A WEIGHTED OSTROWSKI TYPE INEQUALITY FOR FUNCTIONS WITH VALUES IN
HILBERT SPACES AND APPLICATIONS
S. S. Dragomir
Abstract. Some weighted Ostrowski type integral inequalities for vector-valued functions in Hilbert spaces are given. Applications for quadrature rules with values in Hilbert spaces are also pointed out.
1. Introduction
In [8], Peˇcari´c and Savi´c obtained the following Ostrowski type in- equality for weighted integrals (see also [5, Theorem 3]):
Theorem 1. Let w : [a, b] → [0, ∞) be a weight function on [a, b] . Suppose that f : [a, b] → R satisfies
(1.1) |f (t) − f (s)| ≤ N |t − s| α , for all t, s ∈ [a, b] ,
where N > 0 and 0 < α ≤ 1 are some constants. Then for any x ∈ [a, b]
(1.2)
¯
¯
¯
¯
¯
f (x) − R b
a w (t) f (t) dt R b
a w (t) dt
¯
¯
¯
¯
¯
≤ N · R b
a |t − x| α w (t) dt R b
a w (t) dt . Further, if for some constants c and λ
0 < c ≤ w (t) ≤ λc, for all t ∈ [a, b] , then for any x ∈ [a, b], we have
(1.3)
¯
¯
¯
¯
¯
f (x) − R b
a w (t) f (t) dt R b
a w (t) dt
¯
¯
¯
¯
¯
≤ N · λL (x) J (x) L (x) − J (x) + λJ (x) ,
Received May 6, 2002.
2000 Mathematics Subject Classification: Primary 26D25, 26D10; Secondary 41A55, 46B10.
Key words and phrases: Ostrowski’s inequality, vector-valued functions, Bochner’s
integral.
where
L (x) := · 1
2 (b − a) +
¯
¯
¯
¯
x − a + b 2
¯
¯
¯
¯
¸ α
and
J (x) := (x − a) 1+α + (b − x) 1+α (1 + α) (b − a) .
The inequality (1.2) was rediscovered in [3] where further applications for different weights and in Numerical Analysis were given.
For other results in connection to weighted Ostrowski inequalities, see [2], [6] and [7].
In the present paper we extend the weighted Ostrowski’s inequality for vector-valued functions and Bochner integrals in Hilbert spaces.
Let X be a Banach space and −∞ < a < b < ∞. We denote by L (X) the Banach algebra of all bounded linear operators acting on X.
The norms of vectors or operators acting on X will be denoted by k·k . A function f : [a, b] → X is called measurable if there exists a se- quence of simple functions f n : [a, b] → X which converges punctually almost everywhere on [a, b] at f. We recall also that a measurable func- tion f : [a, b] → X is Bochner integrable if and only if its norm function (i.e. the function t 7→ kf (t)k : [a, b] → R + ) is Lebesgue integrable on [a, b].
The following theorem holds [1].
Theorem 2. Assume that B : [a, b] → L (X) is H¨older continuous on [a, b], i.e.,
(1.4) kB (t) − B (s)k ≤ H |t − s| α for all t, s ∈ [a, b] ,
where H > 0 and α ∈ (0, 1].
If f : [a, b] → X is Bochner integrable on [a, b], then we have the inequality:
°
°
°
° B (t)
Z b a
f (s) ds − Z b
a
B (s) f (s) ds
°
°
°
° (1.5)
≤ H Z b
a
|t − s| α kf (s)k ds
≤ H ×
(b − t) α+1 + (t − a) α+1
α + 1 k|f |k [a,b],∞
if f ∈ L ∞ ([a, b] ; X) ;
"
(b − t) qα+1 + (t − a) qα+1 qα + 1
#
1qk|f |k [a,b],p
if p > 1, 1 p + 1 q = 1 and f ∈ L p ([a, b] ; X) ;
· 1
2 (b − a) +
¯
¯
¯
¯
t − a + b 2
¯
¯
¯
¯
¸ α
k|f |k [a,b],1
for any t ∈ [a, b].
The following corollary holds.
Corollary 1. Assume that B : [a, b] → L (X) is Lipschitzian with the constant L > 0. Then we have the inequality
°
°
°
° B (t)
Z b a
f (s) ds − Z b
a
B (s) f (s) ds
°
°
°
° (1.6)
≤ L Z b
a
|t − s| kf (s)k ds
≤ L ×
"
1
4 (b − a) 2 + µ
t − a + b 2
¶ 2 #
k|f |k [a,b],∞
if f ∈ L ∞ ([a, b] ; X) ;
"
(b − t) q+1 + (t − a) q+1 q + 1
#
1qk|f |k [a,b],p
if p > 1, 1 p + 1 q = 1 and f ∈ L p ([a, b] ; X) ;
· 1
2 (b − a) +
¯
¯
¯
¯
t − a + b 2
¯
¯
¯
¯
¸
k|f |k [a,b],1
for any t ∈ [a, b].
Remark 1. If we choose t = a+b 2 in (1.5) and (1.6), then we get the following midpoint inequalities:
°
°
°
°
B µ a + b 2
¶ Z b a
f (s) ds − Z b
a
B (s) f (s) ds
°
°
°
° (1.7)
≤ H Z b
a
¯
¯
¯
¯
s − a + b 2
¯
¯
¯
¯
α
kf (s)k ds
≤ H ×
1
2 α (α + 1) (b − a) α+1 k|f |k [a,b],∞
if f ∈ L ∞ ([a, b] ; X) ; 1
2 α (qα + 1)
1q(b − a) α+1q k|f |k [a,b],p
if p > 1, 1 p + 1 q = 1 and f ∈ L p ([a, b] ; X) ; 1
2 α (b − a) α k|f |k [a,b],1
and
°
°
°
°
B µ a + b 2
¶ Z b a
f (s) ds − Z b
a
B (s) f (s) ds
°
°
°
° (1.8)
≤ L Z b
a
¯
¯
¯
¯
s − a + b 2
¯
¯
¯
¯
kf (s)k ds
≤ L ×
1
4 (b − a) 2 k|f |k [a,b],∞
if f ∈ L ∞ ([a, b] ; X) ; 1
2 (q + 1)
1q(b − a) 1+1q k|f |k [a,b],p
if p > 1, 1 p + 1 q = 1 and f ∈ L p ([a, b] ; X) ; 1
2 (b − a) k|f |k [a,b],1 respectively.
Remark 2. Consider the function Ψ α : [a, b] → R, Ψ α (t) := R b
|t − s| α kf (s)k ds, α ∈ (0, 1). If f is continuous on [a, b], then Ψ α is a
differentiable and dΨ α (t)
dt = d
dt
·Z t a
(t − s) α kf (s)k ds + Z b
t
(s − t) α kf (s)k ds
¸
= α
·Z t a
kf (s)k (t − s) 1−α ds −
Z b t
kf (s)k (s − t) 1−α ds
¸ . If t 0 ∈ (a, b) is such that
Z t0
a
kf (s)k
(t 0 − s) 1−α ds = Z b
t
0kf (s)k (s − t 0 ) 1−α ds
and Ψ ′ s (·) is negative on (a, t 0 ) and positive on (t 0 , b) , then the best inequality we can get in the first part of (1.5) is the following one (1.9)
°
°
°
° B (t 0 )
Z b a
f (s) ds − Z b
a
B (s) f (s) ds
°
°
°
°
≤ H Z b
a
|t 0 − s| α kf (s)k ds.
If α = 1, then, for
Ψ (t) :=
Z b a
|t − s| kf (s)k ds,
we have
dΨ (t)
dt =
Z t a
kf (s)k ds − Z b
t
kf (s)k ds, t ∈ (a, b) , d 2 Ψ (t)
dt 2 = 2 kf (t)k ≥ 0, t ∈ (a, b) , which shows that Ψ is convex on (a, b).
If t m ∈ (a, b) is such that Z tm
a
kf (s)k ds = Z b
t
mkf (s)k ds,
then the best inequality we can get from the first part of (1.6) is
°
°
°
° B (t m )
Z b a
f (s) ds − Z b
a
B (s) f (s) ds
°
°
°
° (1.10)
≤ L Z b
a
sgn (s − t m ) s kf (s)k ds.
We recall that a function F : [a, b] → L (X) is said to be strongly continuous if for all x ∈ X, the maps s 7→ F (s) x : [a, b] → X are continuous on [a, b]. In this case the function s 7→ kB (s)k : [a, b] → R + is (Lebesgue) measurable and bounded ([4]). The linear operator L = R b
a F (s) ds (defined by Lx := R b
a F (s) xds for all x ∈ X) is bounded, because
kLxk ≤ µZ b
a
kF (s)k ds
¶
· kxk for all x ∈ X.
The following theorem also holds [1].
Theorem 3. Assume that f : [a, b] → X is H¨older continuous, i.e., (1.11) kf (t) − f (s)k ≤ K |t − s| β for all t, s ∈ [a, b] ,
where K > 0 and β ∈ (0, 1].
If B : [a, b] → L (X) is strongly continuous on [a, b] , then we have the inequality:
(1.12)
°
°
°
° µZ b
a
B (s) ds
¶
f (t) − Z b
a
B (s) f (s) ds
°
°
°
°
≤ K Z b
a
|t − s| β kB (s)k ds
≤ K ×
(b−t)
β+1+(t−a)
β+1β+1 k|B|k [a,b],∞
if kB (·)k ∈ L ∞ ([a, b] ; R + ) ; h (b−t)qβ+1+(t−a)
qβ+1
qβ+1
i
1qk|B|k [a,b],p
if p > 1, 1 p + 1 q = 1
and kB (·)k ∈ L p ([a, b] ; R + ) ;
£ 1
2 (b − a) + ¯
¯t − a+b 2 ¯
¯
¤ β
k|B|k [a,b],1 for any t ∈ [a, b].
The following corollary holds.
Corollary 2. Assume that f and B are as in Theorem 3. If, in addition, R b
a B (s) ds is invertible in L (X) , then we have the inequality:
°
°
°
°
° f (t) −
µZ b a
B (s) ds
¶ −1 Z b a
B (s) f (s) ds
°
°
°
°
° (1.13)
≤ K
°
°
°
°
° µZ b
a
B (s) ds
¶ −1 °
°
°
°
° Z b
a
|t − s| β kB (s)k ds for any t ∈ [a, b].
Remark 3. It is obvious that the inequality (1.13) contains as a particular case what is the so called Ostrowski’s inequality for weighted integrals (see (1.2)).
2. The results
The following lemma concerning an integral identity that will be used in the following holds.
Lemma 1. Let f : [a, b] → H be an absolutely continuous function and g : [a, b] → H be Bochner integrable on [a, b] , where (H, h·, ·i) is a Hilbert space on K (K = R, C) . Then for any x ∈ [a, b] , we have the identity
(2.1)
¿
f (x) , (B) Z b
a
g (t) dt À
= Z b
a
hf (t) , g (t)i dt + Z b
a
f ′ (τ ) , K (τ, x)® dx,
where
K (τ, x) :=
(B) R τ
a g (s) ds if a ≤ τ ≤ x ≤ b;
− (B) R b
τ g (s) ds if a ≤ x < τ ≤ b and (B) R b
a g (t) dt denotes the Bochner’s integral of g on [a, b] . Proof. Integrating by parts, we may write:
Z x a
¿
f ′ (τ ) , (B) Z τ
a
g (s) ds À (2.2) dτ
=
¿
f (τ ) , (B) Z τ
a
g (s) ds À¯
¯
¯
¯
x a
− Z x
a
hf (τ ) , g (τ )i dτ
=
¿
f (x) , (B) Z x
a
g (s) ds À
− Z x
a
hf (τ ) , g (τ )i dτ and
Z b x
¿
f ′ (τ ) , − (B) Z b
τ
g (s) ds À (2.3) dτ
= −
¿
f (τ ) , (B) Z b
τ
g (s) ds À¯
¯
¯
¯
b
x
− Z b
x
hf (τ ) , g (τ )i dτ
=
¿
f (x) , (B) Z b
x
g (s) ds À
− Z b
x
hf (τ ) , g (τ )i dτ.
If we add (2.2) and (2.3) we deduce the desired identity (2.1).
For g as above, we now define the following associated functions γ (τ ) : =
°
°
°
° (B)
Z τ
a
g (s) ds
°
°
°
°
, τ ∈ [a, b]
˜
γ (τ ) : =
°
°
°
° (B)
Z b τ
g (s) ds
°
°
°
°
, τ ∈ [a, b]
and Γ 1 (x) :=
Z x a
γ (τ ) dτ + Z b
x
˜
γ (τ ) dτ, x ∈ [a, b] provided γ, ˜ γ ∈ L 1 [a, b] ,
Γ q (x) : = µZ x
a
γ q (τ ) dτ + Z b
x
˜
γ q (τ ) dτ
¶
1 q
, x ∈ [a, b]
provided γ, ˜ γ ∈ L q [a, b] , q ∈ (1, ∞) ,
Γ ∞ (x) : = max Ã
sup
τ ∈[a,x]
γ (τ ) , sup
τ ∈[x,b]
˜ γ (τ ) dτ
!
, x ∈ [a, b]
provided γ, ˜ γ ∈ L ∞ [a, b] . We may state the following estimation result:
Theorem 4. Let f and g be as in Lemma 1. Then for any x ∈ [a, b]
we have the inequality:
¯
¯
¯
¯
¿
f (x) , (B) Z b
a
g (t) dt À
− Z b
a
hf (t) , g (t)i dt
¯
¯
¯
¯ (2.4)
≤ Z x
a
° °f ′ (τ ) °
° γ (τ ) dτ + Z b
x
° °f ′ (τ ) °
° γ ˜ (τ ) dτ =: M (x) . If we denote (for a ≤ α < β ≤ b)
¯
¯
°
° f ′ °
°
¯
¯ [α,β],∞ = ess sup
τ ∈[α,β]
°
° f ′ (τ ) °
° ,
¯
¯
° °f ′ °
°
¯
¯ [α,β],p = µZ β
α
° °f ′ (τ ) °
°
p dτ
¶
1 p
, p ≥ 1 then we have the inequalities for M (x) as follows
M (x) (2.5)
≤
|kf ′ k| [a,x],∞ · R x
a γ (τ ) dτ + |kf ′ k| [x,b],∞ · R b
x ˜ γ (τ ) dτ
if f ′ ∈ L ∞ [a, b] , γ, ˜ γ ∈ L ∞ [a, b] ,
|kf ′ k| [a,x],p · ¡R x
a γ q (τ ) dτ ¢1q
+ |kf ′ k| [x,b],p · ³ R b
x ˜ γ q (τ ) dτ ´1q
if p > 1, 1 p + 1 q = 1, f ′ ∈ L p [a, b] , γ, ˜ γ ∈ L q [a, b] ,
|kf ′ k| [a,x],1 · sup
τ ∈[a,x]
γ (τ ) + |kf ′ k| [x,b],1 · sup
τ ∈[x,b]
˜ γ (τ ) dτ
≤
Γ 1 (x) · |kf ′ k| [a,b],∞ if f ′ ∈ L ∞ [a, b] , γ, ˜ γ ∈ L ∞ [a, b] , Γ p (x) · |kf ′ k| [a,b],p
if p > 1, 1 p + 1 q = 1, f ′ ∈ L p [a, b] , γ, ˜ γ ∈ L q [a, b] ,
Γ ∞ (x) · |kf ′ k| [a,b],1 if γ, ˜ γ ∈ L ∞ [a, b] .
Proof. Taking the modulus in (2.1), we may write that
¯
¯
¯
¯
¿
f (x) , (B) Z b
a
g (t) dt À
− Z b
a
hf (t) , g (t)i dt
¯
¯
¯
¯
≤ Z x
a
¯
¯
¯
¯
¿
f ′ (τ ) , (B) Z τ
a
g (s) ds À¯
¯
¯
¯ dτ +
Z b x
¯
¯
¯
¯
¿
f ′ (τ ) , (B) Z b
τ
g (s) ds À¯
¯
¯
¯ dτ (by Schwartz’s inequality in H, h·, ·i )
≤ Z x
a
°
° f ′ (τ ) °
°
°
°
°
° (B)
Z τ a
g (s) ds
°
°
°
° dτ +
Z b x
°
° f ′ (τ ) °
°
°
°
°
° (B)
Z b τ
g (s) ds
°
°
°
° dτ
= M (x)
and the inequality (2.4) is proved.
Now, observe that Z x
a
° °f ′ (τ ) °
° γ (τ ) dτ ≤ ¯
¯
° °f ′ °
°
¯
¯ [a,x],∞ · Z x
a
γ (τ ) dτ and
Z b x
° °f ′ (τ ) °
° ˜ γ (τ ) dτ ≤ ¯
¯
° °f ′ °
°
¯
¯ [x,b],∞ · Z b
x
˜ γ (τ ) dτ giving the first part of the first inequality in (2.5).
Using H¨older’s integral inequality, we may write for p > 1, 1 p + 1 q = 1, that
Z x a
° °f ′ (τ ) °
° γ (τ ) dτ ≤ µZ x
a
° °f ′ (τ ) °
°
p dτ
¶
1p· µZ x
a
γ q (τ ) dτ
¶
1q= ¯
¯
° °f ′ °
°
¯
¯ [a,x],p
µZ x a
γ q (τ ) dτ
¶
1qand
Z b x
°
° f ′ (τ ) °
° γ ˜ (τ ) dτ ≤ ¯
¯
°
° f ′ °
°
¯
¯ [x,b],p · µZ b
x
˜ γ q (τ ) dτ
¶
1 q
giving the second part of the first inequality in (2.5).
The last part is obvious.
For the second inequality in (2.5) we observe that
¯
¯
° °f ′ °
°
¯
¯ [a,x],∞ · Z x
a
γ (τ ) dτ + ¯
¯
° °f ′ °
°
¯
¯ [x,b],∞ · Z b
x
˜ γ (τ ) dτ
≤ max n ¯
¯
° °f ′ °
°
¯
¯ [a,x],∞ , ¯
¯
° °f ′ °
°
¯
¯ [x,b],∞
o
·
½Z x a
γ (τ ) dτ + Z b
x
˜ γ (τ ) dτ
¾
= ¯
¯
° °f ′ °
°
¯
¯ [a,b],∞ · Γ 1 (x) ,
¯
¯
° °f ′ °
°
¯
¯ [a,x],p · µZ x
a
γ q (τ ) dτ
¶
1q+ ¯
¯
° °f ′ °
°
¯
¯ [x,b],p · µZ b
x
˜ γ q (τ ) dτ
¶
1 q
≤ ³ ¯
¯
°
° f ′ °
°
¯
¯
p
[a,x],p + ¯
¯
°
° f ′ °
°
¯
¯
p [x,b],p
´
p1×
"
µZ x a
γ q (τ ) dτ
¶
1q# q
+
µZ b
x
˜
γ q (τ ) dτ
¶
1 q
q
1 q
= ¯
¯
° °f ′ °
°
¯
¯ [a,b],p · Γ q (x) , and
¯
¯
° °f ′ °
°
¯
¯ [a,x],1 · sup
τ ∈[a,x]
γ (τ ) + ¯
¯
° °f ′ °
°
¯
¯ [x,b],1 · sup
τ ∈[x,b]
˜ γ (τ )
≤ max (
sup
τ ∈[a,x]
γ (τ ) , sup
τ ∈[x,b]
˜ γ (τ ) dτ
) h ¯
¯
°
° f ′ °
°
¯
¯ [a,x],1 + ¯
¯
°
° f ′ °
°
¯
¯ [x,b],1
i
= ¯
¯
° °f ′ °
°
¯
¯ [a,b],1 · Γ ∞ (x) ,
and the last part of the inequality (2.5) is thus proved.
Remark 4. If g ∈ L ∞ [a, b] , then, for any τ ∈ [a, b]
γ (τ ) ≤ (τ − a) |kgk| [a,τ ],∞ and γ ˜ (τ ) ≤ (b − τ ) |kgk| [τ,b],∞ , if g ∈ L q [a, b] ³
q > 1, 1 p + 1 q = 1 ´ , then
γ (τ ) ≤ (τ − a)
1p|kgk| [a,τ ],q and γ ˜ (τ ) ≤ (b − τ )
1p|kgk| [τ,b],q , and finally, if g ∈ L 1 [a, b] , then
γ (τ ) ≤ |kgk| [a,τ ],1 and γ ˜ (τ ) ≤ |kgk| [τ,b],1 .
Consequently, we may bound M (x) (defined in Theorem 4) in an- other manner than those in Theorem 4, as follows:
M (x) (2.6)
≤
Z x
a
kf ′ (τ )k (τ − a) |kgk| [a,τ ],∞ dτ +
Z b x
kf ′ (τ )k (b − τ ) |kgk| [τ,b],∞ dτ if g ∈ L ∞ [a, b] ,
Z x a
kf ′ (τ )k (τ − a)
1p|kgk| [a,τ ],q dτ +
Z b
x
kf ′ (τ )k (b − τ )
p1|kgk| [τ,b],q dτ if p > 1, 1 p + 1 q = 1, g ∈ L p [a, b] , Z x
a
kf ′ (τ )k |kgk| [a,τ ],1 dτ +
Z b x
kf ′ (τ )k |kgk| [τ,b],1 dτ if g ∈ L 1 [a, b] ,
≤
|kgk| [a,x],∞
Z x a
kf ′ (τ )k (τ − a) dτ + |kgk| [x,b],∞
Z b x
kf ′ (τ )k (b − τ ) dτ =: M ∞ (x) if g ∈ L ∞ [a, b] ,
|kgk| [a,x],q Z x
a
kf ′ (τ )k (τ − a)
1pdτ + |kgk| [x,b],q
Z b x
kf ′ (τ )k (b − τ )
1pdτ =: M q (x) if p > 1, 1 p + 1 q = 1, g ∈ L p [a, b] ,
|kgk| [a,x],1 |kf ′ k| [a,x],1 + |kgk| [x,b],1 |kf ′ k| [x,b],1 =: M 1 (x)
if g ∈ L 1 [a, b] .
Since
x
Z
a
° °f ′ (τ ) °
° (τ − a) dτ (2.7)
≤
|kf ′ k| [a,x],∞
Z x a
(τ − a) dτ
|kf ′ k| [a,x],α µZ x
a
(τ − a) dτ
¶
1β, α > 1, α 1 + β 1 = 1 (x − a) |kf ′ k| [a,x],1
=
1
2 (x − a) 2 |kf ′ k| [a,x],∞ if f ′ ∈ L ∞ [a, b]
1 (β + 1)
β1(x − a) 1+1β |kf ′ k| [a,x],α
if f ′ ∈ L α [a, b] , α > 1, α 1 + β 1 = 1 (x − a) |kf ′ k| [a,x],1
and, similarly,
b
Z
x
° °f ′ (τ ) °
° (b − τ ) dτ (2.8)
≤
1
2 (b − x) 2 |kf ′ k| [x,b],∞ if f ′ ∈ L ∞ [a, b]
1 (β + 1)
β1(b − x) 1+β1 |kf ′ k| [x,b],α
if f ′ ∈ L α [a, b] , α > 1, α 1 + β 1 = 1
(b − x) |kf ′ k| [x,b],1
then we get the following bound for M ∞ (x) (defined in (2.6)) M ∞ (x)
(2.9)
≤
1 2
h (x − a) 2 |kgk| [a,x],∞ |kf ′ k| [a,x],∞
+ (b − x) 2 |kgk| [x,b],∞ |kf ′ k| [x,b],∞ i if g ∈ L ∞ [a, b] and f ′ ∈ L ∞ [a, b] ; 1
(β + 1)
β1h (x − a) 1+1β |kgk| [a,x],∞ |kf ′ k| [a,x],α + (b − x) 1+β1 |kgk| [x,b],∞ |kf ′ k| [x,b],α i
|kgk| [x,b],∞ |kf ′ k| [x,b],α i
if g ∈ L ∞ [a, b]
and f ′ ∈ L α [a, b] , α > 1, α 1 + β 1 = 1;
(x − a) |kgk| [a,x],∞ |kf ′ k| [a,x],1 + (b − x) |kgk| [x,b],∞ |kf ′ k| [x,b],1 if g ∈ L ∞ [a, b] and f ′ ∈ L 1 [a, b] . We also have
(2.10)
x
Z
a
°
° f ′ (τ ) °
° (τ − a)
p1dτ
≤
|kf ′ k| [a,x],∞
Z x a
(τ − a)
1pdτ
|kf ′ k| [a,x],α µZ x
a
(τ − a)
βpdτ
¶
β1, α > 1, α 1 + β 1 = 1
(x − a)
β1|kf ′ k| [a,x],1
=
p
p + 1 (x − a)
p1+1 |kf ′ k| [a,x],∞ if f ′ ∈ L ∞ [a, b]
µ p p + β
¶
1β
(x − a)
1p+
1β|kf ′ k| [a,x],α , if f ′ ∈ L α [a, b]
α > 1, α 1 + β 1 = 1
(x − a)
1p|kf ′ k| [a,x],1
and, similarly,
b
Z
x
° °f ′ (τ ) °
° (b − τ )
1pdτ (2.11)
≤
p
p + 1 (b − x)
1p+1 |kf ′ k| [x,b],∞ if f ′ ∈ L ∞ [a, b]
µ p p + β
¶
β1(b − x)
1p+
β1|kf ′ k| [x,b],α , if f ′ ∈ L α [a, b]
α > 1, α 1 + β 1 = 1 (b − x)
1p|kf ′ k| [x,b],1
and thus we may point out the following bounds for the M q (x) (defined in (2.6))
M q (x) (2.12)
≤
p p + 1
h
(x − a)
1p+1 |kgk| [a,x],q |kf ′ k| [a,x],∞
+ (b − x)
1p+1 |kgk| [x,b],q |kf ′ k| [x,b],∞ i
if g ∈ L q [a, b] , p > 1, 1 p + 1 q = 1, f ′ ∈ L ∞ [a, b] ; µ p
p + β
¶
1β