임펄스 함수의 Shifting property :
임펄스 응답으로 표현된 시스템의 응답
0 0 0 0
( ) ( ) (0) ( ) (0)
( ) ( ) ( ) ( ) ( )
x t t dt x t dt x
x t t t dt x t t t dt x t
0 0 0
( ) ( ) ( ) ( ) ( t) ( ) ( )
x t
x t t t dt
x t t dt t t
( ) ( ) ( )
x t
x t d
임펄스 응답(Impulse Response)
• 정의 :
• 선형 시불변 시스템(LTI System) : 1) :
2) 3)
( ) [ ( )]
h t T t
[ ] T ( )t
h t( )
t ( ) ( )
x t t
0 t
( ) ( ) y t h t
0 (1)
[ ( )] ( )
T t h t [3 ( )] 3 ( )
T t h t
1 2 1 2 1 2
[3 ( ) 5 ( )] 3 [ ( )] 5 [ ( )] 3 ( ) 5 ( ) T t t T t T t h t h t
1 1
[3 ( )] 3 ( ),
T t h t T[5 ( t 2)]5 (h t2)
( ) ( ) ( ) ( ) ( ) ( )
T x t d x T t d x h t d
컨볼루션 적분(Convolution integral)
•
•
( ) ( ) ( ) ( ) ( ) ( )
T x t d x T t d x h t d
( ) ( ) ( ) ( ) ( ) ( )T x t y t x h t d x t h t
[ ] T
( ) ( ) ( )
x t x t d
T[ ]( ) ( ) x t t
( ) ( ) ( ) ( ) ( ) y t x t h t x h t d
( ) ( ) ( ) ( ) ( ) ( )
y t t h t h t d h t
[예제3.5]
Convolution 적분의 계산
( ) ( ), 0
( ) ( )
x t e
atu t a h t u t
( ) x t
0 t
1
( ) h t
0 t 1
0
1 x( )
( )
h t
shift
t
( ) ( ) ( )
( ) ( ) y t x t y t
x h t d
0 1
( )
h t
t 0
1 ( ) x
i) t0
0
1
( )
h t
0 t 1 ( ) x
t
ii) t 0
no overlap ( ) 0
y t 0
2
( ) ( ) ( ) 1(1 )
If 2, then ( ) 1(1 ) ( ) 2
t a at
t
y t x h t d e d e
a
a y t e u t
( ) 1 (1 at) ( )
y t e u t
a
( ) y t
0 t
1
a
[예제3.6]
( ) x t
0 t
1
a
( ) h t
0 t
1
b
( ) ( ) ( )
( ) ( ) ( ),
x t u t u t a
h t u t u t b b a
( ) x
0
1
a
( )
h t
0 1
tb
t
(a) t0
( ) x
0
1
a
( )
h t
0 1
tb
t (b) 0 t a
no overlap y t( ) 0 y t( )
0t(1)d t( ) x
0
1
a
( )
h t
0 1
tb
t (c) a t b
( ) x
0
1
a
( )
h t
0 1
tb
t (d) b t a b
( ) 0a(1)
y t
d a y t( )
t ba (1)d a b t( ) x
0
1
a
( )
h t
0 1
tb
t (e) a b t
( ) y t
0 t
a
a b a b
( ) 0 y t
교환성
결합성
분배성
Convolution의 성질
( ) ( ) ( ) ( )
x t
h t
h t
x t
1 2 1 2
{ ( )
x t
h t
( )}h t
( ) x t
( ) { ( )h t
h t
( )}1 2 1 2
( ) { ( ) ( )} ( ) ( ) ( ) ( ) x t h t h t x t h t x t h t
( ) h t ( )
x t y t( )
h t( ) x t( ) y t( )1( ) ( ) h t
x t h t2( ) y t( )
1 2
( ) ( ) ( )
h t h t h t ( )
x t y t( )
1( ) h t ( )
x t
2( ) h t
( )
y t
x t( ) h t( ) h t1( )h t2( ) y t( )
[예제 3.3]
1) 균일해
2) 특수해
3) 완전해
( ) 2 ( ) ( ), (0) 4
dy t y t u t y
dt
2 0 2
s s
yp A
2 1
( ) 2
t
h p
y t y y Ke
7 2 1
( ) , 0
2 2
y t e t t
0 2 1 1
A A 2
st
yh Ke
Initial condition: (0) 1 4 y K 2
( )
2ty t
h Ke
미분방정식과 임펄스 응답의 관계
[예제 3.3]
1) 균일해
2) 특수해
3) 완전해
(0) 0 ( )
y no initial stored energy
2 0 2
s s
yp A
2 1
( ) 2
t
h p
y t y y Ke
1 2 1
( ) , 0
2 2
y t e t t
0 2 1 1
A A 2
st
yh Ke
Initial condition: (0) 1 0 y K 2
( )
2ty t
h Ke
( ) 2 ( ) ( ), (0) 4
dy t y t u t y
dt
Let
1) 균일해
2) 특수해
3) 완전해
( ) 2 ( ) ( ), (0) 0
dy t y t u t y
dt
2 0 2
s s
yp A
2 1
( ) 2
t
h p
y t y y Ke
1 2 1
( ) , 0
2 2
y t e t t
0 2 1 1
A A 2
st
yh Ke
Initial condition: (0) 1 0 y K 2
( )
2ty t
h Ke
Let
1) 균일해
2) 특수해
3) 완전해
( ) 2 ( ) ( ), (0) 0 ?
dy t y t t y
dt
2 0 2
s s
yp A
( ) h p 2t
y t y y Ke
( ) 0 ?, 0
y t t
0 2 A 0 A 0
st
yh Ke
Initial condition: (0)y K 0 ?
( )
2ty t
h Ke
Let
1) 균일해
2) 완전해 3) 초기조건
좌변 우변
4) 임펄스 응답
2 0 2
s s
( ) h( ) 2t
h t h t ICs Ke ICs ( ) st
h th Ke
( )
2th t
h Ke
( ) 2 ( ) ( ), (0) ?
dh t h t t h
dt
Initial condition: (0 )h K 1 (0) :
h
0 0
0 0
0 0
( ) ( ) (0 )
( ) 1 (0 ) 1
dh d h d h
dt
d h
2 2
( ) t, 0 ( ) t ( )
h t e t or h t e u t
5) Convolution 적분 :
라고 가정하면 [예제 3.5]의 결과로부터
( ) ( ) x t u t
2 2
0
2
( ) ( ) ( )
( ) ( )
1 (1 ), 0
2 ( ) 1 (1 ) ( )
2
t t
t
y t x t y t
x h t d
e d e t
y t e u t
[예제3.8] : Overall impulse response
1( ) h t ( )
x t
3( ) h t
( )
y t
2( ) h t
4( ) h t
3 1
2
2 3
4
( ) ( )
( ) ( )
( ) ( )
( ) ( 1)
t
t
h t e u t h t u t h t e u t h t t
1 2 3 4
3 2( 1)
( ) ( ) ( ) ( ) ( )
1 1 ( ) ( 1)
3
t t
h t h t h t h t h t e
u t e
u t
Identity 시스템과 delay 시스템의 임펄스 응답
적분기의 임펄스 응답
Convolution is a smoothing operator
Convolution의 성질
0 0
( ) ( ) ( ) ( )
( ) ( ) ( ) ( )
h t t y t x t
h t t t y t x t t
( ) ( ) ( ) ( )
t( )
x t u t
x u t d x d
( ) ( ) ( )
t( )
h t u t y t x d
미적분 특성
( ) h t ( )
x t y t( )
( )
1 h t
( ) dx t( ) x t dt
( )
2( ) t ( ) h t x t x d
1
( ) dy t( ) y t dt
2( ) t ( )
y t y d
d dt
d dt
t
t
( ) h t ( )t
h t( ) T
( )t( ) h t ( )
u t ( )
( )t ( ) s t T u t
h d
t
t
impulse response
unit step response
Memoryless system
Causal system
• LTI system is causal if
• Output of causal LTI system
Stable system
• LTI system is BIBO stable iff impulse response is absolutely integrable.
LTI System의 임펄스 응답
( ) ( ), ( ) ( )
y t
Kx t K
는 상수 h t
K t
( ) 0, 0 h t t
0
( ) ( ) ( ) ( ) ( )
( ) ( ) ( ) ( )
t
y t x h t d x h t d
h x t d h x t d
( ) h t dt