DOI 10.4134/JKMS.2009.46.3.561
WEAK AND STRONG CONVERGENCE THEOREMS FOR AN ASYMPTOTICALLY k-STRICT PSEUDO-CONTRACTION
AND A MIXED EQUILIBRIUM PROBLEM
Yonghong Yao, Haiyun Zhou, and Yeong-Cheng Liou
Abstract. We introduce two iterative algorithms for finding a common element of the set of fixed points of an asymptotically k-strict pseudo- contraction and the set of solutions of a mixed equilibrium problem in a Hilbert space. We obtain some weak and strong convergence theorems by using the proposed iterative algorithms. Our results extend and improve the corresponding results of Tada and Takahashi [16] and Kim and Xu [8, 9].
1. Introduction
Let H be a real Hilbert space and let C be a nonempty closed convex subset of H. Let ϕ : C → R be a real valued function and Θ : C × C → R be an equilibrium bifunction, i.e., Θ(u, u) = 0 for each u ∈ C. Now we concern the following mixed equilibrium problem (MEP) which is to find x ∗ ∈ C such that (MEP) Θ(x ∗ , y) + ϕ(y) − ϕ(x ∗ ) ≥ 0, ∀y ∈ C.
In particular, if ϕ ≡ 0, this problem reduces to the equilibrium problem (EP), which is to find x ∗ ∈ C such that
(EP) Θ(x ∗ , y) ≥ 0, ∀y ∈ C.
Denote the set of solutions of (MEP) by Ω and the set of solutions of (EP) by Γ. The mixed equilibrium problems include fixed point problems, optimiza- tion problems, variational inequality problems, Nash equilibrium problems and the equilibrium problems as special cases; see, e.g., [1, 3, 4, 10, 22]. Some methods have been proposed to solve the equilibrium problems and the mixed equilibrium problems, see, e.g., [2, 5, 6, 7, 10, 12, 14, 15, 16, 17, 18, 19, 20, 21].
Received August 25, 2007.
2000 Mathematics Subject Classification. 49J30, 47H10, 47H17, 49M05, 90C25, 90C99.
Key words and phrases. mixed equilibrium problems, fixed point problems, iterative al- gorithm, asymptotically k-strict pseudo-contraction, Hilbert space.
The first two authors were supported by National Natural Science Foundation of China Grant 10771050 and the third author was supported by the grant NSC 97-2221-E-230-017.
c
°2009 The Korean Mathematical Society
561
On the other hand, recently, Kim and Xu [8, 9] introduced some itera- tive methods for solving fixed point problems of asymptotically nonexpansive mappings and asymptotically k-strict pseudo-contractions, respectively. The corresponding iterative algorithms are as follows. The first one introduced in [8] is:
(KX1)
x 0 ∈ C chosen arbitrarily, y n = α n x n + (1 − α n )T n x n ,
C n = {z ∈ C : ky n − zk 2 ≤ kx n − zk 2 + θ n }, Q n = {z ∈ C : hx n − z, x 0 − x n i ≥ 0}, x n+1 = P Cn∩Q
nx 0 ,
where T : C → C is an asymptotically nonexpansive mapping and θ n = (1 − α n )(k 2 n − 1)(diam C) 2 → 0 as n → ∞. And the second one introduced in [9] is:
(KX2)
x 0 ∈ C chosen arbitrarily, y n = α n x n + (1 − α n )T n x n ,
C n = {z ∈ C : ky n − zk 2 ≤ kx n − zk 2
+ [k − α n (1 − α n )]kx n − T n x n k 2 + θ n }, Q n = {z ∈ C : hx n − z, x 0 − x n i ≥ 0},
x n+1 = P Cn∩Q
nx 0 ,
where T : C → C is an asymptotically k-strict pseudo-contraction and θ n =
∆ 2 n (1 − α n )γ n → 0(n → ∞), ∆ n = sup{kx n − zk : z ∈ F (T )} < ∞. Subse- quently, Kim and Xu proved that the iterative algorithm (KX1) and (KX2) are strongly convergent. For more details, see [8, 9]. However, we note that the (n + 1)th iterate x n+1 is defined as the projection of the initial guess x 0 onto the intersection of two closed convex subsets C n and Q n . Therefore, an interesting problem is how to construct appropriately C n and Q n such that the computations become easier.
Motivated by the above works, in this paper we introduce two iterative algo- rithms for finding a common element of the set of fixed points of an asymptoti- cally k-strict pseudo-contraction and the set of solutions of a mixed equilibrium problem in a Hilbert space. We obtain some weak and strong convergence the- orems by using the proposed iterative algorithms. Our results extend and improve the corresponding results of Tada and Takahashi [16], Kim and Xu [8, 9].
2. Preliminaries
Let H be a real Hilbert space with inner product h·, ·i and norm k · k. Let C be a nonempty closed convex subset of H. Then, for any x ∈ H, there exists a unique nearest point in C, denoted by P C (x), such that
kx − P C (x)k ≤ kx − yk
for all y ∈ C. Such a P C is called the metric projection of H onto C. We know that P C is nonexpansive. Further, for x ∈ H and x ∗ ∈ C,
(1) x ∗ = P C (x) ⇔ hx − x ∗ , x ∗ − yi ≥ 0 for all y ∈ C.
Recall that a mapping T : C → C is said to be an asymptotically k-strict pseudo-contraction if, there exists a constant k ∈ [0, 1) satisfying
(2) kT n x − T n yk 2 ≤ (1 + γ n )kx − yk 2 + kk(I − T n )x − (I − T n )yk 2 for all x, y ∈ C and all integers n ≥ 1, where γ n ≥ 0 for all n and such that γ n → 0 as n → ∞. Note that if k = 0, then T is an asymptotically nonexpansive mapping, that is, there exists a sequence {γ n } of nonnegative numbers with γ n → 0 such that
kT n x − T n yk ≤ (1 + γ n )kx − yk 2 for all x, y ∈ C and all integers n ≥ 1.
In the sequel, we will use F (T ) to denote the set of fixed points of T . For given sequence {x n } ⊂ C, let ω w (x n ) = {x : ∃x nj → x weakly} denote the weak ω-limit set of {x n }.
In this paper, for solving the mixed equilibrium problems for an equilibrium bifunction Θ : C × C → R, we assume that Θ satisfies the following conditions:
(H1) Θ is monotone, i.e., Θ(x, y) + Θ(y, x) ≤ 0 for all x, y ∈ C;
(H2) for each fixed y ∈ C, x 7→ Θ(x, y) is concave and upper semicontinuous;
(H3) for each x ∈ C, y 7→ Θ(x, y) is convex.
A mapping η : C × C → H is called Lipschitz continuous, if there exists a constant λ > 0 such that
kη(x, y)k ≤ λkx − yk, ∀x, y ∈ C.
A differentiable function K : C → R on a convex set C is called:
(i) η-convex if
K(y) − K(x) ≥ hK
0(x), η(y, x)i, ∀x, y ∈ C, where K
0is the Frechet derivative of K at x;
(ii) η-strongly convex if there exists a constant σ > 0 such that K(y) − K(x) − hK
0(x), η(y, x)i ≥ (σ/2)kx − yk 2 , ∀x, y ∈ C.
Let C be a nonempty closed convex subset of a real Hilbert space H, ϕ : C → R be real-valued function and Θ : C × C → R be an equilibrium bifunction.
Let r be a positive number. For a given point x ∈ C, the auxiliary problem for (MEP) consists of finding y ∈ C such that
Θ(y, z) + ϕ(z) − ϕ(y) + 1
r hK
0(y) − K
0(x), η(z, y)i ≥ 0, ∀z ∈ C.
Let S r : C → C be the mapping such that for each x ∈ C, S r (x) is the solution set of the auxiliary problem, i.e., ∀x ∈ C,
S r (x) =
½
y ∈ C : Θ(y, z) + ϕ(y) + 1
r hK
0(y) − K
0(x), η(z, y)i ≥ 0, ∀z ∈ C
¾ .
We need the following important and interesting result for proving our main results.
Lemma 2.1 ([21]). Let C be a nonempty closed convex subset of a real Hilbert space H and let ϕ : C → R be a lower semicontinuous and convex functional.
Let Θ : C×C → R be an equilibrium bifunction satisfying conditions (H1)-(H3).
Assume that
(i) η : C × C → H is Lipschitz continuous with constant λ > 0 such that (a) η(x, y) + η(y, x) = 0, ∀x, y ∈ C,
(b) η(·, ·) is affine in the first variable,
(c) for each fixed y ∈ C, x 7→ η(y, x) is sequentially continuous from the weak topology to the weak topology;
(ii) K : C → R is η-strongly convex with constant σ > 0 and its deriva- tive K
0is sequentially continuous from the weak topology to the strong topology;
(iii) for each x ∈ C, there exist a bounded subset D x ⊂ C and z x ∈ C such that for any y ∈ C \ D x ,
Θ(y, z x ) + ϕ(z x ) − ϕ(y) + 1
r hK
0(y) − K
0(x), η(z x , y)i < 0.
Then there hold the following:
(I) S r is single-valued;
(II) S r is nonexpansive if K
0is Lipschitz continuous with constant ν > 0 such that σ ≥ λν and
hK
0(x 1 ) − K
0(x 2 ), η(u 1 , u 2 )i ≥ hK
0(u 1 ) − K
0(u 2 ), η(u 1 , u 2 )i, ∀(x 1 , x 2 ) ∈ C × C where u i = S r (x i ) for i = 1, 2;
(III) F (S r ) = Ω;
(IV) Ω is closed and convex.
We also need the following lemmas.
Lemma 2.2. Let H be a real Hilbert space. There hold the following well- known identities:
(i) kx − yk 2 = kxk 2 − 2hx, yi + kyk 2 ∀x, y ∈ H.
(ii) ktx+(1−t)yk 2 = tkxk 2 +(1−t)kyk 2 −t(1−t)kx−yk 2 ∀t ∈ [0, 1], ∀x, y ∈ H.
Lemma 2.3 ([9]). Assume C is a closed convex subset of a real Hilbert space
H and let T : C → C be an asymptotically k-strict pseudo-contraction. Then
the following conclusions hold:
(i) for each n ≥ 1, T n satisfies the Lipschitz condition:
kT n x − T n yk ≤ L n kx − yk ∀x, y ∈ C, where L n = k+
√ 1+γn(1−k)
1−k ;
(ii) the mapping I − T is demiclosed at zero, that is, if {x n } is a sequence in C such that x n → x ∗ weakly and (I − T )x n → 0 strongly, then (I − T )x ∗ = 0;
(iii) the fixed point set F (T ) of T is closed and convex so that the projection P F (T ) is well-defined.
Lemma 2.4 ([11]). Let C be a closed convex subset of a real Hilbert space H.
Let {x n } be a sequence in H and u ∈ H. Let q = P C u. If {x n } is such that ω w (x n ) ⊂ C and satisfies the condition
kx n − uk ≤ ku − qk for all n, then x n → q.
3. Main results
In this section, we first introduce the following new iterative algorithm.
Algorithm 3.1. Let C be a nonempty closed convex subset of a real Hilbert space H, ϕ : C → R be a lower semicontinuous and convex real valued function, Θ : C×C → R be an equilibrium bifunction and T : C → C be an asymptotically k-strict pseudo-contraction. Assume that F (T ) ∩ Ω is nonempty and bounded.
Let r be a positive parameter and δ ∈ (k, 1) be a constant. Let {α n } be a sequence in [0, 1]. Define the sequences {x n } and {y n } by the following manner:
(3)
x 0 ∈ C chosen arbitrarily, Θ(y n , x) + ϕ(x) − ϕ(y n ) + 1
r hK
0(y n ) − K
0(x n ), η(x, y n )i ≥ 0, ∀x ∈ C, z n = (1 − α n )x n + α n [δy n + (1 − δ)T n y n ],
C n = {z ∈ C : kz n − zk 2 ≤ kx n − zk 2 + θ n }, Q n = {z ∈ C : hx n − z, x 0 − x n i ≥ 0}, x n+1 = P Cn∩Q
nx 0 ,
where θ n = γ n ∆ 2 n , ∆ n = sup{kx n − pk : p ∈ F (T ) ∩ Ω} < ∞.
Now we give a strong convergence result concerning iterative Algorithm 3.1 as follows.
Theorem 3.1. Let C be a nonempty closed convex subset of a real Hilbert space H. Let ϕ : C → R be a lower semicontinuous and convex functional. Let Θ : C × C → R be an equilibrium bifunction satisfying conditions (H1)-(H3) and let T : C → C be an asymptotically k-strict pseudo-contraction. Assume that F (T ) ∩ Ω is nonempty and bounded. Assume that:
(i) η : C × C → H is Lipschitz continuous with constant λ > 0 such that;
(a) η(x, y) + η(y, x) = 0, ∀x, y ∈ C, (b) η(·, ·) is affine in the first variable,
(c) for each fixed y ∈ C, x 7→ η(y, x) is sequentially continuous from the weak topology to the weak topology;
(ii) K : C → R is η-strongly convex with constant σ > 0 and its derivative K
0is not only sequentially continuous from the weak topology to the strong topology but also Lipschitz continuous with constant ν > 0 such that σ ≥ λν;
(iii) for each x ∈ C; there exist a bounded subset D x ⊂ C and z x ∈ C such that, for any C 3 y / ∈ D x ,
Θ(y, z x ) + ϕ(z x ) − ϕ(y) + 1
r hK
0(y) − K
0(x), η(z x , y)i < 0;
(iv) α n ∈ [a, 1] for some a ∈ (0, 1).
Then the sequence {x n } generated iteratively by (3) converges strongly to P F (T )∩Ω x 0 provided S r is firmly nonexpansive.
Proof. First, we show that the sequence {x n } is well-defined. It is obvious that C n and Q n are closed and convex. Let p ∈ F (T ) ∩ Ω. From y n = S r x n , we have
(4) ky n − pk = kS r x n − S r pk ≤ kx n − pk.
From Lemma 2.2, (2) and (4), we obtain (5)
kz n − pk 2 ≤ (1 − α n )kx n − pk 2 + α n kδ(y n − p) + (1 − δ)(T n y n − p)k 2
= (1 − α n )kx n − pk 2 + α n [δky n − pk 2 + (1 − δ)kT n y n − pk 2
− δ(1 − δ)kT n y n − y n k 2 ]
≤ (1 − α n )kx n − pk 2 + α n {δky n − pk 2 + (1 − δ)[(1 + γ n )ky n − pk 2 + kky n − T n y n k 2 ] − δ(1 − δ)ky n − T n y n k 2 }
= (1 − α n )kx n − pk 2 + α n {ky n − pk 2 + (1 − δ)γ n ky n − pk 2 + (1 − δ)(k − δ)ky n − T n y n k 2 }
≤ (1 − α n )kx n − pk 2 + α n (1 + γ n )ky n − pk 2
≤ (1 + γ n )kx n − pk 2 .
Hence, we have kz n − pk 2 ≤ kx n − pk 2 + θ n . This implies that p ∈ C n ; thus,
(6) F (T ) ∩ Ω ⊂ C n
for every n ≥ 0. Next we show by induction that F (T ) ∩ Ω ⊂ C n ∩ Q n for each n ≥ 0. Since F (T ) ∩ Ω ⊂ C 0 and Q 0 = C, we get
F (T ) ∩ Ω ⊂ C 0 ∩ Q 0 .
Suppose that F (T )∩Ω ⊂ C k ∩Q k for k ∈ N. Then, there exists x n+1 ∈ C k ∩Q k
such that
x n+1 = P Ck∩Q
kx 0 . Therefore, for each z ∈ C k ∩ Q k , we have
hx k+1 − z, x 0 − x k+1 i ≥ 0.
Note that F (T ) ∩ Ω ⊂ C k ∩ Q k . Hence, for any z ∈ F (T ) ∩ Ω we have hx k+1 − z, x 0 − x k+1 i ≥ 0,
therefore z ∈ Q k+1 . So, we get
F (T ) ∩ Ω ⊂ Q k+1 . From this and (6), we have
F (T ) ∩ Ω ⊂ C k+1 ∩ Q k+1 . This denotes that the sequence {x n } is well-defined.
Since F (T ) ∩ Ω is a nonempty closed convex subset of C, there exists a unique z
0∈ F (T ) ∩ Ω such that z
0= P F (T )∩Ω x 0 . From x n+1 = P Cn∩Q
nx 0 , we have
kx n+1 − x 0 k ≤ kz − x 0 k
for all z ∈ C n ∩ Q n . Since z
0∈ F (T ) ∩ Ω ⊂ C n ∩ Q n , we have (7) kx n+1 − x 0 k ≤ kz
0− x 0 k
for every n ≥ 0. Therefore, {x n } is bounded, so are {y n } and {z n }. Since x n = P Qnx 0 and x n+1 ∈ Q n , we get
kx n − x 0 k ≤ kx n+1 − x 0 k.
This together with the boundedness of {kx n −x 0 k} implies that lim n→∞ kx n −x 0 k exists. The fact that x n+1 ∈ Q n implies that hx n+1 −x n , x n −x 0 i ≥ 0. Applying Lemma 2.2, we obtain
(8)
kx n+1 − x n k 2 = k(x n+1 − x 0 ) − (x n − x 0 )k 2
= kx n+1 − x 0 k 2 − kx n − x 0 k 2 − 2hx n+1 − x n , x n − x 0 i
≤ kx n+1 − x 0 k 2 − kx n − x 0 k 2
→ 0.
From x n+1 ∈ C n , we have
kx n − z n k ≤ kx n − x n+1 k + kx n+1 − z n k
≤ (2 + γ n )kx n − x n+1 k
→ 0.
For p ∈ F (T ) ∩ Ω, noting that S r is firmly nonexpansive, we have ky n − pk 2 = kS r x n − S r pk 2
≤ kS r x n − S r p, x n − pi
= hy n − p, x n − pi
= 1
2 {ky n − pk 2 + kx n − pk 2 − kx n − y n k 2 }, and hence,
ky n − pk 2 ≤ kx n − pk 2 − kx n − y n k 2 . From (5), we have
kz n − pk 2 ≤ (1 − α n )kx n − pk 2 + α n (1 + γ n )ky n − pk 2
≤ (1 − α n )kx n − pk 2 + α n (1 + γ n ){kx n − pk 2 − kx n − y n k 2 }
= (1 + α n γ n )kx n − pk 2 − α n (1 + γ n )kx n − y n k 2 , that is,
(9)
kx n − y n k 2 ≤ 1
α n (1 + γ n ) {kx n − pk 2 − kz n − pk 2 } + γ n kx n − pk 2 1 + γ n
≤ 1
α n (1 + γ n ) kx n − z n k{kx n − pk + kz n − pk} + γ n kx n − pk 2 1 + γ n
→ 0.
Combining (8) and (9), we have
n→∞ lim ky n+1 − y n k = 0.
By the fact α n (1 − δ)(T n y n − y n ) = z n − (1 − α n )x n − α n y n , we get kα n (1 − δ)(T n y n − y n )k ≤ kz n − x n k + α n kx n − y n k → 0, which implies that
kT n y n − y n k → 0.
Next we show that
n→∞ lim ky n − T y n k = 0.
As a matter of fact, we have
ky n − T y n k ≤ ky n − T n y n k + kT n y n − T n+1 y n k + kT n+1 y n − T y n k
≤ (1 + L 1 )ky n − T n y n k + kT n y n − T n+1 y n k.
Note that
kT n y n − T n+1 y n k ≤ kT n y n − y n k + ky n − y n+1 k + ky n+1 − T n+1 y n+1 k + kT n+1 y n+1 − T n+1 y n k
≤ kT n y n − y n k + (1 + L n+1 )ky n − y n+1 k
+ ky n+1 − T n+1 y n+1 k.
Therefore, we have
(10) ky n − T y n k ≤ (2 + L 1 )ky n − T n y n k + (1 + L n+1 )ky n − y n+1 k + ky n+1 − T n+1 y n+1 k → 0.
Since {y n } is bounded, there exists a subsequence {y ni} of {y n } which converges weakly to w. From (7), we also obtain that T y ni → w weakly. Next we show that w ∈ Ω. Since y n = S r x n , we derive
→ w weakly. Next we show that w ∈ Ω. Since y n = S r x n , we derive
Θ(y n , x) + ϕ(x) − ϕ(y n ) + 1
r hK
0(y n ) − K
0(x n ), η(x, y n )i ≥ 0, ∀x ∈ C.
From the monotonicity of Θ, we have 1
r hK
0(y n ) − K
0(x n ), η(x, y n )i + ϕ(x) − ϕ(y n ) ≥ −Θ(y n , x) ≥ Θ(x, y n ), and hence
*
K
0(y ni) − K
0(x ni)
)
r , η(x, y ni) +
+ ϕ(x) − ϕ(y ni) ≥ Θ(x, y ni).
).
Since K
0