Chapter 4
The statistical
interpretation of entropy
4.1 Introduction
• From the formal statement of the Second Law of Thermodynamics, it is difficult to assign a physical
significance or a physical quality to entropy. (different from internal energy, U)
• The 2
ndlaw- law only in that it has not been disproved.
Evidence? No perpetual motion machine.
• The physical interpretation of entropy had to await the
development of quantum theory and statistical mechanics
4.2 Entropy and disorder on an atomic scale
• The more mix-up the constituent particles in the system, the larger the value of its entropy. (Gibbs)
• Atomic arrangement from solid, to liquid, to gas: more disorder (entropy increases)
• Thus, S, can be related with atomic scale randomness or disorder
• If the melting process (more randomness of atoms) is conducted at constant pressure
∆S > 0 more mix-up-ness
4.2 Entropy and disorder on an atomic scale
• In super-cooled liquid case: spontaneous freeze (irreversible), it appears decrease in the degree disorder (l → s).
• Entropy has to increase due to ∆S
irr> 0
• Thus, it is not true if we consider the degree of order of the heat bath:
Increase in ordering is less tan increase in disordering of bath: ∆S
total> 0
4.2 Entropy and disorder on an atomic scale
• If the freezing occurs at the equilibrium melting point,
then, the increase in the degree of order of the freezing system = the decrease in the degree of order of the heat reservoir absorbing the heat of solidification
• ∆s
total= 0
• The equilibrium melting or freezing temperature = temp. at which no
change in the degree of order of the system + heat bath occurs. Only at
this temperature the solid phase is in equilibrium with the liquid phase.
4.3 The concept of microstate
• The effect of the quantization of energy with a perfect crystal: The crystal contains n
particles and has he energy, U. Then statistical mechanics asks this: (1) in how many ways can the n particles be distributed over the available energy levels such that the total energy of the crystal is U, and (2) which is the most probable?
• Consider that the crystal contains 3 identical particles located on 3 indistinguishable sites A, B, and C. If the energy levels are ε0 (=0), ε1 (=u), ε2 (=2u) and ε3 (=3u) and total energy is U=3u (4 energy levels available), the answer will be..
4.3 The concept of microstate
Total 10 microstates correspond to one macrostate!
(1) Representative cases to meet the U requirement (2) Possible # of combination for each case
4.4 Determination of the most probable microstate
• The number of arrangement within a given distribution, Ω, can be calculated.
• If n particles are distributed among the energy level such that n0 in level ε0, n1 in level ε1, nr in level εr ….
(eq 4.1)
(eq 4.2)
4.4 Determination of the most probable microstate
(eq 4.3) As the macrostate of a system is determined by the fixed values of U, V and n, any distribution of particles among the energy levels must conform with the following conditions.
U = constant = n0ε0 + n1ε1 + n2ε2 ……..+ nrεr ….
n = constant = n0 + n1 + n2 +……..+ nr …. (eq 4.4)
Thus, δU = Σ δniε1= 0 and δn = Σ δni = 0
(eq 4.5) (eq 4.6)
4.4 Determination of the most probable microstate
(eq 4.8) (eq 4.7)
4.4 Determination of the most probable microstate
(eq 4.5)
(eq 4.8) (eq 4.6)
(eq 4.10) (eq 4.9)
4.4 Determination of the most probable microstate
(eq 4.13) (eq 4.12) (eq 4.11)
4.4 Determination of the most probable microstate
The distribution of particles in the energy levels for max. Ω (the most probable
distribution) is the one which the occupancy of the levels decreases exponentially with εi and actually be determined by β.
β = 1/kT (eq 4.14)
4.5 The influence of temperature
(eq 4.15) As T increases, β decreases, where β = 1/kT. Upper levels become
more populated since avg. energy of the particles increases (increase in U/n). For fixed V, n: U increases as T does.
• When the number of particles is extremely large, total number of arrangements can be equated with max number of arrangements. i.e., ln Ωmax ~ ln Ω total
P ?
4.5 The influence of temperature
(eq 4.15)
4.6 Thermal equilibrium and the Boltzman equation
When the exchange of energy carried out at constant total volume (eq 4.16)
Consider a system of particles in thermal equilibrium with a heat bath and let the sate of the combined system be fixed by fixing U, V, and n where,
4.6 Thermal equilibrium and the Boltzman equation
When the exchange of heat occurs at constant temperature and occurs reversibly
As both entropy and number of arrangements are state functions (eq 4.16)
(eq 4.17)
4.7 Heat flow and the production of entropy
• The condition for A to be in thermal equilibrium with B is
• And if total energy remains constant
(eq 4.18)
(eq 4.19)
(eq 4.20)
4.7 Heat flow and the production of entropy
• When a quantity of heat is transferred from A to B at total constant energy
• So if the temperature of A and B is same, the equation will be zero.
(eq 4.21)
4.8 Configurational entropy and thermal entropy
4.8 Configurational entropy and thermal entropy
4.8 Configurational entropy and thermal entropy
• If 𝑛𝑛
𝑎𝑎atoms of A are mixed with 𝑛𝑛
𝑏𝑏atoms of B
(eq 4.22)
(eq 4.23)
4.8 Configurational entropy and thermal entropy
• The total entropy of a system consists of its thermal entropy(𝑆𝑆𝑡𝑡𝑡) and its configurational entropy(𝑆𝑆𝑐𝑐𝑐𝑐𝑐𝑐𝑐𝑐)
• The number of spatial configurations available to two closed systems placed in thermal contact is unity.
(eq 4.24)