C HAPTER 3. H IGHER O RDER L INEAR ODE S
2019.4
서울대학교
조선해양공학과
서유택
3.1 Homogeneous Linear ODEs
ODE of nth order (n계 상미분 방정식):
Linear ODE of nth order:(Standard Form)
Homogeneous: r(x) =0
Nonhomogeneous: r(x) ≠ 0 n n 1 n 1 1 ' 0
y p x y p x y p x y r x
, , ', , n 0
F x y y y
Homogeneous Linear ODE: Superposition Principle, General Solution
Theorem 1 Fundamental Theorem for the Homogeneous Linear ODE
For a homogeneous linear ODE, sums and constant multiples of solutions on some open interval I are again solutions on I.
3.1 Homogeneous Linear ODEs
Definition General Solution (일반해), Basis (기저), Particular Solution (특수해)
A general solution of an ODE on an open interval I is a solution on I of the form arbitrary
y = c 1 y 1
(x) + ···+ cn y n
(x) (c1
, …, cn
)where y
1
, …, yn
is a basis (or a fundamental system) of solutions of the equation on I;that is, these solutions are linearly independent on I.
A particular solution of the equation on I is obtained if we assign specific values to the n constants y
1
, …, yn
in c1
, …, cn .
3.1 Homogeneous Linear ODEs
Definition Linear Independence and Dependence (1차독립과 1차종속)
n functions y 1
(x), …, yn
(x) are called linearly independent on some interval I where they are defined if the equationk 1 y 1
(x) + ···+ kn y n
(x) = 0 (c1
,…, cn
) on I implies that all k1
, …, kn
are zero.These functions are called linearly dependent on I if this equation also holds on I
for some k 1 , …, k n not all zero.
Ex. 1 Linear Dependence
Show y 1 = x 3 , y 2 = -2x, y 3 = 3x 3 are linearly dependent on any interval.
3.1 Homogeneous Linear ODEs
Theorem 2 Existence and Uniqueness Theorem for Initial Value Problems
If the coefficients p
0
(x), …, pn-1
(x) of the equation are continuous on some open interval I and x0
is in I, then the initial value problem has a unique solution y(x) on I. Initial Value Problem (초기값문제). Existence and Uniqueness
Initial value problem n n 1 n 1 1 ' 0 0
y p x y p x y p x y
andy x
0 K y x
0, '
0 K
1, , y
n1 x
0 K
n1 Ex. 2 Solve the following initial value problem on any open interval I on
the positive x-axis containing x = 1.
Step 1 General solution of the homogeneous ODE
Substitution ofCorresponding general solution of the homogeneous ODE:
y h = c 1 x + c 2 x 2 + c 3 x 3
Step 2 Particular Solution
Answer y h
= 2x + x2
- x3
1 2 3 1 6 6 0 1, 2, 3 y x
m m m m m m m m
3.1 Homogeneous Linear ODEs
Initial Value Problem for a Third-Order Euler-Cauchy Equation
4 )
1 ( ,
1 ) 1 ( , 2 ) 1 ( , 0 6
6 3
2
3 y
x y
x y
y
y
y
y
x
4 6
2 )
1 (
1 3
2 )
1 (
2 )
1 (
3 2
3 2
1
3 2
1
c c
y
c c
c y
c c
c y
1 2, 2 1, 3 1
c c c
3.1 Homogeneous Linear ODEs
Linear Independence of Solutions. Wronskian
1 2
1 2
1
1 1 1
1 2
' ' '
, ,
n
n n
n n n
n
y y y
y y y
W y y
y y y
Theorem 3 Linear Dependence and Independence of Solutions
Let the ODE have continuous coefficients p
0
(x), …, pn-1
(x) on an open interval I.Then n solutions y
1
, …, yn
of the equation on I are linearly dependent on Iif and only if their Wronskian is zero for some x = x 0 in I.
Furthermore, if W is zero for x = x
0
, thenW is identically zero on I.
Hence if there is an x
1
in I at which W is not zero, then y1
, …, yn
are linearly independent on I,so that they form a basis of solutions of the equation on I.
Ex. Show that the given functions are solutions and form a basis on any interval.1, x, x 2 , x 3
3.1 Homogeneous Linear ODEs
Initial Value Problem for a Third-Order Euler-Cauchy Equation
Q:?
3.1 Homogeneous Linear ODEs
Theorem 5 General Solution Includes All Solutions
If the ODE has continuous coefficients p
0
(x), …, pn-1
(x) on some open interval I, then every solution y = Y(x) on I is of the formwhere y
1
, …, yn
is a basis of solutions and C1
, …, Cn
are suitable constants.
1 1
n n
Y x C y x C y x
A General Solution Includes All Solutions
Theorem 4 Existence of a General Solution
If the coefficients p
0
(x), …, pn-1
(x) of the equation are continuous on some open interval I, then the equation has a general solution on I. nth-order homogeneous linear ODEs with constant coefficients:
We try .
Characteristic equation (특성방정식):
General Solutions
Distinct Real Roots: all the n roots λ 1
, …, λn
are real and different.
constitute a basis.
Simple Complex Roots: λ = γ±iω
are simple roots two corresponding linearly independent solutions are
1 2
.y e x cos x y , e x sin x
3.2 Homogeneous Linear ODEs with Constant Coefficients
1
1 1 ' 0 0
n n
y a n y a y a y
1
1 1 0 0
n n
a n a a
1
1 x , , n n x y e y e
y e x
General Solutions
Multiple Real Roots: λ is a real root of order m.
m corresponding linearly independent solutions are
e λx , xe λx , x 2 e λx , ···, x m-1 e λx .
Multiple Complex Roots: λ = γ±iω are double roots.
corresponding linearly independent solutions are
e γx cos ωx, e γx sin ωx, xe γx cos ωx, xe γx sin ωx.
3.2 Homogeneous Linear ODEs with Constant Coefficients
Ex 2. Solve the initial value problem.
3.2 Homogeneous Linear ODEs with Constant Coefficients
Simple Complex Roots. Initial Value Problem
299 0
11 0
4 0
0 100
100
y y y y ( ) y ( ) y ( )
y
3 2
100 100 0
1, 10i
1 1
1
cos10 sin10
10 sin10 10 cos10 100 cos10 100 sin10
x x
x
y c e A x B x
y c e A x B x
y c e A x B x
1 1 1
4 10 11
100 299
c A
c B
c A
101 A 303, A 3
1
B
1
1c
3cos10 sin10
y e x x x
Ex. Solve the ODE.
3.2 Homogeneous Linear ODEs with Constant Coefficients
Real Double and Triple Roots
Q:?
2 0
y iv y y
Nonhomogeneous linear ODEs of nth order (n 계 비제차 선형 상미분방정식)
General solution: y(x) = yh
(x) + yp
(x) y h
= c1 y 1
(x) + ···+ cn y n
(x) is a general solution of y p
is any solution of on I containing no arbitrary constants.
Initial value problem
n n 1
n 1 1 '
0 , 0 y p
x y
p x y p x y r x r x
n n 1
n 1 1 '
0 0 y p
x y
p x y p x y
n n 1
n 1 1 '
0
y p
x y
p x y p x y r x
3.3 Nonhomogeneous Linear ODEs
n n 1
n 1 1 '
0
y p
x y
p x y p x y r x
andy x
0 K
0, ' y x
0 K
1, , y
n1 x
0 K
n13.3 Nonhomogeneous Linear ODEs
Method of Undetermined Coefficients (미정계수법)
n n 1
n 1 1 '
0 , 0 y p
x y
p x y p x y r x r x
Choice Rules for the Method of Undetermined Coefficients
a. Basic Rule. If r(x) is one of the functions in the first column in Table 2.1, choose y p in
the same line and determine its undetermined coefficients by substituting y p and its
derivatives into y (n) +a n-1 y (n-1) + ··· + a 1 y ʹ + a 0 y = r(x).
3.3 Nonhomogeneous Linear ODEs
Choice Rules for the Method of Undetermined Coefficients
b. Modification Rule. If a term in your choice for y p is a solution of the
homogeneous ODE corresponding to y (n) +a n-1 y (n-1) + ··· + a 1 y ʹ + a 0 y = r(x) then multiply this term by x k , where k is the smallest positive integer such that this term times x k is not a solution of the homogeneous ODE.
Method of Undetermined Coefficients (미정계수법)
n n 1
n 1 1 '
0 , 0
y p
x y
p x y p x y r x r x
3.3 Nonhomogeneous Linear ODEs
Choice Rules for the Method of Undetermined Coefficients
c. Sum Rule. If r(x) is a sum of functions in the first column of Table 2.1, choose for y p the sum of the functions in the corresponding lines of the second column.
Method of Undetermined Coefficients (미정계수법)
n n 1
n 1 1 '
0 , 0
y p
x y
p x y p x y r x r x
Ex 1. Solve the initial value problem.3.3 Nonhomogeneous Linear ODEs
Simple Complex Roots. Initial Value Problem
47 0
3 0
3 0
30 3
3
y y y e y ( ) y ( ) y ( )
y x
(not satisfied)
(from modification rule)
Ex 3. Solve the initial value problem.3.3 Nonhomogeneous Linear ODEs
Simple Complex Roots. Initial Value Problem
47 0
3 0
3 0
30 3
3
y y y e y ( ) y ( ) y ( )
y x
3.3 Nonhomogeneous Linear ODEs
Method of Undetermined Coefficients (미정계수법)
Method of Variation of Parameters (매개변수변환법)W j
is obtained from W by replacing the jth column of W by the column [0 0 ···0 1]T
When n = 2, this becomes identical with
If it starts with f (x)y, divide first by f (x).
1 1
n
p n
W x W x
y x y x r x dx y x r x dx
W x W x
1 1
1 2
2 2
2 1
2 1
2 1
1 0 1
0 y
y W y
y y W y
y y
y
W y
, ,
1 2 2 1p
y r y r
y x y dx y dx
W W
Ex. 2 Solve the nonhomogeneous Euler-Cauchy equation.
Step 1 General solution of the homogeneous ODE
Substitution ofCorresponding general solution of the homogeneous ODE:
y h
= c1 x + c 2 x 2
+ c3 x 3
y
1
= x, y2
= x2
, y3
= x3 Step 2 Determinants
3 2 4
''' 3 '' 6 ' 6 ln
x y
x y
xy
y
x x
1 2 3 1 6 6 0 1, 2, 3 y x
m m m m m m m m
2 3 2 3 3 2
2 3 2 4 2 3 2
1 2 3
0 0 0
1 2 3 2 , 0 2 3 , 1 0 3 2 , 1 2 0
0 2 6 1 2 6 0 1 6 0 2 1
x x x x x x x x x
W x x x W x x x W x x W x x
x x x
3.3 Nonhomogeneous Linear ODEs
Ex. 2 Solve the nonhomogeneous Euler-Cauchy equation
Step 3 Integration
Here, since it starts with x 3 y, divide first by x 3 . Then, r(x) = x 3 lnx/x 4 = xlnx.
3 2 4
''' 3 '' 6 ' 6 ln
x y
x y
xy
y
x x
3 4 3 2
1 2 3
2 , , 2 ,
W
x W
x W
x W
x
2 3 4
2 3 4
1 2 3
1 1 11
ln ln ln ln
2 2 6 6
1 11
ln
6 6
p
y x x x xdx x x xdx x x xdx x x x
y c x c x c x x x
3.3 Nonhomogeneous Linear ODEs
1 1
n
p n