¤ , OC”¤ =84
OC”=2'2å1(km)( OC”>0)
S¡+S™=S£ S¡+S™=;2!;_p_8¤ =32p(cm¤ )
BDC™ BDE CBD= EBD
AD” BC” FDB= CBD( )
FBD= FDB BFD BF”=DF”
AF”=x DF”=BF”=10-x
ABF (10-x)¤ =x¤ +6¤ , 20x=64 x= (cm)
ABF=;2!;_AB”_AF”=;2!;_6_ (cm¤ )
"6√¤ +6¤ ='7å2=6'2(cm)
3'2 cm 3 cm
( )=p_(3'2)¤ -p_3¤
=18p-9p=9p(cm¤ )
A BC” H
BH”=15-10=5
ABH AH”=DC”="1√3¤ -ç5¤ ='1∂44=12 DBC BD”="1√5¤ +√12¤ =3'4å1
a 6
6_{ _a¤}=18'3, a¤ =12 a=2'3(cm)( a>0)
'34
A BC” H
BH”=x CH”=6-x
AH”¤ =7¤ -x¤ =5¤ -(6-x)¤ x=5 AH”="7√¤ -5¤ ='2å4=2'6
ABC=;2!;_6_2'6=6'6 ABC AC”="6√¤ +6¤ ='7å2=6'2
ACE 6'2 CE”='3 2 CE”=4'6 DCE CD” 4'6=1 '2 CD”=4'3 y=-(x¤ -6x+9-9)-2=-(x-3)¤ +7 P(3, 7)
x=0 y=-2 Q(0, -2)
PQ”="(√0-3√)¤ +√(-√2√-√7≈)¤ ='9å0=3'1å0 EG”="1√2¤ +ç8¤ ='2∂08=4'1å3(cm)
EP”=;2!;EG”=;2!;_4'1å3=2'1å3(cm)
AEP AEP=90
AP”="1√0¤ +√(2'1çå3)Ω¤ ='1∂52=2'3å8(cm) BD”=BG”=DG”=9'2 cm
BGD 9'2 cm
BGD= _(9'2)¤ = (cm¤ )
C BGD x cm
D-BCG
;3!;_ _x=;3!;_{;2!;_9_9}_9 x=3'3(cm)
( ABC )= _12¤ =36'3(cm¤ )
r
2pr=2p_12_ r=8
h
h="1√2¤ -ç8¤ ='8å0=4'5
( )=;3!;_p_8¤ _4'5= p
( )
=AD”'”
="(√4+3√+5)√¤ +8¤
='2∂08
=4'1ß3(cm)
256'5 3 240
360 '34 81'3
2
81'3 '3 2
4
8 cm 4 cm 3 cm
A
D E F D'
5 cm A'
B C
h 12
r
sin A=;5#;, cos A=;5$;, tan A=;4#; '6 6
1
-11
-22
-12
-2 ;3*;3
-1 ;5&;3
-24
-1 44
-2 '25
-15
-2 3(1+'3)6
-16
-2 1.27387
-17
-2 -1 18
-11.3724 40
8
-2 0.1344'53
;4#;
5'3 101
3+'5 ;3*;
2
1
-1 tan A= = ™;;1
-2AC”="6√¤ -4¤ ='2å0=2'5 cos A= =2
-1BC”="7√¤ -5¤ ='2å4=2'6 tan A=
2
-23 cos A-1=0 cos A=;3!;BC”="3√¤ -1¤ =2'2
sin A_tan A= _2'2=;3*;
3
-1BC”="8√¤ +6¤ =10ABHª CBA(AA )
BCA= BAH= x
sin x= =;5#;, cos x= =;5$;
sin x+cos x=;5#;+;5$;=;5&;
3
-2 ACDª DCH x= DACAC”="1√6¤ +ç12Ω¤ ='∂40å0=20 sin x= =;2!0@;=;5#;
4
-1 ( )=2_ _'3+4_;2!;_;2!;=3+1=44
-2cos (x+15 )=;2!; x+15 =60 x=45sin x+cos x=sin 45 +cos 45 = +'2='2 '2 2
2 '32
CD”
AC”
AC”
BC”
BA”
BC”
2'2 3 2'6
5
'53 2'5
6 BC”
AC”
5
-1 sin 30 =;1”2;=;2!; x=6 cos 30 =;1’2;= y=6'3xy=6_6'3=36'3
5
-2 ABH sin 60 = = AH”=3'3cos 60 = =;2!; BH”=3
AHC tan 45 = =1 CH”=3'3 BC”=BH”+CH”=3+3'3=3(1+'3)
6
-1 cos 40 =0.77 cos 50 =0.64 tan 40 =0.84 tan 50 =1.196
-2 sin 35 = =0.5736 tan 35 = =0.7002 sin 35 +tan 35 =1.27387
-1 sin 90 =1 , tan 907
-2 ( )=(0-1)(1-0)=(-1)_1=-1 ( )=1¤ +1¤ -1¤ =1+1-1=18
-1 sin 39 =0.6293, cos 42 =0.7431 ( )=0.6293+0.7431=1.3724tan 40 =0.8391 x=40
8
-2 tan 42 =0.9004, cos 40 =0.7660 tan 42 -cos 40 =0.9004-0.7660=0.1344
CD”
OD”
AB”
OA”
3'3 CH”
BH”6
'32 AH”6 '32
A C
B 7
5 2'6
A B
C
1
3 2'2
AB”="5√¤ +√1≈2¤ ='1∂69=13 sin A=;1!3@;, cos A=;1∞3;
sin A-cos A=;1!3@;-1∞3;=;1¶3;
BC”="5√¤ -4¤ ='9=3 tan A=;4#;
ABCª ACDª CBD x= B, y= A
A
B 90 -A C 5
3 4
BC”="1√7¤ -ç8¤ ='2∂25=15(cm) cos x=cos B=;1!7%;, cos y=cos A=;1•7;
cos x-cos y=;1!7%;-;1•7;=;1¶7;
3x+4y-12=0
x 4, y 3
AB” ="3√¤ +4¤ =5 sin a=;5#;
EG”="3√¤ +3¤ =3'2, “CE="(√3'2)¤√ +3¤ ='2å7=3'3
cos x= = = =
;2!;= _ = =
{;2!;}¤ +{;2!;}¤ =;2!;+1 ;2!;+ = +1
ABC tan 60 = AC”=10 tan 60 =10'3
ACD sin 30 = AD”=10'3 sin 30 =5'3
ABD tan 30 = = BD”=6'3
ACD tan 60 = ='3 CD”=2'3 BC”=BD”-CD”=6'3-2'3=4'3
x sin x .
;2!; '3 1 0
sin 50 =0.7660 x=50 tan 51 =1.2349 y=51
x+y=50 +51 =101
cos 51 = =0.6293 AB”=6.293
QC”=PC”=AP”=6 cm CR”=AB”=4 cm
CQR
QR”="6√¤ -4¤ =2'5(cm) H”A”=QB”=QR”=2'5 cm PH”=(6-2'5)=2(3-'5) cm
HQP
tan x= = =
= 2(3+'5) = 3+'52 (3-'5)(3+'5)
2 3-'5 4
2(3-'5) HQ”
PH”
AB”10 '32
6 CD”
'33 6 BD”
AD”
10'3 AC”10
1+'3 '3 2
2 '33 '31 '33 '33
'32
'63 '2'3 3'2 3'3 EG”
CE”
sin x= =;3!; AC”=9 ABCª EDC(AA ) 9 3=3 CD” CD”=1
CDE DE”="3√¤ -1¤ =2'2 tan y= =
ABC
tan 60 = = ='3 BC”=4'3(cm) DBC
sin 45 = = = BD”=4'6(cm)
45 <x<90 , sin x>cos x sin x+cos x>0, cos x-sin x<0 ( )=sin x+cos x+(cos x-sin x)
=2 cos x
2 cos x=;3@; cos x=;3!;
sin x_tan x=2'2_2'2=;3*;
3 '22 4'3 BD”
BC”
BD”
BC”4 BC”
AB”
'25 2'2
10 3 AC”
x 4, y -5 6('3-1) cm
9'4å1 8'2 41
3
æ≠ ≠ ≠ ≠
A
B 4 O
3
a y
x 5
A
B Q
R C P D
6 cmH
4 cm x
A
B x C
1 2'2 3
A BCD H
A’M”=D’M”= _4=2'3 M”H”=;3!;D’M”=;3!;_2'3=
AH”= (2'3)¤ -{ }¤ = , sin x= = ÷2'3=
tan x= = ÷ =2'2
sin x+tan x= +2'2=
-5x+4y+20=0 y=;4%;x-5
y=;4%;x-5 y=0 x=4
A(4, 0)
y=;4%;x-5 x=0 y=-5 B(0, -5)
x 4, y -5 .
8'2 2'2 3
3 2'3 4'6 3 AH” 3 MÚH”
2'2 4'6 3
AH” 3 A’M”
4'6 2'3 3
3
2'3 3 '32
AOB AB”='4ƒ¤ +5¤ ='4å1
sina= =
cosa= =
sina+cos a= + =
BEF=90 -45 =45 , CEF=90 -30 =60 EF”=x cm
BEF tan 45 = BF”=x tan 45 =x(cm)
CEF tan 60 = CF”=x tan 60 ='3x(cm)
BF”+CF”=BC” x+'3x=12, (1+'3)x=12
x= = =6('3-1)
EF” 6('3-1) cm 12(1-'3) (1+'3)(1-'3) 12
1+'3
CF”x BF”x
9'4å1 4'4å1 41 5'4å1 41
41 4'4å1 4 41
'4å1 5'4å1 5 41
'4å1
AC”=5 cm, BC”=5'3 cm 12'3 27'3
1
-11
-2 6'3 m2
-12
-23
-150(3-'3) m
3
-2 9(3-'3)4
-14
-25(1+'3) cm
5
-1 20'3 cm¤5
-2 1206
-16
-21
-1 sin 50 = BC”=AB” sin 501
-2AB”=6 tan 30 =6_ =2'3(m)AC”= =6÷ =4'3(m)
( )=AB”+AC”=2'3+4'3=6'3(m)
2
-1 AH”=3'2 sin 45 =3'2_ =3ABH BAH=45 BH”=AH”=3
'22 '32 cos 306
'33 BC”
AB”
CH”=BC”-BH”=5-3=2 AHC AC”="√3¤ √+2¤ ='1å3
2
-2 ABC A=180 -(30 +105 )=45C AB” H
BCH CH”=12sin 30 =6(cm)
AHC AC”= =6'2(cm)
3
-1 AH”=hBH”=h tan (90 -45 )=h tan 45 =h CH”=h tan (90 -60 )=h tan 30 = h BC”=BH”+CH”
h+ h=100, { }h=100 h= =50(3-'3)(m)
3
-2 BH”=h AH”=h tan 30 = h CH”=h tan 45 =hAC”=AH”+CH” h+h=18
h= =9(3-'3)
4
-1 AH”=hBH”=h tan 60 ='3h CH”=h tan 30 = h BC”=BH”-CH”
12='3h- h, h=12
h=12_ =6'3
4
-2 AH”=hBH”=h tan 60 ='3 h, CH”=h tan 45 =h BC”=BH”-CH”=('3 -1)h=10
h= =5(1+'3 )(cm)
5
-1 ABC=;2!;_8_10_sin 60 =20'3(cm¤ )5
-2 ABC=;2!;_8_9_sin (180 -C)=18'3 sin (180 -C)= 180 -C=60C=120
6
-1ABCD=6_6_sin(180 -135 )=18'2
6
-2 ABCD=;2!;_5_4_sin (180 -135 )=5'2 '3210 '3-1
3 2'3
2'3 '3 3
3 '33 3+54'3
'33
'33 300
3+'3
3+'3 '3 3
3
'33 sin 456
A O
B
a 4 '4å1 5
4(1+'3) cm 75('3-1) m
12p-9'3
1.76 m ;;5#;
100'3 m 50 m 50'1å3 m (2+'3) cm 2-'3 40'3 cm¤
3 BC”=100 tan 31 =60(m)
( )=1.5+60=61.5(m) DH”=AH”=BD”=50(m)
CH”=AH ” tan 30 =50_ = (m)
“CD=“CH+“DH= +50= (m)
A BC” H
AH”=8 sin 60 =4'3(cm), BH”=8 cos 60 =4(cm) CH”= =4'3(cm)
“BC=BH”+CH”=4+4'3=4(1+'3)(cm) A
H ,
“AH=h “BH=h
AHC ACH=30
CAH=60 “CH=h tan 60 ='3h
“BC=“BH+“CH=h+'3h, ('3+1)h=150 h= =75('3-1)(m)
ABC CBH=60 ACB=30
“AB=“BC=50'3(m)
“CH=50'3 sin 60 =50'3_ =75(m) cos B=;3!;
A’'C'”="3√¤ -1¤ ='8=2'2 sin B=
ABC=;2!;_8_9_sin B
=;2!;_8_9_ =24'2(cm¤ )
BD”
ABCD= ABD+ BCD
=;2!;_5_5_sin(180 -120 )+;2!;_5'3_5'3_sin60
= +75'3=25'3(cm¤ ) 25'3 4
4
2'2 3 2'2
3
'32 '3+1150
4'3 tan 45
50('3+3) 50'3 3
3
50'3 '3 3
3
( )=8_{;2!;_4_4_sin 45 }=32'2 AMC=;4!; ABCD=;4!;_(4_3_sin 60 )=
“AC=“BD ABCD=;2!;_AC”_BD”_sin(180 -120 )
=;2!;_BD”¤ _sin60 =16'3 BD”¤ =64 BD”=8(cm)( BD”>0) OC”
( )
=( AOC )- AOC
=p_6¤ _ -;2!;_6_6_sin(180 -120 )
=12p-9'3 OH”=OC”_cos 45
=3.2_ =2.24(m) h=4-2.24=1.76(m)
B AC”
H
“BH=100sin 45 =50'2(m)
“AB= =
= (m)
AH”=CH” cos 60 = = CH”=200 cos 60 =200_;2!;=100(m) D’M”=D’N”="2√¤ +1¤ ='5
ABCD= AMD+ DMN+ DNC+ MBN
2_2=;2!;_2_1+;2!;_'5_'5_sinx+;2!;_1_2+;2!;_1_1 4=;2%;+;2%; sin x, ;2%; sin x=;2#; sin x=;5#;
CH”
200 AH”
200 100'6
3
50'2 cos 30 cos 30BH”
'22 120 360
3'3 2
ABH AH”=200 sin 60 =100'3(m) ABH BH”=200 cos 60 =100(m)
CH”=BC”-BH”=150-100=50(m)
150 m 45
45 30
B H
h
C A
A'
C' B
3
1
30
45 45
A
B C
H
100 m
O D
B A C
H 45 45 3.2 3.2
0.8 h
4
ACH
AC”="(√100√'3)¤√ +√50¤ ='3∂25∂00 =50'1å3(m)
CDB BD”= ='3(cm)
CD”= =2(cm)
AB”=AD”+BD”=CD”+BD”=2+'3(cm) CDB=30
CAD= ACD=;2!;_30 =15 CAB
tan 15 = = =2-'3 DCH
CD”= = (cm)
BH'C
BC”= = (cm)
ABCD
ABCD= _ _sin (180 -120 )
=40'3(cm¤ ) 3
10'3 8'3 3
3 8'3 4 3
sin 60
10'3 5 3
sin 60
1 2+'3 BC”
AB”
sin 301
1 tan 30
8 cm 8 cm 6 cm 18 cm
1
-11
-2 20 cm2
-1 '1å1 cm2
-23
-15 cm
3
-2 8'34
-1 3 cm¤4
-2 4 cm5
-15
-2 3'3 cm6
-16
-27
-1 137
-21
-1CE”+2AB”
1
-2OD” AD” OC”OAD= BOC=30
AO”=OD” OAD= ODA=30
AOD=180 -2_30 =120
120 30 =µAD 5 µAD=20(cm)
2
-1 AH”=;2!;AB”=5(cm)OAH OH”="6√¤ -5¤ ='1å1(cm)
2
-2 M”B”=;2!;AB”=6(cm) OB”=x O’M”=x-4OBM x¤ =6¤ +(x-4)¤ , 8x=52 x=6.5(cm)
3
-1 O’M”=ON” AB”=CD”=6(cm) CN”=;2!;CD”=3(cm)OCN OC”="3√¤ +4¤ =5(cm)
3
-2 OA”OA”=4 A’M”="4√¤ -2¤ =2'3 AB”=2A’M”=4'3
O’M”=ON” CD”=AB”=4'3 AB”+CD”=4'3+4'3=8'3
4
-1 PAO= PBO=90AOB=360 -(90 +90 +60 )=120
p_3¤ _ =3p(cm¤ )
4
-2 PT O OT” PT”PA”=x
6¤ +8¤ =(6+x)¤ , x¤ +12x-64=0
(x+16)(x-4)=0 x=4(cm)( x>0)
5
-1 PBO=90PBO PB”="1√5¤ -≈9¤Ω =12(cm) PA”=PB”=12(cm)
PA”+PB”=24(cm)
5
-2 OP” AOP™ BOPAPO= BPO=30 , AOP= BOP=60 AOP AP” OA”='3 1 9 OA”='3 1 OA”= =3'3(cm)
O 3'3 cm
6
-1 BP”=BQ”=xAP”=AR”=8-x, CQ”=CR”=10-x AC”=AR”+CR” 6=(8-x)+(10-x) 2x=12 x=6(cm)
6
-2 O r cmAD”=AF”=(8-r) cm CE”=CF”=(15-r) cm AC”="8√¤ +1≈5Ω¤ =17(cm) AC”=AF”+CF”=AD”+CE”
17=(8-r)+(15-r) r=3(cm) '39
120360
4 cm
5 cm
C H B
H' A D
60
A C
O
M B
x-4 x 46
7
-1AB”+CD”=AD”+BC”AB”+6=12+7 AB”=13
7
-2 POSD, ORCSDS”=SC”=2(cm)
AP”=x cm DP”=DS”=2(cm) 5+4=(x+2)+6 x=1(cm)
9 cm
4'5 2 cm
4.2 cm 20(2-'3) cm
DO”=DE” EOD= OED=25
ODE ODC=25 +25 =50
OC”=OD” OCD= ODC=50
OCE AOC=50 +25 =75 75 25 =µAC 3 µAC=9(cm) OB”=x
OH”=x-6, AH”=BH”=8
OHB x¤ =(x-6)¤ +8¤
12x=100 x= ™3∞;;(cm) OP”=PQ”=6(cm)
OAP AP”="1√2¤ -≈6Ω¤ ='1∂08=6'3(cm) AB”=2AP”=2_6'3=12'3(cm)
O’M”=ON”=2 AB”=CD”
AOM A’M”="√(2'2ç)¤ ç-ç2¤ =2 CD”=AB”=2A’M”=4
ABC AB”=AC”
B= C=;2!;_(180 -40 )=70 AOB=180 -60 =120
OAB OA”=OB”
x=;2!;_(180 -120 )=30
PO” AB” H
PO”="1√0¤ +≈5Ω¤ ='1ß2å5=5'5 APO PO” AB”
;2!;_PA”_OA”=;2!;_PO”_AH”
;2!;_10_5=;2!;_5'5_AH” AH”= =2'5 AB”=2AH”=4'5
'510
D AC” H
CD”=12+5=17(cm), CH”=12-5=7(cm) CHD DH”="1√7¤ -≈7Ω¤ =4'1å5(cm)
AB”=DH”=4'1å5(cm)
BD”=BE”=7(cm), AD”=AF”=10-7=3(cm) CF”=CE”=8-3=5(cm)
BC”=BE”+CE”=BD”+CF”=7+5=12(cm)
O r
(r+10)¤ +(r+3)¤ =13¤ , r¤ +13r-30=0 (r+15)(r-2)=0 r=-15 r=2
r=2(cm)( r>0)
AB”+CD”=AD”+BC”=3+7=10(cm) AB” CD”=3 2 2AB”=3CD
CD”=;3@;AB”
AB”+;3@;AB”=10, ;3%;;AB”=10 AB”=10_;5#;=6(cm)
CF”=C’I’=2(cm) EH”=E’I’=x
BE”=7-(2+x)=5-x, AE”=5+x ABE 4¤ +(5-x)¤ =(5+x)¤
x=0.8(cm)
BE”=5-0.8=4.2(cm)
AB” M , OA”, O’M”
O’M” AB”, A’M”=B’M”
OA”,
O’M” , 16p cm¤
OA”¤p-O’M”¤ p=16p, (OA”¤ -O’M”¤ )p=16p OA”¤ -O’M”¤ =16
OAM
A’M”="√OA”¤ √-O’çM”¤ ='1å6=4(cm) AB”=2A’M”=8(cm)
OD”=OE”=OF” AB”=BC”=CA”=8'3 cm
ABC .
ABC=3 OBC
_(8'3)¤=3_{;2!;_8'3_OE”} OE”=4(cm) '34
10 cm 9.6 cm 12 8 cm (8-x) cm 10 cm
AOO' O’O'”="6√¤ +8¤ =10(cm) AOO' BOO'(SSS )
O'AB , O’'M”
AB” O’'M” . AOO'
6_8=10_A’M”, A’M”=4.8(cm) AB”=2A’M”=9.6(cm) CE”=CF”=x
AB”=(10-x)+(14-x)=12 x=6
O PQ” R
PR”=PF”, QR”=QE”
( PQC )=PQ”+QC”+CP”
=2CE”=2_6=12 CD”=DP” DP”=8(cm)
EP”=EB”=x(cm) AE”=(8-x)(cm) AED
(8+x)¤ =(8-x)¤ +8¤ , 32x=64 x=2(cm) DE”=DP”+EP”=8+2=10(cm)
BOE OB”="√4¤ +√(√4'3≈)Ω¤ =8(cm) ( O )=p_8¤ =64p(cm¤ ) BE”=x BD”=x, AE”=7+x
CF”=CD”=5-x, AF”=6+(5-x)=11-x AE”=AF” 7+x=11-x, 2x=4
x=2(cm)
AE”=AB”+BE”=7+2=9(cm) O'
x
(10-x)¤ +(20-x)¤
=(10+x)¤
x¤ -80x+400=0 x=40—20'3
x=20(2-'3)(cm)( x<10)
120 55 30 68
1
-1 50 1001
-22
-12
-23
-13
-2 284
-14
-2 665
-1 605
-250
6
-16
-2 1807
-1 627
-21
-1 x=;2!; AOB=;2!;_100 =50x=;2!;_(360 -160 )=100
1
-2 AOB=2_65 =130A, B PAO= PBO=90
APB=360 -(90 +90 +130 )=50
2
-1 D= C=40PBD APB= D+ x
70 =40 + x x=30
2
-2 BR”ARB= APB=46 , BRC= BQC=20 x= ARB+ BRC=46 +20 =66
3
-1 µ BCBDC= BAC=47
AC” ABC=90
x=180 -(90 +47 )=43
3
-2 DAC= xAPD x=180 -(90 +62 )=28
4
-1 µAB=µ BC x= BAC=404
-2 BAC= BDC=32µAB=µ BC ADB= BDC=32 ABD
x=180 -(32 +50 +32 )=66
5
-1 CED= CAD=20BAC CAD=6 3=2 1 BAC=2 CAD=2_20 =40
BAD= BAC+ CAD=40 +20 =60
5
-2 µAB µCD= ACB CAD2 6=25 CAD CAD=75
APC P+25 =75 P=50
6
-1 µAB µ BC µ CA=3 4 5C A B=3 4 5
C= _180 =45
6
-2 x=;3!;_180 =60 y=;6!;_180 =30 z= x+ y=60 +30 =90x+ y+ z=60 +30 +90 =180 3
3+4+5
A
O
O' B
D
C 30
10 x
20 10-x 10+x 20-x
20
60 200 45
6 cm
y=2_110 =220
x=;2!;_(360 -220 )=70 x+ y=70 +220 =290 BOC=2 BAC=2_68 =136
OBC OB”=OC”
x=;2!;_(180 -136 )=22 OA”
AOB=2 AEB=40 , AOC=2 ADC=152 BOC= AOC- AOB=152 -40 =112 OA”, OB”
AOB=360 -2 AQB=160
APBO PAO= PBO=90
x=360 -(90 +90 +160 )=20 µCD
CAD= CBD=45
BPC x+45 =80 x=35
BDC= BAC=58 , ACB= ADB=40 BCD DBC=180 -(58 +22 +40 )=60
BD” ADB=90
µ BC
BAC= BDC=34
ADC= ADB- BDC=90 -34 =56 µAC=µ BD DCB= ABC=24
x= PCB+ PBC=24 +24 =48
4 2= x 25 x=50
y=2 APB+2 BQC
=2_50 +2_25 =100 +50 =150 x+ y=50 +150 =200
7
-1 ABC ACB=180 -(43 +75 )=62 A, B, C, Dx= ACB=62
7
-2 ABD=180 -(85 +60 )=35 x= ABD=3579 30 114 40 80
18p cm
BC” ABC=180 _;6!;=30 BCD=180 _;1¡2;=15
APC= ABC+ BCD=30 +15 =45 BAC= BDC=35
ACB=90 -35 =55 ADB= ACB
ADB+ ACB ADB+ ACB BDC=100 -65 =35 BAC+ BDC BDC= BAC= x
AQC ACD=30 + x
, PCD
x+(30 + x)=70 x=20
AE” AEB=90
DAE=;2!; DOE=;2!;_40 =20
ACE ACE=180 -(90 +20 )=70 APB=;2!;_220 =110
µ PA µ PB=2 3 PBA PAB=2 3 , PBA=;3@; PAB
PAB 110 + PAB+;3@; PAB=180
;3%; PAB=70 PAB=42
µAC ADC= x
µ BD DAB= y
APD x+ y= BPD=60
µAC µ BD 120
(µAC+µ BD )=2p_9_120 =6p(cm) 360
BAP= BQP=32 ( µ BP )
APB=90 APC=90 -43 =47
APC x= BAP+ APC=32 +47 =79 µDE=;3!;µAB DOE=;3!;_180 =60
x=;2!;_60 =30