Fuel Cell System Design
How to Design A FC System?
1. Construct a reasonable system configuration and make a good guess on the specifications.
2. Calculate the thermal and mass balance of the complete system based.
3. Refine the choice and specification of system components
according to the thermal and mass balance calculated in 2. For according to the thermal and mass balance calculated in 2. For coupled components, verify compatibility based on the
expected magnitude and rate of mass, heat or current transfer between them
between them.
4. Review the system’s performance considering the original design goals If system refinement is required decide which design goals. If system refinement is required, decide which components or parameters should be changed and repeat the design process.
20 W (12 V)Portable SOFC Schematic
SOFC System Components
1. Fuel cell stack:
• Should supply net power output of 20 WShould supply net power output of 20 W.
• Obviously, stack power is significantly larger than 20W.
• Support BOP’s such as the air blower and the DC/DC converter
P t 12 V (17 ll t 0 7 V lt ti l
• Power at 12 V (17 cells at 0.7 V or alternatively fewer cells with a 12 V DC-DC converter)
2. Hydrogen supply
• Use metal hydrides for simplicity in a portable system
system.
• Relatively high pressures/flow rates
• Hydrocarbon-fuel provide better energy density, y p gy y, but complicated
SOFC System Components
3. Air Supply:
• For electricity and thermal management (cooling)For electricity and thermal management (cooling)
• Relatively large flow rates will be needed for cooling
• Options: compressor, fan, or blower
• Choose blower working at 12 V DC 4. Heat management
• Recycle heat from the stack
• Heat exchanger can warm up the cold fuel cell inlet gases using the hot fuel cell exhaust gases.
SOFC System Components
5. DC-DC converter
• 6~8 cells generates 4 2~5 6V at 0 7V6 8 cells generates 4.2 5.6V at 0.7V.
• DC-DC converter to boost up the output voltage to 12 V sacrificing efficienty.
• Stabilizes stack voltage fluctuation
SOFC Unit Cell Performance
Q1: How to get this?
Q2: Operating point? (voltage, cell temerpature, t i hi t ffi i
stoichiometry, efficiency Q3: How many stacks?
System Design = Chicken and Egg
Stack power = f(power density)
Power density of SOFC = f(operating temperature) Operating temperature = f(cooling flow rate, say air) Flow rate f(blower power)
Flow rate = f(blower power) Blower power = f(stack power)
-The various parameters in the system are strongly coupled nonlinearly
Solve thorough initial guess and iteration - Solve thorough initial guess and iteration
Initial Guess on Stack and BOPs
Stack design parameters Value
F l ll i T 00 C
Fuel cell operating temperature, Tfc 700 C Hydrogen and air pressure 1 atm Hydrogen stoichiometry, 1.2
Air stoichiometry, y, 8
Fuel cell operating voltage, Voper 0.7 V
Fuel cell output power P 50W
Fuel cell output power, Pfc 50W System component design parameters Value System component design parameters Value DC-DC converter efficiency, 90%
Heat exchanger efficiency, 90%
Bookkeeping: 1, Mass Balance
Afc = 47.62 cm2 = 50 W / (0.7 V X 1.5A/cm2)) . i = 71 43 A (= 50 W / 0 7 V)
itotal = 71.43 A (= 50 W / 0.7 V).
2 supply 2
71.43 2 96400 / 1.2
total
H H
i A
v = F ×
λ
= C l ×2,supply 2
4
2 96400 /
4.442 10 / 0.02665 / min
H H
nF C mol
mol s mol
−
×
= × =
2,supply 2
71.42 4 96400 / 8
total
O O
i A
v = F ×
λ
= C l ×2,supply 2
4 96400 /
0.001481 / 0.08884 / min
O O
nF C mol
mol s mol
×
= =
2 2
3
,supply ,supply
1.481 10 / 0.79
N O
0.21
v = v × =
ω
× − mol s×0.
0.005571
mol s/ 0.3342
mol/ min
= =
Bookkeeping: 1, Mass Balance
2 2
,supply ,supply ,supply 0.3342 / min 0.08884 / min 0.4230 / min
Air N O
v = v +v = mol + mol = mol
,supply 25
,supply
0.4230 / min 0.0820578 / 298.15 1
C Air Air
v RT mol atm L mol K K
V p atm
× ⋅ ⋅ ×
= =
10.35LPM
=
71.42 4
3 702 10 / 0 0222 / min
total
i A
v = = = × − mol s = mol
2 , 3.702 10 / 0.0222 / min
2 96400 /
H O prod
v mol s mol
nF C mol
= = = × =
×
2 2 2
5
, ,supply ,
l
7.403 10 / 0 001296 /
H exhaust H H cons
O h O O
v v v mol s
v v v mol s
= − = × −
= − =
2 2 2
2 2
, ,supply ,
, ,supply
0.001296 / 0.005571 /
O exhaust O O cons
N exhaust N
v v v mol s
v = v = mol s
2 2
4
, ,
3.702 10 /
H O exhaust H O prod
v = v = × − mol s
Bookkeeping: 1, Mass Balance
FLOW RATES VALUE (MOL/S)
vH2,supply 4.442 x 10-4
vO2,supply 0.001481
vN2 l = vN2 h t 0 005571
vN2,supply vN2,exhaust 0.005571
vH2,exhaust 7.403 x 10-5
0 001296
vO2,exhaust 0.001296
vH2O,exhaust = vH2,cons = 2vO2,cons 3.702 x 10-4
Bookkeeping: 2, Thermal Balance
Assuming adiabatic Pheat = (EH −Voper)×itotal
(1.28V 0.7 ) 71.43V 41.71W
= − × =
Heat is only removed by convection
( )
, , , , , ,
heat p i i exhaust fc p i i exhaust fc out fc in
i i
P = ⎛⎜ c v ⎞⎟ΔT = ⎛⎜ c v ⎞⎟ T −T
⎝
∑
⎠ ⎝∑
⎠⎝ ⎠ ⎝ ⎠
( )
41.71
heat
H H h t O O h t N N h t H O H O h t f t f i
P W
c v c v c v c v T T
= =
⎡ + + + ⎤ −
⎣ , 2 2, , 2 2, , 2 2, , 2 2 , ⎦
(
, ,)
(30.116 / 0.00007403 / 34 366 / 0 001296 /
p H H exhaust p O O exhaust p N N exhaust p H O H O exhaust fc out fc in
c v c v c v c v T T
J mol K mol s
J mol K mol s
⎡ + + + ⎤
⎣ ⎦
= × +
× +
34.366 / 0.001296 / 32.409 / 0.005571 /
40 924 / 0
J mol K mol s J mol K mol s J mol K
× +
× +
× 00037mol s T/ )
(
f −973 15)
40.924 /J mol K ×0.
(
,)
,
00037 / ) 973.15
1145
fc out fc out
mol s T
T K
∴ =
Bookkeeping: 2, Thermal Balance
Heat exchanger HX p i i, hot HX p i i,
(
hot in, hot out,)
HXi i
Q = ⎛⎜ c v ⎞⎟ΔT ε = ⎛⎜ c v ⎞⎟ T −T ε
⎝
∑
⎠ ⎝∑
⎠
( )
, , , ,
i i
p i i cold p i i cold in cold out
i i
c v T = c v T T
⎝ ⎠ ⎝ ⎠
⎛ ⎞ ⎛ ⎞
= ⎜ ⎟Δ ⎜ ⎟ −
⎝
∑
⎠ ⎝∑
⎠i i
⎝ ⎠ ⎝ ⎠
( )
⎡ , 2 2, , 2 2, , 2 2, ⎤
(
, ,)
(30.116 / 0.000444 /
HX p H H exhaust p O O exhaust p N N exhaust cold out cold in
Q c v c v c v T T
J mol K mol s
⎡ ⎤
= ⎣ + + ⎦ −
= × +
( )
34.366 / 0.001481 /
32.409 / 0.005571 / ) 973.15 298.15 J mol K mol s
J mol K mol s K K
× +
×
(
−)
165.3W
=
Bookkeeping: 2, Thermal Balance
( )
165.3
HX
H H h t O O h t N N h t H O H O h t h t i h t t HX
Q W
c v c v c v c v T T ε
= =
⎡ + + + ⎤ −
⎣ ⎦
( )
2 2 2 2 2 2 2 2
, , , , , , , , , ,
(30.116 / 0.00007403 / 34.366 / 0.001296 /
p H H exhaust p O O exhaust p N N exhaust p H O H O exhaust hot in hot out HX
c v c v c v c v T T
J mol K mol s
J mol K mol s
ε
⎡ + + + ⎤
⎣ ⎦
= × +
× +
32.409 / 0.005571 / 40.924 /
J mol K mol s J mol
× +
(
,)
0.00037 / ) 1145 hot out 0.9 K × mol s
(
K −T ,)
×, 388 115
hot out
T K C
∴ = =
THERMAL PARAMETERS VALUES THERMAL PARAMETERS VALUES
PHeat 41.7 W
165.3 W
Tfc,in= Tcold,out 973.15 K
Tfc,out= Thot,in 1145 K
Tcold,in= Tambient 298.15 K
Tcold,out 388K
Component Selection
SPECIFICATION VALUE Max flow rate 15 5 LPM
Air Blower
Max flow rate 15.5 LPM Max current 3.2 A
Operating voltage 12 V Operating voltage 12 V
Max pressure 1200 mbar Power vs flow rate Linear ( ) Power vs. flow rate Linear ( )
Heat Exchangerg Specificationp Values Max fluid temperature 900°C
Rated flo range 5 20 LPM Rated flow range 5–20 LPM Number of paths 4
Thermal efficiency 90%
Component Selection
DC-DC converter SPECIFICATION VALUES
Input voltage Min 4.0 V, Max 25 V Output voltage (Adjustable) Min 1.5, Max 15 V Max input current 20 A
Max output current 5 A
Metal hydride
Efficiency 90%
SPECIFICATION VALUES
y SPECIFICATION VALUES
Dimension D 6.4cm, H 26.5cm
Weight 2 2 kg
Weight 2.2 kg
Hydrogen capacity 250 L 1
Internal pressure 17 atm
System Characteristic
N t P P P
Net power Blower
net fc DC DC blower
P = P ×
ε
− − PMax current
Actual flow rate
P × ×V
Blower
power Actual flow rate
Max flow rate
3.2 10 35 12 25 64
blower blower
P V
A LPM V W
= × ×
= × × =
N t
10.35 12 25.64
15.5 LPM V W
= LPM × × =
50 0 9 25 64 19 36 P = W × W = W Net power
Efficiency
50 0.9 25.64 19.36 Pnet = W × − W = W
net net
net
P P
h h
ε = =
Δ Δ
Efficiency
2,supply
19.36 19.36
.176
H 110
HHV H
HHV h v
h
W W
l J
Δ ×
Δ
= = =
4 2
2
H 110
247, 700 J 4.442 10 mol W
mol H s
× ∗ −
Design Review
SPECIFICATION VALUE
System net power 19.35 W (Need to be increseas)
Fuel cell power 50 W
Fuel cell voltage 4.2 V (Maybe too low)
Number of cells in the fuel cell stack 6 (Need to be increase)( ) Temperature range of the fuel cell 700~872°C (T_diff too high) Temperature range of the heat exchanger 25~872°C (T_diff larege) System operation time 6 4 hour (Too short)
System operation time 6.4 hour (Too short)
Air blower power consumption 25.64 W (More than 50%)
-Heat dissipation to the environmentHeat dissipation to the environment -Increase air flow? Blower power?
-Increase cell number? How about cost?
-Pressure drop in the stack?
-Weight, volume and cost?
Cell performance change in different operation condition?
-Cell performance change in different operation condition?
-Single cell performance vs stack performance?