Kyungpook Mathematical Journal Volume 32
,
Number 1,
June,
1992ON I-OPEN SETS AND I-CONTINUOUS FUNCTIONS
M.E. Abd EI-Monsef
,
E.F. Lashien and A.A. NasefIn 1990
,
D. Jankovic’
and T.R. Hamlett have introduced the notion of I-open sets in topological spaces. The aim of this paper is to introduce more new properties of I-openness. Also,
we introduce and study new topological notions via ideals,
namely,
I-c\osed sets,
I-continuous func- tions,
I-open (c1osed) functions. Relationships between these c\asses and other relevant c1asses are investigated1.
Introduction
Throughout the present paper
,
(X, T)
and (Y, (7)
(or simply X and Y) denote topological spac얹 on wl삐1 no separation axioms are assumedunl얹s explicitly stated. Let A be a subset of (X
,
T). The c\osure of A and the interior of A are denoted by Cl(A) and int(A),
respectively. Recall that A is said to be regular closed if Cl(intA) = A. A is said to be 0•open (0.0.) [8] (resp. semi-open (5.0.)
[5],
preopen(P.
O.) [6],
β-open (β 0.) [1]) if Ac
ir벼 CI(int(A))) (resp. A C Cl(int(A)),
Ac
int(Cl(A)),
A C CI(int(CI(A))). The complement of an o-open (resp. serni-open
,
preopen
,
β-open) set is called o-c\osed (resp. semi-closed,
pre-closed,
βc1osed). The family of all o-open (resp. sem야pen , preopen
,
ß-open) sets of (X, T)
is denoted byT
Q (resp. SO(X, T) ,
PO(X, T) ,
(더O(X, T))lt is shown in [8] that
T'"
is a topology on X andT
CT
Q•An ideal on a nonempty set X is a collection 1 of subsets of X which is closed uIldel the opeI
a t k m d i t i v l t y ) [lO] We denote by (X
, T ,
I) a topological space (X, T)
and anR.eceived J anuary 4, 1991
Key Words and Phrases. Ideal
,
regular open set,
a-open set,
semi-open set,
preopen set,
β-open set,
1←。pen set,
/-c1osed set,
pre-continuous function,
M-pre-continuous function,
I-open function,
I-closed function,
I-continuous function1980 AMS Subject Classification Codes Primary: 54C10;Secondary; 54D25, 54D30 21
22 M.E. Abd EI-Monsef. E.F. Lashien and A.A. Nasef
ideal 1 on X. Given a space (X
,
T,1)
and a subset A 드 X,
we denote by A*(I)=
{x E X : U n Arf.
1 for every (open) neighborhood U of x},
wri t ten simply as A* when there is no chance for confusion; CI*(A)=
A U A‘defines a Kuratowski closure operator [10] for a topology T*(
I)
(also de- noted T* when there is no chance for confusion) finer than T. The topol ogy T* has as a basis 더 (I, T) = {U \ E : U E T, E EI}
[9]. Recall that Ac
(X,
T, 1)
is called *-dense-in-itself [2] (resp. T‘-closed [3],
*-perfect [2]) iff Ac
A* (resp. A*c
A,
A = A*)A function
f :
(X, T)
• (Y, (7)
is said to be pre-continuous [6] (resp M-pre-continuous [7]) if for each V E σ (resp. V E PO(Y)),
f-l(V) E PO(X). f is called preopen [6] (resp. preclosed [6]) if the image of each open (resp.closed) set in X is preopen (resp. preclosed).2. On I-open and I-closed sets
Definition 2.1 [4]. Given a space (X
,
T, 1)
and A 드 X,
A is said to be 1-open if...1
드 int(A*)We denote by IO(X
, T)
={...1
드 X:A 드 int(A‘)}
or simply write 10 forIO(X, T)
、애en there is no chance for conf뼈 onRemark 2.1. It is clear that
,
1-openness and openness are independent concepts (Examples 2.1,
2.2)Example 2.1. Let X = {a
,
b,
c,
d} with a topologyr = {X, ø ,
{c},
{a,
b},
{a,
b,
c}}and 1 =
{</>,
{a}}. Then {b,
c,
d} E IO( X, T)
but {b,
c,
d}rf. T
Example 2.2. Let
X
be as in Example 2‘ 1 ,
T ={X , ø , {d} , {a ,
c}, {a ,
c, d} }
and 1= {ø ,
{c},
{d},
{c,
d}}. It is clear that {a,
c,
d} E T,
but {a,
c,
d}rf.
IO(X
, T)
Remark 2.2. One can deduce that: I-open set =수 preopen set
,
and the converse is not true,
in general,
as shown by the following example.Example 2.3. Let X
,
T and 1 be as in Example (2.2). Then,
we can easily deduce that {d} E PO(X, T) ,
but {d}rf.
IO(X, T).
Remark 2.3. The intersection of two I-open sets need not be 1-open 잃 IS
illustrated by the following example.
Example 2.4. Let X = {a
,
b,
c,
d},
T = {X, ø ,
{a,
b}, {a,
b,
c}} and 1 ={</>}‘
Then {a,
c}, {b,
c,
d} E IO(X, T) ,
but {a,
c} n {b,
c,
d}rf.
IO(X, T).
Theorem 2.1. For a space (X
,
T, 1)
and...1 c
X,
ψe have:(i)
1f1
={ø
}, then...1*(1)
= CI(A),
and hence each of I-open set andOn I-open sets and /-continuous functions 23
preopeη
set are
coiη cide.(ii) /1/=
P(X) , then A* (1) =
</>and hence A is /-open iJJ A =
</>.Theorem 2.2. For aηy
1 -open set A 01
a space(X ,
T, 1), we
haveA*
=(int(A*))*.
Definition 2.2. A subset
F
드(X ,
T, 1)
is called /-closed if its complement is /-open.Remark
2.4. The concept of /-closeness makes a very important deviation from the closeness for the topology in ordinary sense.Theorem 2.3. For
A
ζ(X ,
T,I)
ψe haνe((int(A))*)C
카int((AC)*) in
geη eral
(Example
2.5) 뼈eπAC
denotesthe
complemeηt01 A.
Example 2.5. If
X = {a , b , c , d
}, T= {X ,</>, {a} , {a , b} ,
{a,
b,
c}} and / ={</> , {a}}.
Then it is clear that ifA
={a ,
b},
then : ((int(
A))γ= {a
}, butint((Ac)*) =
</>Theorem 2.4.
/1 A
드 (X,
T,I) is
/-c/osed , then
A ::J(intA))
‘Proof
Follows from the definition of /-closed sets and Theorem 2.3(c) [3]Theorem 2.5.
Let A
드 (X,
T, 1) and (X \ (int(A))*) = int((X\ A) ‘)
Theη
A is /
-c/osediJJ A
그(int(A))
‘Proof
ObviousTheorem 2.6.
Let (X ,
T, 1) be a space and A , B ç X. Then:
(i) /1 {U
o : a E ,",} 드IO(X , T) ,
theη U{u
o:a
E ,",} EIO(X , r)
μ].(ii)
/J A
EIO(X , T) and B
ET , then A n B
EIO(X , T)
μl (i끼11페1
(iω비v끼) IIAEIO(X
, T) andBESO(X , T) , thenAnBESO(A).
(v)
/J A
EIO(X , T)
aη dB
ET ,
theη AnB 드int(B n (B n A)*).
Proof
(i) Since{U
O :a
E ,",} 드IO(X , T) ,
then Uo드
int(U~) , for everya E ,"" thus
,
UU" 드 U(in tU~)) 드 int(UU~) 드int(UU
o)'‘
for everya
E ,",.(ii)
A n
B 드 1ηt(A*)n B
=int(A* n B)
(sinceB
ET) ,
from Theorem 2.3 (g) [3], we have :A n B ç int(A n B)*.
(iii) Obvious
,
since A*(1)
is closed and A* 드 Cl(A).(iv) Follows from Theorem (2.3) (c) [3].
(v) Follows directly [rom Theorem 2.3 (g) [3]
Corollary 2.1. (i)
The union 01 /-closed set and
c/osed set is /-closed.
24 M.E. Abd 티 Monsef. E.F. Lashien and A.A. Nasef
(ii)
Th
e union of 1 -c/osed set and an a-closed
set is preclosedTheorem 2.7. If A
드
(X ,
T,I) is 1 ~open and sem
i-closed , then A
=
int(A-
).
Proof Follows (rom Theorem 2.3(c) [3].
Theorem 2.8.
Let A
EIO( X
) and B EIO
(Y), th
en A xB
EIO
(X xY
)ν A- x
B-
= (A xB
)",
ψheπX
xY
isthe product spa
ceProof
AxB
드int
(A")
xint(B"
) =int
(A‘ xB-
),
from hypothesis,
=
int
(A xB)".
Therefore, A
xB
EIO
(X
x y)Theorem 2.9. If
A c W
CCI( A) and A
E IO( χ T),then
Wis
ß-open
.Proof Follows directly from Theorem 2.3 (c) [3J.
Theorem 2.10. If(X
, T
,I) is aspace and
W E IO(X, T) , then CI(V) n
Wc (V n
W)*,
forevery V
ESO(X).
Proof Let
V
ESO(X) ,
then:CI(V)
=CI(int(V)) ,
since W E IO(X),
then
CI(V) n
W CCI(int(V)) n int(W")
C
CI(int(V) n W*)
c CI(V n
W)",
by using Theorem 2.3 (c) [3]=
(vnw)".
Theorem 2.11. If(X
,
T,I) is a space , A
E Tand
B E IO(X,
T),
thenthere exists an open subset G of X such that AnG = 4>,
implies AnB= 4>
Proof Since
B
E IO(X, T) ,
then B 드int(B-) ,
by talcing G= int( B")
to be an open set such that Bc
G,
butA n
G =4>,
then Gç
X\A
implies that CI(G)
드 (X\A
). Hence B 드 (X\A
) and this completes the proof.Theorem 2.12. If (X
,
T,If) is a 되 -spaceand A
E IO(X), then A
드int(A
d),
ψheπA
ddenotes the
d따erivedset of A
and Ifdenotes the ideal of finit
e subsels.Proof Follows directly from the definition of I-open set and the fact that
A* (I f)
=A
d in a T1-space [3].On I-open sets and I-continuous functions 25
Theorem 2_13. Let {X" : a E
l'-}
be a family of spaces,
X== n X。
be the prodπct space and A
== II ’‘
A" xII
x,β a non empty subset of X,
0=1 o :J:.β
where n is a positive integer and A"
c
X". Then,
A" E IO(X,,) for each (1 ~ a ~ n) iJJ A E IO(X).Proof (Nece5sity): Suppose A" E IO(X,,) for each (1 ~ (l' ~ n). Since
a
A
== II A" x II
Xß 드
int(A')‘ Then A E IO(X).
0=1 0#β
(Sufficiency): AS5ume that A E 1 O( X). So A 드 int(A')
== n := ,
A: xn. ,βXβ. Since A
fo
rþ and A E IO(X) then int(A')fo
rþ and hence int(A:) 폼 rþ,
for each (1<
(l' ~ η). Therefore,
A" 드 int( A:) and 50,
A" E IO(X) for each (1 ~ (l' ~ n).
Theorem 2.14. For a subset A 드 (X
,
r,1)
ψe have:(i) If A is r' -c/osed and A E IO(X)
,
theπ, int(A)==
int(A*) (ii) A is r' -c/osed íJJ A is open and 1 -c/osed.(iii) If A 생 *-perfecl
,
then A==
int(A'),
for every A E IO(X,
r)(iv) Jf A is regular closed and I-open
,
then A'(J
n)==
int(A'Un)) ψhe1'eIn is the ideal of nowhere dense sets.
(T
n==
{Ac
X : int(CαI(A꺼))==
rþ}ηn ) ..
p좌roof (i띠i) ,’ (ii) and (ii폐l
(iv비v) Follows from the definition of J-open and the fact that A is regular closed iff A
==
A*(J
n) [3]3. I-continuous functions
Definition 3.1. A function
f (X ,
r, 1)
• (κ0")
is 5aid to be1-
continuous iffor every V EO",
f-'(V) E IO(X,
r).From the above definition one may notice that
1 -continuity =추 precontinuity[6]
and the converse is not true as 5hown by the following example.
Example 3.1. Let X
==
Y== {a ,
b, c ,
d},
r is the in띠1κ띠d미liscre cthe discrete topology and 1
==
{rþ,
{c}} on X. Then the idcntity functionf :
(X,
r,1)
• ()이0")
is precontinuou5 but not I-continuous,
because{c} E
0",
but f-'({c})==
{c}f/.
IO(X).The following two examples show that the concept of continuity and I-continuity are independent
26 M.E. Abd EI-Monsef, E.F. Lashien and A.A. Nasef
Example 3.2. Let X
=
Y=
{a,
b, c} ,
T= {X , 4>,
{a}, {c} , {a , b}, {a , c}} ,
1 = {4>, {b
}, {c}, {b,
c}} on X and u=
{Y, 4>, {a
}, {c}, {a, c}}.
Then the identity functionf :
(X,
T,
1) • (Y,
u) is continuous but not I-continuous because{c}
Eu ,
butf-l({C}) = {c} rf.
JO(X)Example 3.3. Let X
=
Y= {a ,
b, c},
T=
U=
{X,
rþ,
{a}} and 1 ={4>, {b}}
on X. Thenf: (X ,
T,I)
• (κ u) which is defined by:f(a)
=a = f(b)
andf(c) =
c is I-continuous but not continuous.Theorem 3.1.
For a funclion f
:(X ,
T,I)
• (Y, u) the
follouηngare
equivalent:
(i) f is
1 -contin.LOUS.(ii)
For each x
E Xand each V
εu containing f( x) , there exists W
E IO(X) containing x such that f(W)
CV.
(iii)
For each x
E Xand each V
Eu containing f(x) , (J -l(V )t is a neighborhood of x.
Proof
(i) =} (ii) : SinceV
E u containing f(x) ,
then by (i),
f-l(V)
EIO(X) ,
by puttingW
=f
-l(V)
which containingx.
Thereforef(W)
Cv
(ii) =추 (iii): Since V E u containing f(
x) ,
then by (ii),
there exislsW
EIO(X)
containing x such that f(W)
C V. So, x
E W 드int(W ‘)
드int (J
-l(V))' ç U-
1(V))*
. HenceU-
1(V))
‘ is a neighborhood ofx
(iii) =추 (i) : ObviousTheorem 3.2.
For
f : (X,
T, 1)
•(Y , u) the following
areequivalenl:
(i) 1 is 1
-contin uous.
(ii)
The inverse image of each closed set
inY is
1 -closed.(iii)
(int (J -
l(M)))‘ c f-l(M
‘), foreach *-dense-in-ilself su
bset M
C Y(iv) 1((int(U))*)
C(J (U))' ,
foreach U c
X, and
foreach *-perfect subset 01 Y
Proof
(i) =} (ii): LetF
CY
be c1osed,
thenY \ F
is open,
by (i),
1
-1(y \F)
= X\f-l(F)
is I-open
. Thus, 1-
1(F)
is I-c1osed
(ii) =송 (iii): Let
M
CY ,
sinceM"
is c1osed,
then by(ü) f-l(M')
is I-c1osed.
Thus,
by using Theorem (2.4)
f-l(M")
::l(int (J
-l(M ’)))",
sinceM
is *-dense-in-itself,
then f-
l(M")
그(int (J -l (M")))"
그(int (J -
l(M)))".
(iii) =} (iv): Let
U
C X andW =
I(U) ,
then by (iii), f-l(W')
그(int (J -l(W)))*
::l(int(U))*.
Hence,
f((int(U))')
CW'
=(J (U))"
. (iv) =} (i): LetV
E u,
W= Y \ V
andU =
f-l(W) ,
then I(U) c W
and by (iv),
1((int(U))*)
C(J (U))'
C W" (by using Theorem 2.3(a) [3])On I-open sets and I-continuous functions 27
=
W
(becauseW
is *-perfect).Thus
,
f-l(W) 그 (int(U))*=
(int(J
-l(W)))*,
and therefore,
f-1(W)=
f-l(y \ V) is I-closed. Hence
,
f-l(V) is I-open in X and f is I-continuousTheorem 3.3. The function f : (X
,
T, I)
• (Y,
a) is 1 -continuous 퍼 the graph function 9 : X • X x Y is 1 -continuousProof (Necessity): Let f be I-continuous. Now let x E
X
and let V be any open set in X x Y containing g(x) = (x,
f(x)). Then there exists a basic open set U x W such that g(x) E U x W C V. Sincef
is 1 continuous,
there exists I-open set U!, in X sucht that x E U1 C X and f(U1) C W. Since U1n
U is I-open set in X and U1n
Uc
U,
then g(U1n
U)c
U x W C V showing that 9 is I-continuous.(Sufficiency): Let 9 : X • X x Y be I-continuous and let V be open containing f (x). Then X x V is open in X x Y and the I-continuity of 9 1r때lies there exists I-open set W such that g(W) C X x V. But this implies f(W) C V. Therefore
,
f is I-continuous.Theorem 3.4. Let f : (X
,
T, I)
• (Y,
a) be an 1 -contínuous and U E T.Then the Testriction flU is an 1 -continuous.
Proof Let V E a. Then f-1(V)
ç
int(J
-1(V))* and so,
Un
f-l(V) 드U
n
intU-
1(V))*. Thus (JlUt 1(V) 드 Un
int(J-1(V))“ since U E T,
then
(J
lut1(V) = int[Un (r
1(V))*],
by using Theorem 2.3 (g) [3]C
i떠 [U n r 1(V) ]
‘
int[(JIUt1(V)]*. Therefore
,
flU is 1 - continuous Theorem 3.5. Let f : (X,
T, I)
• (Y,
a, J)
be a function and {U", : Q E6 }
be an open cover of X. If the restriction funciion f lU '" 양 1 -continuous,
for each Q E
6 ,
then f is 1 -continuous.Proof Similar to Theorem 3.4.
The folJowing results are immediate and the obvious proofs are omit- ted.
Theorem 3.6. Let f : (X
,
T, I)
• (Y,
a) be 1 -continuous and open func- tion,
then the inverse image of each 1 -open set in Y ís preopen ín X.Theorem 3.7. Let f: (X
,
T,I)
• (Y,
a) be I-continuous and f- 1(V*) C28 M.E. Abd EI-Monsef. E.F. Lashien and A.A. Nasef
U-
1 (V)t , Jor each V C Y. Then the inVel‘'se image oJ each 1 -open
set is
I-open.
Remark
3.1. The composition of two I-continuous functions need not be I-continuous,
in general,
as shown by the following example.Example 3.4. Let X
=
Z= {a , b , c} ,
Y= {a , b , c , d}
with topologies r=
{X,Iþ,
{a}}, 17= {Y ,Iþ, {a , c}}
andv =
{Z,.p,
{c}, {b, c}}
and let1 = {.p,
{c}} on X and J= {Iþ,
{a}} onY
and let the identity functionJ :
(X,
T,I)
• (Y,
σ) and 9 : (Y,
17,
J) •(Z ,
v) defined as:g(a)
=a
,
g(b)=
g(d)= b
andg(c) =
c. It is clear that both J and 9 are 1- continuous. However,
the composition function 9 0J
is notI-continuou
s because {c} E v,
but(g
0J)
-I({C}) = {c}rt
IO(X).Theorem 3.8.
The Jollowing hold Jor the Junctions: J: (X ,
T, 1)
• (Y, (7) and
9 : (Y,
17,
J) • (Z,
μ)(i)
9 0J
isJ-continuous ,
iJ J is J-continuous and 9 iscontinuous
(ii)go J
is precoη tinuous ν J is M-P-coη tinuousand
9 is 1 -continuous (iii)JJ J
is surjectioη,J-l(B*) c [J -l(B)]* Jor
eachB c Y and both J and
9 areJ-continuous , then
9 0J
isalso J-continuous
Proof
(i) This is obvious.(ii) Follows from the fact that each
I-open
set is preopen set.(iii) Is c1ear by using Theorem 3.7.
4. I-open and I-closed functions
Definition 4.1. A function
J: (X , T)
•(Y ,
17,
J) is called I-open (resp I-closed) if for each U E T (resp. U is closed),
J(U) E IO(Y) (resp. J(U) isJ-closed).
Remark 4
.1. (i) l-open(I
-closed) function=>
preopen (preclosed) function and the converse is not true in general (Example 4.1)(ii) Each of l-open function and open function are independent (Ex- amples 4.2
,
4.3).Example 4.1. Let X
=
Y= {a ,
b, c}
with two topologies T=
{X,Iþ {a} ,
{a , b} , {a , c}} ,
17= {Y ,Iþ, {a} , {a , b}}
andJ = {Iþ, {a} , {b} , {a , b}}
on Y‘ Then the identity functionJ :
(X, T)
• (Y,
17, J)
is preopen but not J- open,
because, {a}
E T,
butJ({a})
={a} rt
IO(Y).Example 4.2. lf
X = {a , b ,
c,
d}= Y ,
T= {X ,Iþ, {a , b} , {a , b , d}} ,
17
= {Y ,.p, {a , b}, {a , b ,
c}} andJ = {Iþ, {c} , {d
},{c , d}}
onY.
Then theOn 1-open sets and l-continuous functions 29
identity function f: (X
,
T) • (Y,
17,
J) is 1-open function but not open function.Exar매 le 4.3. If X
=
Y=
{ι b, c},
T=
{X, 1>,
{a}},
17=
{Y, 1>,
{a},
{a,
b}}and J =
{1>,
{a}},
then the identity functionf :
(X, T)
• (Y,
17,
J) is open but not 1-open because {a} E T,
but f({a}) = {a} (j 10(Y).Theorem 4.1. Let f: (X
, T)
• (Y,
σ, J) be a function. Then the folloψing are equivalent:
(i) f is 1 -open function
(ii) For each x E X and each neighborhood U of x
,
there exists an 1-open set W C Y containing f(x) such that Wc
f(U)Proof Immediate.
Theorem 4.2. Let f: (X
, T)
• (Y,
17,
J) be an 1 -opeη (resp. 1 -closed)funclioη, if W C Y and F
c
X is a closed (resp. ope띠 set containmg f-1 (W),
then there exists aη 1-closed(resp. 1-open) set Hc
Y containiηg W such that f-1(H) C F.Proof This is obvious.
Theorem 4.3. If f : (X
, T)
• (Y,
17,
J) is 1 -open,
theη f-1(int(B)t
C(f
-1(B))* such that f-l(B) is *-dense-in-itselj, for every B C Y Proof Obvious by using Theorem (4.2)Theorem 4.4. For any bijeclive function f (X
, T)
• (κ 17, J)
the following are equivalent:(i) f-1 : (Y
,
σ,J)
• (X, T)
is 1-contiηuous(ii) f is 1-open.
(iii) f is 1 -c/osed.
Theorem 4.5. 1f f : (X
, T)
• (Y,
σ,J)
is 1 -open and for each Ac
X,
f(A
‘) c [J
(A)]",
then the image of each 1-opeη 8et is J -openTheorem 4.6. Let f : (X
,
T, 1)
• (Y,
17,
J) and 9 : (Y,
17,
J) • (Z,
ι J() be two funclions,
where 1,
J and κ are ideals on X,
Y and Z respeclively Then:(i) 9 0 f is J-opeη, if f is open and 9 is J -open.
(ii) f is 1 -opeη if 9 0 f is opeη and 9 is 1 -contin uous iη:jective.
(“11패 l
each V
c
Y,
then 9 0 f is 1-open.Proof Obvious.
30 M.E. Abd EI-Monsef, E.F. Lashien and A.A. Nasef
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