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Homework reminder (22

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(1)

Homework reminder (22 nd Mar)

@Copyright Prof. Juhyuk Moon (문주혁), CEE, SNU

(2)

Interesting Question.

• Shear or Moment?

(3)

Kahoot discussion

@Copyright Prof. Juhyuk Moon (문주혁), CEE, SNU

(4)

Truss vs Frame

(5)

Static Review

@Copyright Prof. Juhyuk Moon (문주혁), CEE, SNU

A plane truss has downward applied load P at joint 2 and another load P applied leftward at joint 5. The force in member 4-5 is:

(A) 0

(B) –P/2 (C) -P

(D) + 1.5 P

(6)

In Truss joint

Original

Equilibrium

In “real” truss system In “engineering” truss system

Satisfied Cannot be satisfied

(7)

Another view point

@Copyright Prof. Juhyuk Moon (문주혁), CEE, SNU

Original

Moment

Equilibrium Cannot be satisfied In truss

(8)

Other zero-force members in truss

(9)

Other zero-force members in truss

@Copyright Prof. Juhyuk Moon (문주혁), CEE, SNU

Equilibrium Equilibrium

(10)

Frame

Original Equilibrium

In “real” and “engineering” frame Satisfied

In “real” and “engineering” frame Satisfied

(11)

Static Review

The moment reaction at A in the plane frame below is approximately:

(A) +1400 N.m (B) -2280 N.m (C) -3600 N.m (D) +6400 N.m

+ -

(12)

Static Review

• Truss system

• No. of members (m) = 9

• No. of joints ( j) = 6

• No. of unknown reactions (R) = 3 m + R = 2j

: Statically Determinate Structure

(13)

Static Review

@Copyright Prof. Juhyuk Moon (문주혁), CEE, SNU

• Add member FC

• No. of members (m) = 10

• No. of joints ( j) = 6

• No. of unknown reactions (R) = 3

m + R > 2j

: Statically Indeterminate Structure

FC = Additional sharing for forces, Additional Stability

3

(14)

Static Review

• Other examples.

Statically Determinate Structure Statically Indeterminate Structure

(15)

Determinacy

@Copyright Prof. Juhyuk Moon (문주혁), CEE, SNU

• When more number of members/supports are present than are needed to prevent collapse/stability

• Cannot be analyzed using equations of equilibrium alone!

• Additional members or supports which are not necessary for maintaining the equilibrium

configuration

• We can solve the statically indeterminate structure but it is more difficult (but possible!)

: Statically Indeterminate Structure (truss)

: Redundant member

3

(16)

Zero force members in “Truss (All pin joints)”

• Element 4-5

• Cannot satisfy “Force Equilibrium (y)” condition at joint 4

• How about in “Frame”?

(17)

Chapter 2. Axially Loaded Members

@Copyright Prof. Juhyuk Moon (문주혁), CEE, SNU

• Stiffness (Flexibility)

• Changes under non-uniform conditions

• Statically Indeterminate Structures

• Thermal effect

• Stress on inclined section

• Strain energy

• Impact loading

• Stress concentration

• Nonlinear behavior

(18)

Stiffness (Flexibility)

• Changes in lengths of axially loaded member

• L (unstressed length)

• Load and elongation will be proportional:

• Stiffness and flexibility are the reciprocal of each other

(19)

Stiffness (Flexibility)

@Copyright Prof. Juhyuk Moon (문주혁), CEE, SNU

• Prismatic Bars

• Stiffness (k) and Flexibility (f ) ->

(20)

Changes in lengths under non-uniform condition

• Prismatic bar with multiple loading points

(21)

Changes in lengths under non-uniform condition

@Copyright Prof. Juhyuk Moon (문주혁), CEE, SNU

• Prismatic bar with multiple loading points

(22)

Changes in lengths under non-uniform condition

• Prismatic bar with multiple loading points with various sections

(23)

Statically indeterminate structures

• Compute net axial force in each cases.

Statically Determinate Structure Statically Indeterminate Structure

@Copyright Prof. Juhyuk Moon (문주혁), CEE, SNU

(24)

Statically indeterminate structures

• What should we calculate?

• There are two vertical reactions but only one useful equation of equilibrium

• We need something else! -> Use an equation of compatibility

(25)

Statically indeterminate structures

• Decompose members

@Copyright Prof. Juhyuk Moon (문주혁), CEE, SNU

(26)

Statically indeterminate structures

• Example 2-6

(27)

Thermal effect

• Temperature change will result in thermal strain

• Thermal expansion coefficient α

• Sign convention (expansion +, contraction -)

(unit: 10-6/K or /K or /‘C)

Temperature-displacement relation (force-displacement relation)

(28)

Thermal effect

• Thermal expansion coefficient α (unit: 10-6/K or /K)

(29)

Thermal effect

• Does it always induce thermal stress?

• If delta T1 is different from delta T2, will thermal stress occur?

• No stresses in either bar and no reactions at supports in structurally determinate structure. (less restraint, freely movable)

@Copyright Prof. Juhyuk Moon (문주혁), CEE, SNU

(30)

Thermal effect

• Example 2-7

(31)

Thermal effect

• Thermal properties of concrete and steel

@Copyright Prof. Juhyuk Moon (문주혁), CEE, SNU

Linear coefficient at

20°C (10-6/K) Volumetric coefficie nt at 20°C (10-6/K)

Concrete 12 36

steel 11~13 33~39

(32)

Stresses on inclined sections

(33)

Stresses on inclined sections

@Copyright Prof. Juhyuk Moon (문주혁), CEE, SNU

(34)

Stresses on inclined sections

Trigonometry relation

Notation and sign convention

(35)

Stresses on inclined sections

@Copyright Prof. Juhyuk Moon (문주혁), CEE, SNU

(36)

Stresses on inclined sections

(37)

Stresses on inclined sections

@Copyright Prof. Juhyuk Moon (문주혁), CEE, SNU

• Implication:

• Although the max. shear stress in an axially loaded bar is only one-half the max. normal stress, the shear stress can cause failure if the material is much weaker in shear than in tension.

• Shear failure along a 45 degree of a wood block loaded in compression

• Slip bands in a polished steel specimen loaded in tension

(38)

Other topics

• Stress concentrations

• Saint-Venant’s principle

(39)

Other topics

@Copyright Prof. Juhyuk Moon (문주혁), CEE, SNU

• Stress concentration factor K:

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