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Chapter 6 Equations of Continuity and Motion

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(1)

Session 6-1 Continuity equation

(2)

Contents

6.1 Continuity Equation

6.2 Stream Function in 2-D, Incompressible Flows 6.3 Rotational and Irrotational Motion

6.4 Equations of Motion

6.5 Examples of Laminar Motion 6.6 Irrotational Motion

6.7 Frictionless Flow 6.8 Vortex Motion

(3)

Objectives

- Derive 3D equations of continuity and motion

- Derive Navier-Stokes equation for Newtonian fluid - Study solutions for simplified cases of laminar flow

- Derive Bernoulli equation for irrotational motion and frictionless flow - Study solutions for vortex motions

(4)

∙ Derivation of 3-D Eq.

conservation of mass → continuity eq.

conservation of momentum → eq. of motion → Navier-Strokes eq.

x y z

∆ ∆ ∆

Consider infinitesimal control volume ( ) → point form [Cf] Finite control volume – arbitrary CV → integral form

Apply principle of conservation of matter to the CV

→ sum of net flux = time rate change of mass inside C.V.

1) mass flux per unit time (mass flow)

mass vol

Q u A

time ρ time ρ ρ

= = = = ∆

(5)
(6)

∙ net flux through face perpendicular to x -axis

= flux in –flux out

∙ net flux through face perpendicular to y -axis

∙ net flux through face perpendicular to z -axis

( u ) ( u )

u y z u x y z x y z

x x

ρ ρ

ρ ρ

= ∆ ∆ −   + ∂ ∆ ∆ ∆ = −   ∂ ∆ ∆ ∆

( v )

x y z y

ρ

= − ∂ ∆ ∆ ∆

( w )

x y z z

ρ

= − ∂ ∆ ∆ ∆

(A)

(7)

2) time rate change of mass inside C.V.

( x y z ) t ρ

= ∂ ∆ ∆ ∆

(B)

Thus, equating (A) and (B) gives

( ) ( ) ( )

( ) u v w

x y z x y z x y z x y z

t x y z

ρ ρ ρ

∂ ρ ∆ ∆ ∆ = − ∂ ∆ ∆ ∆ − ∂ ∆ ∆ ∆ − ∂ ∆ ∆ ∆

∂ ∂ ∂ ∂

( ) ( )

LHS x y z x y z x y z

t t t

ρ ρ ρ

∂ ∂ ∂

= ∆ ∆ ∆ = ∆ ∆ ∆ + ∆ ∆ ∆

∂ ∂ ∂

(8)

Since C.V. is fixed →

( ) x y z 0

t

∂ ∆ ∆ ∆ =

LHS x y z

t ρ

∴ = ∆ ∆ ∆ ∂

Cancelling terms makes

( ) ( ) ( )

u v w 0

t x y z

ρ ρ ρ ρ

∂ + ∂ + ∂ + ∂ =

∂ ∂ ∂ ∂

0 t q

ρ ρ

∂ + ∇ ⋅ =

∂ 

→ Continuity Eq. for compressible fluid in unsteady flow (point form) (6.1)

(9)

The 2 term of Eq. (6.1) can be expressed as

( ρ q ) q ρ ρ q

∇ ⋅  = ∇ + ∇ ⋅  

I II

gradient divergence

(I): q ( ui vj wk ) i j k

x y z

ρ ρ ρ

ρ

∇ = + +   ∂ + ∂ + ∂  

 

   

u v w

x y z

ρ ρ ρ

∂ ∂ ∂

= + +

∂ ∂ ∂

(II): u v w

q x y z

ρ ∇ ⋅ = ρ   ∂ + ∂ +  

( ) q u v w u v w

x y z

x y z

ρ ρ ρ ρ

ρ + +

∴∇ ⋅ = ∂ + ∂ + ∂ +   ∂ ∂ ∂  

(i)

(10)

Substituting (i) into Eq (6.1) yields

u v w 0

u v w

t x y z x y z

ρ ρ ρ ρ ρ

∂ ∂ + ∂ ∂ + ∂ ∂ + ∂ ∂ +   ∂ ∂ + ∂ ∂ + ∂ ∂   =

d dt

ρ

d u v w 0

dt ρ ρ +   x + y + z   = ( ) 0

d q

dt ρ ρ + ∇ ⋅  =

(6.2a)

(6.2b)

0 t q

ρ ρ

∂ + ∇ ⋅ =

∂ 

(6.1)

(11)

[Re] Total derivative (total rate of density change)

d dx dy dz

dt t x dt y dt z dt ρ = ∂ ρ + ∂ ρ + ∂ ρ + ∂ ρ

∂ ∂ ∂ ∂

u v w

t x y z

ρ ρ ρ ρ

∂ ∂ ∂ ∂

= + + +

∂ ∂ ∂ ∂

1) For steady-state conditions

0 t

→ ∂ ρ

∂ =

(12)

Then (6.1) becomes

( ) ( ) ( )

( ) 0

u v w

x y z q

ρ ρ ρ ρ

∂ + ∂ + ∂ = ∇ ⋅ =

∂ ∂ ∂

(6.3)

2) For incompressible fluid (whether or not flow is steady)

0 d

dt

→ ρ =

Then (6.2) becomes

0 u v w

x y z q

∂ + ∂ + ∂ = ∇ ⋅ =

∂ ∂ ∂

(6.5)

(6.4)

(13)

[Re] Continuity equation derived using a finite CV method Eq. (4.5a):

CV

dV

CS

q dA 0

t

ρ ρ

∂ + ⋅ =

∫ ∂  ∫

(4.5)

→ volume-averaged (integrated) form

● Gauss' theorem:

volume integral ↔ surface integral

– reduce dimensions by 1 (3D → 2D)

( )

v

∇ ⋅ X dV =

A

X dA

(14)

Thus,

2 ( )

CS CV

nd term =  ∫ ρ q dA = ∫ ∇ ⋅ ρ q dV

( ) ( ) 0

CV

dV

CV

q dV

CV

q dV

t t

ρ ρ ρ ρ

∂ ∂ + ∇ ⋅ =    ∂ ∂ + ∇ ⋅    =

∫ ∫

Eq. (4.5) becomes

Since integrands must be equal to zero.

( q ) 0 t

ρ ρ

∂ + ∇ ⋅ =

→ same as Eq. (6.1) → point form

(A)

(15)

where V = cross-sectional average velocity

 1D Continuity equation

( ) : u 0

A dA dA

t x

ρ ρ

∂ + ∂ =

∂ ∂

∫ ∫

0

dA udA

t ρ x ρ

∂ + ∂ =

∂ ∫ ∂ ∫

For incompressible fluid flow

0

dA udA

t x

ρ + ρ =

∂ ∫ ∂ ∫

A VA

(16)

where q = flow through σ

A VA 0

t x

∂ ∂

∴ + =

∂ ∂

Consider lateral inflow/outflow

A VA

t x

σ

qd σ

∂ + ∂ =

∂ ∂ ∫

For steady flow;

A 0 t

∂ =

VA 0

x

∴ ∂ =

.

VA = const = Q

(17)

[Re] Continuity equation in polar (cylindrical) coordinates

radial

, - u r

azimuthal

, - v θ

axial

, - w z

For compressible fluid of unsteady flow

1 ( ) 1 ( ) ( )

ur v w 0

t r r r z

ρ ρ ρ ρ

θ

∂ + ∂ + ∂ + ∂ =

∂ ∂ ∂ ∂

For incompressible fluid

1 ( ) 1

ur v w 0

r r r θ z

∂ + ∂ + ∂ =

∂ ∂ ∂

(18)

For incompressible fluid and flow of axial symmetry

( )

0, 0, v 0

t r z

ρ ρ ρ ρ ρ

θ θ

∂ = ∂ = ∂ = ∂ = ∂ =

∂ ∂ ∂ ∂ ∂

1 ( )

ur w 0

r r z

∂ ∂

∴ + =

∂ ∂

→ 2-D boundary layer flow Example: submerged jet

r, u

z, w

(19)

[Re] Green's Theorem

1) Transformation of double integrals into line integrals

( )

2 1

1 2

C R

F F

dxdy F dx F dy

x y

 ∂ − ∂  = +

 ∂ ∂ 

 

∫∫ ∫

( )

C

R

curl Fkdxdy = F dr

∫∫  ∫  

1 2

F  = F i  + F j

2) 1st form of Green's theorem

(

2

)

T S

f g grad f grad g dV f g dA n

∇ + ⋅ = ∂

∫∫∫ ∫∫ ∂

(20)

where n = outer unit normal vector of S 3) 2nd form of Green's theorem

(

2 2

)

T S

g f

f g g f dV f g dA

n x

∂ ∂

 

∇ + ∇ =   ∂ − ∂  

∫∫∫ ∫∫

[Re] Divergence theorem of Gauss

→ transformation between volume integrals and surface integrals

T S

divF dV = F n dA

∫∫∫ ∫∫  

1 2 3

F = F i + F j + F k

   

(21)

cos cos cos n = α i + β j + γ k

1 2 3

T

F F F

dxdydz

x y z

 ∂ + ∂ + ∂ 

 ∂ ∂ ∂ 

 

∫∫∫

(

1

cos

2

cos

3

cos )

S

F α F β F γ dA

= ∫∫ + +

By the way

(

1 2 3

)

S S

F ndA ⋅ = F dydz + F dzdx + F dxdy

∫∫   ∫∫

( )

1 2 3

1 2 3

T

S

F F F

dxdydz

x y z

F dydz F dzdx F dxdy

 ∂ ∂ ∂ 

∴   ∂ + ∂ + ∂  

= + +

∫∫∫

∫∫

(6.6)

(22)

In 2D flowfield, define stream function ψ(x, y) as

 2-D incompressible continuity eq. is

u v 0

x y

∂ + ∂ =

∂ ∂

(6.7)

u y

ψ

= − ∂

v x

ψ

= ∂

(6.9)

(6.8)

• We can a simplified equation by having to determine only one unknown function.

(23)

→ Thus, continuity equation is satisfied.

1) Apply stream function to the equation for a stream line in 2-D flow Eq. (2.10):

Substitute (6.8) into (6.11)

(6.10)

2 2

=0

u v

x y x y y x x y x y

ψ ψ ψ ψ

 

∂ ∂ + ∂ ∂ = ∂ ∂   − ∂ ∂   + ∂ ∂ ∂    ∂    = − ∂ ∂ ∂ + ∂ ∂ ∂

0

vdxudy =

(6.11)

= =0

dx dy d

x y

ψ ψ ψ

∂ ∂

∂ + ∂

(6.12)

(24)

ψ = constant

2) Apply stream function to the law of conservation of mass

Substitute (6.8) into (6.14)

(6.13)

→ The stream function is constant along a streamline.

qdn udy vdx

− = − +

(6.14)

qdn dy dx d

y x

ψ ψ ψ

∂ ∂

− = + =

∂ ∂

(6.15)

(25)

→ Change in ψ () between adjacent streamlines is equal to the volume rate of flow per unit width.

• Stream function in cylindrical coordinates

radial

v

r

r ψ

θ

= − ∂

v azimuthal

θ

r

ψ

= ∂

(26)

Assume the rate of rotation of fluid element ∆x and ∆y about Z -axis is positive when it rotates counterclockwise.

- time rate of rotation of ∆x -face about z -axis 6.3.1 Rotation and vorticity

1

v v x v t

x v

t x x

   +   ∂   ∆ − ∆   

   ∂    ∂

 

= =

∆ ∆ ∂

(27)

- time rate of rotation of ∆y -face about z - axis

net rate of rotation = average of rotations of ∆x -and ∆y -face

1

u u y u t

y u

t y y

 +  ∂ ∆ −   ∆

   ∂    ∂

 

= − = −

∆ ∆ ∂

1

z

2

v u

x y

ω =   ∂ −  

(28)

1

x

2

w v

y z

ω =   ∂ −  

1

y

2

u w

z x

ω =   ∂ −  

(6.16a)

1) Rotation

1 1 1

2 2 2

w v u w v u

i j k

y z z x x y

ω =   ∂ −   +   ∂ −   +   ∂ −  

  

( )

1 1

2 q 2 curl q

= ∇ ×  = 

(6.16b)

(29)

2 2 2

x y z

ω  = ω + ω + ω

a) Ideal fluid → irrotational flow

0

∇ × = q

x y z

0

ω = ω = ω =

, ,

w v u w v u

y z z x x y

∂ = ∂ ∂ = ∂ ∂ = ∂

∂ ∂ ∂ ∂ ∂ ∂

(6.17)

b) Viscous fluid → rotational flow

0

∇ × ≠ q

(30)

2) Vorticity

2 curl q q

ζ = = ∇ × = ω

 Rotation in cylindrical coordinates

1 1 2

z r

v v

r z

ω

θ

θ

∂ ∂

 

=   ∂ − ∂  

1 2

v

r

vz

z r

ω

θ

=   ∂ −   1 1

2

r z

v v v

r r r

θ θ

ω θ

∂ ∂

 

=   − ∂ + + ∂  

(31)

rotational flow

(32)

irrotational flow

rotational flow

(33)

Γ = line integral of the tangential velocity component about any closed contour S

6.3.2 Circulation

Γ =  ∫ q ds  

(6.19)

(34)

– take line integral from A to B, C, D, A ~ infinitesimal CV

2 2 2 2

u dy v dx u dy v dx

d u dx v dy u dx v dy

y x y x

 ∂   ∂   ∂   ∂ 

Γ ≅   − ∂   +   + ∂   −   + ∂   −   − ∂  

v u

x y dxdy

 ∂ ∂ 

=   ∂ − ∂  

v u

d dxdy

x y

 ∂ ∂  Γ ≅   ∂ − ∂  

( )

2

z z

A A A

v u

dA dA q dA

x y ω

 ∂ ∂ 

Γ = ∫∫   ∂ − ∂   = ∫∫ = ∫∫ ∇ ×

(6.20)

(35)

For irrotational flow,

circulation Γ = 0 (if there is no singularity vorticity source).

[Re] Fluid motion and deformation of fluid element translation

Motion

rotation

linear deformation Deformation

angular deformation

(36)

(1) Motion

1) Translation: ξ, η

, d u dt u

dt ξ = = ξ

, d v dt v

dt η = = η

2) Rotation ← Shear flow

1

x

2

v u

x y

ω =   ∂ −  

(37)

1) Linear deformation – normal strain

x

x

ε = ξ

y

y

ε = η

i) For compressible fluid, changes in temperature or pressure cause change in volume.

ii) For incompressible fluid, if length in 2-D increases, then length in another 1-D decreases in order to make total volume unchanged.

(38)

2) Angular deformation– shear strain

xy

x x

η ξ

γ = +

∂ ∂

참조

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