CO
2PSA
* * †
*
(2000 2 1 , 2000 9 18 )
Effect of Evacuation and Rinse Conditions on Performance in PSA Process for CO
2Recovery
Hawung Lee, Jae-ho Choi*, Yeong-Koo Yeo*, Hyung Keun Song and Byung-Ki Na†
Clean Technology Research Center, KIST, Seoul 136-791, Korea
*Dept. of Chem. Eng., Hanyang University, Seoul 133-791, Korea (Received 1 February 2000; accepted 18 September 2000)
& "'( ) *+ ,- ./- %. 01 23 4567 89 : ;<) =>, ?@A BC" ; 4D) E ! F 4D 0G 45 H I $%. J- => 45 2345K LM67 "# & ! NO * 2P23
Q D RS%. => T 6 U CO2 V T67 '(W% XD9 T Y 8& W$
<Z, => [\ ] T67 :^ '( T8& _` a<) bcd%. & =>23 0G NO ?@A efg h i D RS%.
Abstract−The effect of evacuation and rinse step on the process performance was studied using numerical simulation to recover heavy component in a PSA process. Rinse and evacuation steps are very important to obtain heavy component as a product. Therefore, to improve the process performance, the rinse pressure, reflux ratio and flow direction of rinse step were selected as variables, and the performance change of process according to changing variables was investigated. The effect of eva- cuation condition combined with the rinse condition was studied also. As a result, the optimum operating condition was obtained to have maximum process performance. Increasing rinse pressure conduced to increase the recovery by increasing adsorbed amount of CO2 during the rinse step. Decreasing evacuation pressure contributed to increase the purity by increasing desorbed amount of CO2 during the evacuation step. At this point, the optimum reflux ratio was existed at certain pressure conditions.
Key words: CO2, PSA, Rinse, Evacuation, Simulation
†E-mail: nabk@kist.re.kr
1.
PSA 1957-1958 Skarstrom
[1, 2] . PSA !
" # $% &' ()* +,-%. #/0 1
1950& 234 5 6 . 7 &8-9 : 9 Skarstrom cycle ;, cycle <= ' > ?=
' @ A <= BC :-%. 3DE%.F PSA GH#I; J" $[2]. 1960& 23KL 6
M PSA NH #/ , 1980& OP
QRSG, T SG > USG* V W ()* XY Z[\ T ] . ^_ OP `<=a CMb. c%d ()*
[3, 4]. m XnP o p qr O s > t u vN w' ()* T] .
QRSG Skarstrom cycle xy w z{%. V | S G. Berlin [5] 0 SG G- }~
CMb. c w' QRSG RSG
1 b <=@ A ! CMb " J 6
q" vN#I 5 '[6].
T SG , z{ <=a CMb. c w'
38 6 2000 12
`<=a <=@ A P BC Pd~ BC
%. V [7]. ' T SG BC 5 `<=a C Mb. A 5. r P, `<=a CMb. c w'
6-9 SG. " .
+ () -%. USG `<=a CMb . c wJ V0 SG. z{ USG *R-<=-R-H
4SG : <=SG { ] ;, <=SG"
`<=a <=0 @ # `<=a P%. @
" `<=a. H#I, P RSG CMb c %.
P¡[2]. `<=a 6" w' USG ¢t 9£
P p % SG ¤¥ xH ¦§ ^-H () ¨l ©O. + () ª]() « [6] (*¬.
KL `<=a9 CO2" CMb. c USG "
®$. ¯° USG V%. q* 20%N vN ±" c 6 . ²' USG ¤¥ xH"
tu XY vN#³ 6 { ´f, ¦4 + () U
SG ¤¥ xH#µ *W ¦§ tu xH" M¶p"
sE%.F tu ^&H#³ 6 USG ¤¥ ¨
· ¸-%. $. m E¹ ?=Rº > r»¼*
tu ´½ ¾v E¹ ®$.
2.
+ () -9 USG ¾v wJ 8SG.
)t0 &N ¿$. &N *R, <=, R, T ?
=SG. PT qr QRSGm USG" À*' .
&N UK SG { Á )t P%f ª]()[6]"
cPT ^- Â. )t$.
(1) *RSG (2) <=SG (3) û RSG (4) û Ry QRSG (5) *R USG (6) R USG (7) T ?=SG (8) v» *Ry QRSG
USG* e K%. ÄP T 1, QRSG" ½W @ A
Rº NR . ÅP~Æ Ç.(0.55 atm) Ctb J
" NRÈ~ Éd: Ê* 7°. &'
" Ë wJ Fig. 1 ¤Ì q" ÍA ¶£" . <=
Rº 1.5 atm, QRRº 0.55 atm%. $%f, Ur»¼
¾v l wJ Ur»¼ 0.6, 0.65, 0.7, 0.75, 0.8, 0.85 Î
Rº 1.0, 1.15, 1.3 Î 1.5 atm 4*~ . ÄP
s$.
U ¤¥ xH ¦§ tu Ïl wJ e US G" J *~ . UJ s$. ¤Ð5 6
6 J *~* ~Ñ + () U ¤¥%. U v
U Rº xH#µ Ò ¤¥ tu M¶p"
J ¼Ó$.
ÔÕ *R USGm R USG Ö× v ¦§ ¾v
dW { 4*~ . ÍØ 6 .
(1) û *Ry USG, û Ry USG (2) û *Ry USG, v» Ry USG (3) v» *Ry USG, û Ry USG (4) v» *Ry USG, v» Ry USG
{%. Ur»¼ ¦§ tu xH" Ù' %. Ú_
J s$;, URº ?=Rº ¦4 tu PÛÆ Ü 4~*" ¼Ó$. Ý ?=Rº 0.1R 0.05R, URº
1R 1.5R%. ªÞJ " ¤ÐJ { 4*~ ¤¥%.
s #$.
(5) ?=Rº 0.1R, URº 1.0R (6) ?=Rº 0.05R, URº 1.0R (7) ?=Rº 0.1R, URº 1.5R (8) ?=Rº 0.05R, URº 1.5R
m Á ¤¥%. r»¼ ¦§ tu s' ß URº
?=Rº ¦4 r»¼* ´½ ¾v " 1%. àá
7°. + () ÔÕ ?=Rº URº 1R9 (5)
¤¥ â%., (1) (4) ¤¥ ¦§ U v " s ' 2 ^- Ö× v ªÞ$. " Â. (5) (8)
m Á U > ?=Rº ¦§ tu s 6]$.
+ () ¸- PSA tu vN w' ¤¥ ¨A 1Ç. PSA tu &' * ã ¢. PSA
ä' ¯°å æç èÆ tu ;, + ()
*é 3-%. p " p$%f qm 6
e *~" ê* â%. $. q CMb oB
CO2 êQ . $, 6 ßV0 CO2 Ù &
' cPT CO2 Ù%. $. USG* V ~ ë
T SG ì ¶í CO2" 60 CO2. ~Ñ, US G* V T SG 60 CO2 Ù U
b. 0 CO2" î GM'. ²' USG ¢' x69 Ur»¼ USG V ï CMb ï%. ð 1%. $.
GM0 ±O Ïl ñÆ ÍA wJ tuê*òª
$. tuê*òª ßï ¦§ 6 q xH" ÍA 1%. òª ó* ô õ§ö NS%. ½÷6ø t u X ù 1 ´Æ 0. + () tuê*òª
#" wJ !ú ßï 7.6, 10, 15, 20 SLPM9 &
J GM$.
Fig. 1. Flow schedule of PSA process.
PR: Pressurization, AD: Adsorption, CD: Countercurrent depressur- ization, PE: Pressure equalization, RN: Rinse, EV: Evacuation
3.
+ () ¶p" ^ tu û USG ¤¥ ¨
Aü 7° { Á ¶ý ¶p $.
PSA &' ba 6~£, <= êy£, baÜ£, }~ 6
~£ J ¶ýþE%.F ´ ª0 &N O s$.
¶ý£ ã x6O ÿ´ y. (G P P ¶p N
' Pdi :Æ 0. ¦4 N ÀP C5 K
¿J M¶p ñÆ Ú_ø $. (*¬ ¤t
N2(79-84%), CO2(12-17%), O2(4%), Î ´ï SO2, NOx.
P % , SO2, NOxt > O2 CO2 - ¾v
{%. #, N2m CO2 tG. l ¶p" #
$[8]. SO2, NOx Î Ù N&-%. ã / <=. Zt
<= tu Æ ¾v :~ ë%f, O2 Zt p' êy<= <=ta N2m ã
ßpÆ Í * â[9]. ²' N
N. GM$%f, @ ¼ v
J @ A Rº` ¾v { Ï 6 %
f[9], ì ¦§ x6O \ Cp, ρ ¤Ìw xH*
t ¾v :~ ë æ:$. ó @ A <= ¶p; P @ A" SN4 *$
[10, 11],N <=N p baÜ Linear Driving Force(LDF) model ¦èf Ðb <=êy Sqé¶ý(Extended Langmuir
Isotherm model) ¦è 1%. $. ¶ý£O W {
Á[6].
Overall mass balance:
(1)
where
Mass Balance of i-component:
(2) Energy Balance:
(3)
Mass Transfer Rate:
(4)
Cim ÒÒ N <=N f u ª, ρbulk N , ε <=@ A . Cpgm Cps ÒÒ
m <= ï, ρg Ðb , ∆Hj Ò t <=
. <= Clausius-Clapeyron £ J GM$. ba
Ü£ ki baÜG6f, CO2m N2 Zt ¶e <=
Ç. N&-9 k ã ¢' ´" *T. + () p0 k CO2 0.2 s−1, N2 0.015 s−1$. GM
w' äG£ # ! $~Ñ[2] £%.KL cPT ba
¦èÇ. + () 6]J cPT òª
J baÜG6" _p##. qi* <= 8W <=0 êy<=
ï ´ extended Langmuir isotherm J GM$.
w ÿ´£ $ w -%' ¤¥ G¤¥ : Pü '. Ò SG &' ¤¥ SG ± ½
G¤¥ Ò SG ¦4 Table 1 Í& ¤¥ Ñ''[13].
J P(t) pressure history" ´; PSA ¶p ¢' ¤
¥Ç. b- N ½ø _p#I 1 ¢. E 6 3-%. ~6E6. _p#³ 6 %f { Á #æ
&' ô6 y" ([3].
(5) where
P0m Pts ÂRº ^Rº ÍAf, γ P0m Pts ¼"
´. ²' G6 a Rº)) *Ñ' " ÍA +.,
Ò SGå § *T. 3-%. *RSG MFC(mass
flow controller) ï ¤% P ßV Ç. Î ó* *
ÑÆ ß~* 0. Î RSG ¼ªyt , 1%. àN P *RSG # 1.1, RSG # 0.99" p$. ²' T SG T -. ï äG Ç. 0.8 p$. J p0 ¤ ÌRº <=Rº 1.5 atm, ?=Rº 0.05 atm, RRº 1.0 atm, RºQH Rº ?=Rº RRº æRº, Î USG RºQHRº URºÈ~ ¤Ì P~ #æ ~ W R N. USG" ß~Æ 0. ²' + () GM
w p0 <=@ <= &' t ¤Ì¤¥ Table2
%f[9], ¶p p0 ¢ ãx6O Table 3
.
w 0 ¶ý£O PSA ¶p w # $P ü ; b-9 N dJ { Á q. q/-%.
$$. ÔÕ £ (4) <=£ GM' 2 Î ±
∂(uCtotal)
∂z
--- ∂Ctotal ---∂t ρbulk
--- ε ∂qi
∂t ---=0
i=1
∑
n+ +
Ctotal Ci
i=1
∑
n=
∂Ci --- u∂t ∂Ci
∂z --- Ci∂u
∂z --- ρbulk
---ε ∂qi
---∂t=0, i= ,1…, n
+ + +
ερgCpg+ρbulkCps
( )∂T
---∂t (ερgCpg)u∂T
∂z
--- ρbulk ∂qj --- H∂t∆ j
j=1
∑
n =0+ +
∂qi
---∂t =ki(qi*–qi)
qi
P t( )=C0+C1exp(–C2t) C0=aPts.
C1=P0–aPts C2 (1 a– )
γ–a
( )
--- ⁄ts ln
–
=
Table 1. Boundary conditions of each step
Step Concentration Temperature Pressure Velocity
Pressurization yi(t, 0)=yf,i T(t, 0)=Tfeed P=P(t) u(t, L)=0
Adsorption yi(t, 0)=yf,i T(t, 0)=Tfeed P=PH u(t, 0)=ufeed
Blowdown P=P(t) u(t, 0)=0
Evacuation P=P(t) u(t, L)=0
Pressure equalization Depressurized yi(t, L)=yEq T(t, L)=TEq P=P(t) u(t, 0)=0
Pressurized yi(t, L)=yEq T(t, L)=TEq P=P(t) u(t, 0)=0
Rinse Pressurized, cocurrent yi(t, 0)=yproduct T(t, 0)=TEv P=P(t) u(t, L)=0
Constant pressure, cocurrent yi(t, 0)=yproduct T(t, 0)=TEv P=PRn u(t, 0)=uOR2
Pressurized, countercurrent yi(t, L)=yproduct T(t, L)=TEv P=P(t) u(t, 0)=0
Constant pressure, countercurrent yi(t, L)=yproduct T(t, L)=TEv P=PRn u(t, L)=uOR2
38 6 2000 12
J £ (1) 0g" GM'. 1Æ GM0 ± O J
£ (2) t6~£ £ (3) }~ 6~£ GM$. PSA J SG" 2 h Ç. -9 finite difference method(FDM)" M %. $. \ convection ¾v
, FDM *~ t °" D w b-9 N
dJ / upwind method" -%\ J ¶p$
[6, 13-15].
4.
4-1.
USG U Ö× v &' " Ïl w
J ÔÕ &N Ö×v &' 3 *~ [(1)-(4)]
& ¼Ó" ]$. 7 <=Rº 1 atm, ?=Rº 0.1 atm
. ±" ÒÒ ßï ¦4 ¼ÓJ Fig. 2 ÍA.
Î4 l5 v» Ry USG" ' tu ±
U v ´½ ¾v -%. lJâ 6
. Ý, v» Ry USG U 5 ~ 7 1%
. 8 6 . ' 6 q" c w <=#æ
> U#æ ¤%ü ;, USG @ AK" CO2. *
\ H w N' #æ ¢4 àá0. ï
6 c w U#æ / Æ 5 6 %Ç. U
b OP* vKL H9 6: . ¦4 û. U
<=@ Ub OP* K CMb A K
Ç. H0 @%.KL CMb c 6 % , v
». U ?=0 N2. õ;0 K%. CMb Æ <
%.F U/ ~ ë 1 å=*~ " cÆ 0. ¦
4 6 q ¶e* USG" V~ ë ±m
¼> ¤? Æ @ 8 6 . ²' v» *Ry USG ßï / 7 û *Ryl q* ÅP~~Ñ ßï
Æ W v Nä tu A 8 6 . !ú
ßï ~Æ W l CMb CO2 q* ~Æ Ç . U# CMb CO2q* ~Æ ¦4
q CMb. v» *R Æ P [C N4 JBT
. T SG v v». $ 7° Uv ¶e û
. 1 tu vN#I; *é -4 ±" c.
¦4 C%. ¶pÆ &N ¶e û*Ry U Ã
» Ry U J )t0 Â. Æ 9 1.
4-2.
C% Dô' "m Á U v ' N URº
¦§ tu ¼Ó$. URº PSA tu ´½ ¾v Fig. 3 ÍE 1 Á. Î4 ?=Rº 0.1R, r»¼* 0.759 URº ¦§ qm 6 Í& Î 4%., URº 6ø qm 6 vN P tuê*òª
á NS%. E 8 6 . USG*
´½ ¾v d 8 7 (' ±. OJT. Ý, US G CMb r»#µ @ A CMb " F*#G%. q
CMb c " *õ;, ' CO2m N2 êy<=ï / [C'. êy<=ï N CO2
m Rº ± ;, ' CO2 ¤t , Rº
Éd:W l CO2* <=9 6 . <=ìª%.
àá5 6 ±. Fig. 4 Í& <=ìª lW, Rº
F* ¦4 <=ï ~ 1 8 6 ; U
CO2 !ú CO2 m Ü q H Æ Table 2. Characteristics of adsorption bed and operating conditions
Adsorbent Particle size [mesh]
Feed gas composition Bed diameter [mm]
Bed height [mm]
Adsorbent amount [kg]
Bed bulk density [g/cm3] Bed porosity, ε
Heat capacity of adsorbent, Cps [J/g/K]
Heat capacity of gas, Cpg [J/g/K]
Adsorption pressure, PH [atm]
Evacuation pressure, Pev [atm]
Equalization pressure, Peq [atm]
Time for adsorption [s]
Time for blowdown [s]
Time for pressure equalization [s]
Time for rinse/evacuation [s]
Activated carbon 8-12
17% CO2, in N2 41.2
900 0.57 0.47 0.4 1.05 0.9942 1.5 0.1 0.55 300 20 20 360
Table 3. Langmuir parameters and heat of adsorption used in the cal- culation
Parameter CO2 N2
t1*[mmol/g]
t2*[mmol/g]
t3**[atm−1] t4**[K]
∆H [kJ/mol]
23.944
−0.0517 2.1265×10−3
1588.315 24.103
7.052
−0.0106 4.2169×10−4
1680.038 16.928
*qm=t1+t2T
**b=t3 exp(t4/T)
Fig. 2. The effect of flow directions on rinse step.
Case (1): cocurrent pressurization by product, cocurrent pressurized rinse, Case (2): cocurrent pressurization by product, countercurrent pressurized rinse, Case (3): countercurrent pressurization by product, cocurrent pressurized rinse, Case (4): countercurrent pressurization by product, countercurrent pressurized rinse(Reflux ratio=0.75).
Ç. <=@ A <=5 6 CO2 Ù ~Æ 0. CO2 R J :Æ P Ctb. c 6 <=0 CO2 * F*4 1 àá5 6 . URº k Rº%
. ¿5 , ÒÒ Î Rº êy<=ï tu
±0. ' v Fig. 3 Ò URº ¦§ tuòª
æ, 8 6 . Ý, 1R 1.15R, 1.3R%. UR º ÉI 7 tu / Æ NJ* êy<=ï /
* l F* 1.5R q* NJ 1%. Í K. 6 å=*~. URº NJ E¹ F*
v ÍA. Á Ù CMb r»## , Rº
l CO2* <= Ç. RUSG )L CO2
Ù POÆ 0. ¦4 6 ¤?ç NJ v *
ì 6.
N URº F*#IW 3-%. tu vN#³ 6 { Ï 6 . Î Î4 ' *~ ' pM [N5 6 ; URº F* ¦§ tuê*òª ó. ß ï 6ø q* F* N lÿ-%. PSA Í
v. <=SG <= CO2 Ù ßï /
7l , 7 ~ 7°. <=SG <=0 CO2* J
SG" 2 P CMb. õ 1Ç. Á <=#
æ * P ~ ë w A ßï , * <=
0 CO2 Ù F*#µ q" XY / '. URº
1.5R 7" lW, ßï / w ßï ¦§ q
xH* § URºm ¼>' v%. F* 1%. ÍK
% ßï O~W òª l *ÑÆ F* v lJ:
. USG <=@ #æ o 14 C Ò0. 6 , URº * P Rºl Î /* F* v Í· Ï 6 . # Q URº
6ø ßï ¦§ q / PO 6 / R P ±" c 6 . PSA" ¤ÌE P ¢'
l" ±. <=@ S¶* ~W ßï ¦§ ^ - U¤¥ ±0 p. URº F* q > 6 F*" 3~Ñ URº F*56ø ¢ N ßï F* q vN ¦§ Tl 6 * X O
~ 7° õ\d tu " *õÆ 0. 9dW JU 3D ±5 6: . Î
¶p" ñÆ 95 6 { Ï 6 .
4-3.
Î1W U ' URº T Ur»¼
¦§ tuê*" #$. &' tuê*òª Fig. 5 Í A. Î4 l5 Ur»¼* F*56ø q* G NJ
v%. T]< Ï 6 . r»¼* 0.89 È~ r»¼
F* ¦4 q Õ\ NJ % 6
{ 8 6 . ²' Ur»¼ ¦§ tu xH ÀU ßï
Nä ' v *~ { 8 6 . Î
Ur»¼* 0.85N9 ßï F* äG ' q" ß~J, q F* ¼ 6 * ÕE 8 6 . Î4 r»¼ 0.85 7l 0.9 7* q 1% * ï ÍA 6 Ò ßï P 10% N Õ\
E 8 6 . l )-%. Ur»¼ ¦§ ¾v Ï
l wJ qm 6 ÒÒ r»¼ & Í& Î4
Fig. 6 7. Ur»¼* F*E ¦4 z{ ô. q*
Fig. 3. The effect of rinse pressure at PEV=0.1, R=0.75.
Fig. 4. Equilibrium adsorption isotherm of CO2, N2 and O2 on activated carbon at 25oC.
Fig. 5. The performance curve of the Case (5), PEV=0.1 atm, PRN=1.0 atm.
38 6 2000 12
NJ v l , Ur»¼ 0.8-0.85 p ó* *Ñ
~ #/ v%. "V 8 6 . ²' ~KL ß ï äG q* Æ NJ< Ï 6 . 6
Ur»¼ 0.8 *ÑÆ v ~W 0.8
N ô,\ ÅP~ ÙN *X. ¦4 + () p
' ?=Rº 0.1R, URº 1R 7 Ur»¼
" 0.8N%. ¤Ì 1 6 áW n Q5 6 . m Á ± ßï 10 SLPM U#æ YÁ 190 Â. Ur»¼" xH#³ , 0.8K_ * P
´'. ¦4 Ur»¼ # ^- oBf, Z M¶p" J ñÆ ¨ 6 1 Ï 6 .
4-4.
w ¿[$5 URº r»¼ ¦4 tu ^-
oBÆ 0. Î1W U e *~ m ?=Rº
xH" # ¼ÓJ ^- tu *~ ¤Ì ¤¥ ¨%d
'. " wJ &N ¿' ?= > URº ¦§
4*~ " s' ±" ÒÒ ¼Ó$; " Fig. 8 ÍA
. 4*~ 3-9 v q Ur»¼
F* ¦4 G-%. tu F* ÀU" l9 1 6
^- Ur»¼* oB' 1. Î4 Ò ò ª 3 õ§öKL ßï ÒÒ 7.6, 10, 15, 20 SLPM9
" Í&.
URº ?=Rº xH ¦§ 3 *~ P (5)m (6)
" ¼ÓJ ?=Rº ' ¾v ÏlW, T SG
?=Rº P~ , l Ù ?= P qm 6
J :Æ 0. ¦4 (6) * (5) l ù tu l 9. mÁ v Fig. 8 (c)m (d) å=*~. Í ; e Î4 # ?=Rº P ù tu l .
*h; ' *~ ' ?=Rº URº F*
l q X ¾v â p. #Q, Fig.
8 lW (a)m (b) Î (c)m (d)" ¼Ó5 7 (a)m (c), (b)m (d)
l q NJ l ÕE 8 6 . ?=Rº
PÀW ¼Ó- P r»¼ q Ctb c 6 {
lJ: 1. ' p, ?=Rº PL ?=ï
F* ¦4 6ï RP Ç. Á Ur»¼4 U#
ßV r»ï * RP Æ <%.F Í N%. 8 6 .
3W URº F*, ?=Rº ' m ¼Ó\ 7, w m 3&. q F*l 6 F** U p Ï 6 . Á ?=Rº URº xH" ]^lW, Fig. 8
(a)m (c), Î (b)m (d)" ¼Ó8 7, 6 Õ\ F*
N 8 6 . , URº J:W 3-%. 6
F*' p lJ: . ' N U Rº J
%.F <= CO2 Ù F*Æ P #æ _~Ç.
PE ±. 8 6 . URº 1.5R9 6
C Dô' "m Á ^- *~Æ ; Fig. 8 (c)m (d)
r»¼ F* P` #È~ 6 F*" 3Æ
<=@ # 2 a 6 ÅP~ N
ÍAÆ 0. Ý r»¼* P ¾ r»¼ F* ¦4 ô,\ F* 6 *Ñ\ F* 1. 7 ^&
oBf ^& 2 r»¼ q F* P~ 3&. 6 ô,' " ÍAÆ 0. r»¼* P
¾ 6 F* ß URº , U#
CO2 <=ï F*. cP~ 6 F* * r»¼ F*
' 6 ' l 7°%., U#æ <=
@ *\ #È~ q F*m E¹ æ 6
F** Í 1[16].
²' URº * P l r»¼ F* ¦§
p Ï 6 . Ý, NR U ßï xH ¦§ q
xH* b òª ó" Ï 6 . Î URº
1.5R9 òª ó* *Ñ ßï F* ¦4 q
xHï /A Ï 6 . ßï ¦§ q NJ /
~ N ¤Ì P URº V ßï J ¤Ì 1 6 W ß' vk ´'
. " cX Ïl ñÆ ÍA wJ ?=Rº 0.05R
, ßï 7.6 SLPM9 m 20 SLPM9 " ¼ÓJ qm
6 Fig. 9 ÍA. Î4 8 6 "m Á UR º r»¼ ¦§ 6 ^& Í Æ
; N r»¼ ´ <=@ H#IÆ P õ\d tu
Fig. 6. The effect of reflux ratio on the purity in the Case (5), PEV=0.1 atm, PRN=1.0 atm.
Fig. 7. The effect of reflux ratio on the recovery in the Case (5), PEV= 0.1 atm, PRN=1.0 atm.
" *õÆ 0. ' N ßï P * l
\ Í ; ßï / * 6 W de ßE
Ï 6 .
C Dô' "m Á ?=Rº m URº F* '
b-%. . § [CÆ 0. Ý,
?=ï F* U# Ub Ù C
2 <=ï F* U# <=ï C
. ' ß* ?=Rº $ 7l URº
F*#I * r»¼ F* ¦§ q xHï O~ ! 9 1.
±-%., URº F* ?=Rº ¶e r»¼"
#³ 6 " *õÆ ; qW ?=Rº PÀ 1, 3&. 6 W URº 1 l
-k Ï 6 . f-%. e *~" ¶e -5 6 Fig. 8. Comparison of the performance curves at different rinse and evacuation conditions.
(a) PEV=0.1 atm, PRN=1.0 atm; (b) PEV=0.05 atm, PRN=1.0 atm; (c) PEV=0.1 atm, PRN=1.5 atm; (d) PEV=0.05 atm, PRN=1.5 atm. : reflux ratio=0.6; :
reflux ratio=0.65;: reflux ratio=0.7; : reflux ratio=0.75; : reflux ratio=0.8; : reflux ratio=0.85; : reflux ratio=0.9.
Fig. 9. The effect of feed flow rate on the purity and recovery at PEV=0.05 atm.
(a) feed flow rate: 7.6 SLPM; (b) feed flow rate: 20 SLPM
38 6 2000 12
W *é ù ¤Ð , Î 7 ¤¥ r»¼" 1
tu vN i ~ ë p Ï 6 . r»¼ ¤Ì ¤¥ ¦4 ^- oBÆ Ctb q g 6 ! ö ªÞJ ^- ¤¥ ªü 5 1.
+ () U Rº 1R 1.5R%. J: 7m
?=Rº 0.1R 0.05R%. PÀ 7, o NRUS G" c 6 | 6l ^& U ) N 6 NJ
c 6 ;, r»¼ ¦§ ^- 6 o B' p 95 6 . 6½-%. lW, 7.6 SLPM ß ï NRU > 0.1R ?=Rº 0.9 r»¼"
J c 6 q" c w, ?=Rº 0.05R%. P ÀP : 7 r»¼" 0.8. PL 6 " c 6
%f 7 6 e ) F*$. 3&. URº 1.5
R%. r»¼" # 0.8. PL 6 %f 7
6 2.5)* F*$. e *~ " ¶e -'
r»¼" 0.75. PL 6 %f 6 3)È~ F*$
. + () ' S¶ é½" 5 7, *é ù ¤Ì ¤
¥ 0.05R ?=Rº 1.5R URº 0.75 r»
¼" J P ßï%. ¤Ì 1 -%. *é 6E
95 6 .
5.
`<=a9 CO2" Ctb. c w' PSA ^- ¤Ì¤
¥ ¨ w 2ü 3D , ¶p" ^-¤
¥ ¨ w' ¸-%., tu vN#I; 6-9 SG9 U > T SG ¤¥ ¦§ ¾v s$. &N Zt <=. ', RºQHm USG* E0 qr %.
F USG > T SG ¤¥O xH#µ*W tu xH"
¼Ó$. USG Rº F* U# <=ï F*#µ Ctb 6 F*#h p 95 6 %f 7 r
»¼ F* È~ ô,' q NJ%. ÍK. ?=
Rº ?=ï F*#µ r»# ßï F*#I "
*õf ô,' q vN%. ÍK. ¦4 e *~
¶e USG r»¼" 6 . /f 7
^- tu c r»¼* oBE 9$. ¦4 " i
¤ÐJ <=@ A ¤Ì PTW *é ^-
¤Ì¤¥ c 6 { Ï 6 .
+ () 'j º()! ~! k 6] %f p lmW.
bi : Langmuir parameter [atm−1]
Ci : gas concentration of component i [mol/cm3] Ctotal : total gas phase concentration [mol/cm3] Cps : heat capacity of adsorbent [J/g/K]
Cpg : specific heat of gas mixture [J/g/K]
∆Hi : heat of adsorption of component i [KJ/mol]
ki : overall mass transfer(LDF) rate coefficient of component i [s−1] L : bed height [cm]
qi : amount adsorped of component i on the solid phase [mol/g]
q*i : amount adsorped of component I in equilibrium with gas phase [mol/g]
qm : langmuir parameter [mol/g]
t : time [s]
t1 : Langmuir parameter [mol/g]
t2 : Langmuir parameter [mol/g]
t3 : Langmuir parameter [atm−1] t4 : Langmuir parameter [K]
T : temperature [K]
To : feed temperature [K]
u : interstitial gas velocity [cm/s]
ufeed : interstitial velocity of feed gas [cm/s]
uOR : interstitial velocity of rinse gas [cm/s]
yEQ,i : mole fraction of component i fed in pressurized equalization step yf, i : mole fraction of component i in gas mixture
yProduct,i: mole fraction of component i fed in rinse step ρg : density of gas mixture [g/cm3]
ρbulk : bulk density [g/cm3] ε : bed porosity [-]
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