Electric Circuit Theory
Nam Ki Min
010-9419-2320
nkmin@korea.ac.kr
Simple Resistive Circuits Chapter 3
Nam Ki Min
nkmin@korea.ac.kr
3 Fundamental Laws of Circuit Analysis
Summary
Ohm’s Law
Kirchhoff’s Current Law (KCL)
Kirchhoff’s Voltage Law (KVL)
Ohm’s Law establishes the proportionality of voltage and current in a resistor.
Specifically,
𝑣 = 𝑖𝑅
If the current flow in the resistor is in the direction of the voltage drop across it,
or
𝑣 = −𝑖𝑅
Kirchhoff’s current law states that the algebraic sum of all the currents at any node in a circuit equals zero.
Kirchhoff’s voltage law states that the algebraic sum of all the voltages around any closed path in a circuit equals zero.
3.1 Resistors in Series 4
Series Circuits
Two or more circuit elements are said to be in series if the identical current flows through each of the elements.
• The two resistors are in series, since the same current 𝑖 flows in both of them.
• The current 𝑖𝑠 flows through each of the eight series elements.
3.1 Resistors in Series 5
Series Combinations of Resistors
The equivalent resistance of any number of resistors connected in series is the sum of the individual resistances.
𝑣
1= 𝑖𝑅
1𝑣
2= 𝑖𝑅
2• Ohm’s law
• KVL
−𝑣 + 𝑣
1+ 𝑣
2= 0
𝑖 = 𝑣 𝑅
1+ 𝑅
2𝑣 = 𝑖 𝑅
1+ 𝑅
2= 𝑖𝑅
𝑒𝑞𝑅
𝑒𝑞= 𝑅
1+ 𝑅
2 Equivalent circuit Original circuit𝑣
𝑠= 𝑖
𝑠𝑅
1+ 𝑅
2+ 𝑅
3+ 𝑅
4+ 𝑅
5+ 𝑅
6+ 𝑅
7= 𝑖
𝑠𝑅
𝑒𝑞𝑅
𝑒𝑞= 𝑅
1+ 𝑅
2+ 𝑅
3+ 𝑅
4+ 𝑅
5+ 𝑅
6+ 𝑅
7The seven resistors could thus be replaced by a single resistor of value R
eqwithout changing the amount of current required of the battery.
3.1 Resistors in Series 6
In general, k resistors in series
Series Equivalent Resistance
𝑅
𝑒𝑞= 𝑅
1+ 𝑅
2+ ⋯ + 𝑅
𝑘= 𝑅
𝑖𝑘
𝑖=1
𝑅
𝑒𝑞𝑅
1𝑅
2𝑅
3⋯ 𝑅
𝑖⋯ 𝑅
𝑘3.2 Resistors in Parallel 7
Parallel Circuits
Two or more circuit elements are said to be in parallel if the identical voltage appears across each of the elements.
• The two resistors are in parallel, since the same voltage 𝑣 appears across each of the elements.
• The same voltage 𝑣𝑠 appears across each parallel element.
8
Parallel Combinations of Resistors
The equivalent resistance of two parallel resistors is equal to the product of their resistances divided by their sum.
𝑣 = 𝑖
1𝑅
1= 𝑖
2𝑅
2• Ohm’s law
• Applying KCL at node a gives the total current i as
𝑖 = 𝑖
1+ 𝑖
2𝑖
1= 𝑣
𝑅
1𝑖
2= 𝑣 𝑅
2= 𝑣
𝑅
1+ 𝑣
𝑅
2= 𝑣 1
𝑅
1+ 1
𝑅
1= 𝑣 𝑅
𝑒𝑞1
𝑅
𝑒𝑞= 1
𝑅
1+ 1 𝑅
1𝑅
𝑒𝑞= 𝑅
1𝑅
2𝑅
1+ 𝑅
2or
(1) 3.2 Resistors in Parallel
3.2 Resistors in Parallel 9
Replacing the k parallel resistors with a single equivalent resistor.
We can extend the result in Eq.(1) to the general case of a circuit with k resistors in parallel.
The parallel equivalent resistance is
Parallel Equivalent Resistance
1
𝑅
𝑒𝑞= 1
𝑅
1+ 1
𝑅
2+ 1
𝑅
3+ ⋯ + 1
𝑅
𝑘= 1 𝑅
𝑖𝑘
𝑖=1
It is often more convenient to use conductance rather than resistance when dealing with resistors in parallel. From Eq.(2), the equivalent conductance for k resistors in parallel is
(2)
𝐺
𝑒𝑞= 𝐺
1+ 𝐺
2+𝐺
3+ ⋯ + 𝐺
𝑘= 𝐺
𝑖𝑘
𝑖=1
3.3 The Voltage-Divider and Current-Divider Circuits 10
The voltage across each resistor in a series circuit is directly proportional to the ratio of its resistance to the total series resistance of the circuit.
The two resistor voltage divider is used often to supply a voltage different from a single voltage supply.
KVL
Voltage Divider
𝑣
𝑠= 𝑖𝑅
1+ 𝑖𝑅
2𝑖 = 𝑣
𝑠𝑅
1+ 𝑅
2 Ohm’s law
𝑣
1= 𝑖𝑅
1= 𝑅
1𝑅
1+ 𝑅
2𝑣
𝑠𝑣
2= 𝑖𝑅
2= 𝑅
2𝑅
1+ 𝑅
2𝑣
𝑠3.3 The Voltage-Divider and Current-Divider Circuits 11
In application the output voltage depends upon the resistance of the load it drives.
Voltage Divider 𝑅
𝑒𝑞= 𝑅
2𝑅
𝐿𝑅
2+ 𝑅
𝐿 Output voltage:
𝑣
𝑜= 𝑖𝑅
𝑒𝑞= 𝑅
𝑒𝑞𝑅
1+ 𝑅
𝑒𝑞𝑣
𝑠= 𝑅
𝑒𝑞𝑅
1+ 𝑅
𝑒𝑞𝑣
𝑠= 𝑅
2𝑅
11 + 𝑅
2𝑅
𝐿+ 𝑅
2𝑣
𝑠If
𝑅
𝐿→ ∞, 𝑣
𝑜= 𝑅
2𝑅
1+ 𝑅
2𝑣
𝑠3.3 The Voltage-Divider and Current-Divider Circuits 12
The total current i is shared by the resistors in inverse proportion to their resistances.
Ohm’s law
Current Divider
𝑖
𝑠= 𝑖
1+ 𝑖
2𝑖
1= 𝑣
𝑅
1 KCL
𝑖
2= 𝑣 𝑅
2= 𝑣
𝑅
1+ 𝑣 𝑅
2𝑣 = 𝑅
1𝑅
2𝑅
1+ 𝑅
2𝑖
𝑠𝑖
1= 𝑣
𝑅
1= 𝑅
2𝑅
1+ 𝑅
2𝑖
𝑠𝑖
2= 𝑣
𝑅
2= 𝑅
1𝑅
1+ 𝑅
2𝑖
𝑠- The total current i is shared by the resistors in inverse proportion to their resistances.
- Notice that the larger current flows through the smaller resistance.
3.4 Voltage Division and Current Division 13
We can now generalized the results from analyzing the voltage divider circuit and the current divider circuit.
Voltage Division
The general form of the voltage divider rule for a circuit with n series resistors and a voltage source is:
𝑅
𝑒𝑞= 𝑅
1+ 𝑅
2+ ⋯ 𝑅
𝑗⋯ + 𝑅
𝑛−1+ 𝑅
𝑛𝑖 = 𝑣
𝑅
1+ 𝑅
2+ ⋯ 𝑅
𝑗⋯ + 𝑅
𝑛−1+ 𝑅
𝑛= 𝑣 𝑅
𝑒𝑞𝑣
𝑗= 𝑅
𝑗𝑅
1+ 𝑅
2+ ⋯ 𝑅
𝑗⋯ + 𝑅
𝑛−1+ 𝑅
𝑛𝑣
= 𝑅
𝑗𝑅
𝑒𝑞𝑣
3.4 Voltage Division and Current Division 14
Current Division
The general expression for the current divider for a circuit with n parallel resistors is the following:
𝑖 = 𝑖
1+ 𝑖
2+ ⋯ 𝑖
𝑗⋯ + 𝑖
𝑛−1+ 𝑖
𝑛= 𝑣
𝑅
1+ 𝑣
𝑅
2+ ⋯ 𝑣
𝑅
𝑗⋯ + 𝑣
𝑅
𝑛−1+ 𝑣 𝑅
𝑛= 1
𝑅
1+ 1
𝑅
2+ ⋯ 1
𝑅
𝑗⋯ + 1
𝑅
𝑛−1+ 1
𝑅
𝑛𝑣
= 𝑣
𝑅
𝑒𝑞1
𝑅
𝑒𝑞= 1
𝑅
1+ 1
𝑅
2+ ⋯ 1
𝑅
𝑗⋯ + 1
𝑅
𝑛−1+ 1 𝑅
𝑛𝑣 = 𝑖𝑅
𝑒𝑞𝑖
𝑗= 𝑣
𝑅
𝑗= 𝑅
𝑒𝑞𝑅
𝑗𝑖
3.5 Measuring Voltage and Current 15
Ammeter
An instrument designed to measure current.
It is placed in series with the circuit element whose current is being measured.
Voltmeter
An instrument designed to measure voltage.
It is placed in parallel with the circuit element whose voltage is being measured.
An ideal ammeter or voltmeter has no effect on the circuit variable it is designed to measure.
• An ideal ammeter has zero internal resistance.
Ideal Ammeter or Voltmeter
𝑅
𝑎𝑚= 0
• An ideal voltmeter has infinite internal resistance.
𝑅
𝑣𝑚= ∞
3.5 Measuring Voltage and Current 16
Practical Ammeter or Voltmeter
A practical ammeter will contribute some series resistance to the circuit in which it is measuring current.
a practical voltmeter will not act as an ideal open circuit but will always draw some current from the measured circuit.
Figure depicts the circuit models for the practical ammeter and voltmeter.
Practical voltmeter Practical ammeter
𝑅𝑎𝑚
𝑅𝑣𝑚
Digital Meters
3.5 Measuring Voltage and Current 17
Analog Meters
A schematic diagram of a d’Arsonval meter movement.
The basic dc meter movement is known as the D'Arsonval meter movement because it was first employed by the French scientist, D'Arsonval, in making electrical measurement.
Deflection torque: The deflection torque causes the moving system to move from zero position when the instrument is connected to the circuit to measure the given electrical quantity.
𝜏 = 𝐵𝐼𝑁𝐴 (Nm)
𝐵 𝐼
3.5 Measuring Voltage and Current 18
Analog Meters
Analog ammeter
Analog voltmeter
𝐼 = 𝐼
𝑑𝑚+ 𝐼
𝑅𝐴Small (1 mA)
𝑉 = 𝑉
𝑑𝑚+ 𝑉
𝑅𝑣Small (50 mV)
In both meters, the added resistor(RA or Rv) determines the full scale reading of the meter movement.
3.6 Measuring Resistance -The Wheatstone Bridge 19
Resistance Measurement
Resistance
Ohmmeters: They are designed to measure resistance in low, mid, or high range.
Milliohmmeters : Very low values of resistances are measured.
Wheatstone bridges: They are used to measure resistance in the mid range, say, between 1Ω and 1 MΩ.
Megger tester: very high resistance
• Low resistance : <1Ω
• Medium resistance : 1 Ω<R<1 MΩ
• High resistance : >1 MΩ
Ohmmeters Megger testers Milliohmmeters
3.6 Measuring Resistance -The Wheatstone Bridge 20
Wheatstone Bridge
The bridge was invented by Charles Wheatstone (1802–1875), a British professor who also invented the telegraph, as Samuel Morse did independently in the United States.
The Wheatstone bridge (or resistance bridge) circuit is used in a number of applications.
Here we will use it to measure an unknown resistance.
The bridge circuit consists of four resistors, a dc voltage source, and a detector.
The detector is generally a d’Arsonval movement in the microamp range and is called a galvanometer.
21
Balanced Condition
The variable resistor, R3, is adjusted until the detector reads zero current(Ig=0).
𝑖
1= 𝑖
3𝑖
2= 𝑖
𝑥 Because Ig=0, there is no voltage drop across the detector, therefore points a and b are the same potential.
𝑣
𝑎= 𝑣
𝑏𝑖
3𝑅
3= 𝑖
𝑥𝑅
𝑥→ 𝑖
1𝑅
3= 𝑖
2𝑅
𝑥𝑖
1𝑅
1= 𝑖
2𝑅
2𝑅
3𝑅
1= 𝑅
𝑥𝑅
2→ 𝑅
𝑥= 𝑅
2𝑅
1𝑅
33.6 Measuring Resistance -The Wheatstone Bridge
22
Balanced Condition
• To cover a wide range of unknown resistors , we must be able to vary the ratio R2/R1.
𝑅
𝑥= 𝑅
2𝑅
1𝑅
33.6 Measuring Resistance -The Wheatstone Bridge
V D
𝑅
𝑥𝑅
2𝑅
123
Unbalanced Condition
If Ig is not zero,
𝑣
𝑎𝑏= 𝑣
𝑎− 𝑣
𝑏= 𝑖
3𝑅
3− 𝑖
𝑥𝑅
𝑥𝑉
𝑜𝑢𝑡= 𝑅
3𝑅
1+ 𝑅
3𝑣 − 𝑅
𝑥𝑅
𝑥+ 𝑅
2𝑣 = 𝑅
3𝑅
1+ 𝑅
3− 𝑅
𝑥𝑅
𝑥+ 𝑅
2𝑣
3.6 Measuring Resistance -The Wheatstone Bridge
𝑖
𝑔= 𝑣
𝑎𝑏𝑅
𝑚3.7 Delta-to-Wye (Pi-to-Tee) Equivalent Circuits 24
More Complex Circuits
In many circuits, resistors are neither in series nor in parallel, so the rules for series or parallel circuits described in previous sections cannot be applied.
For example, consider the bridge circuit in Fig. 3.28.
How do we combine resistors R1,R2,R3,Rm, and Rx when the resistors are neither in series nor in parallel?
Many circuits of the type shown in Fig.3.28 can be simplified by means of a delta-to-wye(Δ-to-Y) or pi-to-tee(π-to-T) equivalent circuit.
Delta(Δ) Interconnection
R1,Rm,R2 (or R3,Rm,Rx ): delta(Δ) connection because the interconnection can be shaped to look like the Greek letter Δ.
It is also referred to as a pi interconnection because the Δ can be shaped into a π without disturbing the electrical equivalence of the two configurations.
3.7 Delta-to-Wye (Pi-to-Tee) Equivalent Circuits 25
Wye(Y) Interconnection
R1,Rm,R3 (or R2,Rm,Rx ): Wye(Δ) connection because the interconnection can be shaped to look like the letter Y.
It is also referred to as a tee(T) interconnection because the Y structure can be shaped into a T structure without disturbing the electrical equivalence of the two structures.
3.7 Delta-to-Wye (Pi-to-Tee) Equivalent Circuits 26
For terminals a and b,
Delta(Δ)-to-Wye(Y) Transformation
Saying the Δ-connected circuit is equivalent to the Y-connected circuit means that the Δ configuration can be replaced with a Y configuration to make the terminal behavior of the two
configurations identical.
● ●
●
○
○
𝑎 𝑏
𝑐
○
○
𝑎
●𝑐
𝑏 𝑅
𝑐𝑎(∆) = 𝑅
𝑏𝑅
𝑑𝑅
𝑏+ 𝑅
𝑑○
○
𝑎
𝑐
●
●
𝑅𝑑 = 𝑅𝑐+ 𝑅𝑎
𝑅
𝑐𝑎(Y) = 𝑅
1+ 𝑅
3= 𝑅
𝑏(𝑅
𝑐+ 𝑅
𝑎) 𝑅
𝑎+ 𝑅
𝑏+ 𝑅
𝑐𝑅
𝑐𝑎= 𝑅
𝑏(𝑅
𝑐+ 𝑅
𝑎)
𝑅
𝑎+ 𝑅
𝑏+ 𝑅
𝑐= 𝑅
1+ 𝑅
3Setting Rca(Δ)= Rca(Y) gives
3.7 Delta-to-Wye (Pi-to-Tee) Equivalent Circuits 27 Similarly,
𝑅
𝑐𝑎= 𝑅
𝑏(𝑅
𝑐+ 𝑅
𝑎)
𝑅
𝑎+ 𝑅
𝑏+ 𝑅
𝑐= 𝑅
1+ 𝑅
3𝑅
𝑎𝑏= 𝑅
𝑐(𝑅
𝑎+ 𝑅
𝑏)
(1)𝑅
𝑎+ 𝑅
𝑏+ 𝑅
𝑐= 𝑅
1+ 𝑅
2𝑅
𝑏𝑐= 𝑅
𝑎(𝑅
𝑏+ 𝑅
𝑐)
𝑅
𝑎+ 𝑅
𝑏+ 𝑅
𝑐= 𝑅
2+ 𝑅
3 (2) (3)Subtracting Eq. (2) from Eq. (3), we get
𝑅
𝑐(𝑅
𝑏− 𝑅
𝑎)
𝑅
𝑎+ 𝑅
𝑏+ 𝑅
𝑐= 𝑅
1− 𝑅
2 (4) Adding Eqs.(1) and (4) gives2𝑅
𝑏𝑅
𝑐𝑅
𝑎+ 𝑅
𝑏+ 𝑅
𝑐= 2𝑅
1𝑅
1= 𝑅
𝑏𝑅
𝑐𝑅
𝑎+ 𝑅
𝑏+ 𝑅
𝑐Subtracting Eq.(1) from Eq. (4) yields
𝑅
2= 𝑅
𝑐𝑅
𝑎𝑅
𝑎+ 𝑅
𝑏+ 𝑅
𝑐Subtracting Eq.(5) from Eq. (3) yields
(5)
𝑅
3= 𝑅
𝑎𝑅
𝑏𝑅
𝑎+ 𝑅
𝑏+ 𝑅
𝑐(6)
(7)
3.7 Delta-to-Wye (Pi-to-Tee) Equivalent Circuits 28
Summary
𝑅
1= 𝑅
𝑏𝑅
𝑐𝑅
𝑎+ 𝑅
𝑏+ 𝑅
𝑐𝑅
2= 𝑅
𝑐𝑅
𝑎𝑅
𝑎+ 𝑅
𝑏+ 𝑅
𝑐𝑅
3= 𝑅
𝑎𝑅
𝑏𝑅
𝑎+ 𝑅
𝑏+ 𝑅
𝑐Each resistor in the Y network is the product of the resistors in the two adjacent “ branches, divided by the sum of the three " resistors.
We do not need to memorize Eqs.(5) to (7).
To transform a “ network to Y, we create an extra node n as shown in Fig. 3.31 and follow this conversion rule:
(5)
(6)
(7)
3.7 Delta-to-Wye (Pi-to-Tee) Equivalent Circuits 29
Wye-to-Delta(Δ) Transformation
To obtain the conversion formulas for transforming a wye network to an equivalent delta network, we note from Eqs.(5) to (7) that
𝑅
1𝑅
2+𝑅
2𝑅
3+ 𝑅
3𝑅
1= 𝑅
𝑎𝑅
𝑏𝑅
𝑐𝑅
𝑎+ 𝑅
𝑏+ 𝑅
𝑐𝑅
𝑎+ 𝑅
𝑏+ 𝑅
𝑐 2= 𝑅
𝑎𝑅
𝑏𝑅
𝑐𝑅
𝑎+ 𝑅
𝑏+ 𝑅
𝑐 (8)Dividing Eq.(8) by each of Eqs.(5) to (7) leads to the following equations:
𝑅
𝑎= 𝑅
1𝑅
2+𝑅
2𝑅
3+ 𝑅
3𝑅
1𝑅
1𝑅
𝑏= 𝑅
1𝑅
2+𝑅
2𝑅
3+ 𝑅
3𝑅
1𝑅
2𝑅
𝑐= 𝑅
1𝑅
2+𝑅
2𝑅
3+ 𝑅
3𝑅
1𝑅
3(9)
(10)
(11)
Each resistor in the Δ network is the sum of all possible products of Y resistors taken two at a time, divided by the opposite Y resistor.