Losses in Fuel Cells
Fuel Cell Thermodynamics
Thermodynamics
Nobel laureate Richard Feynmann said,
“ In physics today, we have no knowledge of what energy is.”
Self-consisting “laws” from fundamental assumptions based on human experience.
Q: How to “prove” Newton’s Law or Schrodinger Equation?
Internal energy (U)
No movement in macroscopic view, but microscopic movement exist.
• Kinetic energy
– Molecular movement &
vibration
• Chemical (potential) energy
– Bonding between atomsLaws of Thermodynamics
First law: conservation of energy
d(Energy)
univ= d(Energy)
system+ d(Energy)
surroundings= 0 d(Energy)
system= -d(Energy)
surroundingsdU = dQ – dW (dW)
mech= pdV dU = dQ – pdV
Second law: Entropy of a system increases (dS
univ≥0)
Macroscopic: dS=dQrev/TMicroscopic: S = k log Ω
k: boltzmann’s constant
Ω: No. of possible microstates accessible to the system
* Two-property rule (Gibbs rule)
Two independent properties are sufficient to define the state of simple systems of constant mass (e.g. ideal gas law : PV=nRT)
Entropy Example I
a) S = k log Ω
b) Entropy is an extensive property (i.e. amount dependent).
S = S
1+ S
1= k log Ω
1+ k log Ω
1= k log (Ω
1* Ω
1)
Ω1 Ω1 Ω1
a) S = S1, Ω = Ω1 b) S=2S1, Ω = Ω1 * Ω1
Entropy Example II
a) A perfect crystal of 100 atoms: only 1 microstate (configuration)
S = k log Ω = k log 1 = 0
b) A crystal of 97 atoms with 100 lattice space:
Ω=
100C
3=1.6 * 10
5 S = 1.66 * 10-22 J/KThermodynamic Potentials
Rules describe energy transfer form one form to another Let’s define four potentials U(S,V), H(S,p), G(T,p),F(T,V) for the
variables S, V, T, p
Starting from dU = dQ – pdV = TdS – pdV ⇔ U = U(S, V) or
(T, p) (S, p) (T, V)
Thermodynamics Potential
Enthalpy of Reaction
Heat of reaction dH = TdS + Vdp
⇔
dH = TdS = dQ (heat of reaction)
= dU + dW for p=const
For general reactions (molar based) aA + bB -> mM + nN
Δh
rxn= { mΔh(M) + nΔh(N) } - { aΔh(A) + bΔh(B) }
similar for entropy: Δs
rxn= {mΔs(M)+nΔs(N)}-{aΔs(A)+bΔs(B)}
Temperature dependency
RTP (room temperature & pressure) is defined as thermodynamic quantity at 298.15 K (so-called room temperature) and 1 bar (or 1 atm). All the
thermodynamic potentials defined at RTP are tabulated as reference, often denoted with superscript 0. (e.g. ΔH0)
Gibbs Free Energy
Gibbs Energy: potential under constant p & T
G = H – TS by definition⇔ dG = dH – TdS – SdT
⇔ Δg = Δ h – TΔs (can be found from tables.)
Electrical work
dG = d(U+pV) – TdS – SdT
= dU – TdS – SdT + pdV + Vdp use dU = dQ-dW = d(TS) – dW
= SdT + TdS – (pdV + dWelec)
⇔ dG = – dWelec
⇔ Welec = -Δgrxn
This is valid for any T & p not-changing through reaction
Voltage of electric work
Welec= EQ = EnFF: Faraday number, n: number of electrons involved in reaction
⇔ E = -Δg/nF
Gibbs Free Energy
Dimensional analysis
Standard Electrode Potential
Standard Electrode Potential
E
cell= ΣE
half-reactionsCell potentials of most
reaction are tabulated
from reaction energy.
Standard Electrode Potential
Hydrogen fuel cell
Direct methanol fuel cell
* Note that half cell voltages of cathode for hydrogen fuel cell
and direct methanol fuel are identical even though
stoichiometry is different. (1/2 vs 3/2)
Standard Electrode Potential
Maximum Possible Efficiency
90 80 70 60 50 40 30 20 10 0
0 200 400
Carnot Limit Fuel Cell
600 800
Temperature / Celsius
Efficiency limit / %
1000
ε = 1 − T
lowT
highε= ΔG
ΔH =1−TΔS ΔH
Fuel Cell Efficiency
Temperature Effect
( )
(
0)
) (
p const for
T nF T
E s E
nF s dT
dE
nFE g
dT s g d
dT S dG
Vdp SdT
dG
T
p p p
D - +
=
= D
÷ ø ç ö
è æ
-
= D D
-
÷ = ø ç ö
è
æ D
-
÷ = ø ç ö
è æ
+ -
=
As Δs is almost constant vs. temperature, E decrease with increasing temperature
Gibbs Free Energy
Lab environment (p=const, T=const)
Among four thermodynamic potentials,Gibbs energy difference drives the spontaneous chemical reaction
Reaction:
A ⇔ B
Extent of a reaction ξ: amount of substahce that reacts from A to B and vice versa dξ=-dnA=dnB
ΔG=0
reaction is in EquilibriumΔG<0
reaction is in Forward directionΔG>0
reaction is in Backward directionConcentration Effect: Nernst Equation
Concentration Effect: Nernst Equation
Example: Available Work at Constant T
1
0
1 1
0 0
0 0
0
0
0
0 1 0
0 1
0 1 0
0
or
ln ln
ln ln
V
V
V V
V V
W pdV pV nRT const p nRT
V
nRT dV
dV nRT
V V
V p
nRT nRT
V p
W g nRT p nRT p
p
= = = =
= =
= =
= -D = =
ò
ò ò
In general
Nernst Equation
Equation Nernst
: ln
) (
ln
ln )
( ) (
1 0
1 0
1
b B A
n N m M
b B A
n N m M
b B A
n N m M B
A N
M
p p
p p nF
E RT E
nFE g
p p
p RT p
g g
p p
p RT p
b m
m g
-
=
-
= D
+ D
= D
+ +
- +
=
D µ µ µ µ
nN mM
bB
A + Û + 1
÷÷ ø çç ö
è æ
P - P
P - P
=
ii i
i
v v v
v
a a nF
E RT p or
p nF
E RT E
Reactants Product 0
Reactants Product
0
ln ln
Consider the following electrochemical reaction
Using the definition of the chemical potential
In general, Nernst Equation can be expressed as:
Nernst Equation: Examples
) ( 2 2
2 2
1
O g
H O
H + Û
(
T T0)
nF E s
ET = + D - Consider the hydrogen-oxygen reaction at 120C
Using the Nernst Equation
Q: At STP, how to calculate the voltage? (when water is liquid)
E120C is calculated considering
temperature effect
) ( 2 2
2
2
1
O
lH O
H + Û
A: For pure component, activity = 1 (read the textbook). Thus
Q: What about G when the product is water or vapor?
A: G will change by condensation energy (E0 from Lower Heating Value)
Concentration Cell
V
p p nF
E RT
E x
H y H
296 . 0
100 ln10 96400
2
15 . 298 314
. 0 8
ln
8 0
2 2
=
× - ×
=
-
=
-
From Nernst Equation:
Q: How a fuel cell without chemical reaction is possible?
What is the driving force?
A: Electrochemical potential will answer your question.
.) . ( 2 .)
. (
2 h p
H
l pH Û
Electrochemical Potential
In concentration cell, concentration gradient will drive the migration (or diffusion) of hydrogen.
Previously, we found chemical potential is:
Thus, high pressure hydrogen has higher chemical potential. The difference in chemical potentials generates the voltages in the cell.
More conveniently, we may use “electrochemical potential” defined as
i i
i i
i i
i
µ z F f µ RT p z F f
µ ~ = + =
0+ ln +
Electrochemical Potential
i i
i
i i i
i i
i
i i i
i i
F z f µ
n µ
n
µ n µ
n
D -
÷ = ø ç ö
è - æ
÷ ø ç ö
è Û æ
÷ = ø ç ö
è - æ
÷ ø ç ö
è æ
å å
å å
reactans products
reactans products
~ 0
~
At electrochemical equilibrium, the net change in the electrochemical potential is 0. (Remember Δg=0 at chemical equilibrium)
From this fact, you may re-derived the Nernst Equation as:
i i
i i
v v
v v e
p p nF
E RT
p p nF
RT nF
E g
Reactants Product 0
Reactants Product 0
ln
ln
P - P
=
P - P
- D
=
=
D f
-1. Entropy loss
2. Internal loss in fuel cells: activation, ohmic, concentration losses
Heat Dissipation by Fuel Cells
(for HHV)
Mass Balance in Fuel Cells
If air at 20 mol/s is supplied to a hydrogen-air fuel cell that generates 1000 kA, we can find the oxygen output flux from the fuel cell:
Here, wO2 represents the volume ratio of oxygen in air (=0.21)
Voltage (V)
iin
Current (A)
i E0
EH
V EH-V
iout
Maximum Possible Efficiency Real Fuel Cell Efficiency
l i i V
E
E
HMaximum Possible Efficiency Real Fuel Cell Efficiency
Example
If we A fuel cell jV is given as:
When what is heat dissipation from the fuel cell?
Assume HHV:
(For LHV, )
* No Stoichiometry number is considered.
Heat Dissipation in Fuel Cells
Alternatively,
Assume HHV:
Maximum Possible Efficiency
Reversible (Regenerative) Fuel Cells
2 2 2
2 2 2
Fuel Cell Mode: H + O1 H O + Electricity 2
Electrolyzer Mode: H O + Electricity H + O 1 2
®
®
,
ˆ
thermo electrolyzer
ˆ
h
h = D g
D
ˆ0 237.17
Dg = DhˆHHV0 = 286
thermo,electrolyzer
286 1.2
e = 237 =
Fuel Cells Stacks
V
total= V
cell× number of cells I
total= I
cellP
total= I
total× V
total= I
cellV
cell× number of cells
= P
cell× number of cells