Turbulent Boundary-Layer Flows (2)
24.1 Velocity Profiles
24.2 Surface Resistance Formulas
Objectives
- Derive equations of velocity distribution and friction coefficient for both smooth and rough walls
Relations describing the mean-flow characteristics in boundary layer
- It is useful to predict velocity magnitude and relation between velocity and wall shear or pressure gradient forces.
- It is desirable that these relations should not require knowledge of the turbulence details.
- For laminar boundary layer, it is possible to obtain a solution by integrating the equations of motion (Prandtl’s 2D boundary layers equation, Eq. (17.7)) - However, the turbulent boundary layer is composed of zones of different types of flow, and effective viscosity varies from wall out through the layer.
- Thus, theoretical solution is not practical for the general non-uniform boundary layer → use semiempirical procedure
- No single equation will describe the velocity profile over its entire thickness d.
- Close to the smooth boundary, a law of wall applies.
- For outer reaches of boundary layers for both smooth and rough walls, a velocity-defect law applies.
Regions of inner law (wall law)
logarithmic
linear
- Inner layer might be divided into three regions
① Viscous sublayer
② Buffer zone
③ Turbulent zone
- Velocity profile is very nearly linear.
- Mean shear stress is controlled by the dynamic molecular viscosity.
- Reynolds stress is negligible, and mean flow is laminar.
- Energy of velocity fluctuation is nearly zero.
2) Buffer zone:
- Viscous and Reynolds stress are of the same order.
- Both laminar flow and turbulent flow exist.
- Sharp peak in the turbulent energy occurs.
du dy
4 u y* 30 ~ 70
3) Turbulent zone - inner region:
- Flow is fully turbulent.
- Intensity of turbulence decreases from its peak value.
- Velocity profile is logarithmic.
* 30 ~ 70 , 0.15
u y y
and d
- Outer layer might be divided into two regions.
① Turbulent zone-outer region:
② Intermittent zone:
- In the intermittent zone, flow is intermittently turbulent and non-turbulent.
0.15d y 0.4d 0.4d y 1.2d
d
- All zones merge smoothly into a continuous mean velocity profile.
- On rough wall, laminar sublayer is destroyed by the roughness elements. Overlapping region
- Close to smooth boundaries, molecular viscosity is dominant.
- Law of wall assumes that the relation between wall shear stress and velocity at distance y from the wall depends only on fluid density and viscosity.
- Dimensional analysis yields
( , * , , , ) 0 f u u y
*
*
u u y
u f
(24.1)
Inner region
- A unique law of wall, Eq. (24.1), shows as a single line up to - At higher values of , a single velocity law no longer holds
because viscosity is no longer a major factor.
* 2,000 u y
*
u u u y*
- The mean velocity is
- The shear stress may be assumed constant and equal to
- Then Eq. 24.2 becomes u u
0
0 y
u u
y y
*
*
u u y u
0(24.2)
(24.3)
Thickness of laminar sublayer
- Define thickness of laminar sublayer (d' ) as the value of y which makes
(24.4)
where
- cf decreases slowly with increasing Reynolds number, Thus, increases with distance along the surface.
* * 4
u y ud
1
* 0 2 2
4 4 4 4
' / 2
/ 2 f
f
u U c
c U
d
2
0 ; .
f 2 f
c u c local shear stress coeff
Re] For the laminar sublayer in pipe flows
*
' 11.6 u d
d '
Rex Ux
- Start with equation of 2D turbulent boundary layer, Eq. (21.15a)
- In the turbulent zone of near wall region, the mean shear stress remains nearly equal to the wall shear;
2
2 2 2
0
du du du
l y
dy dy dy
(1)
2 2
2
' ' '
u u u p u u u v
u v
t x y x x y y
0 2
' 0
' ' 0
u u u p u u
u v u v
t x y x x y y y y
- Hence a solution is obtained if we have a relation for
0- We can use Prandtl’s mixing length theory for near wall, l y
Integrate (1)
Substitute BC [ at ] into (24.5)
Assume
Then (24.6) becomes
*
ln 1
u u y C
1
*
1 ln
u y C
u 0
u y y'
1
0 1 ln 'y C
1
1 ln '
C y
2
* *
( / )
' '
( / ) m s
y y C
u m s u
1 2
* *
1 1 1
ln ' ln ln
C y C C
u u
(24.5)
(24.6)
(24.7)
0
u*
Substitute (24.7) into (24.5)
Changing the logarithm to base 10 yields
Empirical values of and for inner region of the boundary layer,
→ Prandtl's velocity distribution law; inner law; wall law
*
2 2
* *
1 1 1
ln ln ln
u u y
y C C
u u
*
10 2
*
2.3 log
u u y
u C
0.41 ; C2 4.9
* *
*
5.6 log 4.9, 30 ~ 70 , 0.15
u u y u y y
u and d
(24.8)
(24.9)
C2 y 0.15
d
x-eq.
y-eq.
Continuity eq.:
2 2
2
' ' '
u u u p u u u v
u v
t x y x x y y
0 (p v' )2
y
u v 0 x y
(24.10a)
(24.10b)
(24.10c)
[Re] Prandtl’s turbulent boundary layer equation
Solution to these equations: u x y t( , , ), ( , , ), ( , , )v x y t p x y t
*
*
5.6 log 4.9
u u y
u
u u y( )
- In the outer reaches of the turbulent boundary layer for both smooth and rough walls, Reynolds stresses dominate the viscous stresses to
produce the velocity profile.
- It was observed that the velocity defect (reduction) at y -values was dependent on the magnitude of the wall shear stress
- A logarithmic relation for the function g can be obtained by assuming that Eq. (24.8) will give .
(24.11)
(24.12)
*
U u y
u g d
* '
2
*
2.3 log
U u
u C
d
u U at y d
Subtract (24.8) from (24.12)
*
2
*
*
2
*
* *
2 2
*
*
3 3
*
2.3log '
2.3log
2.3 log log '
2.3 2.3
log log
U u
u C
u u y
u C
U u u u y
C C
u
u y
C C
u y d
d
d
d
3
*
2.3 log
U u y
u d C
(24.13)
- A single log-equation does not fit the data over the entire boundary layer.
- Instead one equation will fit an inner region overlapping with Eq. (24.8), while second equation will approximate the outer region.
y d
i) Inner region;
→ 0.41, C3 2.5
ii) Outer region;
→ = 0.267, C3 = 0
→ Eqs. (24.14) & (24.15 ) apply to both smooth and rough surfaces.
→ Eq. (24.14) = Eq. (24.9)
(24.14)
(24.15)
d
*
5.6 log 2.5
U u y
u d
y 0.15 d
*
8.6 log
U u y
u d
*
*
5.6 log 4.9
u u y
u
[Re] Eq. (24.12) - Eq. (24.14) = Eq. (24.9)
Wall law Velocity-defect law Smooth wall Smooth wall Rough wall
Outer region -
Inner region
Laminar sublayer
-
*
*
u u y u
*
*
5.6 log 4.9
u u y
u
*
8.6 log
U u y
u d
*
5.6 log 2.5
U u y
u d
y 0.15
d
30 ~ 70 *
0.15 u y y
d
Overlapping region
Local shear-stress coefficient on smooth walls velocity profile ↔ shear-stress equations
where cf = local shear stress coefficient
[Re] Skin drag force
*
*
/ 2
2
f
f
c U
u U
u c
2 0 2
0
1
2 2
f f
c U c U
0
* 2
cf
u U
(24.16)
2 0
1
f 2 f
D A A c U D Df Dp
(i) Assume that logarithmic law will give the relation Substituting into Eq. (24.8) yields
Substitute (24.16) into (A)
(24.17)
- is a function of Reynolds number for smooth walls.
- is not given explicitly.
*
4
*
2.3log
U u
u C
d
4 4
2 2.3 2.3
log log Re
2 2
f f
f
c c
U C C
c d
d
(A)
u U at y d
𝑐𝑓 𝑐𝑓
Red
(ii) For explicit expression, use displacement thickness and momentum thickness θ instead of d
Clauser:
Squire and Young:
where
*
1 3.96 log Re 3.04
cf d
1 4.17 log Re 2.54
cf
*
*
Re U ; Re U
d
d
Red* , Re f (Re )x
(24.18)
(24.19)
(24.20)
iii) Karman's relation
- Assume turbulence boundary layer all the way from the leading edge (i.e., no preceding stretch of laminar boundary layer)
(24.21)
1 4.15log(Rex f ) 1.7
f
c c
- Karman's equation is useful for ships and aircraft wings where the laminar boundary layer is insignificant.
iv) Explicit equation by Schultz-Grunow (1940)
Comparison of (24.21) and (24.22)
(24.22)
2.58
0.370 (log Re )
f
x
c
0.001 ~ 0.01 cf
Average shear-stress coefficient on smooth walls
Consider average shear-stress coefficient over a distance l along a flat plate of a width b
1 2
( )
f 2 f
Total frictional drag D bl C U bl
2 / 2
f
C D
bl U
U
b l
24.2.2 Average shear stress coefficient
i) Schoenherr (1932)
- Assume turbulence boundary layer all the way from the leading edge - Similar to von Karman’s equation
where
ii) Schultz-Grunow
(24.23)
(24.24)
1 4.13log(Rel f )
f
C C
Rel Ul
6 9
2.64
0.427
, 10 Re 10 (log Re 0.407)
f l
l
C
Comparison of (24.23) and (24.24)
■ Boundary layer developing on a smooth flat plate
∼ At upstream end (leading edge), laminar boundary layer develops because viscous effects dominate due to inhibiting effect of the smooth wall on the development of turbulence.
∼ Thus, when there is a significant stretch of laminar boundary layer preceding the turbulent layer, total friction is the laminar portion up to xcrit plus the turbulent
portion from xcrit to l.
∼ Therefore, average shear-stress coefficient is lower than the prediction by Eqs.
(24.23) or (24.24).
→ Use transition formula
(24.25)
2.64
0.427
(log Re 0.407) Re
f
l l
C A
where = correction term =
- Since A is a function of , the curve in Fig. 10 is given for - For flow along smooth walls
- For laminar flow:
/ Rel
A (Recrit) , Recrit Uxcrit
f
1/2
1.328
f Re
l
C
Recrit Recrit 5 105
300,000 Recrit 600,000
(17.26)
A 1,060 1,400 1,740 2,080 3,340 Recrit 3 10 5 4 10 5 5 10 5 6 10 5 106
[Ex. 24.1] Turbulent boundary-layer velocity and thickness
An aircraft flies at 25,000 ft with a speed of 410 mph (600 ft/s).
Compute the following items for the boundary layer at a distance 10 ft from the leading edge of the wing of the craft.
① Frictional drag = surface resistance = skin drag
② Pressure drag = form drag
~ depends largely on shape or form of the body
For airfoil, hydrofoil, and slim ships: surface drag > form drag
For bluff objects like spheres, bridge piers: surface drag < form drag
(a) Thickness (laminar sublayer; ) at x = 10ft Air at El. 25,000 ft:
Find
Therefore, assume that turbulent boundary layer develops all the way from the leading edge.
4 2
3 10 ft / s
3 3
1.07 10 slug / ft
5
4
600( )
Re 5 10
crit 3 10
x
0.25 ~ negligible comparaed to 10
xcrit ft l ft
7 4
600(10)
Re 2 10
(3 10 )
x
Ux
*
4 u d d
2.58 7 2.58 2.58
0.370 0.370 0.370
0.0022 (log Re ) log 2 10 (7.30)
f
x
c
2 3 2 2
0
1(1.07 10 )(0.0022)(600) 0.422 /
2 c Uf 2 lb ft
0
* 3
0.422
19.8 / 1.07 10
u ft s
4
4 4
*
4 4(3 10 )
0.61 10 7.3 10
19.8 ft in
u
d
10 x ft
(b) Velocity at Eq. (24.1):
(c) Velocity at y / d 0.15 Use Eq. (24.14) – outer law
u
*
*
u u y
u
'
2 2 4
*
4
[ ]
(19.8) (0.61 10 )
79.7 / 13% of (3 10 )
600 /
Cf
y
u u ft s U
U ft s
d d
u
*
5.6 log 2.5
U u y
u d
600 5.6 log 0.15 2.5 19.8
u
600 91.35 49.5 459.2 / 76% of
u ft s U
y d
[Cf]
(d) Distance at and thickness Use Eq. (24.9) – inner law
* *
5.6 log y 2.5
u U u u
d
y y /d 0.15 d
*
*
5.6 log 4.9
u u y
u
0.15 : At y
d 4
459 19.8
5.6 log 4.9
19.8 3 10
y
4 4
19.8 19.8
log 3.26; 1839
3 10 3 10
y y
0.028' 0.33 0.8
y in cm (B)
Substitute (B) into
0.186' 2.24 5.7 0.15
y in cm
d
3 4
0.186
At 10': 3049 3 10
' 0.61 10
x d
d
' 0.0003
d d
10 ft
[Ex. 24.2] Surface resistance on a smooth boundary given as Ex. 24.1 (a) Find displacement thickness d*
Neglect laminar sublayer and approximate buffer zone with Eq. (24.14) (A)
(B)
*
0h 1 u U dy d
* /
0h 1 u y , / 1
d h
U
d d d
d d
*
( ) / 0.15, U u 5.6 log y 2.5 (24.14)
i y d u
d
* * *
1 u 5.6u log y 2.5u 2.43ln y 2.5 u
U U d U d U
Divide (24.14) by U
(17.4)
lnx 2.3logx
Substituting (B) and (C) into (A) yields
(C)
*
( ) / 0.15, U u 8.6 log y (24.15)
ii y d u
d
* *
1 u 8.6u log y 3.74u ln y
U U d U d
* 0.15 1.0
* *
'/ 0.15
0.15 1
*
0.0003 0.15
*
2.43ln 2.5 3.74 ln
2.43 ln 2.5 3.74 ln
(19.8)
3.74 3.74 0.1184
600
y u y y u y
d d
U U
u y y y y y y y
U u U
d d
d
d d d d d
d d d d d d d
lnx dx xlnxx
(b) Local surface-resistance coeff. cf Use Eq. (24.18) by Clauser
[Cf] = 0.0022 by Schultz-Grunow Eq.
*
0.1184 11.8%
d
d
* * 4
3
1 600 0.022
3.96 log Re 3.04 Re 44, 000
3 10 3.96 log 44, 000 3.04
2.18 10 0.00218
f
f
c
c
d d
cf