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PDF Lecture 24 Turbulent Boundary-Layer Flows (2) - Seoul National University

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(1)

Turbulent Boundary-Layer Flows (2)

(2)

24.1 Velocity Profiles

24.2 Surface Resistance Formulas

Objectives

- Derive equations of velocity distribution and friction coefficient for both smooth and rough walls

(3)

 Relations describing the mean-flow characteristics in boundary layer

- It is useful to predict velocity magnitude and relation between velocity and wall shear or pressure gradient forces.

- It is desirable that these relations should not require knowledge of the turbulence details.

- For laminar boundary layer, it is possible to obtain a solution by integrating the equations of motion (Prandtl’s 2D boundary layers equation, Eq. (17.7)) - However, the turbulent boundary layer is composed of zones of different types of flow, and effective viscosity varies from wall out through the layer.

- Thus, theoretical solution is not practical for the general non-uniform boundary layer → use semiempirical procedure

(4)

- No single equation will describe the velocity profile over its entire thickness d.

- Close to the smooth boundary, a law of wall applies.

- For outer reaches of boundary layers for both smooth and rough walls, a velocity-defect law applies.

(5)

 Regions of inner law (wall law)

logarithmic

linear

- Inner layer might be divided into three regions

① Viscous sublayer

② Buffer zone

③ Turbulent zone

(6)

- Velocity profile is very nearly linear.

- Mean shear stress is controlled by the dynamic molecular viscosity.

- Reynolds stress is negligible, and mean flow is laminar.

- Energy of velocity fluctuation is nearly zero.

2) Buffer zone:

- Viscous and Reynolds stress are of the same order.

- Both laminar flow and turbulent flow exist.

- Sharp peak in the turbulent energy occurs.

du dy

4 u y* 30 ~ 70

(7)

3) Turbulent zone - inner region:

- Flow is fully turbulent.

- Intensity of turbulence decreases from its peak value.

- Velocity profile is logarithmic.

* 30 ~ 70 , 0.15

u y y

and d

(8)

- Outer layer might be divided into two regions.

① Turbulent zone-outer region:

② Intermittent zone:

- In the intermittent zone, flow is intermittently turbulent and non-turbulent.

0.15d y 0.4d 0.4d y 1.2d

d

(9)

- All zones merge smoothly into a continuous mean velocity profile.

- On rough wall, laminar sublayer is destroyed by the roughness elements. Overlapping region

(10)

- Close to smooth boundaries, molecular viscosity is dominant.

- Law of wall assumes that the relation between wall shear stress and velocity at distance y from the wall depends only on fluid density and viscosity.

- Dimensional analysis yields

( , * , , , ) 0 f u u y   

*

*

u u y

u f

 

(24.1)

(11)

Inner region

- A unique law of wall, Eq. (24.1), shows as a single line up to - At higher values of , a single velocity law no longer holds

because viscosity is no longer a major factor.

* 2,000 u y

*

u u u y*

(12)

- The mean velocity is

- The shear stress may be assumed constant and equal to

- Then Eq. 24.2 becomes u u

0

0 y

u u

y y

 

*

*

u u y u

0

(24.2)

(24.3)

(13)

 Thickness of laminar sublayer

- Define thickness of laminar sublayer (d' ) as the value of y which makes

(24.4)

where

- cf decreases slowly with increasing Reynolds number, Thus, increases with distance along the surface.

* * 4

u y ud

1

* 0 2 2

4 4 4 4

' / 2

/ 2 f

f

u U c

c U

d

2

0 ; .

f 2 f

c u c local shear stress coeff

Re] For the laminar sublayer in pipe flows

*

' 11.6 u d

d '

Rex Ux

(14)

- Start with equation of 2D turbulent boundary layer, Eq. (21.15a)

- In the turbulent zone of near wall region, the mean shear stress remains nearly equal to the wall shear;

2

2 2 2

0

du du du

l y

dy dy dy

  

(1)

2 2

2

' ' '

u u u p u u u v

u v

t x y x x y y

 

  0 2

' 0

' ' 0

u u u p u u

u v u v

t x y x x y y y y

- Hence a solution is obtained if we have a relation for

0

- We can use Prandtl’s mixing length theory for near wall, l y

(15)

Integrate (1)

Substitute BC [ at ] into (24.5)

Assume

Then (24.6) becomes

*

ln 1

u u y C

1

*

1 ln

u y C

u 0

u y y'

1

0 1 ln 'y C

1

1 ln '

C y

 

2

* *

( / )

' '

( / ) m s

y y C

u m s u

1 2

* *

1 1 1

ln ' ln ln

C y C C

u u

   

(24.5)

(24.6)

(24.7)

0

u*

(16)

Substitute (24.7) into (24.5)

Changing the logarithm to base 10 yields

Empirical values of and for inner region of the boundary layer,

→ Prandtl's velocity distribution law; inner law; wall law

*

2 2

* *

1 1 1

ln ln ln

u u y

y C C

u u

*

10 2

*

2.3 log

u u y

u C

0.41 ; C2 4.9

* *

*

5.6 log 4.9, 30 ~ 70 , 0.15

u u y u y y

u and d

(24.8)

(24.9)

C2 y 0.15

d

(17)

x-eq.

y-eq.

Continuity eq.:

2 2

2

' ' '

u u u p u u u v

u v

t x y x x y y

 

0 (p v' )2

y

 

u v 0 x y

(24.10a)

(24.10b)

(24.10c)

[Re] Prandtl’s turbulent boundary layer equation

Solution to these equations: u x y t( , , ), ( , , ), ( , , )v x y t p x y t

*

*

5.6 log 4.9

u u y

u

u u y( )

(18)

- In the outer reaches of the turbulent boundary layer for both smooth and rough walls, Reynolds stresses dominate the viscous stresses to

produce the velocity profile.

- It was observed that the velocity defect (reduction) at y -values was dependent on the magnitude of the wall shear stress

- A logarithmic relation for the function g can be obtained by assuming that Eq. (24.8) will give .

(24.11)

(24.12)

*

U u y

u g d

   

* '

2

*

2.3 log

U u

u C

d

u U at y d

(19)

Subtract (24.8) from (24.12)

*

2

*

*

2

*

* *

2 2

*

*

3 3

*

2.3log '

2.3log

2.3 log log '

2.3 2.3

log log

U u

u C

u u y

u C

U u u u y

C C

u

u y

C C

u y d

d

d 

d

 

   

 

3

*

2.3 log

U u y

u d C

      (24.13)

- A single log-equation does not fit the data over the entire boundary layer.

- Instead one equation will fit an inner region overlapping with Eq. (24.8), while second equation will approximate the outer region.

y d

(20)

i) Inner region;

→   0.41, C3  2.5

ii) Outer region;

→  = 0.267, C3 = 0

→ Eqs. (24.14) & (24.15 ) apply to both smooth and rough surfaces.

→ Eq. (24.14) = Eq. (24.9)

(24.14)

(24.15)

d

*

5.6 log 2.5

U u y

u d

    

 

y 0.15 d

*

8.6 log

U u y

u d

    

 

*

*

5.6 log 4.9

u u y

u

[Re] Eq. (24.12) - Eq. (24.14) = Eq. (24.9)

(21)

Wall law Velocity-defect law Smooth wall Smooth wall Rough wall

Outer region -

Inner region

Laminar sublayer

-

*

*

u u y u

*

*

5.6 log 4.9

u u y

u

*

8.6 log

U u y

u d

    

 

*

5.6 log 2.5

U u y

u d

    

  y 0.15

d

30 ~ 70 *

0.15 u y y

d

Overlapping region

(22)

 Local shear-stress coefficient on smooth walls velocity profile ↔ shear-stress equations

where cf = local shear stress coefficient

[Re] Skin drag force

*

*

/ 2

2

f

f

c U

u U

u c

 

2 0 2

0

1

2 2

f f

c U c U

0

* 2

cf

u U

(24.16)

2 0

1

f 2 f

D A A c U D Df Dp

(23)

(i) Assume that logarithmic law will give the relation Substituting into Eq. (24.8) yields

Substitute (24.16) into (A)

(24.17)

- is a function of Reynolds number for smooth walls.

- is not given explicitly.

*

4

*

2.3log

U u

u C

d

4 4

2 2.3 2.3

log log Re

2 2

f f

f

c c

U C C

c d

d

(A)

u U at y d

𝑐𝑓 𝑐𝑓

Red

(24)

(ii) For explicit expression, use displacement thickness and momentum thickness θ instead of d

Clauser:

Squire and Young:

where

*

1 3.96 log Re 3.04

cf d

1 4.17 log Re 2.54

cf

*

*

Re U ; Re U

d

d

Red* , Re f (Re )x

(24.18)

(24.19)

(24.20)

(25)

iii) Karman's relation

- Assume turbulence boundary layer all the way from the leading edge (i.e., no preceding stretch of laminar boundary layer)

(24.21)

1 4.15log(Rex f ) 1.7

f

c c

- Karman's equation is useful for ships and aircraft wings where the laminar boundary layer is insignificant.

(26)

iv) Explicit equation by Schultz-Grunow (1940)

Comparison of (24.21) and (24.22)

(24.22)

2.58

0.370 (log Re )

f

x

c

0.001 ~ 0.01 cf

(27)

 Average shear-stress coefficient on smooth walls

Consider average shear-stress coefficient over a distance l along a flat plate of a width b

1 2

( )

f 2 f

Total frictional drag D    bl C U bl

2 / 2

f

C D

bl U

U

b l

24.2.2 Average shear stress coefficient

(28)

i) Schoenherr (1932)

- Assume turbulence boundary layer all the way from the leading edge - Similar to von Karman’s equation

where

ii) Schultz-Grunow

(24.23)

(24.24)

1 4.13log(Rel f )

f

C C

Rel Ul

6 9

2.64

0.427

, 10 Re 10 (log Re 0.407)

f l

l

C

(29)

Comparison of (24.23) and (24.24)

(30)

Boundary layer developing on a smooth flat plate

At upstream end (leading edge), laminar boundary layer develops because viscous effects dominate due to inhibiting effect of the smooth wall on the development of turbulence.

Thus, when there is a significant stretch of laminar boundary layer preceding the turbulent layer, total friction is the laminar portion up to xcrit plus the turbulent

portion from xcrit to l.

Therefore, average shear-stress coefficient is lower than the prediction by Eqs.

(24.23) or (24.24).

→ Use transition formula

(24.25)

2.64

0.427

(log Re 0.407) Re

f

l l

C A

(31)

where = correction term =

- Since A is a function of , the curve in Fig. 10 is given for - For flow along smooth walls

- For laminar flow:

/ Rel

A (Recrit) , Recrit Uxcrit

f

1/2

1.328

f Re

l

C

Recrit Recrit  5 105

300,000 Recrit 600,000

(17.26)

A 1,060 1,400 1,740 2,080 3,340 Recrit 3 10 5 4 10 5 5 10 5 6 10 5 106

(32)
(33)

[Ex. 24.1] Turbulent boundary-layer velocity and thickness

An aircraft flies at 25,000 ft with a speed of 410 mph (600 ft/s).

Compute the following items for the boundary layer at a distance 10 ft from the leading edge of the wing of the craft.

(34)

① Frictional drag = surface resistance = skin drag

② Pressure drag = form drag

~ depends largely on shape or form of the body

For airfoil, hydrofoil, and slim ships: surface drag > form drag

For bluff objects like spheres, bridge piers: surface drag < form drag

(35)

(a) Thickness (laminar sublayer; ) at x = 10ft Air at El. 25,000 ft:

Find

Therefore, assume that turbulent boundary layer develops all the way from the leading edge.

4 2

3 10 ft / s

 

3 3

1.07 10 slug / ft

5

4

600( )

Re 5 10

crit 3 10

x

 

0.25 ~ negligible comparaed to 10

xcrit ft l ft

7 4

600(10)

Re 2 10

(3 10 )

x

Ux

 

*

4 u d  d

(36)

 

 

2.58 7 2.58 2.58

0.370 0.370 0.370

0.0022 (log Re ) log 2 10 (7.30)

f

x

c

2 3 2 2

0

1(1.07 10 )(0.0022)(600) 0.422 /

2 c Uf 2 lb ft

0

* 3

0.422

19.8 / 1.07 10

u ft s

4

4 4

*

4 4(3 10 )

0.61 10 7.3 10

19.8 ft in

u

d 

10 x ft

(37)

(b) Velocity at Eq. (24.1):

(c) Velocity at y / d  0.15 Use Eq. (24.14) – outer law

u

*

*

u u y

u

'

2 2 4

*

4

[ ]

(19.8) (0.61 10 )

79.7 / 13% of (3 10 )

600 /

Cf

y

u u ft s U

U ft s

d d

 

u

*

5.6 log 2.5

U u y

u d

     

 

600 5.6 log 0.15 2.5 19.8

u

 

600 91.35 49.5 459.2 / 76% of

u ft s U

y d

(38)

[Cf]

(d) Distance at and thickness Use Eq. (24.9) – inner law

* *

5.6 log y 2.5

u U u u

d

     

y y /d  0.15 d

*

*

5.6 log 4.9

u u y

u

0.15 : At y

d 4

459 19.8

5.6 log 4.9

19.8 3 10

y

4 4

19.8 19.8

log 3.26; 1839

3 10 3 10

y y

 

0.028' 0.33 0.8

y in cm (B)

(39)

Substitute (B) into

0.186' 2.24 5.7 0.15

y in cm

d

3 4

0.186

At 10': 3049 3 10

' 0.61 10

x d

d

 

' 0.0003

d d

10 ft

(40)

[Ex. 24.2] Surface resistance on a smooth boundary given as Ex. 24.1 (a) Find displacement thickness d*

Neglect laminar sublayer and approximate buffer zone with Eq. (24.14) (A)

(B)

*

0h 1 u U dy d

* /

0h 1 u y , / 1

d h

U

d d d

d d

  

    

*

( ) / 0.15, U u 5.6 log y 2.5 (24.14)

i y d u

d

 

    

* * *

1 u 5.6u log y 2.5u 2.43ln y 2.5 u

U U d U d U

     

Divide (24.14) by U

(17.4)

lnx 2.3logx

(41)

Substituting (B) and (C) into (A) yields

(C)

*

( ) / 0.15, U u 8.6 log y (24.15)

ii y d u

d

 

    

* *

1 u 8.6u log y 3.74u ln y

U U d U d

   

        

   

* 0.15 1.0

* *

'/ 0.15

0.15 1

*

0.0003 0.15

*

2.43ln 2.5 3.74 ln

2.43 ln 2.5 3.74 ln

(19.8)

3.74 3.74 0.1184

600

y u y y u y

d d

U U

u y y y y y y y

U u U

d d

d

d d d d d

d d d d d d d

   

     

 

 

lnx dx xlnxx

(42)

(b) Local surface-resistance coeff. cf Use Eq. (24.18) by Clauser

[Cf] = 0.0022 by Schultz-Grunow Eq.

*

0.1184 11.8%

d

d

 

* * 4

3

1 600 0.022

3.96 log Re 3.04 Re 44, 000

3 10 3.96 log 44, 000 3.04

2.18 10 0.00218

f

f

c

c

d d

cf

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