• 검색 결과가 없습니다.

Microelectronic Circuits II Ch 9 : Feedback

N/A
N/A
Protected

Academic year: 2022

Share "Microelectronic Circuits II Ch 9 : Feedback"

Copied!
23
0
0

로드 중.... (전체 텍스트 보기)

전체 글

(1)

CNU EE 9.1-1

Microelectronic Circuits II

Ch 9 : Feedback

9.5 The Feedback Transconductance Amplifier (Series-Series ) 9.6 The Feedback Transresistance Amplifier (Shunt-Shunt)

9.7 The Feedback Current Amplifier (Shunt-Series)

Appendix C Two-port Network Parameters

(2)

CNU EE 9.1-2 - b circuit samples short-circuit output current Io

& provides a feedback signal Vf à Vi=Vs-Vf - zero resistance to output load à b circuit does

not load the amplifier output

- Ideal voltage source Vf= b Io à b circuit does Not load the amplifier input

- A : transconductance & b : transresistance à Loop gain Ab = dimensionless quantity - Ideal structure : load and source resistances

are absorbed inside the A circuit, and b circuit does not load the A circuit

- Closed loop gain Af :

- Af =short-circuit transconductance

Feedback Transconductance Amplifier (Series-Series)

§Ideal case

b

A A V

A I

s o

f º = +

1

- Stabilize Io/Vs à transconductance amplifier - Unilateral open loop amplifier (A circuit) +

ideal feedback network (b circuit)

- A circuit : input resistance Ri, short-circuit transconductance A=Io/Vi, output resistance Ro

Ideal structure

Equivalent circuit for series-series feedback amplifier

(3)

CNU EE 9.1-3 - Negative feedback increases the output resistance in the current (series) sampling

- Negative feedback à Io is constant in spite of changes in output voltage à increase in output resistance - While voltage (shunt) sampling reduces the output resistance, current (series) sampling increases it.

- Series-series feedback topology increases the input and output resistance

§ Output Resistance Rof of feedback transconductance amplifier (Series-Series)

x x

of I

R º V

- Vs à 0 & breaks the output loop (at OO/) to apply a test current Ix

- Output resistance Rof :

x o

f

i V I I

V = - = -

b

= -

b

(

x i

)

o

(

x x

)

o

x I AV R I A I R

V = - = + b

( )

o

of A R

R = +

b

\ 1

Feedback Transconductance Amplifier (Series-Series)

( A b )

R R

if

=

i

+

\ 1

Equivalent circuit for series-series feedback amplifier

§Input resistance with feedback

Series mixing always increases the input resistance by a factor equal to the amount of feedback

(4)

CNU EE 9.1-4 - Feedback network is not an ideal current

controlled voltage source

à resistive and hence, load the basic amplifier

à affect A, Ri & Ro

- Rs & RL affect A, Ri & Ro

- Simple method for finding A circuit & b circuit from a given series-series feedback amplifier

•Practical series-series feedback amplifier

- Source and load resistances should be lumped with the basic amplifier - Two-port feedback network is

represented in terms of z parameters - z parameter : a series circuit at the input and a series circuit at the output

Feedback Transconductance Amplifier (Series-Series)

Ideal structure

Practical case

Ri & Ro vs. Rin & Rout vs. Rif & Rof

(5)

CNU EE 9.1-5

§ Derivation of A Circuit & β Circuit

use of z parameters (appendix C)

ú û ù ê ë é ú û ù ê ë

= é ú û ù ê ë é

2 1 22

21

12 11

2 1

I I z

z

z z

V V

Feedback Circuit Input Impedance (w/ Output open)

Feedback Circuit Output Impedance (w/ input open) negligible

β Feedback network is represented by a series network at port 1 and a series network at port 2

Feedback Transconductance Amplifier (Series-Series)

Ri & Ro vs. Rin & Routvs. Rif & Rof

(6)

CNU EE 9.1-6 à Dispense with the voltage source z21I1

- Forward transmission through the feedback network is negligible in comparison to that through the basic amplifier

- A circuit is composed of the basic amplifier augmented at the input with Rs and z11 and augmented at the output with RL and z22.

- z11 & z22 : impedance looking into ports 1 & 2 of the feedback network while the other port is open- circuited or short-circuited so as to destroy the feedback(open if series & short if shunt)

- b is measured with port 1 open

- Feedback network samples the output current [I2 = Io) & provides a voltage [Vf = V1] that is mixed in series with the input source

§ Derivation of A Circuit & β Circuit

2 0 1 12

1=

º

=

I

I

z V b

amplifier basic network

feedback

z

z

21

<<

21

network feedback amplifier

basic

z

z

12

<<

12

- Includes z11 and z22 with the basic amplifier - If basic amplifier is unilateral,

Feedback Transconductance Amplifier (Series-Series)

(7)

CNU EE 9.1-7

§ Summary of the rules for finding A and β Circuit

- Ri & Ro : input & output resistance of the A circuit - Rif & Rof : input & output resistance of the feedback amplifier, including Rs & RL - Actual input & output resistance of the feedback amplifier usually exclude Rs

& RLà Rin & Rout I2=0 I1=0

I1=0

Feedback Transconductance Amplifier (Series-Series)

L of

out

s if

in

R R

R

R R

R

-

=

-

=

Ro by breaking the output loop at YY/ & measuring the resistance between Y & Y/

(8)

CNU EE 9.1-8 - b circuit samples open-circuit output voltage Vo

& provides a feedback signal If à Ii=Is-If

- infinite resistance to amplifier output àb circuit does not load the amplifier output

- Ideal current source If= bVo à b circuit does not load the amplifier input

- A : transresistance & b : transconductance à Loop gain Ab = dimensionless quantity - Ideal structure : load and source resistances

are absorbed inside the A circuit, and b circuit does not load the A circuit

- Closed loop gain Af :

- Af : open-circuit transresistance

Feedback Transresistance Amplifier (Shunt-Shunt)

§Ideal case

b

A A I

A V

s o

f º = +

1

- Stabilize Vo/Isà transressitance amplifier - Unilateral open loop amplifier (A circuit) +

ideal feedback network (b circuit)

- A circuit : input resistance Ri, open-circuit transresistance A=Vo/Ii, output resistance Ro

Ideal structure

Equivalent circuit for shunt-shunt feedback amplifier

(9)

CNU EE 9.1-9 - Shunt connection in the input à a reduced current

Ii into the A circuit : Ii = Is – If

- Shunt mixing reduces the input current by the amount of feedback (Vi/Ii = Ri)

- Shunt connection at the input lowers the input resistance by a factor equal to the amount of feedback

§ Output Resistance Rof of feedback tranresistacne amplifier (Shunt-Shunt)

Shunt connection at the output lowers the output resistance by a factor equal to the amount of feedback à The output voltage will change less as we draw current from the amplifier output

- Shunt feedback connection, whether at the input or at the output, always reduces the corresponding resistance

( b )

A

b

R I

A V I

R V i

i i s

i

if = +

= +

º 1 1

Equivalent circuit for series-series feedback amplifier

§Input resistance with feedback

Feedback Transresistance Amplifier (Shunt-Shunt)

b b

b

A

I I AI

V

If o i i s

= +

=

= > 1

b

A Rof Ro

= + 1

(10)

CNU EE 9.1-10 - Simple method for finding A & b circuit - Assume the basic amplifier is unilateral &

the feedforward transmission through the feedback network is negligibly small - A circuit includes Rs across the input

terminals of the amplifier & RL across its output terminal

- Loading effect of the feedback network on the amplifier input à R11 is obtained by looking into port 1 of the feedback network while port2 is shorted (shunt connected output) - Loading effect at the output à R22 is found

by looking into port 2 while port 1 is shorted (shunt connected input)

- Since the feedback network senses Vo & is fed by Vo; delivers a current If that is mixed in shunt at the input, its port 1 is short-circuited àb is found as If/Vo, where If flows through

the short circuit

ú û ù ê ë é ú û ù ê ë

= é ú û ù ê ë é

2 1 22 21

12 11

2 1

V V y

y

y y

I

y parameter

I

Ri & Ro vs. Rin & Rout vs. Rif & Rof

Feedback Transresistance Amplifier (Shunt-Shunt)

Ideal structure

Practical case

(11)

CNU EE 9.1-11

§Summary of the rules for finding A and β Circuit

÷÷ ø ö çç

è

æ -

=

s if

in R R

R 1 1

/ 1

÷÷ ø ö çç

è

æ -

=

L of

out R R

R 1 1

/ 1

network feedback amplifier

basic

y

y

12

<<

12

amplifier basic network

feedback

y

y

21

<<

21

Condition for Reverse y parameter of the basic amplifier & feedback network

Condition for Forward y parameter

Actual input & output resistance of the feedback amplifier usually exclude Rs

& RL V2=0 V1=0

V1=0

Feedback Transresistance Amplifier (Shunt-Shunt)

(12)

CNU EE 9.1-12 - b circuit samples short-circuit output current Io

& provides a feedback current If à Ii=Is-If - zero resistance to the output loop à b circuit

does not load the amplifier output

- Ideal current source If= bIo à b circuit does not load the amplifier input

- A & b : current gain

à Loop gain Ab = dimensionless quantity - Ideal structure : load and source resistances

are absorbed inside the A circuit, and b circuit does not load the A circuit

- Closed loop gain Af :

- Af : closed-loop current gain

§Ideal case

b

A A I

A I

s o

f º = +

1

- Stabilize Io/Isà current amplifier

- Unilateral open loop amplifier (A circuit) + ideal feedback network (b circuit)

- A circuit : input resistance Ri, short-circuit current gain A=Io/Ii, output resistance Ro

Ideal structure

Equivalent circuit for shunt-shunt feedback amplifier

Feedback Current Amplifier (Shunt-Series )

(13)

CNU EE 9.1-13 - Shunt mixing reduces the input current by the

amount of feedback (Vi/Ii = Ri)

- Shunt connection at the input lowers the input resistance by a factor equal to the amount of feedback

§ Output Resistance Rof of feedback current amplifier (Shunt-Series)

- By setting Is = 0, breaking the short-circuit output loop, at say OO/, and measuring the resistance between the two terminals à Output Resistance Rof

- Series connection at the output always raises the output resistance by a factor equal to the amount of feedback

b

A Rif Ri

= + 1

Equivalent circuit for shunt-series feedback amplifier

§Input resistance with feedback

( )

o

of A R

R = 1+

b

Feedback Current Amplifier (Shunt-Series )

(14)

CNU EE 9.1-14 - Simple method for finding A & b circuit - Assume the basic amplifier is unilateral &

the feedforward transmission through the feedback network is negligibly small - A circuit includes Rs across the input

terminals of the amplifier & RL in series with its output terminal

- Loading effect of the feedback network on the amplifier input à R11 is obtained by looking into port 1 of the feedback network while port2 is open (series connected output) - Loading effect at the output à R22 is found

by looking into port 2 while port 1 is shorted (shunt connected input)

- Since the feedback network senses Io & is fed by Io; delivers a current If that is mixed in shunt at the input, its port 1 is short-circuited à b is found as If/Io, where If flows through

the short circuit Ri & Ro vs. Rin & Rout vs. Rif & Rof

Ideal structure

Practical case

Feedback Current Amplifier (Shunt-Series )

ú û ù ê ë é ú û ù ê ë

= é ú û ù ê ë é

2 1 22 21

12 11

2 1

I V g

g

g g

V

g parameter

I

(inverse hybrid)

(15)

CNU EE 9.1-15

§ Summary of the rules for finding A and β Circuit

÷÷ ø ö çç

è

æ -

=

s if

in R R

R 1 1

/ 1

L of

out R R

R = -

amplifier basic network

feedback

g g

21

<<

21

network feedback amplifier

basic

g

g

12

<<

12

Most of the forward

transmission occurs in the basic amplifier

Most of the reverse

transmission takes place in the feedback network

Actual input & output resistance of the feedback amplifier usually exclude Rs

& RL I2=0 V1=0

V1=0

Feedback Current Amplifier (Shunt-Series )

Ro by breaking the output loop at YY/ & measuring the resistance between Y & Y/

(16)

CNU EE 9.1-16

Summary for four Feedback-Amplifier Topologies

h

g

z

y

(17)

CNU EE 9.1-17

Summary of the Feedback Analysis Method

1. Always begin the analysis by determining an approximate value for the closed-loop gain Af, assuming that the loop gain Ab is large and thus

Af ~ 1/b : the approximate value depends on how large Ab is compared to unity

2. The shunt connection at input or output always results in reducing the corresponding resistance (input or output). The series connection at input or output always results in increasing the corresponding resistance (input or output).

3. In utilizing negative feedback to improve the properties of an amplifier under design, the starting point in the design is the selection of the feedback topology appropriate for the application at hand.

Then the required amount of negative feedback (1+ Ab) can be ascertained utilizing the fact that it is this quantity that determines the magnitude of improvement in the various amplifier parameters.

Also, the feedback factor b can be determined from b ~ 1/ Af

(18)

CNU EE 9.1-18

Two-port Network Parameters

§ Characterization of Linear two-port networks

2 22 1

21 2

2 12 1

11 1

V y V

y I

V y V

y I

+

=

+

=

§ Four port variables of two-port network - V1, I1, V2, I2

§ Linear two-port network

- two of the variables à excitation variables - the other two à response variables

§ Example : excited by V1 & V2, responded by I1 & I2 - V1, V2 : independent variables

- I1, I2 : dependent variables

- network operation is described by the two equations

§ y11, y12, y21, y22 : admittances à completely characterized the linear two-port network

§ Depending on which two of the four port variables are used to represent the network excitation, a different set of equations (and a correspondingly different set of parameters) is obtained for characterizing the network

§ Four parameters sets commonly used in electronics

§ Independent Variable : Shunt à V, Series à I

§ Dependent Variable : Shunt à I, Series à V

(19)

CNU EE 9.1-19

y Parameters

2 22 1

21 2

2 12 1

11 1

V y

V y I

V y V

y I

+

=

+

=

§ Excitation by V1 & V2

§ Short-circuit admittance (or y-parameter) characterization

(b) y11 : input admittance at port 1 with port 2 short- circuited

1 0 1 11

2=

º V V

y I

2 0 1 12

1=

º V V

y I (c) y12 : transmission from port 2 to port 1, internal feedback

1 0 2 21

2=

º V V

y I

(d) y21 : transmission from port 1 to port 2, forward gain or transmission

2 0 2 22

1=

º V V

y I

(e) y22 : admittance looking into port 2 with port 1 short-circuited, output short-circuit admittance

(20)

CNU EE 9.1-20

z Parameters

2 22 1

21 2

2 12 1

11 1

I z I

z V

I z I

z V

+

=

+

=

§ Excitation by I1 & I2

§ Open-circuit impedance (or z-parameter) characterization

- Duality between the z- and y- parameters characterization

(21)

CNU EE 9.1-21

h Parameters

2 22 1

21 2

2 12 1

11 1

V h I

h I

V h I

h V

+

=

+

=

§ Excitation by I1 & V2

§ Hybrid (or h-parameter) characterization

(b) h11 : input impedance at port 1 with port 2 short- circuited

1 0 1 11

2=

º I V

h V

2 0 1 12

1=

º V I

h V

(c) h12 : reverse or feedback voltage ratio with input port open-circuited

1 0 2 21

2=

º I V

h I

(d) h21 : current gain with output port short-circuited, short-circuit current gain

2 0 2 22

1=

º V I

h I

(e) h22 : output port admittance with input port open-circuited

(22)

CNU EE 9.1-22

g Parameters

2 22 1

21 2

2 12 1

11 1

I g V

g V

I g V

g I

+

=

+

=

§ Excitation by V1 & I2

§ Inverse-hybrid (or g-parameter) characterization

- Duality between the g- and h- parameters characterization

(23)

CNU EE 9.1-23

Equivalent-circuit representation

§ Four possible equivalent circuits

참조

관련 문서

_____ culture appears to be attractive (도시의) to the

is unilateral and that the forward transmission through the feedback is negligibly small. - The actual input and output R of the

Figure 8.4 The four basic feedback topologies: (a) voltage-mixing voltage-sampling (series–shunt) topology;.. (b) current-mixing current-sampling (shunt–series)

ß circuit is desensitized, input impedance of a voltage amplifier is increased, bandwidth is extended - The basic idea of negative feedback is to trade off gain for

The index is calculated with the latest 5-year auction data of 400 selected Classic, Modern, and Contemporary Chinese painting artists from major auction houses..

The key issue is whether HTS can be defined as the 6th generation of violent extremism. That is, whether it will first safely settle as a locally embedded group

The “Asset Allocation” portfolio assumes the following weights: 25% in the S&amp;P 500, 10% in the Russell 2000, 15% in the MSCI EAFE, 5% in the MSCI EME, 25% in the

1 John Owen, Justification by Faith Alone, in The Works of John Owen, ed. John Bolt, trans. Scott Clark, &#34;Do This and Live: Christ's Active Obedience as the