ASYMPTOTIC NORMALITY OF ESTIMATOR IN NON-PARAMETRIC MODEL UNDER CENSORED SAMPLES
Si-Li Niu and Qian-Ru Li
Reprinted from the
Journal of the Korean Mathematical Society Vol. 44, No. 3, May 2007
c
°2007 The Korean Mathematical Society
ASYMPTOTIC NORMALITY OF ESTIMATOR IN NON-PARAMETRIC MODEL UNDER CENSORED SAMPLES
Si-Li Niu and Qian-Ru Li
Abstract. Consider the regression model Yi= g(xi)+eifor i = 1, 2, . . . , n, where: (1) xiare fixed design points, (2) ei are independent random errors with mean zero, (3) g(·) is unknown regression function defined on [0, 1]. Under Yiare censored randomly, we discuss the asymptotic normal- ity of the weighted kernel estimators of g when the censored distribution function is known or unknown.
1. Introduction Consider the fixed design regression model
(1.1) Yi= g(xi) + ei, i = 1, 2, . . . , n,
where Y1, Y2, . . . , Yn are the observations on the fixed design points x1, x2, . . . , xn; e1, e2, . . . , en are independent random errors with mean zero; g(·) is the unknown regression function defined on [0, 1]. Without loss of generality, we assume that 0 = x0< x1< · · · < xn= 1.
Under independent samples, many researchers have studied the large sample properties of estimator of g(·). For instance, consistency and asymptotic nor- mality have been studied by Priestly and Chao [9], Benedetti [1], Georgiev and Greblicki [5] and Georgiev [4] among others. Under various dependent samples, the estimators of g(·) also have been widely studied, such as Fan [2], Roussas [10], Roussas et al. [11] and Tran et al. [12]. In particular, Prieshey and Chao [9] proposed the following weighted kernel estimator of g(x)
gn(x) = Xn
i=1
xi− xi−1
hn K(x − xi
hn )Yi, x ∈ [0, 1], (1.2)
where K(·) is a kernel function, hn is a sequence of positive constants tending to 0.
Received August 22, 2005.
2000 Mathematics Subject Classification. 62G05.
Key words and phrases. censored sample, non-parametric regression model, weighted ker- nel estimator, asymptotic normality.
c
°2007 The Korean Mathematical Society 525
In this paper, we consider the random censorship case for Yi, 1 ≤ i ≤ n, i.e.
when we observe Yi, 1 ≤ i ≤ n, we observe only the pairs (Z1, δ1), . . . , (Zn, δn):
Zi= min{Yi, Ti}, δi= I[Yi≤ Ti], i = 1, 2, . . . , n,
where {Ti, 1 ≤ i ≤ n} are censored variables, I[·] denotes the indicator func- tion. The estimator of g will be constructed by the censored data {(Zi, δi), i = 1, 2, . . . , n}.
Considering the practical background of the random censorship model, we assume that both Yi, 1 ≤ i ≤ n and Ti, 1 ≤ i ≤ n are nonnegative and independent random variables; moreover every Ti is independent of every Yi
with distribution function Fi, 1 ≤ i ≤ n. The censored variables T1, T2, . . . are assumed to be independent, identically distributed with distribution function G. Then the distribution function of Zi is
Hi(x) = P (Zi≤ x) = 1 − (1 − Fi(x))(1 − G(x)) =: 1 − Fis(x)Gs(x), where Fis= 1 − Fi, 1 ≤ i ≤ n, Gs= 1 − G. Set
F¯s= 1 n
Xn i=1
Fis, His= 1 − Hi= FisGs, ¯Hs= 1 n
Xn i=1
His.
For any distribution function F , define τF = inf{t : F (t) = 1}, F−p(t) =
µ 1 F (t)
¶p
for all p > 0.
Throughout this paper, we assume τFi ≤ τG, i = 1, . . . , n. Note that (1.3) EδiZiG−1s (Zi) =
Z τ
Fi
o
dFi(y) Z τG
y
yG−1s (y)dG(t) = EYi= g(xi).
Therefore, we may assume that {δiZiG−1s (Zi), 1 ≤ i ≤ n} obey the following model:
(1.4) δiZiG−1s (Zi) = g(xi) + e0i, i = 1, 2, . . . , n,
where {e0i, 1 ≤ i ≤ n} are independent random errors with mean zero. Hence, when G is known, taking advantage of model (1.4) and comparing with (1.2), the weighted kernel estimator of g(x) is defined as follows:
gn(1)(x) = Xn i=1
xi− xi−1
hn K(x − xi
hn )δiZiG−1s (Zi), x ∈ [0, 1].
Also, we assume that τ(n) =: max{τFi : 1 ≤ i ≤ n} ≤ τG ≤ +∞ for all n ≥ 1, and that τ0=: limnτ(n)exists.
When G is unknown, the estimate of g(x) is defined by gn(2)(x) =
Xn i=1
xi− xi−1
hn K(x − xi
hn )δiZiGˆ−1ns(Zi)I[Zi≤ Mn], x ∈ [0, 1],
where Mn is a sequence of constants, which are less than τ(n) and monoto- nously increase to τ0, ˆGnsdenotes the Kaplan-Meier estimator of the distribu- tion function G, i.e.,
Gˆns(t) =
Qn
j=1
µ
1+N+(Zj) 2+N+(Zj)
¶I[δj=0, Zj≤t]
, t ≤ Z(n),
0, t > Z(n)
(cf. Kaplan and Meier [6]), Z(n)= max{Z1, Z2, . . . , Zn}, N+(Zj) =Pn
i=1I[Zi
> Zj], 1 ≤ j ≤ n.
In the sequel, let C, C1 and C2, . . . will represent positive constants whose value may change from one place to another.
For model (1.1), the consistent rates of estimators of g have also been studied by some authors under censored assumptions, see Xue [14] and Wang [13]. In particular, Wang [13] discussed the weak consistency and consistent rates of the estimators g(1)n and g(2)n of g. His results are as follows.
Theorem 1.1. Let p >√
2, 0 < α < 1, and let K(u) be a continuous prob- ability density kernel. Set ˆK(u) = |u|αK(u) withR∞
−∞K(u)du < ∞. Supposeˆ that
(A.1) there exists some M0≥ 0 such that ˆK(u) is non-increasing when u > M0, and nondecreasing when u < −M0,
(A.2) max1≤i≤n(xi− xi−1) ≤ C/n for all n ≥ 1,
(A.3) g(x) satisfies Lipschitz condition of order α on [0, 1].
If max1≤i≤nE[YipG1−ps (Yi)] ≤ C, and one of the following conditions holds.
(i)√
2 < p ≤ 2, n2/p−ph1−pn → 0; (ii) p > 2, n−p/2h1−pn → 0.
Then g(1)n (x)−→ g(x) for all x ∈ [0, 1].P Theorem 1.2. Let p > 1−β+
√(1−β)2+8
2 for some 0 ≤ β ≤ 1. Suppose that (A.1)-(A.3) in Theorem 1.1 are satisfied. If max1≤i≤nE[YipG1−ps (Yi)] ≤ C, and one of the following conditions holds.
(a) 0 < β ≤ 1, 1 − β +p
(1 − β)2+ 8
2 < p ≤ 2, X∞ n=1
n2/p−p−βh1−pn < ∞;
(b) 0 ≤ β ≤ 1, p > 2, X∞ n=1
n−2/p−βh1−pn < ∞.
Then, for any fixed x ∈ [0, 1], we have X∞
n=1
n−βP (|g(1)n (x) − g(x)| > ²) < ∞.
Theorem 1.3. Suppose that (A.1)-(A.3) in Theorem 1.1 are satisfied, and that (A.4) both Fi (1 ≤ i ≤ n), and G are continuous distribution functions,
(A.5) τ0< τG,
(A.6) lim infn→∞Fs(Mn) log n ≥ b for some b > 0.
If {Fi, i ≥ 1} are equi-continuous at τ0 andP∞
n=1n−p/2h1−pn < ∞, then X∞
n=1
P (|gn(2)(x) − g(x)| > ²) < ∞ for all ² > 0 and x ∈ [0, 1].
In this paper, we will establish the asymptotic normality of the estimators g(1)n and gn(2) of g under some suitable conditions.
The paper is organized as follows. In Section 2, we introduce the assumptions used throughout the paper and give main results. Proofs will be provided in Sections 3.
2. Main results
In order to state the main results, we first list the following some assump- tions.
(B.1) Let K(u) be a continuous probability density kernel with 0 <R+∞
−∞ K2(u)du < ∞; there exists some M0≥ 0 such that K(u) is non-increasing when u > M0 and nondecreasing when u < −M0. (B.2) For all n ≥ 1, Cn1 ≤ xi− xi−1≤Cn2, 1 ≤ i ≤ n.
(B.3) For 0 < θ < 1, lim infn→∞nθF¯s(Mn) ≥ b for some b > 0;
limn→∞hnp2F¯s1−2p(Mn) = 0 for some p ≥ 2.
Theorem 2.1. Suppose that (B.1) and (B.2) are satisfied and nhn → ∞.
Set ZiG = δiZiG−1s (Zi). If limC→∞supiEZiG2 I(ZiG > C) = 0, and σi2 =:
Var(ZiG) ≥ δ2, 1 ≤ i ≤ n for some δ > 0, then g(1)n (x) − Eg(1)n (x)
q
Var(gn(1)(x))
→dN (0, 1), x ∈ [0, 1].
Theorem 2.2. Suppose that (A.4)-(A.5) and (B.1)-(B.3) are satisfied. If σ2i =:
Var(ZiG) ≥ δ2, 1 ≤ i ≤ n for some δ > 0 and√
nhnsupi[Fi(τ0)−Fi(Mn)] → 0, then
g(2)n (x) − Eg(1)n (x) q
Var(gn(1)(x))
→dN (0, 1), x ∈ [0, 1].
3. Proofs of main results
Lemma 3.1. ([13, Lemma 3.1]) Suppose that ¯K(·) is a continuous function withR∞
−∞K(u)du < +∞, and there exists some M¯ 0≥ 0 such that ¯K(u) is non- increasing when u > M0and non-decreasing when u < −M0. If max1≤i≤n(xi− xi−1) ≤ C/n for all n and limn→∞nhn= ∞, then
h−1n Xn i=1
(xi− xi−1) ¯K
µx − xi
hn
¶
→ Z +∞
−∞
K(u)du.¯
Lemma 3.2. ([7]) For any r > 0,
E[(1 + N+(Zi))−r|(Zi, δi)] ≤ n−r[ ¯Hs(Zi) − n−1]−r.
Lemma 3.3. Suppose that (A.4)-(A.5) and (B.1)-(B.3) are satisfied. If σi2=:
Var(ZiG) ≥ δ2, 1 ≤ i ≤ n for some δ > 0, then sup0≤t≤Mn| log ˆGns(t) − log Gs(t)|
q
Var(gn(1)(x))
→p0.
Proof. For every n ≥ 1 and t ∈ [0, Mn], define βj(t) = I[δj = 0, Zj ≤ t], then by the Taylor expansion we have
log ˆGns(t) = Xn j=1
I[δj = 0, Zj≤ t] log(1 + N+(Zj) 2 + N+(Zj))
= Xn j=1
βj(t) log(1 − 1 2 + N+(Zj))
= − Xn j=1
βj(t) X∞
l=1
1
l(2 + N+(Zj))−l. Hence
log ˆGns(t) − log Gs(t)
= [−1 n
Xn j=1
βj(t) ¯Hs−1(Zj) − log Gs(t)] − Xn j=1
βj(t) X∞ l=2
1
l(2 + N+(Zj))−l
−1 n
Xn j=1
βj(t)[n(2 + N+(Zj))−1− ¯Hs−1(Zj)]
=: Ln1+ Ln2+ Ln3.
Since {δiZiG−1s (Zi), 1 ≤ i ≤ n} are independent random variables, by assump- tion (B.2) and Lemma 3.1, we have
Var(g(1)n (x)) = Var[
Xn i=1
(xi− xi−1
hn )K(x − xi
hn )δiZiG−1s (Zi)]
= Xn i=1
(xi− xi−1
hn )2K2(x − xi
hn )σ2i
≥ Cδ2 nhn
Xn i=1
xi− xi−1
hn K2(x − xi
hn )
≥ C
nhn
. (3.5)
Hence, for any ² > 0 and t ∈ [0, Mn],
P (| log ˆGns(t) − log Gs(t)|
q
Var(g(1)n (x))
> ²)
≤ P (| log ˆGns(t) − log Gs(t)| > C²
√nhn
)
≤ P (|Ln1| > C² 3√
nhn
) + P (|Ln2| > C² 3√
nhn
) +P (|Ln3| > C²
3√ nhn
).
(3.6)
Next, we divide three steps to estimate the three terms in (3.6) respectively.
Step 1. Note that
−Eβj(t) ¯Hs−1(Zj)
= − Z t
o
( Z τFj
u
1
H¯s(u)dFj(y))dG(u)
= − Z t
0
1 − Fj(u)
1 n
Pn
i=1Fis(u)Gs(u)dG(u)
= −n Z t
0
Fjs(u) Gs(u)Pn
i=1Fis(u)dG(u), therefore,
−1 n
Xn j=1
E[βj(t) ¯Hs−1(Zj)] = − Z t
0
1
Gs(u)dG(u) = log Gs(t).
Thus, Ln1(t) = n1Pn
j=1[−βj(t) ¯Hs−1(Zj) + Eβj(t) ¯Hs−1(Zj)] and we obtain from (B.3) and the Dharmadhikar-Jogdeo inequality (Praksas Rao [8]) that for p ≥ 2
P (|Ln1| > C² 3√
nhn
)
≤ Cn−p2hnp2E|
Xn j=1
[−βj(t) ¯Hs−1(Zj) + Eβj(t) ¯Hs−1(Zj)]|p
≤ Cn−p2hnp2np2−1 Xn j=1
E|βj(t) ¯Hs−1(Zj) − Eβj(t) ¯Hs−1(Zj)|p
≤ Cn−p2hnp2np2−1 Xn j=1
[E|βj(t) ¯Hs−1(Zj)|p+ |Eβj(t) ¯Hs−1(Zj)|p]
≤ Cn−1hnp2
Xn j=1
Eβj(t) ¯Hs−p(Zj)
= Cn−1hnp2 · n Z t
0 1 n
Pn
j=1Fjs(u) Gps(u)(n1Pn
i=1Fis(u))pdG(u)
≤ Chnp2F¯s1−p(Mn) → 0.
Step 2. We observe that
|Ln2| ≤ Xn j=1
βj(t) X∞ l=2
(2 + N+(Zj))−l
= Xn j=1
βj(t)
1 (2+N+(Zj))2
1 −2+N1+(Zj)
≤ Xn j=1
βj(t) 1 (1 + N+(Zj))2. Hence, by applying the Minkowski inequality we have
P (|Ln2| ≥ C² 3√
nhn
)
≤ P (|
Xn j=1
βj(t) 1
(1 + N+(Zj))2| > C² 3√
nhn
)
≤ Cnp2hnp2E|
Xn j=1
βj(t) 1
(1 + N+(Zj))2|p
≤ Cnp−1np2hnp2
Xn j=1
Eβj(t)(1 + N+(Zj))−2p
= Cn3p2−1hnp2
Xn j=1
E{βj(t)E[(1 + N+(Zj))−2p|(Zj, δj)]}.
(3.7)
Lemma 3.2 yields
(3.8) E[(1 + N+(Zj))−2p|(Zj, δj)] ≤ n−2p[ ¯Hs(Zj) − n−1]−2p.
The assumptions (A.5) and (B.3) imply that for sufficiently large n and all t ∈ [0, Mn],
n ¯Hs(t) − 1 ≥ n ¯Hs(Mn) − 1 ≥ Gs(τ0)n ¯Fs(Mn) − 1
= Gs(τ0)n1−θnθF¯s(Mn) − 1 ≥ bGs(τ0)n1−θ− 1 → ∞, further we have
(3.9) [ ¯Hs(t) − n−1]−1= 1
H¯s(t)[1 + 1
n ¯Hs(t) − 1] ≤ C ¯Hs−1(t).
From (3.7)-(3.9) and (B.3), we find P (|Ln2| ≥ C²
3√ nhn
)
≤ Cn3p2−1hnp2n−2p Xn j=1
Eβj(t) ¯Hs−2p(Zj)
= Cn−p2−1hnp2
Xn j=1
EI[Yj> Tj, Yj∧ Tj≤ t] ¯Hs−2p(Yj∧ Tj)
≤ Cn−p2−1hnp2
Xn j=1
Z t
o
Z τ
Fj
u
1
H¯s2p(u)dFj(y)dG(u)
≤ Cn−p2−1hnp2
Z t
0
Pn
j=1Fjs(u) G2ps (u)(n1Pn
i=1Fis(u))2pdG(u)
≤ Cn−p2hnp2F¯s1−2p(Mn) → 0.
Step 3. Note that 2+N−1+(Zj)≤ (1+N+1(Zj))2 −1+N1+(Zj), so
Ln3 ≤ 1 n
Xn j=1
βj(t)[ n
(1 + N+(Zj))2 − n
1 + N+(Zj)] + 1 n
Xn j=1
βj(t) ¯Hs−1(Zj)
= Xn j=1
βj(t)
(1 + N+(Zj))2 −1 n
Xn j=1
βj(t)( n
1 + N+(Zj)− ¯Hs−1(Zj))
=: Ln31− Ln32. (3.10)
From Step 2 we have
(3.11) P
µ
|Ln31| ≥ C² 6√
nhn
¶
→ 0.
As to Ln32 we have P
µ
|Ln32| ≥ C² 6√
nhn
¶
= P (|1 n
Xn j=1
βj(t)( n
1 + N+(Zj)− 1
H¯s(Zj))| ≥ C² 6√
nhn
)
≤ Cnp2hnp2n−pE|
Xn j=1
βj(t)( n
1 + N+(Zj)− 1 H¯s(Zj))|p
≤ Cn−p2hnp2np−1 Xn j=1
Eβj(t)| n
1 + N+(Zj)− 1 H¯s(Zj)|p
= Cnp2−1hnp2
Xn j=1
E{βj(t)E[| n
1 + N+(Zj)− 1
H¯s(Zj)|p|(Zj, δj)]}
(3.12)
and
E
·
| n
1 + N+(Zj)− 1
H¯s(Zj)|p|(Zj, δj)
¸
= E
·
|1 + N+(Zj) − n ¯Hs(Zj)
H¯s(Zj)(1 + N+(Zj)) |p|(Zj, δj)
¸
≤ H¯s−p(Zj)E12[(1 + N+(Zj))−2p|(Zj, δj)]
·E12[|1 + N+(Zj) − n ¯Hs(Zj)|2p|(Zj, δj)].
(3.13)
By Lemma 3.2, for 1 ≤ j ≤ n,
E[(1 + N+(Zj))−2p|(Zj, δj)] ≤ n−2p[ ¯Hs(Zj) − n−1]−2p
≤ Cn−2pH¯s−2p(Zj).
(3.14)
On applying the Dharmadhikar-Jogdeo inequality (Praksas Rao [8]) we have E[|1 + N+(Zj) − n ¯Hs(Zj)|2p|(Zj, δj)]
= E[|1 + Xn l=1
(I(Zl> Zj) − Hls(Zj))|2p|(Zj, δj)]
≤ C{1 + np−1 Xn
l=1
E[|I(Zl> Zj) − Hls(Zj)|2p|(Zj, δj)]}
≤ Cnp. (3.15)
Hence, (3.12)-(3.15) and (B.3) yield that
P (|Ln32| ≥ C² 6√
nhn
) ≤ Cn−1hnp2
Xn j=1
Eβj(t) ¯Hs−2p(Zj)
= Cn−1hnp2
Xn j=1
Z t
o
Z τFj
u
1
H¯s2p(u)dFj(y)dG(u)
≤ Cn−1hnp2
Z t
0
Pn
j=1Fjs(u) G2ps (u)(n1Pn
i=1Fis(u))2pdG(u)
≤ Chnp2F¯s1−2p(Mn) → 0.
(3.16)
Then, (3.10), (3.11) and (3.16) follow that P (|Ln3| ≥ 3√C²nh
n) → 0.
(3.6) and Steps 1-3 yield that for all t ∈ [0, Mn],
(3.17) | log ˆGns(t) − log Gs(t)|
q
Var(gn(1)(x))
→p0.
Finally, by the continuity of G and (3.17), utilizing the method used in F¨oldes and Rejt¨o [3] (or see Wang [13]), we can obtain that
sup0≤t≤Mn| log ˆGns(t) − log Gs(t)|
q
Var(gn(1)(x))
→p0
for sufficiently large n. ¤
Proof of Theorem 2.1. Set ξni=xi−xhi−1
n K(x−xh i
n )ZiG. Thengn(1)(x) =Pn
i=1ξni. From the assumption of independence on Yiand Ti, it suffices to verify Linder- berg condition: for any selected x ∈ [0, 1] and any ² > 0,
An(ε) = 1 s2n
Xn i=1
E|ξni− Eξni|2I(|ξni− Eξni| ≥ εsn) → 0,
where s2n = Var(gn(1)(x)). Note that limC→∞supiEZiG2 I(|ZiG| > C) = 0, namely
C→∞lim sup
i
Z
|δiZiG−1s (Zi)|>C
|δiZiG−1s (Zi)|2dP = 0, which follows that
sup
i E|δiZiG−1s (Zi)|2< ∞ and sup
i |g(xi)| ≤ sup
i E|δiZiG−1s (Zi)| < ∞.
(3.18)
Therefore, from (B.1), (B.2) and (3.5) we have
An(ε) = 1 s2n
Xn i=1
E|ξni− Eξni|2I(|ξni− Eξni| ≥ εsn)
= 1
s2n Xn i=1
E[δiZiG−1s (Zi) − g(xi)]2[xi− xi−1
hn
K(x − xi
hn
)]2
·I(|(δiZiG−1s (Zi) − g(xi))xi− xi−1
hn
K(x − xi
hn
)| ≥ εsn)
≤ C Xn i=1
E(δiZiG−1s (Zi) − g(xi))2[xi− xi−1
hn K(x − xi
hn )]
·I(|δiZiG−1s (Zi) − g(xi)| ≥ εsn
|xi−xhi−1
n K(x−xh i
n )|)
≤ C Xn i=1
E(δiZiG−1s (Zi) − g(xi))2[xi− xi−1
hn K(x − xi
hn )]
·I(|δiZiG−1s (Zi) − g(xi)| ≥ C²p nhn).
(3.19)
From Lemma 3.1
(3.20)
Xn i=1
xi− xi−1
hn K(x − xi
hn ) → Z +∞
−∞
K(u)du = 1.
We observe that
E(δiZiG−1s (Zi) − g(xi))2I(|δiZiG−1s (Zi) − g(xi)| ≥ C²p nhn)
≤ C{E(δiZiG−1s (Zi))2I(|δiZiG−1s (Zi) − g(xi)| ≥ C²p nhn) +g2(xi)EI(|δiZiG−1s (Zi) − g(xi)| ≥ C²p
nhn)}
=: E1+ E2. (3.21)
(3.18) and nhn → ∞ yield that
E1 ≤ CE(δiZiG−1s (Zi))2I(|δiZiG−1s (Zi)| ≥ C²p
nhn− |g(xi)|)
→ 0.
(3.22)
On applying the Chebyshev inequality, from (3.18) and nhn→ ∞ we have
E2 ≤ g2(xi)E(δiZiG−1s (Zi) − g(xi))2 C2²2nhn
≤ g2(xi)[E(δiZiG−1s (Zi))2+ g2(xi)]
Cnhn → 0.
(3.23)
Hence, we complete the proof of Theorem 2.1 by (3.19)-(3.23). ¤
Proof of Theorem 2.2. Put ani(x) = xi−xhi−1
n K(x−xh i
n ). For any selected x ∈ [0, 1], we have
g(2)n (x) − Eg(1)n (x)
= [ Xn i=1
aniδiZiGˆ−1ns(Zi)I(Zi ≤ Mn) − Xn i=1
aniZiGI(Zi≤ Mn)]
+[
Xn i=1
aniZiG− Eg(1)n (x)] − E Xn i=1
aniZiGI(Zi> Mn)
−[
Xn i=1
aniZiGI(Zi> Mn) − E Xn i=1
aniZiGI(Zi> Mn)]
=: B1+ B2+ B3+ B4. (3.24)
Note that, from (A.4) and (A.5) we have sup
i EZiG2 I(Zi≥ Mn)
= sup
i
Z τ
Fi
Mn
G−2s (y)y2dFi(y) Z τG
y
dG(t)
= sup
i
Z τ
Fi
Mn
y2
1 − G(y)dFi(y)
≤ τ02 1 − G(τ0)sup
i [Fi(τ0) − Fi(Mn)] → 0 as n → ∞.
(3.25)
Therefore
C→∞lim sup
i EZiG2 I(ZiG> C) = 0.
Next, we will analyse the four parts in (3.24) respectively as follows.
(i) Obviously, B2= g(1)n (x) − Eg(1)n (x). Hence, from Theorem 2.1 we have B2
q
Var(gn(1)(x))
→dN (0, 1).
(ii) Note that
pnhn max
1≤i≤nEZiGI(Zi> Mn)
= p
nhn max
1≤i≤nEYiG−1s (Yi)I(Yi> Mn)
= p
nhn max
1≤i≤n
Z τFi
Mn
G−1s (y)ydFi(y) Z τG
y
dG(t)
= p
nhn max
1≤i≤n
Z τFi
Mn
y(1 − G(y)) Gs(y) dFi(y)
≤ τ0
pnhn max
1≤i≤n[Fi(τ0) − Fi(Mn)] → 0, which, together with Lemma 3.1, follows that
|B3| q
Var(gn(1)(x))
≤ Cp nhn
Xn i=1
(xi− xi−1
hn )K(x − xi
hn )EZiGI(Zi> Mn) → 0.
(iii) We observe that P
µ
|B4| Áq
Var(gn(1)(x)) ≥ ε
¶
≤ P (|B4| ≥ Cε
√nhn
)
≤ CnhnE[
Xn i=1
(aniZiGI(Zi> Mn) − EaniZiGI(Zi> Mn))]2
≤ Cnhn
Xn i=1
E|aniZiGI(Zi> Mn) − EaniZiGI(Zi> Mn)|2
≤ C Xn i=1
xi− xi−1
hn K2(x − xi
hn )EZiG2 I(Zi> Mn).
(3.26)
By Lemma 3.1 we have (3.27)
Xn i=1
xi− xi−1
hn K2(x − xi
hn ) → Z
K2(u)du < ∞.
Hence, (3.25)-(3.27) follow that P µ
|B4| Áq
Var(g(1)n (x)) ≥ ε
¶
→ 0.
(iv) Note that Mn < τ0 < τG. By Lemma 3.1, for sufficiently large n we have
P
µ |B1| q
Var(g(1)n (x))
≥ ε
¶
≤ P µ1
sn
Xn i=1
xi− xi−1
hn K(x − xi
hn )|Ziδi( ˆG−1ns(Zi)
−G−1s (Zi))|I(Zj≤ Mn) > ε
¶
≤ P µτ0
sn sup
0≤t≤Mn
| ˆG−1ns(t) − G−1s (t)|
Xn i=1
xi− xi−1
hn K(x − xi
hn ) > ε
¶
≤ P µ1
sn sup
0≤t≤Mn
| exp{log ˆG−1ns(t)} − exp{log G−1s (t)}| > ε 2τ0
¶
= P µ1
sn sup
0≤t≤Mn
| exp{θ(log ˆG−1ns(t) − log G−1s (t))}
·(log ˆG−1ns(t) − log G−1s (t))| > ε 2τ0
¶
≤ P µ1
snexp{ sup
0≤t≤Mn
| log ˆGns(t) − log Gs(t)|}
· sup
0≤t≤Mn
| log ˆGns(t) − log Gs(t)| > ε 2τ0
¶
≤ P µ
exp{sup0≤t≤Mn| log ˆGns(t) − log Gs(t)|
sn }
· 1 sn sup
0≤t≤Mn
| log ˆGns(t) − log Gs(t)| > ε 2τ0
¶
= P µ
e∆n· ∆n > ε 2τ0
, ∆n> 1
¶ + P
µ
e∆n· ∆n > ε 2τ0
, ∆n≤ 1
¶
≤ P (∆n > 1) + P (∆n> ε/2τ0e),
where 0 < θ < 1, ∆n = sup0≤t≤Mn√| log ˆGns(t)−log Gs(t)|
Var(g(1)n (x)) . Therefore, according to Lemma 3.3 we have
P
µ |B1| q
Var(g(1)n (x))
≥ ε
¶
→ 0.
On combining with (3.24) and (i)-(iv), Theorem 2.2 is proved. ¤ Acknowledgements. This research was supported by the National Natural Science Foundation of China (No. 10571136).
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