Chapter 14 Output Stages and Power Amplifiers
14.1 General Considerations
14.2 Emitter Follower as Power Amplifier
14.3 Push-Pull Stage
14.4 Improved Push-Pull Stage
14.5 Large-Signal Considerations
14.6 Short Circuit Protection
14.7 Heat Dissipation
14.8 Efficiency
14.9 Power Amplifier Classes
Why Power Amplifiers?
Drive a load with high power.
Cellular phones need 1W of power at the antenna.
Audio systems deliver tens to hundreds of watts of power.
Ordinary Voltage/Current amplifiers are not suitable for such applications
Chapter Outline
Power Amplifier Characteristics
Experiences low load resistance.
Delivers large current levels.
Requires large voltage swings.
Draws a large amount of power from supply.
Dissipates a large amount of power, therefore gets “hot”.
Power Amplifier Performance Metrics
Distortion - Linearity
Power Efficiency
Voltage Rating – Transistor Breakdown voltage
Emitter Follower Large-Signal Behavior I
As Vin increases Vout also follows and Q1 provides more current.
1
For 8 ,
1/ 0.8 , thus, 32.5 mA
v L L m
L
m C
A R R g
R
g I
For Vin=4.8V, Vout=4.0V, IL=500mA, IE1=532.5mA
Emitter Follower Large-Signal Behavior II
For Vin=0.8V, Vout=0V, IL=0mA, IE1=32.5mA
For Vin=0.7V, Vout=-0.1V, IL=12.5mA, IE1=20mA
When all current (32.5mA) flows to the load, Vout=-0.26V
However, as Vin decreases, Vout also decreases, shutting off Q1 and resulting in a constant Vout.
Example 14.1: Emitter Follower
For 0.5
211 mV by a few iterations
in out
V V
V
1 1 1
1 1
1
,
ln( / ) ln 1
out
in BE out C
L
BE T C S
out
in T out
L S
V V V V I I
R
V V I I
V V V I V
R I
Vin=0.5V, Vout=?
Example 14.1: Emitter Follower
1
1 1
ln
Cin T C L
S
V V I I I R
I
For what Vin, Q1 carries only 1% of I1?
1 1
For 0.01 390 mV
C in
I I
V
Linearity of an Emitter Follower
As Vin decreases the output waveform will be clipped, introducing nonlinearity in I/O characteristics.
Push-Pull Stage
As Vin increases, Q1 is on and pushes current into RL.
As Vin decreases, Q2 is on and pulls current out of RL.
Example 14.2: I/O Characteristics for Large V
in For positive Vin, Q1 shifts the output down and for negative Vin, Q2 shifts the output up.
V
out= V
in-V
BE1for large +V
inV
out= V
in+|V
BE2| for large -V
inOverall I/O Characteristics of Push-Pull Stage
However, for small Vin, there is a “dead zone” (both Q1 and Q2 are off) in the I/O characteristic, resulting in gross nonlinearity.
Example 14.3: Small-Signal Gain of Push-Pull Stage
The push-pull stage exhibits a gain that tends to unity when either Q1 or Q2 is on.
When Vin is very small, the gain drops to zero.
Example 14.4: Sinusoidal Response of Push-Pull Stage
For large Vin, the output follows the input with a fixed DC offset, however as Vin becomes small the output drops to zero and
causes “Crossover Distortion.”
Improved Push-Pull Stage
With a battery of VB inserted between the bases of Q1 and Q2, the dead zone is eliminated.
V
B= V
BE1+ |V
BE2|
Implementation of V
B Since VB=VBE1+|VBE2|, a natural choice would be two diodes in series.
I in figure (b) is used to bias the diodes and Q .
Example 14.6: Current Flow I
I
in1 1 2
in B B
I I I I
1 2
Usually unless 0
flows even when = 0.
B B out
in out
I I V
I V
Example 14.8: Current Flow II
1 2
0 when 0 if
in out
I V I I
1
→
D BE
V V V
out V
inAddition of CE Stage
A CE stage (predriver) is added to provide voltage gain from the input to the bases of Q1 and Q2.
Bias Point Analysis
For bias point analysis for Vout=0, the circuit can be simplified to the one on the right, which resembles a current mirror.
VA=0 Vout=0
, 1
1 3
S Q
C C
I I I
I
Small-Signal Analysis
Assuming 2rD is small and (gm1+gm2)RL is much greater than 1,
4 1 2
4 1 2 1 2 1 2
4 1 2 1 2
( 1)
1
v m L
m m m L
m m m L
A g r r R
g r r r r g g R
g r r g g R
Example 14.9: Output Resistance Analysis
3 4
1 2 1 2 1 2
1 ||
( )( || )
O O
out
m m m m
r r
R g g g g r
r
If β is low, the second term of the output resistance will rise, which will be problematic when driving a small resistance.
Example14.10: Biasing
1 2
Predriver (CE stage): 5
Output Stage: 0.8 for 8 2 100,
V
V L
npn pnp C C
A
A R
I I
Compute the required bias current.
1 1
1 2 1 2
1 2
1 2
4 1 2 1 2
1
4 4
2 4
Thus, 6.5 mA
|| 400 || 200 133
|| 1 4
133 195 μA
m m m m
C C
m m m L
m C
g g g g
I I r r
g r r g g R
g I
65uA
135uA
6.5mA 6.5mA 195uA
60uA 125uA
Problem of Base Current
195 µA of base current in Q1 can only support 19.5 mA of
collector current, insufficient for high current operation (500 mA for 4 V on 8 ).
Modification of the PNP Emitter Follower
Instead of having a single PNP as the emitter-follower, it is now combined with an NPN (Q2), providing a lower output
resistance.
21 1
3out
m
R g
Example 14.11: Input Resistance
2
33
1 1 1
out L
in L
m
v R
v R
g r
2
32 3
3
Comparing with the standard EF,
1 1
1 1
1
out
m m
r g
g r
Example 14.11: Input Resistance
3
2 3
3 2 3
1
1 1 ( 1)
L
in in in
L
m
in L
i v v R
r R
g
r R r
Additional Bias Current
I1 is added to the base of Q2 to provide an additional bias current to Q3 so the capacitance at the base of Q2 can be
charged/discharged quickly. Additional pole at the base of Q .
2 in
0
out EB
Min V
V V
Example 14.12: Minimum V
in2
3 2
in BE
out EB BE
Min V V
V V V
Power Amplifier Classes
Class A: High linearity, low efficiency
Class B: High efficiency, low linearity
Class AB: Compromise between
Class A and B
HiFi Design
As Vout becomes more positive, gm rises and Av comes closer to unity, resulting in nonlinearity.
Using negative feedback, linearity is improved, providing higher fidelity.
Short-Circuit Protection
Qs and r are used to “steal” some base current away from Q1 when the output is accidentally shorted to ground, preventing short-circuit damage.
Power transistors
Package and heat sink
Small-signal Transistor Power Transistor in Heat Sink Power Transistor Inside
Emitter Follower Power Rating (Class A)
0
0 1
2
1 1 1
1
sin
1 sin
2 if
T
av C CE
T P
CC P
L
P P P
CC CC
L L
P I V dt
T
V t
I V V t dt
T R
V V V
I V I V I
R R
Maximum power dissipated across Q1 occurs in the absence of a signal.
Pull down is done
by a current source
with huge current!
Example 14.13: Power Dissipation
1 0 1
1
1
Tsin
I p EE
EE
P I V t V dt
T
I V
Avg Power Dissipated in the Current Source I1
Push-Pull Stage Power Rating
/2
, 0
/2 0
2
1
sin
1 sin
4 4
T
av NPN C CE
T P
CC P
L
CC P P P CC P
L L L
P I V dt
T
V t
V V t dt
T R
V V V V V V
R R R
No power for half of the period.
Push-Pull Stage Power Rating
/2
, 0
/2 0
2
1
sin
1 sin
4 4
T
av NPN C CE
T P
CC P
L
CC P P P CC P
L L L
P I V dt
T
V t
V V t dt
T R
V V V V V V
R R R
No power for half of the period.
Maximum power occurs between Vp=0 and 4Vcc/π.
2
,max CC2 P
when 2
CCav P
L
V V V
P V
R
Push-Pull Stage Power Rating
Maximum power occurs between Vp=0 and 4VCC/π.
, ,
when
av PNP av NPN CC EE
P P V V
2
,max CC2 P
when 2
CCav P
L
V V V
P V
R
, /2
/2
2
1
sin
1 sin
4 4
T
av PNP T C CE
T P
P EE
T L
EE P P P EE P
L L L
P I V dt
T
V t
V t V dt
T R
V V V V V V
R R R
Heat Sink
Heat sink, provides large surface area to dissipate heat from the chip.
Thermal Runaway Mitigation
1 2
1 2
, 1 , 2
1 2 , 1 , 2
1 2
1 2
, 1 , 2
1 2 , 1 , 2
1 2 1 2
, 1 , 2 , 1 , 2
ln ln
ln
ln ln
ln
With the same ,
D D
D D T T
S D S D
D D T
S D S D
C C
BE BE T T
S Q S Q
C C T
S Q S Q T C C D D
S D S D S Q S Q
I I
V V V V
I I
I I
V I I
I I
V V V V
I I
V I I
I I V I I I I
I I I I
Using diode biasing prevents thermal runaway since the
currents in Q1 and Q2 will track those of D1 and D2 as long as their I ’s track with temperature.
Efficiency
Power Delivered to Load
Power Drawn From Supply Voltage
out out ckt
P
P P
Efficiency is defined as the average power delivered to the load divided by the power drawn from the supply
Emitter Follower (Class A)
2 2
1 1
1
2
2 2
if and 4
P L
EF
P L CC P EE
P P
EE CC
CC L
V R
V R I V V I V
V V
I V V
V R
Maximum efficiency for EF is 25%.
Example 14.15: Efficiency of EF
1
2 2
1 1
2
2
/ 2
With = and 2
2 2
2
2 2
Thus,
1 6.7%
15
P CC
P CC
EE CC
L L
P L
EF
P L CC P EE
P L
CC CC
P L CC P CC
L L
EF V V
V
I V V V
R R
V R
V R I V V I V
V R
V V
V R V V V
R R
EF designed for full swing operates with half swing.
Efficiency
Push-Pull Stage (Class A or AB)
2
2
2 2
2 4
4
P L PP
CC
P P P
L L
P CC
V R
V
V V V
R R
V V
Maximum efficiency for PP is 78.5%.
Example 14.16: Efficiency incl. Predriver
1
2
2
2 ( )
1 4
1 1
1 1
4
P L
P L
P CC P
CC EE
L L
P
CC CC
P CC