Quantum Mechanics – Applications and Atomic Structures
Jeong Won Kang
Department of Chemical Engineering Korea University
Applied Statistical Mechanics
Lecture Note - 3
Subjects
Three Basic Types of Motions (single particle)
Translational Motions
Vibrational Motions
Rotational Motions
Atomic Structures
Electronic Structures of Atoms
One-electron atom / Many-electron atom
Free Translational Motion
ψ Eψ dx
d
m =
− 2 2 2 2
Hψ = Eψ
All values of energies are possible (all values of k)
Momentum
Position See next page
2 2 2
2 dx d H = − m
ikx ikx
k = Ae + Be−
ψ
OR
Solutions
m Ek k
2
2 2
=
k p
eikx → x = + e−ikx → px = −k
Probability Density
B = 0
A = 0
A = B
Ae
ikxψ =
Be
−ikxψ =
kx Acos
= 2
ψ
2 2
= A
ψ
2 2
= B
ψ
kx A
22
= 4 cos
ψ
nodes
A particle in a box
m
Consider a particle of mass m is confined between two walls
L x x
V
L x V
=
=
∞
=
<
<
=
and 0 for
0 for
0
ψ ψ V x ψ E dx
d
m + =
− ( )
2 2
2
2
kx D
kx
k = Csin + cos
ψ m
Ek k
2
2 2
=
All the same solution as the free particle but with different boundary condition
A particle in a box
Applying boundary condition
Normalization
0 ) (
0 ) 0 (
=
=
=
= L x x ψ ψ
kx D
kx
k = Csin + cos
ψ
= 0 D
0 sinkL =
C kL = nπ
1,2,3,...
n ) / sin(
)
(x =C n x L =
n π
ψ
2 1 )
/ (
sin
2 0
2 2
0
2 =
= =
Lψn dx C L nπx L dx C L2 /
2 1
=
C L 2 sin( / ) n 1,2,3,...
) (
2 / 1
=
= n x L
x L
n π
ψ En n8mLh
2 2
= n cannot be zero
A particle in a box
- Properties of the solutions
n : Quantum number (allowable state)
Momentum
1,2,3,...
n ) / 2 sin(
) (
2 / 1
=
= n x L
x L
n π
ψ
L k n
) -e L (e
L i x L n
x ikx -ikx
n
π π
ψ =
=
= 2
2 ) 1 / 2 sin(
) (
2 / 1 2
/ 1
k p
eikx → x = + e−ikx → px = −k
Probability : 1/2 Probability : 1/2
A particle in a box
- Properties of the solutions
n cannot be zero (n = 1,2,3,…)
Lowest energy of a particle (zero-point energy)
If a particle is confined in a finite region (particle’s location is not indefinite), momentum cannot be zero
If the wave function is to be zero at walls, but
smooth, continuous and not zero everywhere, the it must be curved possession of kinetic energy
mL E h
8
2 1 =
Wave function and probability density
) / (
2 sin )
(
22
n x L
x L π
ψ
=
With n→∞, more uniform distribution:
corresponds to classical prediction
“correspondence principle”
Orthogonality and bracket notation
' 0
* =
ψnψn dτ1
0
' = n n =
n n
) ' (
0
' '
* n d n n n n
n = = ≠
ψ ψ τ' nn'
n
n =δ Orthogonality
Dirac Bracket Notation
<n| “BRA”
|n’> “KET”
Kronecker delta
Wave functions corresponding to different energies are orthogonal
Orthonormal
=Orthogonal + Normalized
Motion in two dimension
ψ ψ
ψ E
y x
m =
∂ + ∂
∂
− 2 ∂2 2 2 2 2
ψ(x,y) = X(x)Y(y)
X dx E
X d
m = X
− 2 2 2 2
Y dx E
Y d
m = Y
− 2 22 2
Y
X E
E E = +
1 1 2
/ 1
1
2 sin )
1(
L x n x L
Xn π
=
2 2 2
/ 1
2
2 sin )
2(
L y n y L
Yn π
=
2 2 1
1 2
/ 1
2 2 / 1
1
, 2 2 sin sin
) ,
2(
1 L
y n L
x n L
y L
n x
n
π
ψ π
=
m h L n L
En n n
2
2 2
2 2 2 2
1 2 1 , 2
1
+
= Separation of Variables
Solution
The wave functions for a particle confined to a rectangular surface
2 ,
2 2
1 = n =
n 1
, 1 2
1 = n =
n n1 = n1, 2 = 2 n1 = n2, 2 =1
Degeneracy
Degenerate :
Two or more wave functions correspond to the same energy
If L1=L2 then
2 2 2
,
1 8
5 mL E = h
L y L
x y L
x π π
ψ1,2( , ) 2 sin sin 2
=
L y L
x y L
x π π
ψ2,1( , ) 2 sin 2 sin
= 2
2 1
,
2 8
5 mL E = h
the same energy
with different wave functions
Degeneracy
L y L
x y L
x π π
ψ1,2( , ) 2 sin sin 2
=
L y L
x y L
x π π
ψ2,1( , ) 2 sin 2 sin
=
degenerate not
are functions wave
the ,
if L
1≠ L
2The degeneracy can be traced to the symmetry of the system
Motion in three dimension
ψ ψ ψ
ψ E
z y
x
m =
∂ + ∂
∂ + ∂
∂
− 2 ∂2 2 2 2 2 2 2
3 3 2
2 1
1 2
/ 1
3 2 / 1
2 2 / 1
1 ,
, 2 2 2 sin sin sin
) , ,
3(
2
1 L
y n L
y n L
x n L
L z L
y
n x
n n
π π
ψ π
=
m h L n L
n L
En n n n
2
2 2 3 2 3 2
2 2 2 2
1 2 1 ,
, 2 3
1
+ +
= Solution
Tunneling
If the potential energy of a particle does not rise to
infinity when it is in the wall of the container and E < V , the wave function does not decay to zero
The particle might be found outside the container (leakage by penetration through forbidden zone)
Use of tunneling
STM (Scanning Tunneling Microscopy)
5 nm
uf
Si(111)-7x7
Vibrational Motion
Harmonic Motion
Potential Energy
Schrödinger equation
kx F = −
2
2 1 kx V =
ψ ψ
E dx kx
d
m + =
− 2 2 2 2
2 1 2
m1 m2
k : force constant
2 1
2 1
m m
m m
= + μ
reduced mass
Solutions
α y = x Wave Functions
Energy Levels
4 / 2 1
=
mk α
,...
2 , 1 , 0
2)
( 1
2 / 1
=
= +
= v
m v k
Ev ω ω
2
2/
)
( y
v v
v = N H y e− ψ
Energy Levels
,...
2 , 1 , 0
2)
( 1
2 / 1
=
= +
= v
m v k
Ev ω ω
1 − = ω
+ v
v E
E
2 1
0 = ω
E
Reason for zero-point energy the particle is confined : position is not uncertain, momentum cannot be zero
2
2 1 kx V =
Potential energy
Quantization of energy : comes from B.C
±∞
=
= x
v 0 at ψ
Wave functions
Quantum tunneling
The properties of oscillators
Expectation values
Mean displacement and mean square displacement
Mean potential energy and mean kinetic energy
Virial Theorem
If the potential energy of a paticle has the form V=axb, then its mean potential and kinetic energies are related by
dx v
v ∞
v v∞
−
Ω
= Ω
=
Ω ˆ ψ*ˆ ψ
2 / 1 2
) )(
2 ( 1
v mk
x = +
=0 x
2 / 1 2
) ) (
2 ( 1 2 1 2
1
v mk kx
V = = +
V b EK = 2
Ev
V 2
= 1 EK Ev
2
= 1
Rotation in Two Dimensions : Particles on a ring
A Rotational motion can be described by its angular momentum J
J : vector
Rate at which a particle circulates
Direction : the axis of rotation
A particle of mass m constrained to move in a circular path of radius r in xy-plane
V = 0 everywhere
Total Energy = Kinetic Energy locity
angular ve :
inertial of
moment
: 2
ω
ω
mr I
I I J
=
=
I E J
pr J
m p
E
z z
2 2 /
2 2
=
±
=
=
Rotation in Two Dimension
Wave Functions
Energy Levels
,...
2 , 1 , 0 ± ±
l = m
I m I
Em Jz l
l 2 2
2 2
2 =
=
2 /
)1
2 ) (
(φ π
ψml imlφ
= e
Schrödinger eqn.
) ( )
2
(φ π ψ φ
ψml + = ml
φ ψ ψ
2 2
2 2
IE d
d =
B.C
The wave function have to be single-valued
Wave functions
States are doubly degenerate except for ml = 0
The real parts of wave functions
Rotation in Three dimension
A particle of mass m free to move anywhere on the 3D surface or a sphere
Colatitude (여위도) : θ
Azimuth (방위각) : φ
Rotation in Three dimension
l l
l l
ml = , −1, −2,...,− harmonics
spherical :
) ,
,ml (θ φ Yl
Wave Functions
Energy Levels ,...
, 2 , 1 ,
= 0 l
l I l
E = ( +1) 2 Schrödinger eqn.
ψ ψ E m ∇ =
− 2
2
Wave functions
(2l + 1) fold degeneracy
Orbital momentum quantum number
Magnetic Quantum number
l l
l l
ml = , −1, −2,...,− ,...
, 2 , 1 ,
= 0 l
Location of angular nodes
Wave functions
Angular Momentum
The energy of a rotating particle
Classically,
Quantum mechanical
Angular Momentum
Magnitude of angular momentum
Z-component of angular momentum I
E J 2
2
=
,...
2 , 1 , 0 ) 2
1 (
2
= +
= l
l I l
E
{
l(l +1)}
h1/2=
ml
=
Space Quantization
The orientation of rotating body is quantized : rotating body may not take up an arbitrary
orientation with respect to some specified axis
Space Quantization
The vector model
lx, ly, lz do not commute with each other. (lx, ly, lz are complementary observables)
uncertainty principle forbids the simultaneous, exact specification of more than one component (unless l=0).
-If lz is known, impossible to ascribe values to lx, ly.
l
x= h/2 πi {-sinφ(∂/∂θ) -cotθ cosφ(∂/∂ϕ)}
l
y= h/2 πi {cosφ(∂/∂θ) -cotθ sinφ(∂/∂ϕ)}
l
y= h/2 πi (∂/∂ϕ)
Angular momentum L (l
x, l
y, l
z)
The Vector Model
The vector
representing the
state of angular
momentum lies
with its tip on any
point on the mouth
of the cone.
Experiment of Stern-Gerlach
Otto Stern and Walther Gerlach (1921)
Shot a beam of silver atoms through an inhomogeneous magnetic field
Evidence of space quantization
The classically expected result
The Observed outcoming using silver atoms
Spin
Stern and Gerlach
observed two bands using silver atoms (2)
The result conflicts with prediction : (2l+1) orientation (l must be an integer)
Angular momentum due to the motion of the electron about its own axis : spin
Spin magnetic number : ms
ms =s, s-1,…,-s
Spin angular momentum
Electron spin
s = ½
Only two states
0.866 4
3 1/2
=
=
Fermions and Bosons
Electrons : s=1/2
Photons : s=1
Particles with half-integral spin (s=1/2)
Elementary particles that constitute matters Electrons, nucleus Fermions
Particles with integral spin (s=0,1,…)
Responsible for the forces that binds fermions Photons Bosons
Atomic Structure
and Atomic Spectra
Electronic Structure of Atoms
One Electron Atom : hydrogen atom
Many-Electron Atom (polyelectronic atom)
Spectroscopy
Experimental Technique to determine electronic structure of atoms.
Spectrum
• Intensity vs. frequency (ν), wavelength (λ), wave number (ν/c)
Topics
Structure and Spectra of Hydrogen Atoms
Electric discharge is passed through gaseous hydrogen , H2 molecules and H atoms emit lights of discrete frequencies
Spectra of hydrogenic atoms
Balmer, Lyman and Paschen Series ( J. Rydberg)
n1 = 1 (Lyman)
n1 = 2 (Balmer)
n1 = 3 (Paschen)
n2 = n1 + 1, n1 +2 , …
RH = 109667 cm -1 (Rydberg constant)
Ritz combination principle
The wave number of any spectral line is the difference between two terms
−
= 2
2 2
1
1
~ 1
n RH n
ν
2 1
~ =T −T
2 ν n Tn = RH
The wave lengths can be correlated by two integers
Two different states
Spectra of hydrogenic atoms
Ritz combination principle
Transition of one energy level to another level with emission of energy as photon
Bohr frequency condition
2
1
hcT
hcT hv
E = = −
Δ
원자에서 방출되거나 흡수된 electromagnetic radiation 은 주어진 특정 양자수로 제한된다.
따라서 원자들은 몇 가지 주어진 상태만을 가질 수 있음을 알 수 있다.
남은 문제는 양자역학을 이용하여 허용된 에너지 레벨을 구하는 것이다.
The Structure of Hydrogenic Atoms
Coulombic potential between an electron and hydrogen atom ( Z : atomic number , nucleus charge = Ze)
Hamiltonian of an electron + a nucleus r
e V Ze
0 2
4π
−
=
r Ze m
V m E
E
H N
N e
e nucleus
K electron
K
0 2 2
2 2
2 ,
, 2 2 4
ˆ
ˆ + + = − ∇ − ∇ − πε
=
Electron coordinate
Nucleus coordinate
Separation of Internal motion
Full Schrödinger equation must be separated into two equations
Atom as a whole through the space
Motion of electron around the nucleus
Separation of relative motion of electron from the motion of atom as a whole (Justification 13.1)
r H Ze
0 2 2
2
4 2μ ∇ − πε
−
= me mN me
1 1
1
1 = + ≈
μ
The Schrödinger Equation
ψ ψ E
H = ψ ψ
ψ πε
μ r E
Ze =
−
∇
−
0 2 2
2
4 2
Y l
l
Y ( 1)
2 = − +
Λ
2 2
0 2
2 ) 1 (
4 r
l l r Veff Ze
μ
πε
+ +
−
=
ER R
dr V dR R dr
R d
eff =
−
+
− 2
2 2
2 2
μ
) , ( ) ( )
, ,
( θ φ θ φ
ψ r = R r Y
Separation of Variable :
Energy is centrosymmetric Energy is not affeced by
angular component (Y) (Justification 13.2)
R : Radial Wave Equation New solution required
Y : All the same equation as in Chap.12 (Section 12.7, the particle on a sphere) Spherical Harmonics
The Radial Solutions
0
2 a
= Zr ρ
ER R
dr V dR R dr
R d
eff
=
−
+
− 2
2
22 2
μ
Solution
n l
n l l
n l
n
L e
N n r
R
,( )
,ρ
,( ρ )
−ρ/2
=
r) in l exponentia (decaying
r) in polynomial (
)
( r = ×
R
...
3 , 2 , 1
with 32
2 02 2 24 2
=
−
= n
n e
e E
nZ
π μ
Allowed Energies
Radial Solution
2 2 0 0
4 e a m
e
πε
=
Reduced distance Bohr Radius
Associated Laguerre polynomials
Hydrogenic Radial Wavefunctions
The Radial Solutions
Atomic Orbital and Their Energies
Quantum numbers
n : Principal quantum number (n=1,2,3,…)
• Determines the energies of the electron
an electron with quantum number l has angluar momentum
An electron with quantum number ml has z-component of angular momentum
ml
l n ,,
...
3 , 2 , 1
with 32 2 02 2 2
4 2
=
−
= n
n e
e En Z
π μ
{
l(l+1)}
1/2 with l =0,1,..,n−1±l
±
±
= 0, 1, 2,..., m
with
ml l
Shell
Sub Shell
Bound / Unbound State
Bound State : negative energy
Unbound State : positive energy (not quantized)
Ryberg const. for hydrogen atom
Ionization energy
Mininum energy required to remove an electron form the ground state
32 2 02 2
4
e hcRH He
π
− μ
=
32 2 02 2
4
1 e
hcR e
E H H
π
= μ
−
=
Energy of hydrogen at ground state n=1
hcRH
I =
Ionization Energy
The energy levels
Shells and Subshells
Shell
n = 1 (K), 2 (L), 3 (M), 4(N)
Subshell ( l=0,…. , n-1)
l = 0 (s), 1 (p), 2 (d), 3(f), 4(g), 5 (h), 6 (i)
Examples
n = 1
• l = 0 only 1s (1)
n = 2
• l = 0, 1 2s (1) , 2p (3)
n = 3
• l = 0, 1, 2 3s (1), 3p (3), 3d (5)
number of orbitals in nth shell : n2
n2 –f old degenerate
ml s are limited to the value -l,..,0, …+l
Ways to depicting probability density
Electron densities (Density Shading)
Boundary surface
(within 90 % of electron probability)
Radial Nodes
Wave function becomes zero ( R(r) = 0 )
For 2s orbital :
For 3s orbital : Z a r = 2 0 /
Z a
r =1.90 0 / r = 7.10a0 / Z
0
0
Radial Distribution Function
Wave Function
probability of finding an electron in any region
Probability Density (1s)
Probability at any radius r = P (r ) dr
Radial Wave Function : R(r )
Radial Distribution Function : P(r)
dr 을 곱하면 확률이 된다.
1s orbital 에 대하여 ,
/ 0
2 2Zr a
e− ψ ∝
2
2 ( )
)
(r r R r P =
ψ 2
2
4 2
)
(r πr ψ P =
/ 0
2 2 3 0
4 3
)
( r e Zr a
a r Z
P = −
Radial Distribution Function
Bohr radius
Wave function Radial Distribution Function
p-Orbital
Nonzero angular momentum
l > 0
p-orbital
l = 1
• ml = 0
• ml = + 1
• ml = -1
rl
ψ ∝
r
lψ ∝
pz
ψ
py
ψ
px
ψ
D-orbital
n = 3
l = 2
m
l= +2, +1, 0,1,2
Spectroscopic transitions and Selection rules
Transition (change of state)
All possible transitions are not permissible
Photon has intrinsic spin angular momentum : s = 1
d orbital (l=2) s orbital (l=0) (X) forbidden
• Photon cannot carry away enough angular momentum
...
3 , 2 , 1 with 32 2 02 2 2
4 2
=
−
= n
n e
e En Z
π
n1, l1,ml1 n2, l2,ml2 μ
Photon
hv E = Δ
Selection rule for hydrogenic atoms
Selection rule
Allowed
Forbidden
Grotrian diagram
1 , 0 ±
= Δml
±1
= Δl
Structures of Many-Electron Atoms
The Schrödinger equation for many electron-atoms
Highly complicated
All electrons interact with one another
Even for helium, approximations are required
Approaches
Simple approach based on H atom
• Orbital Approximation
Numerical computation technique
• Hartree Fock self consistent field (SCF) orbital
Pauli exclusion principle
Quantum numbers
Principal quantum number : n
Orbital quantum number : l
Magnetic quantum number : m
l Spin quantum number : m
s Two electrons in atomic structure can never have all four quantum numbers in common
All four quantum number “Occupied”
Penetration and Shielding
Unlike hydrogenic atoms 2s and 2p orbitals are not degenerate in many-electron atoms
electrons in s orbitals generally lie lower energy than p orbital
electrons in many-electron atoms experiences repulsion form all other electrons shielding
Effective nuclear charge, shielding constant
σ
−
= Z Zeff
constant shielding
:
charge nuclear
effective :
σ
Zeff
Penetration and Shielding
An s electrons has a greater “penetration”
through inner shell than p electrons
Energies of electrons in the same shell
s < p < d < f
Valence electrons
electrons in the outer most shell of an atom in its ground state
largely responsible for chemical bonds
The building-up principle
The building-up principle (Aufbau principle )
The order of occupation of electrons
1s 2s 2p 3s 3p 4s 3d 4p 5s 4d 5p 6s
There are complicating effects arising from electron-electron repulsion (when the orbitals have very similar energies)
Electrons occupy different orbitals of a given subshell before doubly occupying any one of them
Example : Carbon
• 1s2 2s2 2p2 1s2 2s2 2px12py1 (O) 1s2 2s2 2px2 (X)
Hund’s maximum multiplicity principle
An atom in its ground state adopts configuration with the greatest number of unpaired electrons
favorable unfavorable
3d and 4s orbital
Sc atom (Z=21)
[Ar]3d3
[Ar]3d24s1
[Ar]3d14s2
3d has lower energy than 4s orbital
3d repulsion is much
higher than 4s (average
distance from nucleus is
smaller in 3d)
Ionization energy
Ionization energy
I1 : The minimum energy required to remove an electron from many- electron atom in the gas phase
I2 : The minimum energy required to remove a second electron from many-electron atom in the gas phase
Li :2s1 Be :2s2
B : 2s2p1
Self-consistent field orbital
Potential energy of electrons
Central difficulty presence of electron-electron interaction
Analytical solution is hopeless
Numerical techniques are available
• Hartree-Fock Self-consistent field (SCF) procedure (HF method)
+
−
=
i o i i j
e
or
ije r
e V Ze
'
,
2 2
4 2
1
4 π ε π ε
Schrödinger equation for Neon Atom 1s
22s
22p
6, 2p electrons
) (
) ) (
( )
( 4
) ) (
( )
( 2
) 4 (
) 2 (
1 2 2
1 2
12
2 2
* 2 2
1 2 2
12
2
* 2 2
1 2 1 2
1 2 2 1 2
r E
r r d
r e r
r r d
r r
e r r Ze m r
p p
i i
p i
o
p i
i i
o
p o
p e
ψ
ψ ψ τ
ψ πε
ψ ψ τ
ψ πε
πε ψ
ψ
=
−
+
−
∇
−
Sum over orbitals (1s, 2s)
Kinetic energy of electron
Potential energy (electron – nucleus)
Columbic operator
(electron – electron charge density)
Exchange operator (Spin correlation effect)
HF Procedure
There is no hope solving previous eqn. analytically
Alternative procedure (numerical solution)
Assume 1s, 2s orbital
Solve 2p
Solve 2s
Solve 1s
Compare E and wave function
Converged
Solution