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Chapter 9. Amplitude Modulation

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Chapter 9. Amplitude Modulation

1

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Goals

 Modulate and demodulate the double sideband-suppressed carrier (DSB-SC) amplitude modulation (AM) signals.

 Investigate the effects of frequency and phase errors on the demodulation performance.

 Modulate and demodulate AM signals by using the sampling and band pass filter (BPF) technique.

2

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Double side-band suppressed carrier(DSB-SC)

3

𝑓𝑓 𝑡𝑡

cos 𝜔𝜔

𝑐𝑐

𝑡𝑡

∅(𝑡𝑡)=𝑓𝑓 𝑡𝑡 × cos(𝜔𝜔

𝑐𝑐

𝑡𝑡)

 Amplitude modulations(AM)

 DSB-SC, DSB-LC, SSB, VSB, etc.

 DSB-SC

 Modulated signal ∅(𝑡𝑡)=𝑓𝑓 𝑡𝑡 cos(𝜔𝜔

𝑐𝑐

𝑡𝑡)

• 𝑓𝑓 𝑡𝑡 : information signal

• cos 𝜔𝜔

𝑐𝑐

𝑡𝑡 : carrier signal, 𝜔𝜔

𝑐𝑐

= carrier frequency.

 Transmitter(modulator) structure

 Spectrum of DSB-SC

F ∅ 𝑡𝑡 = F ∅ 𝑡𝑡 = F 𝑓𝑓 𝑡𝑡 cos(𝜔𝜔

𝑐𝑐

𝑡𝑡) = 1

2 𝐹𝐹 𝜔𝜔 + 𝜔𝜔

𝑐𝑐

+ 1

2 𝐹𝐹 𝜔𝜔 − 𝜔𝜔

𝑐𝑐

• Recall that multiplying sinusoid = frequency shift

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Double side-band suppressed carrier(DSB-SC)

 DSB-SC

 Receiver (demodulator) structure

 [CH19.2B9] Proof:

𝑔𝑔 𝑡𝑡 = ∅ 𝑡𝑡 cos 𝜔𝜔

𝑐𝑐

𝑡𝑡 = 𝑓𝑓 𝑡𝑡 cos(𝜔𝜔

𝑐𝑐

𝑡𝑡)

2

= 𝑓𝑓(𝑡𝑡)

1+cos(2𝜔𝜔2 𝑐𝑐𝑡𝑡)

=

1

2

𝑓𝑓 𝑡𝑡 +

12

𝑓𝑓 𝑡𝑡 cos(2𝜔𝜔

𝑐𝑐

𝑡𝑡)

𝐺𝐺(𝜔𝜔)=

12

𝐹𝐹 𝜔𝜔 +

14

𝐹𝐹 𝜔𝜔 − 2𝜔𝜔

𝑐𝑐

+

14

𝐹𝐹 𝜔𝜔 + 2𝜔𝜔

𝑐𝑐

• Here, let us define LPF[x]: LPF[x] ≜ Ideal(Perfectly flat magnitude response within BW, no delay) LPF output of x.

Then,

LPF[ 𝐺𝐺(𝜔𝜔)]=

12

𝐹𝐹 𝜔𝜔 +

14

𝐹𝐹 𝜔𝜔 − 2𝜔𝜔

𝑐𝑐

+

14

𝐹𝐹 𝜔𝜔 + 2𝜔𝜔

𝑐𝑐

=

1

2

𝐹𝐹 𝜔𝜔

 LPF 𝑔𝑔 𝑡𝑡 = LPF

12

𝑓𝑓 𝑡𝑡 +

12

𝑓𝑓 𝑡𝑡 cos(2𝜔𝜔

𝑐𝑐

𝑡𝑡) =

12

𝑓𝑓(𝑡𝑡)

4

∅(𝑡𝑡)=𝑓𝑓 𝑡𝑡 cos(𝜔𝜔

𝑐𝑐

𝑡𝑡)

LPF 12

𝑓𝑓 𝑡𝑡 : demodulated signal

cos 𝜔𝜔

𝑐𝑐

𝑡𝑡 :local carrier signal

𝑔𝑔(𝑡𝑡)

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Waveforms and Spectra of DSB-SC

[CH9.1F4~1F6]If the BW of LPF is larger than W, noise power in the demodulated signal increases.

[CH9.1F4~1F6]If the BW of LPF is smaller than W, the demodulated information is distorted. 5

LPF

cos 𝜔𝜔𝑐𝑐𝑡𝑡

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Effect of phase error

 What if there exists a phase error between the carrier and the local carrier?

Say, local carrier = cos 𝜔𝜔

𝑐𝑐

𝑡𝑡 +

𝜃𝜃

not cos 𝜔𝜔

𝑐𝑐

𝑡𝑡 . Then,

 𝑔𝑔 𝑡𝑡 = ∅ 𝑡𝑡 cos 𝜔𝜔

𝑐𝑐

𝑡𝑡 +

𝜃𝜃

= 𝑓𝑓 𝑡𝑡 cos(𝜔𝜔

𝑐𝑐

𝑡𝑡)cos 𝜔𝜔

𝑐𝑐

𝑡𝑡 +

𝜃𝜃

= 𝑓𝑓(𝑡𝑡)

12

cos 2𝜔𝜔

𝑐𝑐

𝑡𝑡 +

𝜃𝜃

+ cos −𝜃𝜃

=

12

𝑓𝑓 𝑡𝑡 cos 2𝜔𝜔

𝑐𝑐

𝑡𝑡 +

𝜃𝜃

+

12

𝑓𝑓 𝑡𝑡 cos

𝜃𝜃

 [CH9.2A4] the demodulated signal(LPF output in the receiver) is given as:

LPF 𝑔𝑔 𝑡𝑡 = LPF 1

2 𝑓𝑓(𝑡𝑡) cos 2𝜔𝜔

𝑐𝑐

𝑡𝑡 +

𝜃𝜃

+ 1

2 𝑓𝑓(𝑡𝑡)cos

𝜃𝜃

=LPF

12

𝑓𝑓(𝑡𝑡) cos 2𝜔𝜔

𝑐𝑐

𝑡𝑡 +

𝜃𝜃

+LPF

12

𝑓𝑓(𝑡𝑡)cos

𝜃𝜃

=

12

𝑓𝑓 𝑡𝑡 cos(𝜃𝜃)

 Phase error results in decreased amplitude of the demodulated signal by the factor of cos(𝜃𝜃).

Special case: if

𝜃𝜃

=

𝜋𝜋

2

, then the signal disappears.

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Effect of phase error

 [CH9.2B]Consider the background noise 𝑛𝑛 𝑡𝑡 is added to the received signal 𝑓𝑓 𝑡𝑡 cos(𝜔𝜔𝑐𝑐𝑡𝑡):

 Then, the multiplier output in the receiver 𝑔𝑔 𝑡𝑡 = 𝑓𝑓 𝑡𝑡 cos 𝜔𝜔𝑐𝑐𝑡𝑡 + 𝑛𝑛(𝑡𝑡) cos 𝜔𝜔𝑐𝑐𝑡𝑡 +𝜃𝜃

= 𝑓𝑓 𝑡𝑡 cos 𝜔𝜔𝑐𝑐𝑡𝑡 cos 𝜔𝜔𝑐𝑐𝑡𝑡 +𝜃𝜃 + 𝑛𝑛(𝑡𝑡) cos 𝜔𝜔𝑐𝑐𝑡𝑡 +𝜃𝜃

 𝑛𝑛 𝑡𝑡 cos 𝜔𝜔𝑐𝑐𝑡𝑡 + 𝜃𝜃 = the noise component in 𝑔𝑔 𝑡𝑡 . We denote 𝑛𝑛𝜃𝜃 𝑡𝑡 = 𝑛𝑛 𝑡𝑡 cos 𝜔𝜔𝑐𝑐𝑡𝑡 + 𝜃𝜃

.

 [CH9.2B10a] ACF of 𝑛𝑛𝜃𝜃 𝑡𝑡

 IF 𝜏𝜏=0, 𝑅𝑅 𝑛𝑛𝜃𝜃 𝜏𝜏 = 0 = lim𝑇𝑇→∞− ⁄𝑇𝑇 2

𝑇𝑇 2 𝑛𝑛 𝑡𝑡 cos 𝜔𝜔𝑐𝑐𝑡𝑡+𝜃𝜃 𝑛𝑛 𝑡𝑡 cos 𝜔𝜔𝑐𝑐𝑡𝑡+𝜃𝜃 𝑑𝑑𝑡𝑡

𝑇𝑇 =

𝑇𝑇→∞lim

− ⁄𝑇𝑇 2𝑇𝑇 2 𝑛𝑛 𝑡𝑡 cos 𝜔𝜔𝑐𝑐𝑡𝑡+𝜃𝜃 2𝑑𝑑𝑡𝑡

𝑇𝑇 =Power of 𝑛𝑛𝜃𝜃 𝑡𝑡

• Two sample cases of 𝑛𝑛𝜃𝜃 𝑡𝑡

• These samples illustrate that Power of 𝑛𝑛𝜃𝜃 𝑡𝑡 = Power of 𝑛𝑛 𝑡𝑡 × Power of cos(𝜔𝜔𝑡𝑡+𝜃𝜃), where power of cos(𝜔𝜔𝑡𝑡+𝜃𝜃) =1/2 irrespective of 𝜃𝜃 .

 𝑅𝑅𝑛𝑛𝜃𝜃 𝜏𝜏 = 0 =0.5 𝑅𝑅𝑛𝑛 𝜏𝜏 = 0 7

𝜃𝜃 = 0 𝜃𝜃 = 𝜋𝜋/3

𝑛𝑛 𝑡𝑡 cos 𝜔𝜔𝑐𝑐𝑡𝑡 + 𝜃𝜃 𝑛𝑛𝜃𝜃 𝑡𝑡 = 𝑛𝑛 𝑡𝑡 cos 𝜔𝜔𝑐𝑐𝑡𝑡 + 𝜃𝜃

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Effect of phase error

 [CH9.2B10a] (continued) ACF of 𝑛𝑛

𝜃𝜃

𝑡𝑡

 𝑅𝑅

𝑛𝑛𝜃𝜃

𝜏𝜏 = Correlation between 𝑛𝑛 𝑡𝑡 cos 𝜔𝜔

𝑐𝑐

𝑡𝑡 + 𝜃𝜃 and 𝑛𝑛 𝑡𝑡 + 𝜏𝜏 cos(𝜔𝜔

𝑐𝑐

(𝑡𝑡 +

8

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Effect of phase error

 Demodulated signal (LPF output)

= signal term + noise term

=

1

2

𝑓𝑓 𝑡𝑡 cos(𝜃𝜃) + LPF[𝑛𝑛

𝜃𝜃

𝑡𝑡 ]

Signal amplitude decreases by the factor of cos 𝜃𝜃  Signal power decreases by the factor of cos

2

𝜃𝜃

On the other hand, noise power is constant irrespective of 𝜃𝜃

 [CH9.2B4] Signal to Noise power Ratio (SNR) SNR (𝜃𝜃) =

Signal power

Noise power

=

Power of

1

2𝑓𝑓 𝑡𝑡 cos(𝜃𝜃)

Power of LPF[𝑛𝑛𝜃𝜃 𝑡𝑡 ]

=

cos2 𝜃𝜃 ×Power of

1 2𝑓𝑓 𝑡𝑡 Power of LPF[𝑛𝑛𝜃𝜃 𝑡𝑡 ]

= cos

2

𝜃𝜃 SNR(𝜃𝜃 = 0)

 Phase error results in SNR decrease by the factor of cos

2

𝜃𝜃

 [CH9.2B5] SNR loss = cos

2

𝜃𝜃 = 10𝑙𝑙𝑙𝑙𝑔𝑔

10

cos

2

𝜃𝜃 dB

9

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Effect of frequency error

 Now we consider the case when

local carrier =cos 𝜔𝜔𝑐𝑐 + ∆𝜔𝜔 𝑡𝑡 not cos 𝜔𝜔𝑐𝑐𝑡𝑡 .

 We can rewrite

local carrier = cos 𝜔𝜔𝑐𝑐𝑡𝑡 + ∆𝜔𝜔𝑡𝑡 =cos 𝜔𝜔𝑐𝑐𝑡𝑡 + 𝜃𝜃 where 𝜃𝜃

=

∆𝜔𝜔𝑡𝑡

.

• This implies that the frequency error results in linearly increasing phase error.

• [CH9.2C1] So, we only need to change 𝜃𝜃 into ∆𝜔𝜔𝑡𝑡 in all the derivations for the phase error case.

– For example : demodulated signal=1

2𝑓𝑓 𝑡𝑡 cos(∆𝜔𝜔𝑡𝑡)

 So, Signal to Noise power Ratio (SNR)

SNR(∆𝜔𝜔𝑡𝑡) =cos2 ∆𝜔𝜔𝑡𝑡 SNR ∆𝜔𝜔 = 0

• SNR is time varying according to cos2 ∆𝜔𝜔𝑡𝑡 .

• [CH9.2C2,C3,C6,C7] Even with a very tiny frequency error, cos2 ∆𝜔𝜔𝑡𝑡 periodically changes from 0 to 1.

• [CH9.2C2,C3,C6,C7] Whenever cos2 ∆𝜔𝜔𝑡𝑡 approaches 0, SNR instantaneously becomes 0.  Critical problem!

10

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Generating AM signal without Oscillator

 To generate carrier signal cos(𝜔𝜔𝑐𝑐𝑡𝑡), we need an oscillator which is expensive.

 [CH9.3B] DSB-SC is equal to frequency shifting to center frequencies = ±𝜔𝜔𝑐𝑐

 Recall, in chapter 7, frequency shifting is possible by sampling and BPF

technique if we properly set the sampling frequency and properly design BPF.

• BPF output spectrum=𝑃𝑃−𝑛𝑛𝑋𝑋 𝜔𝜔 + 𝑛𝑛𝜔𝜔0 + 𝑃𝑃𝑛𝑛𝑋𝑋 𝜔𝜔 − 𝑛𝑛𝜔𝜔0

• BPF output signal= 𝑓𝑓(𝑡𝑡)2 𝑃𝑃𝑛𝑛 cos 𝑛𝑛𝜔𝜔0𝑡𝑡 + 𝜃𝜃𝑃𝑃𝑛𝑛

= DSB-SC modulated signal with a carrier signal =2 𝑃𝑃𝑛𝑛 cos 𝑛𝑛𝜔𝜔0𝑡𝑡 + 𝜃𝜃𝑃𝑃𝑛𝑛

 [CH9.3B4] Parameter setting

Condition 1: 𝑛𝑛𝜔𝜔0=carrier frequency 𝜔𝜔𝑐𝑐, n=positive integer

Condition 2: The sampling frequency 𝜔𝜔0 ≥ 2 ×Bandwidth of 𝑓𝑓 𝑡𝑡 .

• Possible sampling frequency 𝜔𝜔0 ∶ 𝑆𝑆𝑆𝑆𝑙𝑙𝑆𝑆𝑆𝑆𝑡𝑡 𝑙𝑙𝑛𝑛𝑆𝑆 𝑙𝑙𝑓𝑓 𝜔𝜔𝑐𝑐,𝜔𝜔2𝑐𝑐,𝜔𝜔3𝑐𝑐,𝜔𝜔4𝑐𝑐, … under

the condition 2 11

P0

P1

P0

P1 Pn nω0 ω0 ω0

nω0

P1

Pn

P0

P1 Pn

nω0

Sampling of 𝑓𝑓 𝑡𝑡

by a periodic signal 𝑝𝑝(𝑡𝑡)

BPF BPF output

=Spectrum of DSB-SC

참조

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