Vol. 63, No. 1, January 2013, pp. 69∼72
New Physics: Sae Mulli, DOI: 10.3938/NPSM.63.69
On the Magnetic Dipole Energy Expression for an Arbitrary Current Distribution
Keeyung Lee ∗
Department of Physics, Inha University, Incheon 402-751, Korea
(Received 2 November 2012 : revised 12 December 2012 : accepted 31 December 2012)
By directly expanding the magnetic potential energy, we show that the magnetic dipole energy of a localized current distribution in an external magnetic field B has the form U = +m · B, which is ‘wrong’ by a sign from the well known −m · B expression. This result is discussed in relation to the expression for the electric dipole energy, −p · E. The implications of this result for the force and the torque expressions of the magnetic dipole are also discussed.
PACS numbers: 13.40Em, 21.10.Ky
Keywords: Magnetic dipole energy, Arbitrary current
I. INTRODUCTION
Potential energy of a charge distribution in an exter- nal electric field and the potential energy of a current distribution in an external magnetic field are important concepts in the electromagnetic theory. It is well known that in the energy expansion of a localized charge or of a localized current distribution, the dipole energy term becomes important.
For an electrically neutral system, since the monopole term vanishes, electric dipole energy which has the form U = −p · E becomes the most important term in most cases. One elementary method of deriving this expres- sion is to consider the potential energy of two point charges ±q in an electric field due to the electrostatic potential φ(r). In that case, the potential energy can be written as U = +qφ(r + d) + (−q)φ(r), which gives the potential energy expression −p · E by taking the first order approximation φ(r + d) = d · ∇φ(r). This expres- sion can also be derived by calculating the amount of work needed to rotate the dipole, if the torque expres- sion τ = pE sin θ has already been considered.
It is also well known that the magnetic dipole energy has the form U = −m · B, when the dipole is located in- side an external magnetic field B. Elementary derivation
∗
E-mail: [email protected]
of this expression can be done most easily by calculating the amount of work needed to rotate the dipole(assuming that the dipole has a fixed magnetic moment), if the torque expression on the dipole τ = mB sin θ has al- ready been obtained. In this derivation, the condition of
‘fixed magnetic moment’ is important, because a rotat- ing dipole moment does not have fixed magnitude due to the electromagnetic induction effect. This means some kind of external energy source is needed to maintain the current with fixed magnitude. However, even with the condition of fixed magnetic moment, the torque on a magnetic moment is difficult to calculate compared with the electric dipole case. Because the calculation of torque for a system with arbitrary geometry is not straightfor- ward, usually a simple geometry such as of square shaped loop current model is usually assumed [1,2]. Some text- books directly consider the force on the rectangular or on the circular loop instead of deriving the torque expres- sion [3, 4]. Many advanced level textbooks also adopt such approach of calculating the force on the dipole, but with systems generalized to arbitrary geometry [5,6].
However, derivation of the force expression ∇(m · B)
of an arbitrary current distribution itself is not an easy
task at all [7]. And even though the force expression is
obtained, one must be careful in obtaining the dipole en-
ergy expression. For example, if the typical energy-force
relation F = −∇U is applied, we get the dipole energy
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70 New Physics: Sae Mulli, Vol. 63, No. 1, January 2013
expression −m · B. But it is known that F = −∇U relation is effective only when the energy U is the to- tal energy of the system. This means that for a mag- netic dipole which can exchange energy with an external source(for which case U is not the total energy), we ex- pect to have a different dipole energy expression.
In fact, magnetic energy is a subtle and difficult con- cept and the magnetic dipole energy of a system with a dipole moment with ‘not fixed magnitude’ should be expressed as +m · B instead of −m · B [4,8]. Although this result is not widely known, such ‘wrong’ sign of the magnetic dipole energy has already been discussed by D.
J. Griffiths [4]. In that paper, the author derives the expression U = +m · B using the the magnetic charge model and provides a lengthy explanation on why such opposite sign result should be obtained. In this work, we consider direct expansion of the magnetic potential energy and show that the expansion of the magnetic en- ergy of an arbitrary current distribution system results in the expression +m · B for the dipole energy term. Im- plication of this result in connection with the force and torque on the dipole is also discussed.
II. MAGNETIC ENERGY EXPANSION
Before discussing the magnetic energy case, let us consider first the expansion of electric potential energy U = R dV ρ(r)φ(r) of a static charge distribution with charge density ρ(r) under the influence of an external potential φ(r). It is straightforward to show that this energy expression can be expanded as
U = qφ(0) − p · E(0) + ... (1) in which q is the amount of total charge, p is the dipole moment, and E(0) is the electric field at an arbitrary point inside the charge distribution. Therefore we find that the electric dipole energy of a sufficiently localized charge distribution system can be approximated as −p·E Now let us consider the magnetic energy of a current distribution with current density J under the influence of an external magnetic field. When the vector potential which represents the magnetic field is A(r), the magnetic potential energy can be expressed as,
U = Z
dV J · A =
3
X
k=1
Z
dV J
kA
k(2)
Now, for a sufficiently localized current distribution, this energy expression can be expanded as follows,
A
k(r) = A
k(0) + r · [∇A
k]
0+ 1 2
3
X
i=1 3
X
j=1
x
ix
j[ ∂
2A
k∂x
i∂x
j]
0+ ...
(3) where the origin of the coordinate is chosen inside the current distribution. Using such expansion, the magnetic energy can be expressed as U = U
0+ U
1+ ..., where
U
0=
3
X
k=1
Z
dV J
kA
k=
3
X
k=1
A
kZ
dV J
k(4)
and
U
1=
3
X
k=1
Z
dV J
kr · [∇A
k]
0(5)
which are the monopole and dipole terms respectively.
For a stationary current system, the monopole term U
0vanishes since R J
kdV = 0. Now, if the constant vector [∇A
k]
0is temporarily denoted as c, the dipole term U
1can be expressed as,
U
1=
3
X
k=1
U
1k(6)
where U
1k= R dV J
k(r · c). U
1kterm can now be ex- pressed as,
U
1k= Z
dV x
k(J · c) − Z
dV [c × (r × J)]
k(7)
if the vector identity c × (r × J) = r(J · c) − J(r · c) is used. It could be noted here that the integral of the second term on the right hand side can be expressed as 2[c × m]
kwhere m is the magnetic dipole moment which is defined as m =
12R r × JdV .
Let us now consider the first term on the right hand side of Eq.(7). Since c is a just constant vector, this term can be written as P
i
c
iR x
kJ
i. Therefore, using the relation R dV (x
kJ
i+ x
iJ
k) = 0 which is satisfied for a stationary current system [9], this term can now be expressed as − P
i
c
iR dV x
iJ
k, or, as − R dV J
k(r · c), which means that the first term reduces to −U
1k. Therefore we get the expression,
U
1k= −[c × m]
k(9)
in which c stands for [∇A
k]
0.
On the Magnetic Dipole Energy Expression for an Arbitrary Current Distribution· · · – Keeyung Lee 71
Therefore, using the Levi-Civita symbol and Einstein summation convention, we finally obtain the expression for the magnetic dipole energy as U
1= −ε
kij(∂
iA
k)m
j, or
U
1= ε
jik(∂
iA
k)m
j(10) using the ε
kij= −ε
jikproperty . Now since ε
jik∂
iA
k= B
jfrom the relation B = ∇ × A, we find that the mag- netic dipole energy can be written as +m·B(0), in which B(0) is the magnetic field at an arbitrary point inside the current distribution. We may note that this dipole term is the only term left in the expansion for the particular case of uniform external magnetic field. To show this point, let us note that the vector potential of the form A =
12r × B produces a uniform magnetic field. Since the vector potential in this expression is of the first order in the coordinate x
i, it is obvious that [
∂x∂2Aki∂xj