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Chapter 6 Equations of Continuity and Motion

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(1)

Session 6-3 Motions of viscous and inviscid fluids

(2)

Contents

6.1 Continuity Equation

6.2 Stream Function in 2-D, Incompressible Flows 6.3 Rotational and Irrotational Motion

6.4 Equations of Motion

6.5 Examples of Laminar Motion 6.6 Irrotational Motion

6.7 Frictionless Flow 6.8 Vortex Motion

(3)

For inviscid flow

→ Assume no frictional (viscous) effects but compressible fluid flows

→ Bernoulli eq. can be obtained by integrating Navier-Stokes equation along a streamline.

Eq. (6.24a): N-S eq. for ideal compressible fluid (µ = 0) 6.7.1 The Bernoulli equation for flow along a streamline

g p

2

q

ρ − ∇ + ∇ µ ( )

3 q

+ µ ∇ ∇ ⋅  q ( q ) q

ρ t ρ

= + ⋅∇

  

( )

p q

g q q

ρ t

∇ ∂

− = + ⋅∇

   

(6.63)

(4)

→ Euler's equation of motion for inviscid (ideal) fluid flow

Substituting (6.26a) into (6.63) leads to

Multiply (element of streamline length) and integrate along the streamline

( )

p q

g h q q

ρ t

∇ ∂

− ∇ − = + ⋅∇

  

g = − ∇g h

(6.64)

idx  +  jdy + kdzdr

( ) ( )

1 q

g h dr p dr dr q q dr C t

ρ t

 ∂ 

− ∫ ∇ ⋅ − ∫ ∇ ⋅ = ∫   ∂   ⋅ + ∫   ⋅∇   ⋅ +

(6.65)

(5)

( ) ( )

dp q

gh dr q q dr C t

ρ t

 ∂ 

− − ∫ = ∫   ∂   ⋅ + ∫   ⋅∇   ⋅ +

I

(6.66)

( ) ( ) ( )

I =   q  ⋅∇ q    ⋅ dr  = dr  ⋅   q  ⋅∇ q    = ⋅ q    dr  ⋅∇ q   

II

By the way,

( ) ( ) ( )

II dr dx dy dz

x y z

∂ ∂ ∂

= ⋅∇ = + +

∂ ∂ ∂

( dr ) q q dx q dy q dz dq

x y z

∂ ∂ ∂

∴ ⋅∇ = + + =

∂ ∂ ∂

  

  

(6)

2 I = ⋅ q dq =   dq

 

 

( )

2 2

2 2

q q

q q dr d  

∴   ⋅∇   ⋅ =   =

 

 

Thus, Eq. (6.66) becomes

2

( )

2

dp q q

gh dr C t

ρ

t

 ∂ 

+ + +  ∂ ⋅ = −

∫ ∫

(6.67)

For steady motion, q 0;C t

( )

C

t

∂ = →

(7)

Divide by g

For incompressible fluids, ρ = const.

2

2 .

dp q

gh const ρ + + =

along a streamline (6.68)

2

2 .

p q

gh const ρ + + =

2

2

p q

h C

γ + + g =

along a streamline (6.69)

(8)

→ Bernoulli equation for steady, frictionless, incompressible fluid flow

→ Eq. (6.69) is identical to Eq. (6.22). Constant C is varying from one streamline to another in a rotational flow, Eq. (6.69); it is invariant throughout the fluid for irrotational flow, Eq. (6.22).

6.7.2 Summary of Bernoulli equation forms

• Bernoulli equations for steady, incompressible flow 1) For irrotational flow

constant throughout the flow field

2

2

p q

H h

γ g

= + + =

(6.70)

(9)

2) For frictionless flow (rotational)

2

2

p q

H h

γ g

= + + =

constant along a streamline (6.71)

3) For 1-D frictionless flow (rotational)

2

2

p V

H h Ke

γ g

= + + =

constant along finite pipe (6.72)

4) For steady flow with friction ~ include head loss hL

2 2

1 1 2 2

1 2

2 2

L

p q p q

h h h

g g

γ + + = γ + + +

(6.73)

(10)

(1) Efflux from a short tube

• Zone of viscous action (boundary layer): frictional effects cannot be neglected.

• Flow in the reservoir and central core of the tube: primary forces are pressure and gravity forces. → irrotational flow

• Apply Bernoulli eq. along the centerline streamline between (0) and (1)

(11)

p0 = hydrostatic pressure = γd0 , p1 = patm → = 0

q0 = 0 (neglect velocity at the large reservoir)

→ Torricelli’s result

0 0 1 1

0 1

2 2

p q p q

z z

g g

γ + + = γ + +

1gage

p

0 1

z = z

2 1

2

0

q d

g = q

1

= 2 gd

0 (6.74)

If we neglect thickness of the zone of viscous influence

2

4 1

Q = πD q

(12)

• Selective withdrawal: Colder water is withdrawn into the intake channel with a velocity q1 (uniform over the height b1 ) in order to provide cool

condenser water for thermal (nuclear) power plant.

During summer months, large reservoirs and lakes become thermally stratified.

→ At thermocline, temperature changes rapidly with depth.

(13)
(14)

(6.75)

p0 = hydrostatic pressure = (γ – ∆γ)(d0 – a0)

2 2

0 0 1 1

0 1

2 2

p q p q

a b

g g

γ + + = γ + +

0

0

q

( )

1 0 1

p = γ d − ∆ − h b

(6.76)

( )

2 1

0 0

2

q h d a

g

γ γ

∴ = ∆ − ∆ −

( )

1 2

1

2

0 0

q g h γ d a

γ

  ∆  

=   ∆ − −  

 

 

(6.77)

(15)

For isothermal (unstratified) case, a0 = d0

1

2

q = g h

→ Torricelli’s result (6.78)

(16)

→ Measure velocity from stagnation or impact pressure

(6.79) (6.80)

2 2

0 0

0

2 2

s s

s

p q p q

h h

g g

γ + + = γ + +

0 s

,

h = h q

s

= 0

2

0 0

2

q p

s

p g γ h

∴ = − = ∆

(17)

• Pitot-static tube

(

0

)

0

2 p

s

p

q ρ

= −

(A)

By the way,

1 s 2 0 m

p = p + ∆ = γ h p = p + ∆ γ h

( )

0

s m

pp = ∆ h γ − γ

Combine (A) and (B)

( )

0

2 h

m

q γ γ

ρ

∆ −

=

(B)

(18)
(19)
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