Chap.5 Flow of an Incompressible Ideal Fluid
• Ideal fluid (or inviscid fluid) → viscosity=0
→ no friction b/w fluid particles or b/w fluid and boundary walls
• Incompressible fluid → ρ =const, d ρ / dt = 0
5.1 Euler’s Equation (1-D steady flow)
- pressure force: pdA − ( p + dp ) dA = − dpdA
- body force: gdAdz
ds
gdsdA dz ρ
ρ ⎟ = −
⎠
⎜ ⎞
⎝
− ⎛ - acceleration:
ds V dV s
V V t
V dt
a dV =
∂ + ∂
∂
= ∂
=
Newton’s 2nd law: F = ma ds dAdsV dV gdAdz
dpdA − ρ = ρ
−
= 0 +
+ gdz VdV dp
ρ ← 1-D Euler ’ s equation
= 0 +
+ dV
g dz V dp
γ
2 0
2
⎟⎟ ⎠ =
⎜⎜ ⎞
⎝
⎛ + + g z V
d p
γ → 2 const
2
= +
+ g
z V p γ
5.2 Bernoulli ’ s Equation with Energy and Hydraulic Grade Lines
For 1-D steady flow of incompressible and uniform density fluid, integration of the Euler equation gives the Bernoulli equation as follows:
{ { { { const (along a streamline ) 2
head total head
elevation head
velocity 2
head pressure
=
= +
+ z H
g V p
γ
정지유체 ( V = 0 ) : p + z = const
γ (2.6)
Assumption: The stream tube is infinitesimally thin, so that it can be assumed to be a streamline.
g H V z + p + =
= 2
EL
2
γ γ z + p
= HGL
g V HGL 2 EL
=
2−
5.3 1-D Assumption for Streamtubes of Finite Cross Section
Assumptions:
1. Streamlines are straight and parallel.
2. V = constant across a cross section (ideal fluid → no friction)
Straight and parallel streamlines
→ No cross-sectional velocity
→ No cross-sectional acceleration
Newton ’ s 2nd law in x-sectional direction:
0 force body
force
pressure + =
c
=
F
(Q no x-sectional acceleration) Read text
1 1
p
2z
2p + z = +
γ γ
or p + z = constant
γ across the x-section
Ex) Ideal fluid flowing in a pipe (IP 5.1)
g z V
p g z V
p
BB B
A A
A
2 2
2
2
= + +
+
+ γ
γ ( Q same streamline)
g z V
p g z V
p
CC C
B B
B
2 2
2
2
= + +
+
+ γ
γ ( Q V
B= V
C)
Therefore, the Bernoulli’s equation can be
applied not only between A and B (on the same
streamline) but also between A and C (on
different streamlines) in the pipe shown below.
5.4 Applications of Bernoulli ’ s Equation (1) If z ≈ const , const
2
2
≈ + g
V p γ
∴ high velocity → low pressure (2) Torricelli ’ s equation
Bernoulli equation b/w 1 and 2:
2
2 2 2
1 2
1 1
2
2 z
g V z p
g V
p + + = + +
γ γ
Using z
1= , z
2p
1= γ h , p
2= 0 , V
1≈ 0 ,
g
h V 2
2
=
2→ V
2= 2 gh ← Torricelli equation
For application of Torricelli’s equation, see IP
5.2 in text.
Note:
In the reservoir ( V = 0 ),
Water surface = EL ( z
g V p + +
= 2
2
γ )
= HGL ( = p + z γ )
= const. in static fluid (reservoir) = z |
surface( Q p = 0 at surface )
(3) Cavitation
Cavitation occurs if p
abs= p
gage+ p
atm≤ p
vor p
gage≤ − ( p
atm− p
v) At initiation of cavitation,
) (
atmgage
p p
vp = − −
p
c(critical gage pressure in text p. 134)
= 0
(4) Pitot tube (for measuring velocity)
) EL 2 (
2
2
2
+ = + + = =
+ z H
g V z p
g V p
S S
S O
O
O
γ
γ
⎟ ⎠
⎜ ⎞
⎝
⎛ −
= γ
Sγ
OO
p g p
V 2
can be measured
∴ V
Ocan be known.
(5) Overflow structure (e.g. spillway of a dam)
Pressure and velocity on the spillway surface at 2?
) fluid ideal
2
( Q V V
V
s=
b=
Bernoulli equation at points
s
andb
:b b
b s
s
s
z
g V z p
g V
p + + = + +
2 2
2 2
γ
γ
←) (
s bb
z z
p = −
∴ γ
Continuity:
V
1y
1= V
2y
2Bernoulli equation at water surfaces at 1 and 2
z
sg V y p
g V
p + + = + +
2 2
2 2 2
1 2
1
1
γ
γ
2 equations for 2 unknowns (
y
1 andV
1)→ can be solved for
y
1 andV
1.See also § 5.3 const / + z =
p γ
across a x-section
5.5 Work-Energy Equation
• Addition or extraction of energy by flow machines - pump: add energy to flow system
(or a pump does work on fluid) - turbine: extract energy from flow system (or fluid does work on a turbine)
• Mechanical work-energy principle
Work done on a fluid system is equal to the change in the mechanical energy (potential + kinetic energy) of the system
dt dE dt
dE dW
dW = → =
Note: Work, energy, and heat have the same unit (J=N⋅m)
• Control volume analysis (Reynolds transport theorem)
Reynolds transport theorem for mechanical energy:
⎥ ⎦
⎢ ⎤
⎣
⎡ ⎟⎟
⎠
⎜⎜ ⎞
⎝
⎛ +
⎟⎟ −
⎠
⎜⎜ ⎞
⎝
⎛ +
=
⎟⎟ ⎠
⎜⎜ ⎞
⎝
⎛ +
⎟⎟ −
⎠
⎜⎜ ⎞
⎝
⎛ +
=
⎟⎟ ⎠
⎜⎜ ⎞
⎝
⎛ +
⎟⎟ −
⎠
⎜⎜ ⎞
⎝
⎛ +
=
⎟⎟ ⋅
⎠
⎜⎜ ⎞
⎝
⎛ + +
⎟⎟ ⋅
⎠
⎜⎜ ⎞
⎝
⎛ + +
⎟⎟ ⎠
⎜⎜ ⎞
⎝
⎛ ⎟⎟ ⎠
⎜⎜ ⎞
⎝
⎛ +
∂
= ∂
∫∫
∫∫
∫∫∫
g z V
g z V
Q
A g gV
z V A
g gV z V
A V V
gz A
V V gz
dA n V v
gz dA
n V v
gz
V V d
t gz dt
dE
in
out CS
CS CV
2 2
2 2
2 2
2 2
2
2 1 1 2
2 2
1 1 2
1 1 2
2 2
2 2
1 1 2 1 1 2
2 2 2 2
2 2
2
γ
ρ ρ
ρ ρ
ρ ρ
ρ
Rate of work done on the flow system
⎟
⎠
⎜ ⎞
⎝
⎛ = ? dt dW
1. flow work rate done by pressure force
∫∫ ⋅ = − = ⎜ ⎝ ⎛ − ⎟ ⎠ ⎞
=
CS
p Q p
V A p V A p dA v
p
1 1 1 2 2 2γ γ
1γ
22. machine work rate done by pumps or turbines
( Ep E
t)
Q −
= γ
t
=
p
E
E ,
work rate per unit weight of fluid3. Shear work rate done by shearing forces on the control surface = 0 (
Q
ideal fluid)⎟ ⎠
⎜ ⎞
⎝
⎛ − + −
=
∴ p p E
pE
tdt Q dW
γ
γ γ
1 2Since
dt dE
dW = dt
, we getg z V
E p g E
z V p
t
p
2
2
2 2 2
2 2
1 1
1
+ + + − = + +
γ γ
Work-energy equation (per unit weight of fluid)
• Power of pump or turbine Power = rate of work done
t
=
p
E
E ,
rate of work done per unit weight of fluid∴
Power of pump or turbine
= ( E
por E
t) × Q γ (ft⋅lb/s or J/s=W)
total weight of fluid passing the x-section per unit time
5.6 Euler ’ s Equations (2-D Steady Flow)
Newton’s 2nd law:
x
-direction:⎟ ⎠
⎜ ⎞
⎝
⎛
∂ + ∂
∂ + ∂
∂
= ∂
⎟ ⎠
⎜ ⎞
⎝
⎛
∂ + ∂
⎟ −
⎠
⎜ ⎞
⎝
⎛
∂
− ∂
z w u x u u t dxdz u dx dz
x p p
dx dz x
p p ρ
2 2
z w u x u u x p
∂ + ∂
∂
= ∂
∂
− ∂ ρ 1
z
-direction:⎟ ⎠
⎜ ⎞
⎝
⎛
∂ + ∂
∂ + ∂
∂
= ∂
⎟ −
⎠
⎜ ⎞
⎝
⎛
∂ + ∂
⎟ −
⎠
⎜ ⎞
⎝
⎛
∂
− ∂
z w w x u w t
dxdz w gdxdz
dz dx z p p
dz dx z
p p ρ ρ
2 2
z g w w x u w z
p +
∂ + ∂
∂
= ∂
∂
− ∂ ρ 1
Continuity:
= 0
∂ + ∂
∂
∂
z w x
u
3 equations for 3 unknowns
( p , u , w )
5.7 Bernoulli ’ s Equation
Euler’s equations:
z dx w u x u u x
p ⎟ ×
⎠
⎜ ⎞
⎝
⎛
∂ + ∂
∂
= ∂
∂
− ∂ ρ 1
dz z g
w w x u w z
p ⎟ ×
⎠
⎜ ⎞
⎝
⎛ +
∂ + ∂
∂
= ∂
∂
− ∂ ρ
1
+
( ) gdz
z u x
wdx w udz
z dz w w z dz
u u x dx
w w x dx
u u
gdz z dz
w w x dz
u w z dx
w u x dx
u u z dz
dx p x p
⎟ +
⎠
⎜ ⎞
⎝
⎛
∂
− ∂
∂
− ∂ +
⎟ ⎠
⎜ ⎞
⎝
⎛
∂ + ∂
∂ + ∂
⎟ ⎠
⎜ ⎞
⎝
⎛
∂ + ∂
∂
= ∂
∂ + + ∂
∂ + ∂
∂ + ∂
∂
= ∂
⎟ ⎠
⎜ ⎞
⎝
⎛
∂ + ∂
∂
− ∂ ρ 1
Using
z dz dx p
x dp p
∂ + ∂
∂
= ∂
z dz w w z dz
u u x dx
w w x dx
u u
z dz w dx u
x w w u
u d
∂ + ∂
∂ + ∂
∂ + ∂
∂
= ∂
∂ + + ∂
∂ +
= ∂ +
2 2
2 2
) (
) ) (
(
2 2
2 2
2 2
we get
ρ ( ) ξ
1 2
) (
2 2udz g wdx
g dz w u
d g
dp + + + = −
Let
X
1= ( x
1, z
1)
andX
2= ( x
2, z
2)
. Integrating fromX
1 toX
2,∫ −
⎟⎟ =
⎠
⎜⎜ ⎞
⎝
⎛ + + +
21 2
1
) 1 (
2
2
2 X
X X
X
udz g wdx
g z w u
p ξ
γ
If the path between
X
1 andX
2 is a streamline (u = dx / dt
,w = dz / dt
), the RHS vanishes so that2 0
2
1
2
2
⎟⎟ ⎠ =
⎜⎜ ⎞
⎝
⎛ + + +
X
X
g z w u
p γ
Therefore,
) ( const 2
2 2
C g z
w u
p + + + =
γ
along a streamline.But, in general, the constant(
C
) may be different for different streamlines.On the other hand, for an irrotational flow,
ξ = 0
, thus2 0
2
1
2
2
⎟⎟ ⎠ =
⎜⎜ ⎞
⎝
⎛ + + +
X
X
g z w u
p γ
for any two points in the flow. Thus
)
const 2 (
2
H g z
V
p + + = γ
over the whole flow field for irrotational flow.
5.8 Applications of Bernoulli ’ s Equation
For irrotational flow of ideal incompressible fluid, the Bernoulli’s equation applies over the whole flow field with a single energy line.
g z V H = p + +
2
2
γ
We are interested in
p
andV
at a point.Exact velocity field → Exact pressure Difficult to solve
Semi-quantitative (approximate) approach
(1) Tornado or bathtub vortex: Higher pressure and lower velocity outwards from the center (Read text)
(2) Flow in a curved section in a vertical plane (Fig.
5.12)
- gravity effect >> centrifugal force (low velocity) - outer wall: sparse streamlines → lower velocity
→ higher pressure - inner wall: dense streamlines → higher velocity
→ lower pressure
(3) Flow in a convergent-divergent section
At section 2:
Center: sparse streamlines → lower velocity
→ higher pressure Wall: dense streamlines → higher velocity
→ lower pressure
g z V
p g z V
p
LL L
U U
U
2 2
2
2
= + +
+
+ γ
γ
L
U
V
V =
→ U Up
Lz
Lp + z = +
γ γ
U
L
z
z <
→p
U< p
LIf cavitation occurs, it will occur first at the upper wall.
(4) Stagnation points
Sharp corner of a surface →
V = 0
(stagnation point) At stagnation point, EL = HGL (Q V = 0
)(5) Sharp-crested weir
At upstream side, pressure is hydrostatic.
y p
A= γ
∴
'At point
A ''
(stagnation point),g y V
p
A2
2 ''
= + γ
Pressure distribution above the weir:
Near free streamlines: dense streamlines → higher velocity
→ lower pressure
Near center: sparse streamlines → lower velocity → higher pressure Note:
p = 0
along free streamlines(6) Flow past a circular cylinder
θ cos
1
22
⎟⎟ ⎠
⎜⎜ ⎞
⎝
⎛ −
= r
U R
v
r ,1
2sin θ
2
⎟⎟ ⎠
⎜⎜ ⎞
⎝
⎛ +
−
= r
U R v
tAt windward stagnation point:
= 0
→
= R v
rr
,θ = π → v
t= 0
At leeward stagnation point:= 0
→
= R v
rr
,θ = 0 → v
t= 0
At surface of the cylinder (r = R
):θ sin 2
,
0 v U
v
r=
t= −
g z U
z p g U p
o o
2
) sin 2
( 2
2
2
θ
γ γ
+ − +
= + +
∴
) , , ,
( θ
γ z fn p z U p
o
=
o+
∴
(7) Flow through an orifice
Streamlines are straight and parallel in the vena contracta.
p = 0
everywhere in the jet, butv
varies across the jet (Read page 131).5.9 Stream Function and Velocity Potential
• Bernoulli equation → Relationship b/w
p
,V
andz
•
z
is known. Therefore, ifV
(u
andv
) can be calculated, thenp
can be calculated by the Bernoulli equation.• Introduce stream function (
ψ
) and velocity potential (φ
),which are related to the velocity field (
u
andv
).• PDE for
ψ ( x , y )
orφ ( x , y )
+ boundary conditions → solve forψ
orφ
→u
andv
→p
(1) Stream function
•
ψ
= flowrate b/w 0 and a streamline• Flowrate
ψ
b/w 0 and any point on streamlineA
is thesame (
Q
no flow across a streamline) →ψ
= const on streamlineA
• Flowrate b/w 0 and streamline
B = ψ + d ψ
→) ( dq
d ψ =
= flowrate b/w streamlinesA
andB
physically
y dy x dx
vdx udy
d ∂
+ ∂
∂
= ∂
−
= ψ ψ
ψ
by definition
v x u y
∂
− ∂
∂ =
= ∂
∴ ψ ψ
,
Now
0
2
2
=
∂
∂
− ∂
∂
∂
= ∂
∂ + ∂
∂
∂
x y y
x y
v x
u ψ ψ
∴ ψ
(stream function) satisfies continuity equation for incompressible fluid.For irrotational flow,
= 0
∂
− ∂
∂
= ∂
y u x
ξ v
or 2
0
2 2 2
2
= ∇ =
∂ + ∂
∂
∂ ψ ψ ψ
y
x
← Laplace equation forψ ( x , y ) )
, ( x y
ψ
can be solved with proper boundary conditions.(2) Velocity potential
Define the velocity potential,
φ ( x , y )
, so as to satisfyv y u x
∂
− ∂
∂ =
− ∂
= φ φ
,
Plug in continuity equation:
2 2 2
2
0 x y
y v x
u
∂
− ∂
∂
− ∂
=
∂ = + ∂
∂
∂ φ φ
2
0
2 2 2
2
= ∇ =
∂ + ∂
∂
∴ ∂ φ φ φ
y
x
← Laplace equation forφ ( x , y )
Vorticity:
0
2
2
=
∂
∂ + ∂
∂
∂
− ∂
∂ =
− ∂
∂
= ∂
x y y
x y
u x
v φ φ
ξ
→ irrotational flow∴ φ
(velocity potential) is defined only in the irrotational flow.Note:
1. irrotational flow = potential flow
(
Q
velocity potential exists in irrotational flow) 2.ψ
satisfies continuity for incompressible fluid → For irrotational flow,∇
2ψ = 0
3.
φ
satisfies irrotationality→ For incompressible fluid,
∇
2φ = 0
(3) Relationship between
φ
andψ
⎪ ⎪
⎭
⎪⎪ ⎬
⎫
∂
= ∂
∂
→ ∂
∂
− ∂
∂ =
− ∂
=
∂
− ∂
∂ =
→ ∂
∂
= ∂
∂
− ∂
=
x y
x v y
y x
y u x
ψ φ
ψ φ
ψ φ
ψ φ
Streamlines (
ψ
=const) and equipotential lines (φ
=const) are orthogonal (Read text p. 167-168).Cauchy-Riemann Conditions